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Z=1+iroot3 in polar form |
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Answer» r(modulus of Z)=root over a^2+b^2,a=1..b=root3Putting in formula of r we get r=2...... r(modulus of Z) = 2, theata= pi/3 ,theate is in frist quardrant so,theata = pi/3 because in 1st quardrant theata is apha.... so eq^n in polar form is 2(cos(pi/3)+i sin(pi/3))........... |
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