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Find two numbers whose meanproportional is 16 and the thirdproportional is 128 |
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Answer» Let the number be a and b ∴√ab = 16 =>ab = 16^2 =256............(i) Again, a/b = b/128 =>b^2=128a=128∗256/b ...... ( a=256/b) ......From (i) =>b^3=128∗256 =>b =32 ∴ab=256 =>a=256/b = 256/32 =8 ∴a = 8 and b = 32 |
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