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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
22 Evaluate\int_{0}^{\pi / 2} \frac{\sin x}{\sin x+\cos x}properties.sinx +cosx |
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| 2. |
/20. Mr Mehta purchased a video forき20000 anda television for30000. On the video he lost5% and on the television he gained 8%. Find his total gain or loss per cent. |
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| 3. |
17. Find the number of permutations of the letters of the word ENCLISHthe word 'ENCLISH.Hw. Howmany of these begin with E and end with I? |
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Answer» if we fix E and Ithen there are left 5 letters in betweenand these can be arranged in 5! wayshence answer is 5! thank you so much |
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| 4. |
20. Mr Mehta purchased a video for 20000 and a television for 30000. On the vidco he lost5% and on the televisionhe gained 8%. Find his total gaina loss per cent. |
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| 5. |
Find in how many years Rs. 2,000 amounts to? Rs. 2247.20 at 5% pa compound |
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Answer» thanks |
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| 6. |
-Lamy mume Whose retail price is 37950?Mr Mehta purchased a video for 20000 and a television for 30000. On the video he lost5% and on the television he gained 8%. Find his total gain or loss per cent.! |
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| 7. |
19. If the manufacturer galls 10,the production cost of a washing machine whose retail price is 37950!20000 and a television for 30000. On the video he lost20. Mr Mehta purchased a video for5% and on the television he gained 8%. Find his total gain or loss per cent. |
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| 8. |
16. Mr Mehta covered a journey of 2315 kilometres. He travelled 1986 kilometres bytrain and the rest by bus. What distance did he cover by bus? |
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Answer» ruytrrf hjjehey e by s d.l d.l Roll ubal guruvani and stitching 329 kilometers distance he covered by bus |
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| 9. |
the degree Ur uionWhat is the relation between deggree of their product ?the relation between degi(5) Divd write the answer in the given formDividend-DivisorOuotient + Remainderinl in standard form, p(x) = 2 + 2x2 |
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| 10. |
Show that\left[ \begin{array}{cc}{5} & {-1} \\ {6} & {7}\end{array}\right] \left[ \begin{array}{ll}{2} & {1} \\ {3} & {4}\end{array}\right] \neq \left[ \begin{array}{ll}{2} & {1} \\ {3} & {4}\end{array}\right] \left[ \begin{array}{rr}{5} & {-1} \\ {6} & {7}\end{array}\right] |
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Answer» Therefore, they are not equal. |
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| 11. |
\left[ \begin{array}{cc}{a} & {b} \\ {-b} & {a}\end{array}\right] \left[ \begin{array}{cc}{a} & {-b} \\ {b} & {a}\end{array}\right] \text { (a) } \left[ \begin{array}{l}{1} \\ {2} \\ {3}\end{array}\right] \left[ \begin{array}{lll}{2} & {3} & {4}\end{array}\right] |
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| 12. |
In 4 years, Rs.6,500 amounts of Rs.8,840 at certain rate of intrest.In what time will Rs.1,600amount to Rs. 1,816 at the same rate |
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Answer» SI = P*R*T/1008840-6500 = 6500*R*3/1002340 = 65*3*RR = 780/65R = 12% Now time taken for SI = 1816-1600 = 216 216 = 1600*12*T/100T = 216/(16*12) = 18/16 = 9/8 = 1.12 years |
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| 13. |
A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 yearsat the rate of simple interest. What is the rate ofinterest? |
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| 14. |
Compute the following:\left[ \begin{array}{cc}{a} & {b} \\ {-b} & {a}\end{array}\right]+\left[ \begin{array}{ll}{a} & {b} \\ {b} & {a}\end{array}\right]\left[ \begin{array}{rrr}{-1} & {4} & {-6} \\ {8} & {5} & {16} \\ {2} & {8} & {5}\end{array}\right]+\left[ \begin{array}{rrr}{12} & {7} & {6} \\ {8} & {0} & {5} \\ {3} & {2} & {4}\end{array}\right]\left[ \begin{array}{cc}{a^{2}+b^{2}} & {b^{2}+c^{2}} \\ {a^{2}+c^{2}} & {a^{2}+b^{2}}\end{array}\right]+\left[ \begin{array}{cc}{2 a b} & {2 b c} \\ {-2 a c} & {-2 a b}\end{array}\right]\left[ \begin{array}{cc}{\cos ^{2} x} & {\sin ^{2} x} \\ {\sin ^{2} x} & {\cos ^{2} x}\end{array}\right]+\left[ \begin{array}{cc}{\sin ^{2} x} & {\cos ^{2} x} \\ {\cos ^{2} x} & {\sin ^{2} x}\end{array}\right] |
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Answer» i)a+a b+b = 2a 2b -b+b a+a 0 2aii) a^2+2ab+b^2 b^2+2bc+c^2 a^2-2ac+c^2 a^2-2ab+b^2=(a+b)^2 (b+c)^2 (a-c)^2 (a-b)^2iii) 11 11 0 16 5 21 5 10 9iv) sin^2x+cos^2x sin^2x+cos^2x= 1 1 sin^2x+cos^2x sin^2x+cos^2x 1 1 |
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| 15. |
x \left[ \begin{array}{l}{2} \\ {3}\end{array}\right]+y \left[ \begin{array}{r}{-1} \\ {1}\end{array}\right]=\left[ \begin{array}{c}{10} \\ {5}\end{array}\right] x=? y=? |
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Answer» 2x-y = 10 3x+y = 5 Solving, we get 5x = 15 x = 3 So, y = 5-9 = -4 Thanks Bhai |
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| 16. |
20. Mr Mehta purchased a video for20000 and a television for30000. On the video he lost5% and on the television he gained 8%. Find his total gain or loss per cent. |
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| 17. |
2. (8 (2)-8) |
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| 18. |
. Find the time in which an amount of Rs 6250amounts to Rs 6760 at 4% per annum, if theinterest is compounded annually |
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| 19. |
in what time will a sum of rupees 3750 at 20% per annum compounded annually amounts to 6480. |
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| 20. |
Long DivisionFour Digit Dividends and Two Digit Dhiser6 4, 21 |
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Answer» 4281 when divided by 66 gives 64 as quotient and 57 as remainder. 6062 when divided by 20 gives 303 as quotient and 2 as remainder. |
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| 21. |
28.Rahul plays for-of an hour while Rohit plays forof an hour. Who plays for more time? |
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Answer» Rahul plays more than Rohit 1 hr =60 min.Rahul plays=2/4 of 60 min.=30 min.Rohit plays=1/5 of 60 min=12 min.Rahul plays for more time |
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| 22. |
५८] 73 एक टिन 40 सेमी लम्था, 40 सेमी० चौड़ा तथा 60 सेमी ऊँचा है. इसमें 30 सेमी ऊँचाई तक वनस्पति तेल भरा(a) 100 लीटर (5) 80 लाटरहुआ हैं. टिन में कितना तेल और भरना चाहिए कि टिन पूरी तरह से भर जाये ?(रेलवे, 2007)(c) 48000 घन सेमोः (a) 480000 घन सेमी(a) 480 घन सेमी. (b) 48000 घन सेंमी.। जागा १ सेमी चौड़ा तथा । सेमी० ऊँधा है. इसे पिघला कर एक घन बनाया |
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Answer» 4800 ans aayega think hai |
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| 23. |
Sanjeev borrowed ? 24000 from a bank to buy a computer. If the rate of interest be10% pa. compounded annually, what interest will he have to make after 2 years?or 3 |
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| 24. |
6.Aman borrows 14,500 at 11% per annum for three years at simple interestand Tarun borrows the same amount at 10% per annum for the same timecompounded annually. Who pays more interest and by how much? |
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| 25. |
The scale of mapart on the map?t a map is 1: 25000000. What is the actual distance between the two towns, if they are 4 cm48000.. . .. . ik, i, a ,5 Find the savings, if the income is |
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| 26. |
Method(buy long division2.3 x - 4x ta |
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| 27. |
Mr Mehta purchased a video for? 20000 and a television for? 30000. On the video he lést5% and on the television he gained 8%. Find his total gain or loss per cent.20. |
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| 28. |
7. Sanjeev borrows25,000 at 8% pa. for 3 years. At the end of 3 years, he pays19,000and a video camera. What is the value of the video camera?HoTs] |
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| 29. |
27. Find the compound interest on R 48000 forone year at 8% per annum, when compundhalf-yearly.(a) 51916(c) 3916.80(b) 51916.80(d) 3910.80 |
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Answer» A = 48000(1+8/200)(1+8/200) = 48000(1.04)(1.04) = 51916.80 I = A - P = 51916.80 - 48000 = 3916.80 here time period is 2 or 1 |
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| 30. |
The weight of one tablet is 144 mg. Find the weightof such 10000 tablets in kilogram |
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Answer» the answer is 14.4 kilogram 1 tablet = 144 mg10000 tablet = 144 * 10000 = 1440000 mg = 1440000/100 =14400 gm =14400/1000=14.4 kg Given,weight of one tablet = 144 mg,weight of 10,000 tablets = 144 * 10,000, = 14.4 kg. 1440000 is the best anser |
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| 31. |
1+3+455+764 |
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Answer» by basic addition 1+ 3+ 455+ 764=1223 |
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| 32. |
Q.13) Find square root of the following.i) 764 ii) | 144 |
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Answer» i) √ 64 = √ 8² = 8 ii) √144 = √ 12² = 12 (i) √64 = 8(ii) √144 = 12 |
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| 33. |
7. In a school, there are 1728 students in theprimary section, 1212 students in the middlesection and 764 students in the seniorsection. Find the total number of students inthe school.bie |
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Answer» Total no. of students= 1728+1212+764=3704 (Ans) 3704 hoga iska answre ok so do it |
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| 34. |
If x and y are inversely proportional then find the value of a. |
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| 35. |
324|4. यदि 324 =2 हो, तो ४ का मान है।हैVX |
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Answer» X=8.1 is the value of X X= 8.1 the correct answer of the given question x=8.1 is the correct answer X=8,1 is the right answer. (√32.4)/2=√x5.69/2=√xx= 8.10is correct answer |
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| 36. |
. Why did India send a Peace Keeping, Force to Sri Lanka? |
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| 37. |
Find the H.C.F. of 252, 324 and 594 by long division methFirst, we find H.C.F. of 252 and 324. |
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| 38. |
(A) 324(C) 600(B) 256(D)216 |
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Answer» % of boys = 60%% of girls= 100%-60%=40% no of girls = 216 let the total no of students be x so 40% of x = 21640/100*x = 216x = 216*100/40x = 540total no of students = 540no of boys = 540 - 216= 324 |
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| 39. |
Shankar takes a loan of RS. 10000 at a compou10% per annuma. Find the compound interest after one yearb. Find the compound interest for 2 years. |
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| 40. |
764 - 324 |
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Answer» 764- 324________ 440your answer is 440plz like Your ans is 440 if we calculate 764-324=44. 440 is the correct answer 764-324=440 is the answer. 764-324=440 is the answer. 440 is the best answer 440 is the right answer |
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| 41. |
find the area of the playground. (lake π22nrectangular piece is 20 m long and 15 m wide. From its four corners, quadrants ofradii3.5 m have been cut. Find the area of the remaining part. |
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| 42. |
tIo06 (a) 0 ) 09 (a) St ()(Vă¤102)E10Z) |
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Answer» Given , 2 cosθ = √3 cosθ = √3/2 cosθ = cos30° θ = 30° θ = 10° |
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| 43. |
Find the principal, if the interest is Rs.180 per year 5% per annum |
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Answer» Interest = Principal × Rate of Interest × time / 100 180 = Principal × 5 × 1 /100 Principal = 180 × 20 = 3600 If you find this answer helpful then like it. |
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| 44. |
10. x,y and z are tiu 192and z are three sums of money such that y is the simple interest on x and z is the simplest on u for the same time and same rate. Which of the following is correct?(b 2interest on y for the sa |
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| 45. |
196:256::324:? |
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Answer» 196/256 = 324/x x = 324*256/196 x = 423.2 l thick not |
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| 46. |
Find two numbers whose meanproportional is 16 and the thirdproportional is 128 |
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Answer» Let the number be a and b ∴√ab = 16 =>ab = 16^2 =256............(i) Again, a/b = b/128 =>b^2=128a=128∗256/b ...... ( a=256/b) ......From (i) =>b^3=128∗256 =>b =32 ∴ab=256 =>a=256/b = 256/32 =8 ∴a = 8 and b = 32 |
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| 47. |
(g. Amount = Rs 1300,Time = 2 years,Interest = 15% per annumPrincipal =LEILULLLIIII |
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Answer» (1300×15×2)/100390 is interest (1300×15×2)/100390 is interest (1300×15×2)/100390 is interest |
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| 48. |
A square whose side is 2 metres has itscorners cut away so as to form anoctagon with all sides equal. Then, thelength of each side of the octagon inmetres is |
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Answer» ABCD is square and PQRSTUVW is octagon with equal sides constructed with in the square. In order to have octagon with equal sides, we should have AP=QB=BR=SC=CT=…. Let AP=AW=x; Let PQ = y; as all sides of octagon are equal, QR=RS=ST=TU=UV=VW=WP=y; As the length of side of square is 2, 2x+y = 2 ------(1) Applying Pythagoras to the right triangle APW, y2= x2+x2= 2x2 => y= x√2 ------(2) Solving (1) and (2): 2x+x√2 = 2 => x = 2/(2+√2) = √2/(√2+1) => y = x√2 = 2/(√2+1) |
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| 49. |
--(a) 22338 (b) 23328 (L).36. वह न्यूनतम पूर्ण वर्ग संख्या क्या होगी जो 12, 15 तथा 25 से पूर्णतया विभक्त हो ?(d) 1600(c) 1300(a) 400(b) 900(एस०एस०सी० परीक्षा, 2070 |
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Answer» 12,15,25 का ल.स. =300 तो 900 पूरी तरह काट जाएगी 900 / 12 = 75900 / 15 = 60900 / 25 = 36 so, 900 is a right answer |
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| 50. |
(IDtiSt13 t26 |
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Answer» thanks |
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