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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 451. |
What do you mean by chord |
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Answer» A chord means a line joining two points of the circle without joining to the centre A chord is a secant line or just secant . In another word chord is line segment joining two pointson any curve, for instance,an ellipsis. |
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| 452. |
Root 3 and -root 3 are the zeroes of f(x) = xcube + 13x square + 32x+2 find its other zeroes. |
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| 453. |
Plz koi channel btayo jha muje maths ka new syllabus k according pdhne ko mile |
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Answer» Vedantu You can consider YouTube channel Easy maths https://www.youtube.com/user/akashchauhancsit It will provide best study Cbse classes |
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| 454. |
If x = p tan θ + q sec θ and y = p sec θ + q tan θ then prove that 2 2 2 2 x − y = q − p . . |
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| 455. |
Solve by cross multiplication(a-b)x+(a+b)y= a^2-2ab-b^2(a+by)+(x+y)=(a^2+b^2) |
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| 456. |
The sum of first 25 terms of an AP whose nth term is 2-3n, is |
| Answer» Put n =1put n =2put n =3So, A.P. become s: -1 , -4 , -7, ........So, first term =a= -1Common difference d = -4-(-1)=-7-(-4)= -3Formula of sum of first n terms :\xa0Put n =25Hence the sum of first 25 terms of an AP is -925 | |
| 457. |
9y²-12y+4 |
| Answer» 9y² - 12y + 2 = 0(3y)² - 2(3y)(2) + 2² - 2² + 2 = 0(3y - 2)² - 4 + 2 = 0(3y - 2)² = 2(3y - 2) =\xa0√2taking (+ve)3y = √2 + 2y = (√2 + 2)/3taking (-ve)3y = -√2 + 2y = (2 - √2)/2 | |
| 458. |
Total no of zeroes in cubic polynomials |
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Answer» Answer is 3 3 3 3 Three (3). |
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| 459. |
Ncrt math 5.4 ka question no. 4 |
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Answer» 4. The houses of a row are numbered consecutively from 1 to 49. Show that there is a value of\xa0\xa0such that the sum of the numbers of the houses preceding the house numbered\xa0\xa0is equal to the sum of the numbers of the houses following it. Find this value of\xa0Ans.\xa0Here\xa0\xa0and\xa0=\xa0=\xa0\xa0=\xa0=\xa0\xa0=\xa0=\xa0\xa0= 49 x 25According to question,\xa0=\xa0\xa0\xa0+\xa0=\xa0\xa0\xa0\xa0=\xa0\xa0Since,\xa0\xa0is a counting number, so negative value will be neglected. |
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| 460. |
If A = 600 and B = 300, verify that: |
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| 461. |
Given tan A is 4/3, find the other trigonometric ratios of angle A. |
| Answer» In triangle ABC given tan A is 4/3hence opposite side is 4x, adjacent side is 3xthen by Pythagoras theorem hypotenuse will be 5x.now,sin A is 4/5cos A is 3/5cosec A is 5/4sec A is 5/3cot A is 3/4. | |
| 462. |
Chapter 12.2 second question |
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| 463. |
X + Y =14, x _ Y = 4 |
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Answer» X + Y =14..............eq(1)X -Y =4.................eq(2)Add both equationX+Y=14X-Y=4------------2X=18X=18/2=9Put value of X in eq(1)X+Y=149+Y=14Y=14-9=5So,x=9,y=5 X=9 and Y=5 Xis9 yis5 |
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| 464. |
Prove that √3is irrational |
| Answer» Let us assume to the contrary that √3 is a rational number.It can be expressed in the form of p/qwhere p and q are co-primes and q≠ 0.⇒ √3 = p/q⇒ 3 = p2/q2\xa0(Squaring on both the sides)⇒ 3q2\xa0= p2………………………………..(1)It means that 3 divides p2\xa0and also 3 divides p because each factor should appear two times for the square to exist.So we have p = 3rwhere r is some integer.⇒ p2\xa0= 9r2………………………………..(2)from equation (1) and (2)⇒ 3q2\xa0= 9r2⇒ q2\xa0= 3r2Where q2\xa0is multiply of 3 and also q is multiple of 3.Then p, q have a common factor of 3. This runs contrary to their being co-primes. Consequently, p / q is not a rational number. This demonstrates that √3 is an irrational number. | |
| 465. |
The of an object is the angle |
| Answer» Eh? | |
| 466. |
Find the hcf and lcm 17,23,37 by using prime factorization |
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| 467. |
If the points P(4,3) and Q(x,5) are on the circle with centre O(2,3).then find the value of x. |
| Answer» M=n1+x/22=4+x/22*2=4+x4-4=xX=0 | |
| 468. |
Exercise 7.4 ka question no. 1 |
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| 469. |
Hi IAM studying class 10 I want some important questions pls |
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Answer» Every question are important Hi swasthi where are you from |
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| 470. |
Solve the following pair of equations 2x+3y=46, 3x+5y=74 by elimation method |
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Answer» Thanks ? Given pair of linear equations is2x + 3y = 46 …(i)And 3x + 5y = 74 …(ii)On multiplying Eq. (i) by 3 and Eq. (ii) by 2 to make the coefficients of x equal, we get the equation as6x + 9y = 138 …(iii)6x + 10y = 148 …(iv)On subtracting Eq. (iii) from Eq. (iv), we get6x + 10y – 6x – 9y = 148 – 138⇒\xa0y = 10On putting y = 10 in Eq. (ii), we get3x + 5y = 74⇒\xa03x + 5(10) = 74⇒\xa03x + 50 = 74⇒\xa03x = 74 – 50⇒\xa03x = 24⇒\xa0x = 8Hence, x = 8 and y = 10 , which is the required solution. |
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| 471. |
Solve for x and y, ax/b -by/a = a+b , ax -by = 2ab |
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| 472. |
The decimal expansion of the rational number 14587/1250 will terminate after2 points |
| Answer» one decimal placetwo decimal placethree decimal placefour decimal place | |
| 473. |
2x2+5√3x+6=0 |
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Answer» Hi 2x^2+4√3x+√3x+6,=2x(x+2√3)+1(x+2√3)=(x+2√3)(2x+1) |
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| 474. |
2x²+x/2-4 |
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| 475. |
(5+√23) (8-√23) |
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Answer» (5+√23) (8-√23)= 5 (8-√23) +\xa0√23 (8-√23)= 5 (8) - 5\xa0√23 + 8\xa0√23 -\xa0√23(√23)= 40 +(-5 + 8)√23 - 23= 17 + 3√23 Raisen ka baap |
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| 476. |
Find an acute angle theta when cos theta-sin theta /cos theta+ sin theta =1-√3/1+√3 |
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Answer» An acute angle of theta is\xa060 degree.To find:Acute angle theta = ?Solution:Given:\xa0Applying componendo dividendo, we getAn acute angle is an angle smaller than a right angle. The\xa0range of acute angle is one that is less than “90 degrees”. Trigonometric functions of an acute angle are\xa0“ratios of the different pairs of sides” of a “right-angled triangle”. Better check in Google for ur answer |
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| 477. |
The pair of linear equations 2x + ky = 11 and 5x – 7y = 5 has no solution when K = ………… |
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Answer» When k is not equal to - 14/5 -2.8 |
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| 478. |
Find the missing term :..... , 13 , ..... , 3 |
| Answer» 18,8 | |
| 479. |
If X=2 and X=3 are roots of the equation 3x² -2kx +2m=0 find the value of k and m |
| Answer» Sum of roots = -( coeff.of x)/coeff.of x^22+3 = -(-2k)/35 = 2k/32k = 15k = 15/2Product of roots = constant term/ coeff.of x^22×3 = 2m/36 = 2m/3m = 6 × 3/2 = 9 | |
| 480. |
Sintheta/ 1+costheta+sintheta/1-costheta |
| Answer» Sin/1+cos +sin/1-cos=sin(1-cos)+sin(1+cos)/(1+cos)(1-cos)=sin-sin.cos+sin+sin.cos/1-cos²=2sin/sin²=2/sin=2cosecPlease inpu theta in all | |
| 481. |
The value of K for which the quadratic equation 2x2+kx+2=0 has equal roots is |
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Answer» K=+4 and k=-4 Comparing the equation with ax²+bx+cWe get, a=2, b=k & c=2We know that, the quadratic equation has real and equal roots if the value of discriminant(D)=0Therefore, D= b²-4ac 0= k²- 4 (2)(2) 0= k²- 1616= k²Therefore, k = ±4Therefore, the quadratic equation 2x²+kx+2=0 has real and equal roots if k=±4 |
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| 482. |
Deg p(x)=deg p(x) |
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| 483. |
If px²+ 3x + q = 0 has two roots x = -1 and x = -2, the value of q - p is |
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Answer» Your and is wrong ? When x=-1Equation1: p(-1)^2 + 3(-1) +q=0p - 3 + q = 0=> q = 3 - p.......aEquation2: p(-2)^2 + 3(-2) + q = 0 4p - 6 + q = 0From eq a:4p - 6 + 3- p = 0 .°. p = 1 So, q =3-p q = 2Now, q - p = 2-1 = 1.......ans. |
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| 484. |
√7is an irrational number |
| Answer» Underroot7 = a/b [ where a and b are co prime ] 7 = a^2 /b^2 [ squaring both side ] 7b^2 = a^2 ------(1)7 divides a^2 7divides a Then , a can be written as 2m , where m is an integer .a = 7m 7b^2 = (7m)^2 [ from equation 1] 7b^2 =49m^2 b^2 =7m^2 7 divides b^2 7 divides b Thus, 7 is a common factor of a and b .a and b have no common factor other than 1. Hence , underroot 7 is irrational. | |
| 485. |
Show that the points (2,4) ,(2,-1) , (-3,-1) and (3,4) are the vertices of a square |
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| 486. |
Can anyone tell ki chapter 4 mein se konsi ex ka konsa q delete hua hai accg to new syllabus |
| Answer» Ex-4.3 | |
| 487. |
If the HCF of 65 and 117 is expressible in the form 65m – 117, then the value of m is |
| Answer» By Euclid\'s division algorithmb = aq + r,0 ≤ r < a [∵ dividend = divisor × quotient + remainder]⇒ 117 = 65 × 1 + 52⇒ 65 = 52 × 1 + 13⇒ 52 = 13 × 4 + 0∴ HCF (65,117) = 13 ...(i) Also, given that, HCF (65,117) = 65m - 117 ...(ii)From Eqs.(i) and (ii),65m - 117 = 13⇒ 65m = 130⇒ m = 2 | |
| 488. |
If triangle ABC of side AB=x ,BC= x+1 and AC= x+2 then find the area of the triangle |
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| 489. |
what is the HCF of smallest composite number and smallest odd number |
| Answer» So, from the factorisation of 3 and 9, we can say that 9 is the LCM of 3 and 9. Hence, we can say that the HCF and LCM of the smallest odd composite number and the smallest odd prime number are 3 and 9 respectively. | |
| 490. |
Find out XY as difference of two square number |
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| 491. |
How do solve zerois |
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Answer» Hello By solving quadratic equations |
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| 492. |
How to slove algrabaric |
| Answer» By your mind and some tactics ? | |
| 493. |
If the graph of a polynomial intereste the x axis at exactly two point then it |
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Answer» Have 2 zeroes Have two zeroes and it\'s a unique solution Have two zeroes |
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| 494. |
Check whether -150 is a term of the AP:11,8,5,2..........so on |
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Answer» https://chat.whatsapp.com/Gt8MJfdaS4RBpFaot9KmMb No -150 is not any term of the given ap |
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| 495. |
3.5 |
| Answer» Kay | |
| 496. |
Please sir all subject updates. |
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| 497. |
Maths update for class 10. |
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| 498. |
Ncert lesson 1 example no. 5 |
| Answer» Hye sir | |
| 499. |
1/x+1/8-x=8/15 |
| Answer» 1/x + 1/8-x =8/15,after taking LCM of the denominator we get 8-x+x/8x-x^2=8/15,15=8x-x^2, x^2-8x+15=(x-5)(x-3) | |
| 500. |
Let an be a finite AP and k be a natural no , a1=r |
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