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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 501. |
Find the coordinates of the points trisection of the line segment joining (4,-1)&(-2,-3) |
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| 502. |
In the adjoining fig angle pqr=angler prs, If pr=5cm and ps=4cm ,then pq is equal to |
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Answer» How do solve zerois X2+7x+12 Where is figure??? |
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| 503. |
Find the sumof first 22 terms of in AP in which d=7and 22nd term is 149 |
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Answer» 1661 22 term= a+21d =a+21×7=a+ 14 7...... 149=a+147.........a=149-147=2.......... S²²=22/2×(2+149) ====11×151=== 1661 Oo sorry 1661 161 |
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| 504. |
Lcm of smallest composite no. And smallest 2digit cimposite no. |
| Answer» 20 is the lcm | |
| 505. |
Simple trick for complaining square |
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| 506. |
3.4 Q no 1 |
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| 507. |
Explain the section formula |
| Answer» A point on the line segment divides it into two parts which may equal or not. The ratio in which the point divides the given line segment can be found if we know the coordinates of that point. Also, it is possible to find the point of division if we know the ratio in which the line segment joining two points has given. These two things can be achieved with the help of a section formula in coordinate geometry.Section formula is used to determine the coordinate of a point that divides a line segment joining two points into two parts such that the ratio of their length is m:n.Let P and Q be the given two points (x1,y1) and (x2,y2) respectively, and M be the point dividing the line-segment PQ internally in the ratio m:n, then form the sectional formula for determining the coordinate of a point M is given by examole | |
| 508. |
Solve this s+n/s-n - s-n/s+n = 33/4. ( Factorization ) |
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| 509. |
Cube Of 4 |
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Answer» Cube=4×4×4=64☺ 64 4^3=4×4×4=4×16=64 4³ = 4×4×4 = 16×4= 64 64 |
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| 510. |
Find LCM and HCF of 6,72,120 |
| Answer» 6 = 2 × 372 =\xa02 × 2 × 2 × 3 × 3 = 2³ × 3²120 =\xa02 × 2 × 2 × 3 × 5 = 2³ × 3¹ × 5¹HCF(6,72,120) => 2¹ × 3¹ = 6LCM(6,72,120) => 2³ × 3² × 5¹ = 360 | |
| 511. |
ax + by = a^2 - 2b , bx +ay = ab - 2a |
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| 512. |
Sin theeta - cos theeta+1 upon sin theeta+cos theeta-1 =cos theeta upon 1- sin theeta |
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| 513. |
The value of p for equation 2x² – 4x + P = 0 to have real roots will be |
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Answer» When discriminant =0 roots are real From given equation b=-4,a=2,c=pSo b^2-4ac=0(-4)^2-4(2)(p)=016-8p=0-8p=-16p=-16/-8P=2 P = 2 |
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| 514. |
Justify, cube root of 64 is not an irrational number |
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Answer» No chance it\'s not irrational Cube root of 64 = 4 , which is rational number |
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| 515. |
3.27¯¯¯¯¯3.27¯\xa0is |
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| 516. |
The 6th term of an A.P is -10 and its 10th term is -26. Determine the 15th term of an A.P |
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Answer» Thanks It\'s - 46 46 |
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| 517. |
tan²A – Sin²A= tan²Asin²A friends please answer me |
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| 518. |
Bhai is saaal boards hai kuch tip do |
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Answer» Only study Self study |
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| 519. |
√x+y =7√y+x=11 |
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Answer» Aapse aacha? Ata kya hai tumko |
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| 520. |
What\'s the meaning of consistent, inconsistent, consistent (dependent)and coincidence. |
| Answer» Consistent Equations. - If we get a solution, then the pair of linear equations in two variables is called\xa0consistent\xa0equations.Inconsistent Equations - If we do not get a solution, then the pair of linear equations in two variables is called inconsistent equations.Consistent (dependent) Equations - If a system has at least one solution, it is said to be\xa0consistent\xa0. If a\xa0consistent\xa0system has exactly one solution, it is independent . If a\xa0consistent\xa0system has an infinite number of solutions, it is\xa0dependent . When you graph the equations, both equations represent the same line.Coincidence lines - If two\xa0lines are\xa0coincident\xa0then, they have infinite solution and pair of linear equations is consistent; If two\xa0lines are intersecting then, they have unique solution and pair of linear equations is consistent. | |
| 521. |
The zeroes of the polynomial x² - 2x - 3 are |
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Answer» x² - 2x - 3 = 0x² - 3x + x\xa0- 3 =0x ( x - 3) + 1 (x - 3) = 0(x + 1) ( x- 3) = 0x + 1 = 0 x - 3 = 0x = -1 or x = 3 Zeroes are 3 and -1 |
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| 522. |
Find the sum of the series 6,27,128,629 |
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| 523. |
Solve equation if x=1. ax2-3(a-1)x-1 |
| Answer» Sydbd oh v | |
| 524. |
If the zeros of the polynomials f(x)=x3-3x2+x+1 are (a-b),a and (a+b), find a and b. |
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| 525. |
7x-2y/xy=5. 8x+7y/xy =15 |
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| 526. |
Write the zeros of the quadratic polynomials f(x) = 6x2 -3. |
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Answer» \xa0f(x) = 6x2 -3.6x2 - 3 = 03 (x2 - 1)= 0x2 - 1 = 0x2 = 1x = +1 x = -1 X is equal to 0 and 1 by root 2 |
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| 527. |
If x3+x2-ax+b is divisible by (x2 - x), write the value of a and b. |
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| 528. |
If (a-b),a and (a+b)are zeros of the polynomials 2x3-6x2+5x -7, write the value of a. |
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| 529. |
If (x + a) is a factor of (2x2 + 2ax + 5x +10) , find the value of a. |
| Answer» Answer is -2 | |
| 530. |
What is competing square method? |
| Answer» it has been deleted from the syllabus | |
| 531. |
show that the square of any positive integer is either of the form 4q or 4q+1 for some integer q |
| Answer» Let be x | |
| 532. |
Sin30°A + cos 60°A |
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Answer» 1 1/2+1/2=2/2=1 Sin30°A = 1/2cos 60°A = 1/2Sin30°A + cos 60°A= 1/2 + 1/2= 2/2= 1 1/2 + 1/2=2/2 =1 Sin30°A = 1/2cos 60°A = 1/2Sin30°A + cos 60°A= 1/2 + 1/2= 2/2= 1 |
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| 533. |
What is the smallest composite nu.bet |
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Answer» 4 4 4 4 4 is the smallest composite number. Because let\'s start. 1 is neither prime not composite..2 is a prime number as we all know as It has 1 and 2 as the only factors.3 is also prime as it has 1 and 3 as its only factors.Now coming to 4. It has 1,2 and 4 as its factors. It has three factors and can\'t be considered as prime so 4 is the smallest composite number |
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| 534. |
If A(k+1,2k) B(3k,2k+3)C(5k-1,5k) are collinear then find value of K.? |
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| 535. |
The product of two consecutive positive integer is 306.we need to find the integer |
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Answer» Let the first integer be xTherefore, the second integer be x+1Hence the product = x(x+1)According to question, x(x+1)=306x^2+x=306x^2+x-306=0 That x(x+1)=306Xsquare+x=306Xsquare +x-306=0It is required quadratic equation |
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| 536. |
Find the number of visit in the square root of each of the following( a) 12,100 |
| Answer» 144 , 10000 | |
| 537. |
Take 12&16 and show that the product of their LCM and HCM =product of 12&16 |
| Answer» LCM × HCF = product of the number12 × 16 = 12 × 16192 = 192 | |
| 538. |
Ex 1.1 important question |
| Answer» 1,3,5,8 | |
| 539. |
2+6√5 |
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Answer» 8√5 is wrong please don\'t write it it is15.416407865 2(1+3^5) 8√5 |
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| 540. |
Find the distance between M (-7,6) and N(-2,-4) . With the graph |
| Answer» Let -7 be x1,6 be y1,-2 be x2,-4 be y2 By distance formula √(x2-x1)^,2+(y2-y1)^2 =√(-2--7)^2+(-4-6)^2 =√(5)^2+(-10)^2 = √25+100 =√125 | |
| 541. |
If ax²+bx + c=0 has equal roots then c = :1 point- b/2ab/2a- b²/4ab²/4a |
| Answer» b/2a | |
| 542. |
The product of two cosecutive natural number is always |
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Answer» Natural Natural |
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| 543. |
how to solve garap paper in exem |
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| 544. |
What is the area is isosceles triangle |
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Answer» Formulas to Find Area of Isosceles TriangleUsing base and HeightA = ½ × b × hUsing all three sidesA = ½[√(a2\xa0− b2\xa0⁄4) × b]Using the\xa0length\xa0of 2 sides and an angle between themA = ½ × b × c × sin(α) U can find the formula byHeron\'s formula |
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| 545. |
Qutratic equarion |
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Answer» Equation in the form of ax²+bx+c Equation in the form of ax2+bx+c=0 |
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| 546. |
Find a cubic polynomials takes two at a time , and the product of its zeros as 5,-2,-24 |
| Answer» 338 | |
| 547. |
Find the value of a when the points (3,a) and (4,1) is root 10 |
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| 548. |
The HCF of (26,169)=13 then lcm of 26 and 169 is |
| Answer» We know thatHCF(26×169)×LCM(26×169)=26×169Let LCM=y13×y=26×169y=338 | |
| 549. |
Coordinate geometery ex 1 |
| Answer» It\'s already there in this app on NCERT solutions ok check it. | |
| 550. |
Tan tetha = 8/15 ,if PQ=16 cm,then the length of PR is |
| Answer» taking x instead of titatan x = 8/15tan x = PQ/QRPQ/QR =8/1516/QR = 8/1516 x 15/8=QRtherefore ,QR = 30 mPQ2\xa0+ QR2\xa0=PR2162\xa0+ 302\xa0= PR2256 + 900= PR21156=PR2PR= root 1156PR = 34 m | |