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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6151. |
Cot(_675) |
| Answer» -cot(2×360-45),-cot(-45)......... (cot is -ve in 4th quardrant)-(-1)=+1 | |
| 6152. |
show that √3cosec 20°- sec20°=4 |
| Answer» | |
| 6153. |
What are multiple and divisor |
| Answer» | |
| 6154. |
Why imaginary axis of a complex number is taken perpendicular to the real axis |
| Answer» Because imaginary axis is y axis and it is perpendicular to x axis | |
| 6155. |
1/3x-5/2=6 |
| Answer» On taking LCM we get......2x/6-15/6=6......2x-15=6×6=36........2x=36+15=51.......x=51/2=25.2,,, | |
| 6156. |
Sin90=? |
| Answer» 1 | |
| 6157. |
Sin x = 1-sin x find principal solution |
| Answer» sinx=1-sinx2sinx=1sinx=1/2x=pi/6 or (pi-pi/6)=5pi/6 | |
| 6158. |
(a+b) whole square |
| Answer» a square + 2ab +b square | |
| 6159. |
Z=1+iroot3 in polar form |
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Answer» r(modulus of Z)=root over a^2+b^2,a=1..b=root3Putting in formula of r we get r=2...... r(modulus of Z) = 2, theata= pi/3 ,theate is in frist quardrant so,theata = pi/3 because in 1st quardrant theata is apha.... so eq^n in polar form is 2(cos(pi/3)+i sin(pi/3))........... |
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| 6160. |
Gehsbdhyxbehs |
| Answer» | |
| 6161. |
If sin C+sinD=a and cosC+ cosD=b,show that cos(C+D)=b^2-a^2/b^2+a^2 |
| Answer» | |
| 6162. |
how i learn parabola |
| Answer» | |
| 6163. |
a(cosC-cosB) =2(b-c) cos`2A÷2 |
| Answer» | |
| 6164. |
What is first quadrant? |
| Answer» The quadrant in which the value on x axis and y axis are both positive. | |
| 6165. |
Any value of 2sinx. cosx |
| Answer» Sin2x | |
| 6166. |
3^(1/2) sin x - cos x = 2 Find general solution |
| Answer» | |
| 6167. |
Show that :n{p[p(p( ))]}=4*{Where ( ) is null set} |
| Answer» Your questions is wrong | |
| 6168. |
If tan a = m/m+1 and tan b = 1/2m+1, prove that a+b=pi/4 |
| Answer» | |
| 6169. |
Shortcut methord |
| Answer» | |
| 6170. |
Find domain of (x-7)^10001 |
| Answer» | |
| 6171. |
Cos18°-sin18°=√2sin27° |
| Answer» Cos18- Sin18= cos18 - cos72= -2×sin(18+72)/2 × sin (18-72)/2 (using CosC-CosD)= -2 sin45×sin(-27)2sin45sin27 (sin(-x)=-sinx)=√2×sin27 | |
| 6172. |
Xsquare2 -9=0 |
| Answer» X =3,-3 | |
| 6173. |
Range and domain of x\'2/1+x\'2 |
| Answer» | |
| 6174. |
Where is the answer for question papers? |
| Answer» | |
| 6175. |
If sec⊙+tan⊙=K Find the value of cos⊙ |
| Answer» | |
| 6176. |
Show that n{P[P(P(phi))]}=4 |
| Answer» | |
| 6177. |
cos-sin=√2cos |
| Answer» | |
| 6178. |
Is it ok to practice questions from ncert book for exams |
| Answer» | |
| 6179. |
5power n+1 + 4.6 power n when divided by 20 leaves remainder 9 |
| Answer» | |
| 6180. |
Supplementary exercises of maths is coming in exam or not in sa 1 |
| Answer» Supplementary exercises will come in sa1 | |
| 6181. |
Sinx/n+1=7 |
| Answer» | |
| 6182. |
Find angle between X axis and the line joining the points (3,-1) and (4,-2). |
| Answer» | |
| 6183. |
Find the squre root of (-√3-3i) |
| Answer» 3√5 | |
| 6184. |
Z-zbar 2i.1m (z) |
| Answer» | |
| 6185. |
A= b and = c |
| Answer» | |
| 6186. |
How many possible 5 letters words from using "HELLINA" |
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Answer» 2520 7!/2! (bcoz there are 7 letters in the word HELLINA and they can arrange themselves in 7! ways and there is a letter L which repeats 2 times so we divide 7! by 2!)7×6×5×4×3×2×1/2×1 7×6×5×4×32520Am i right? |
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| 6187. |
Sum upto infinite terms 6^1/2x6^1/2x6^3/8 |
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| 6188. |
Cos = sin |
| Answer» | |
| 6189. |
What is cos 2 theta and tan 2 theta |
| Answer» | |
| 6190. |
What is sin 2 theta |
| Answer» 2tanA/1+tan square A | |
| 6191. |
Exercise 2 |
| Answer» | |
| 6192. |
Using PMI prove that 2.7^n+3.7^n-5 is divisible by 24 |
| Answer» | |
| 6193. |
General solution of √3cosx+ sinx =√2 |
| Answer» | |
| 6194. |
1+2w+3w²/ + 2+3w+w²/ solve this 2+3w+w² 3+w+2w² |
| Answer» | |
| 6195. |
Sin(-x) |
| Answer» -Sinx | |
| 6196. |
Limt x tending to cos tita |
| Answer» | |
| 6197. |
1. If A and B are two sets such that ሺܣሻ ൌ 115, ݊ሺܤሻ ൌ 326, ݊ሺܣെܤሻ ൌ 47 , then write ݊ሺܣ ת ܤሻ. |
| Answer» Which language did you write | |
| 6198. |
How many element has p(A) , IF A=NULL SET CAN GIVE ANSWERS expanded from |
| Answer» If A is a phi set then p (A)=1 given by 2^0 number of element is 0 then 2 power 0 =1, 1 power set | |
| 6199. |
Since. 4=4 so √2²=√2² Also -2=+2HOW |
| Answer» Whenever a digit or a no.is in root it has two answers that\' s why -2=+2 | |
| 6200. |
Find the numbers of words formed by letter ABHI |
| Answer» 24 | |