Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

24851.

Selaginella sperms swims towards the archaegoina, this movement is(1) Chemotropic (2) Chemotactic (3) Chemonastic (4) Archaenastic

Answer»

(2) Chemotactic

24852.

Long day plant's produces flowers when they exposed to(1) Any duration of light (2) Light period longer than a critical day length (3) Light period longer than 12 hrs. (4) None of these

Answer»

(2) Light period longer than a critical day length

24853.

Who discovered vernalization ? (1) Lysenko (2) Went (3) Boysen & Jenson (4) Darwin

Answer»

 Lysenko discovered vernalization. 

24854.

Active form of phytochrome for seed Germination is (1) Pfr–form (2) Pr–form (3) Both (4) None

Answer»

(1) Pfr–form

24855.

For a reaction, `A+Brarr` Product, the rate law is given by `r=k[A]^((1)/(2))[B]^(2)`. What is the order of the reactio ?

Answer» Correct Answer - `2.5`
Order of reaction `=(1)/(2)+2=(5)/(2)=2.5`
24856.

In a reaction, `2Ararr` Products the concentration of A decreases from `0.5` "mol" litre^(-1)` to `0.4` "mol" litre^(-1)` in `10` minutes. Calculate rate during this interval.

Answer» Correct Answer - `5xx10^(-3)M mi n^(-1)`
Averate rate `=(4xx10^(-4)M)/(60s)`
`=6.66xx10^(-6)Ms^(-1)`
24857.

Phytochrome is related to (1) Seed germination in salad (2) Inhibition of albinism and development of chloroplast (3) Expansion of leaves in dicots (4) All the above

Answer»

(4) All the above

24858.

Which of the following is low spin tostrong field ligandsA. `d_(xy)^(2)d_(zx)^(2)d_(yz)^(1)`B. `d_(xy)^(2), d_(yz)^(1), d_(zx)^(1), d_(x^(2)y^(2))^(1), d_(z^(2))^(1)`C. `d_(xy)^(2), d_(yz)^(1), d_(zx)^(1), d_(z^(2))^(1)`D. `d_(x^(2)^(1) - y_(2)), d_(z^(2))^(1)`

Answer» Correct Answer - A
`[t_(2g) .^(2, 2, 1) l_(g)^(0,0)]`
24859.

Transverse diffusion (flip-flop) is the movement of _____________(a) cholesterol molecule(b) amino acid(c) protein(d) phospholipid

Answer» Right answer is (d) phospholipid

Explanation: In case of a membrane phospholipid, two types of movements are possible: lateral shift i. e. movement from one place in the bilayer membrane to the other within the same leaflet; and transverse diffusion is movement of the phospholipid from one side of the membrane to the other, which is a relatively long process.
24860.

Distinguished between combination and decomposition reaction. Each in 4 points

Answer»

The chemical reaction in which a single product is formed from two or more reactants and energy is also evolved , is known as combination reaction. When a single reactant on gaining enrgy decomposes to give two or more simpler products, such a reaction is called a decomposition reaction.

24861.

Sanchit is a hardworking, organized and dependable employee of his company. According to trait theory, what kind of personality does he have? a. Extraversion b. Agreeableness c. Conscientiousness d. Confident

Answer»

Correct option: c. Conscientiousness

24862.

A synthetic nucleotide analogue, 4-hydroxypyrazolopyrimidine is used in the treatment of(A) Acute nephritis (B) Gout(C) Cystic fibrosis of lung (D) Multiple myeloma

Answer»

Correct option (B) Gout

24863.

IN a DNA molecule, the guanosine content is 40%, the adenine content will be (A) 10% (B) 20% (C) 30% (D) 40%

Answer»

Correct option (A) 10%

24864.

An increased melting temperature of duplex DNA results from a high content of (A) Adenine + Guanine (B) Thymine + Cytosine (C) Cytosine + Guanine (D) Cytosine + Adenine

Answer»

(C) Cytosine + Guanine

24865.

A ______is one that has only one subject and one predicate or has only one finite verb. a. simple sentence b. complex sentence c. passive sentence d. active sentence

Answer»

simple sentence is one that has only one subject and one predicate or has only one finite verb.

24866.

While shelving, the spines of books are kept _________. (a) Parallel to the front border line (b) Parallel to the back border line (c) At the upside (d) At the downside

Answer»

(a) Parallel to the front border line

While shelving, the spines of books are kept Parallel to the front border line.

24867.

Write chemical reactions involved in Van Arkel method for refining titanium.

Answer»

Van Arkel method for refining titanium: The volatile iodide of titanium (formed after treatment of impure titanium with iodine) is electrically heated using tungsten filament above 1700 K. Pure titanium gets deposited on the filament and as the deposition goes on, the current is steadily raised to maintain the temperature.

Ti(s) (Impure) + 2I2(g) \(\overset{523\,K}\longrightarrow\) TiI4(g) (Volatile iodide of titanium)

TiI4(g) (Volatile iodide of titanium) \(\overset{1700\,K}\longrightarrow\) + Ti(s) + 2I2(g) (Pure)

24868.

Choose the suitable meaning of the idiom found in the following sentences:The new movie hit the box office with a flying start and collected the highest revenue on day one. (a) immediate failure (b) introduction scene with a flight(c) more number of flight scenes (d) immediate success

Answer»

(d) immediate success

24869.

Assertion`:-` In a solution having `0.1M` each of `Br^(_)` , `SO_(4)^(2-)` & `Cl^(-)`, on adding `Ag^(+)` ion slowly. Salt having highest value of `K_(sp)` will precipitate first. Reason`:-` Precipitate occurs when `Q_(sp)=K_(sp)``A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False

Answer» Correct Answer - D
24870.

Assertion (A): For every chemical reaction at equilibrium, standard Gibbs enegry of the reaction is zero. Reason (R ) : At constant temperature and pressure chemical reactions are spontaneous in the direction of the decreasing Gibbs energy.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False

Answer» Correct Answer - D
24871.

What is oxidation number of oxygen in hydrogen peroxide?

Answer»

Oxygen in H2O2 = -1

24872.

Mention one use of hydrogen.

Answer»

It is used as rocket fuel in space research.

24873.

What is Avogadro’s number?

Answer»

Avogadro’s number = 6.022 × 1023

24874.

The number of steps, in which orthophosphoric acid is ionised, areA. 3B. 1C. 4D. 2

Answer» Correct Answer - A
As it is a tribasic acid.
`H_(3)PO_(4)hArr H^(+)+H_(2)PO_(4)^(-)hArr H^(+)+HPO_(4_^(2-)hArrH^(+)+PO_(4)^(3-)` Number of steps =3
24875.

Cerium shows oxidation state of `+4` becauseA. it resembles alkali metalsB. it has very low IEC. it has tendency to attain boble gas configurationD. it has tendency to attain `f^(@)` - configuration

Answer» Correct Answer - D
After loss of 4 - electrons cerium attains `f^(0)`-configuraiton.
24876.

Explain hydrogen bonding.

Answer»

Hydrogen bonding is defined as “Attractive force which binds hydrogen atom of one molecule with electronegative atom (F, O, or N) of another molecule.

24877.

A wavelength of 100 nm of a radiation lies in which region?

Answer»

Radiation lies : 100 nm = UV

24878.

Which of the following is not a state function ? (a) Heat (b) Internal energy (c) Enthalpy (d) Entropy 

Answer»

Heat  is not a state function.

24879.

Calculate the percentage composition of carbon and hydrogen in ethanol.

Answer»

Molecular mass of ethanol = 46.06

% carbon = 24/46 x 100 = 52

% of hydrogen = 6/46 x 100 = 13

24880.

Which of the following quantities is not a state function ? (a) Temperature (b) Entropy (c) Enthalpy (d) Work

Answer»

Work is not a state function.

24881.

Which of the following is not an intensive property ? (a) Entropy (b) Pressure (c) Temperature (d) Molar volume 

Answer»

Entropy is not an intensive property.

24882.

Whether internal energy is extensive property or intensive property?

Answer»

Extensive property.

24883.

Which one of the following noble gas is obtained by radioactive disintegration ?A. KrB. ArC. RnD. Xe

Answer» Correct Answer - C
Rn is radioactive and is produced by the decay of radium and thorium minerals.
`._88^226Rato._86^222Rn+._2^4He` it is a `gamma `- emitter.
24884.

During the extraction of copper , the impurity (FeS) is removed as slag by mixing the contaminated copper ore with silica and coke. The molecular formula of slag isA. `FeSiO_(3)`B. `Fe_2O_3`C. `FeSi`(solid)D. FeSi(vapour)

Answer» Correct Answer - A
Copper pyrite is roasted first and forms `Cu_2S` and `FeS`. In blast furnace in presence of air , it oxidises to `Cu_2O` and `FeO`. The impurity FeO reacts with sand (silica) to form slag. `FeO+SiO_2tounderset("Ferrous Silicate" ("slag"))(FeSiO_3)`
24885.

Transition elementsA. exhibit inert pair effectB. exhibit variable oxidation stateC. have low melting pointD. do not show catalytic properties

Answer» Correct Answer - B
d-block elements show variable oxidation state . it is one of the characteristics of transition elements.
24886.

Transition elementsA. exhibit inert pair effect B. exhibit variable oxidation stateC. have low melting pointD. do not show catalytic properties

Answer» Correct Answer - B
d-block elements show variable oxidation state . it is one of the characteristics of transition elements.
24887.

Cn H2n o2   could be for open chain1 ) diketones2) carboxylic  acid3) diols4) dialdehyde 

Answer» Option is (2) carboxylic acid.

Explanation

Ratio of number of atoms of carbon and Hydrogen in the molecule suggests the presence of one double bond. Diols have no double bond . Again each of diketone and dialdehyde has got two double bonds as C=O group.

Only carboxylic acid has one double bond in its carbonyl group attached with hydroxyl group.
24888.

What happens when nitric acid is dropped on pumice stone?

Answer»

When conc. HNO3 is dropped on red-hot pumice stone a brown gas mixture evolves. When this gas mixture is passed through a 'U' tube dipped in a freezing mixture a yellow coloured liquid and a colourless gas is obtained. This gas is oxygen as it is completely absorbed by alkaline pyrogallate solution brown. Hence, nitric acid contains oxygen

4HNO3=4NO2+2H2O+O2

When nitric acid is dropped over heated saw dust (pumice stone) it catches fire spontaneously , i.e., bursts into flame.

24889.

What is the function of pumice stone during thermal decomposition of nitric acid ?

Answer»

Being a volcanic rock  pumice stone can withstand high temperature without being melted and is unreactive with concentrated nitric acid. Here is how these properties help during thermal decomposition of nitric acid.

When  concentrated nitric acid is made to fall dropwise on highly heated pumice stone it remains chemically unreacted with the stone but readily spreads over its highly heated  surface and thus the thin molecular layers of nitric acid easily  get the sufficient thermal kinetic energy required for their decomposition from the molecules of pumice stone vibrating with high thermal kinetic energy at high temperature and we see the following dismutation  reaction to occur ..

\(4HNO_3 \to 4NO_2 + 2NH_2O + O_2\)

Pumice stone is mainly used to separate out oxygen from Nitric acid.

Pumice stone is a volcanic rock and can be withstand high temperature. When Nitric acid is to be decomposed, it is made to fall dropwise on heated pumice stone, where nitric acid's thin layer gets sufficient kinetic energy for its decomposition.

\(4HNO_3 \to 4NO_2 + 2NH_2O + O_2\)

24890.

With reference to periodic table indicate:a) Element that is in group 13 and third period both.b) First transition element of the fourth period.

Answer»

a) Al is the  Element that is in group 13 and third period both.
b) Sc

24891.

What do you expect the nature of hydrides is, it formed by elements of atomic numbers `15,19,23` and `44` with dihydrogen? Compare their behaviour towards water.

Answer» a. Element with atomic number, `Z=15`,i.e., phosphourous `(P)` is a non-metal and hence the hydride formed is covalent, i.e. `PH_(3)`
b. Element with `Z=19` is potassium `(K)` an alkali metal and hence the hydride formed is ionic , i.e. `KH`.
c. Element with `Z=23` , is a transition metal, i.e. vanadium `(V)` and hence the hydride formed is metallic or interstitial .`(VH_(0.56))`
d. Element with `Z=44` is a transition metal, i.e. ruthenicum `(Ru)` and does not form any hydride (hydride gap). Behaviour towards water:Only ionic hydrides react with water. Forming corresponding metal hydroxide and evolve `H_(2)` gas.
`KH_(s)+H_(2)O_(l)to KOH_(aq)+H_(2)(g)`
24892.

The electronic configuration of A is 1s22s22p63s2a) To which period does it belong?b) Write down the formula of the nitrate of A.c) State whether a solution of nitrate is conductor of electricity or not.

Answer»

a) Third period
b) A(NO3)2
c) Conductor of electricity

24893.

A sound wave of frequency `f` travels horizontally to the right. It is reflected from a large vertical plane surface moving to left with a speed `v`. The speed of sound in medium is `C`A. The number of waves striking the surface per second is `f(c + v)/(c )`.B. The wavelength of reflected wave is `f (c - v)/(c + v)`C. The frequency of the reflected wave is `f (c + v)/(c - v)`D. The number of beats heard by a stationary listener to the left of the reflecting surface is `(v f)/( c- v)`

Answer» Correct Answer - A::B::C
Moving plane is like a moving observer. Therefore, number of waves encountered by moving plane
`f_(1)=f((v+v_(0))/(v))=f((c+v)/(c))`
Frequency of reflected wave,
`f_(2)=f_(1)((v)/(v-v_(s)))=f((c+v)/(c-v))`
Wavelength of reflected wave,
`lamda_(2)=(v)/(f_(2))=(c)/(f_(2))=(c)/(f)((c-v)/(c+v))`
Number of beats heard `= f_(2) -f = (2 vf)/(c - v)`.
24894.

Derive an expression for the frequency of radiation emitted when a hydrogen atom de-excites from level n to level (n – 1). Also show that for large values of n, this frequency equals to classical frequency of revolution of an electron.

Answer»

We have: 

frequency, \(\nu\) = \(\frac{me^4}{(4\pi)^3\epsilon_o^2(\frac{h}{2\pi})^3}\) \(\Big[\frac{1}{(n-1)^2}-\frac{1}{n^2}\Big]\)

\(\frac{me^4(2n-1)}{(4\pi)^3\epsilon_o^2(\frac{h}{2\pi})^3n^2(n-1)^2}\)

For large n, \(\nu\) = \(\frac{me^4}{32\pi^3\epsilon_o^2(\frac{h}{2\pi})^3}\times\frac{1}{h^3}\)

Orbital frequency, \(\nu_e=\frac{\nu}{2\pi r}\)

In Bohr model, \(\nu\) = \(\frac{\frac{nh}{2\pi}}{mr}\) and r = \(\frac{4\pi\epsilon_o(\frac{h}{2\pi})^2}{me^2}\)

\(\therefore\) \(\nu_e\) = \(\frac{\frac{nh}{2\pi}}{2\pi mr^2}\) = \(\frac{me^4}{32\pi^3\epsilon_o^2(\frac{h}{2\pi})^3}\times\frac{1}{n^3}\)

which is same as for large n.

Derivation of frequency of radiation emitted when a hydrogen atom de excites from level n to level (n-1). 

 v = me4 (2n-1) / (4\(\pi\))3 (h/2\(\pi\))3 n2 (n-1)2

Comparing for large values of n, with classical freuency v = v / 2\(\pi\)r

24895.

How to find the critical Néel temperature below which the system is in the antiferromagnetic phase ?

Answer»

Neel temperature : The neel temperature is the temperature above it the anti-ferromagnetic material become paramagnetic. Temperature dependence of the magnetic susceptibility of paramagnetic materials is given by the curie law.

Xm\(\frac{\mu_0nm^2}{[3k(T-T_e)]}\)

Xm\(\frac c{(T-T_c)}\)

where μ0 = it is magnetic permeability at vaccume

n = atomic density

m = dipolar magnetic moment of atom A

k = boltzman constant

Tc = curie temp in K

C = curie constant k-1

24896.

Differentiate between adiabatic system and isolated system

Answer»

An adiabatic process is a process where the net heat transfer to the working gas is zero. An isolated system is a system that is completely shut off from the surroundings.

24897.

The message you get from the poem the squirrel class 7

Answer» That no one is superior and no one is inferior, each and every one is equal before God.
24898.

A solid sphere of uniform density and radius 4 units is located with its centre at the origin O of coordinates. Two sphere of equal radii 1 unit, with their centres at A(-2,0 ,0) and B(2,0,0) respectively, are taken out of the solid leaving behind spherical cavities as shown if fig Then: A. the gravitational force due to this object at the origin is zeroB. the gravitational force at the point B `(2,0,0)` is zeroC. the gravitational potential is the same at all poitns of the circle `y^(2)+z^(2)=36`D. the gravitational potential is the same at all points of the circle `y^(2)+z^(2)=4`

Answer» Correct Answer - A::C::D
(A) Net gravitational field at centre due to solid sphere (having cavites) is equal to zero.
let point P is in y-z plane (o,y,z) then equipotential curve must be circle y-z plane `bot^(2)` to the diameter passing through eavities.
24899.

Explain how to find out the zero error in a spring balance with an example.

Answer»

The zero error in a spring balance can be found by suspending it freely.

Hold the spring balance in your hand and do not place any weights on it.

Note, where the pointer points.

If it is zero, then there is no zero error.

If the pointer is slightly down (say 1) then zero error is -1. So, whatever weight you measure, subtract 1 from it to get the exact result.

Now, the range of the spring balance is the maximum weight that it can measure. So, if the spring balance has maximum reading as 100, then the range of the spring balance is 0-100 kg.

The least count is found by dividing the range of the scale with the total number of divisions on the scale.

If the total number of divisions on the scale is 100, then the least count is 100/100 = 1 kg.

So, the least weight difference that a spring balance can measure is 1 kg.

24900.

In the circuit shown if a conducting wire is connected between points A and B, the current in this wire will :- A. Flow form A to BB. Flow in the direction which will be decided by the value of VC. Be zeroD. Flow from B to A

Answer» Correct Answer - D
`V_(A)-V_(B)=[V-((V)/(8)xx4)]-[V-((V)/(4)xx1)]`
`=-(V)/(2)+(V)/(4)=-(V)/(4)impliesV_(B)gt V_(A)`