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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1951. |
144 grams of C5H12 is burnt with 64 grams O2, and 44 grams of CO2 is formed, what is the percentage of excess O2?(a) 25%(b) 50%(c) 75%(d) 100% |
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Answer» Correct option is (a) 25% The explanation is: The balanced chemical reaction is C5H12 + 8O2 -> 5CO2 + 6H2O, => Extent of reaction = (44/44 – 0)/5 = 0.2. Moles of O2 entered the process = 64/32 = 2, Moles of O2 required = 0.2*8 = 1.6, => Percentage of excess oxygen = 100*(2 – 1.6)/1.6 = 25%. |
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| 1952. |
Solution-1 containing 10% nitric acid and 20% acetic acid at the rate F combines with Solution-2 containing 20% nitric acid and 10% acetic acid at the rate D, the product formed contains 30% nitric acid and 20% acetic acid at the rate P, how many independent equations containing F, D, and P are possible?(a) 1(b) 2(c) 3(d) 4 |
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Answer» Correct option is (c) 3 Easy explanation: The equations of material balance are: 0.1F + 0.2D = 0.3P, 0.2F + 0.1D = 0.2P, and F + D = P. |
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| 1953. |
Solution-1 containing 40% nitric acid and 20% carbon dioxide at the rate F combines with Solution-2 containing 30% nitric acid and 40% carbon dioxide at the rate D, the product formed contains 30% nitric acid and 20% carbon dioxide at the rate P, If P = xF what is x?(a) 1(b) 2(c) 3(d) 4 |
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Answer» Right choice is (b) 2 The explanation: The equations of material balance are: 0.4F + 0.2D = 0.3P, 0.2F + 0.4D = 0.3P, and F + D = P, Solving these we get D = F = P/2, => x = 2. |
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| 1954. |
A gas mixture with 20% O2 with pressure 100 Pa at 27^oC at the rate 50 liter/s is passed through a reactor and products a gas mixture with 40% O2 with pressure 25 Pa at 27^oC, what is the rate of product?(a) 50 liter/s(b) 100 liter/s(c) 200 liter/s(d) 400 liter/s |
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Answer» Right answer is (b) 100 liter/s To explain I would say: O2 balance: 0.2*100*50 = 0.4*25*P, => P = 100 liter/s. |
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| 1955. |
Water flowing with TSS at the rate of 40 Liter/min, is discharged into a river flowing at the rate of 20 Liter/min, if the concentration of TSS in the river is 5 mg/L, what is the concentration of TSS in water?(a) 5 mg/L(b) 10 mg/L(c) 15 mg/L(d) 20 mg/L |
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Answer» Correct answer is (b) 10 mg/L The explanation is: Concentration of TSS in water = 5*40/20 = 10 mg/L. |
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| 1956. |
Waste water flowing with TSS concentration 40 mg/L at the rate of 10 Liter/min is discharged into the river if the river is flowing at the rate of 15 Liter/min, what is the concentration of TSS in the river?(a) 10 mg/L(b) 30 mg/L(c) 45 mg/L(d) 60 mg/L |
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Answer» Right option is (d) 60 mg/L The best I can explain: Concentration of TSS in river = 40*15/10 = 60 mg/L. |
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| 1957. |
What is the molar concentration of a solution with 32 grams of SO2 in 0.5 liter solution?(a) 1 mole/liter(b) 2 mole/liter(c) 3 mole/liter(d) 4 mole/liter |
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Answer» Correct option is (a) 1 mole/liter The best I can explain: Molar concentration = (32/64)/0.5 = 1 mole/liter. |
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| 1958. |
What is the molar concentration of a solution with 44 grams of CO2 in 0.5 liter solution?(a) 1 mole/liter(b) 2 mole/liter(c) 3 mole/liter(d) 4 mole/liter |
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Answer» The correct choice is (b) 2 mole/liter To explain: Molar concentration = (44/44)/0.5 = 2 mole/liter. |
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| 1959. |
Solution-1 containing 30% sulfuric acid flowing at the rate 10 Kg/min combines with Solution-2 containing 20% sulfuric acid flowing at the rate 5 Kg/min, if their product is out at the rate 20 Kg/min what is the percentage of sulfuric acid in the product?(a) 10%(b) 20%(c) 30%(d) 40% |
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Answer» Right choice is (b) 20% For explanation: Equation of material balance, 0.3(10) + 0.2(5) = x(20), => x = 0.2, => Percentage of sulfuric acid in the product = 20%. |
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| 1960. |
What is the enthalpy of reaction for C2H4 + 3O2 -> 2CO2+ 2H2O, if the conversion of CH4 is 50%, and heat of formation of CH4, O2, CO2, and H2O are 10 J, 0, 6 J and 4 J?(a) 0(b) 2 J(c) 5 J(d) 10 J |
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Answer» Correct answer is (d) 10 J For explanation I would say: Heat of reaction = 2*4*0.5 + 2*6*0.5 + 10*0.5 – 0 – 10*0.5 = 10 J. |
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| 1961. |
A container with total volume 10 liter is filled with 20% of O2, 40% of N2, and 40% of CO, what is the volume of O2?(a) 2 liter(b) 4 liter(c) 8 liter(d) 10 liter |
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Answer» Correct answer is (d) 10 liter The explanation is: Volume of each gas in the container is equal to the total volume of the container. |
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| 1962. |
A process is carried out for the feed mixture of 95% air and 5% ammonia vapor, the compressor recovered 40% of ammonia, what is the exit pressure of the compressor, if the partial pressure of ammonia vapor is 10 mm Hg?(a) 225.4 mm Hg(b) 326.8 mm Hg(c) 451.2 mm Hg(d) 593.5 mm Hg |
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Answer» Right choice is (b) 326.8 mm Hg Easiest explanation: Exit components, ammonia: 0.05*0.6 = 0.03, air: 0.95, => yammonia = 0.03/0.98 = 0.0306, => Total exit pressure = 10/0.0306 = 326.8 mm Hg. |
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| 1963. |
Water flowing with chlorine concentration 10 mg/L at the rate of 20 Liter/min, is discharged into a river if the concentration of chlorine in a river is 5 mg/L what is the flow rate of river?(a) 10 Liter/min(b) 20 Liter/min(c) 30 Liter/min(d) 40 Liter/min |
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Answer» The correct option is (a) 10 Liter/min Explanation: Rate of flow of river = 20*5/10 = 10 Liter/min. |
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| 1964. |
Solution-1 containing 30% acetic acid and 100% nitrogen at the rate 10 Kg/min combines with Solution-2 containing 20% acetic acid and 10% nitrogen at the rate 20 Kg/min and Solution-3 containing 10% acetic acid and 30% nitrogen at the rate 30 Kg/min the product formed contains 20% acetic acid, what is the percentage of nitrogen in product?(a) 10%(b) 20%(c) 30%(d) Cannot be determined |
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Answer» Right choice is (a) 10% The explanation is: The equations for material balance are: P = 10 + 20 + 30 = 60 Kg/min, and 0.1(10) + 0.1(20) + 0.3(30) = y(60), => y = 0.1, => Percentage of nitrogen in the product = 10%. |
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| 1965. |
Solution-1 containing 30% acetic acid and 20% nitrogen at the rate 10 Kg/min combines with Solution-2 containing 20% acetic acid and 10% nitrogen at the rate 20 Kg/min and Solution-3 containing 10% acetic acid and 30% nitrogen at the rate N the product formed contains 20% acetic acid at the rate P, what is the percentage of nitrogen in product?(a) 10%(b) 17.5%(c) 25.5%(d) 32.5% |
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Answer» Correct option is (b) 17.5% To explain I would say: The equations for material balance, P = F + D + N = 30 + N, and 0.3(10) + 0.2(20) + 0.1N = 0.2P = 0.2(30 + N), => N = 10 Kg/min, => P = 40 Kg/min, equation of material balance for nitrogen: 0.2(10) + 0.1(20) + (0.3)10 = y(40), => y = 7/40 = 0.175, => Percentage of nitrogen in the product is 17.5%. |
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| 1966. |
CH4 at the rate 10 mole/min is reacted with O2 at the rate 30 mole/min, what is the rate of formation of CO2 in the product?(a) 5 mole/min(b) 10 mole/min(c) 20 mole/min(d) 40 mole/min |
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Answer» The correct choice is (b) 10 mole/min The best explanation: The balanced chemical reaction is: CH4 + 2O2 -> CO2 + 2H2O, this means CH4 is the limiting reagent, => rate of formation of CO2 = 10 mole/min. |
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| 1967. |
A gaseous mixture is composed of 20% CO2, 40% O2 and 40% N2. What is the mass fraction of N2?(a) 0.307(b) 0.416(c) 0.529(d) 0.784 |
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Answer» The correct option is (a) 0.307 Best explanation: Let the total moles of the mixture be 100, => mass of CO2 = 20*44 = 880 g, mass of ¬O2 = 40*16 = 640 g, mass of N2 = 40*14 = 560 g, => mass fraction of N2 = 560/(880 + 640 + 560) = 0.307. |
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| 1968. |
What is the weight of 10 moles of a mixture with composition 15% O2, 25% SO2, 30% COCl2, 25% SO3 and 5% N2?(a) 124(b) 345(c) 507(d) 719 |
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Answer» Correct option is (d) 719 To explain I would say: Molecular weight of mixture = (15*32 + 25*64 + 30*99 + 25*80 + 5*28)/100 = 71.9, => Weight of mixture = 71.9*10 = 719. |
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| 1969. |
How many gm moles oxygen are there in 88 gms carbon di oxide?(a) 1(b) 2(c) 3(d) 4 |
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Answer» The correct option is (d) 4 Easiest explanation: 88gms of CO2 = 2 moles of CO2 = 4 moles of oxygen. |
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| 1970. |
What is the value of ω2 for A?(a) 0.5(b) 0.6(c) 0.7(d) 0.8 |
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Answer» The correct answer is (a) 0.5 For explanation I would say: Σω = 1. |
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| 1971. |
A gas mixture of 40% He and 60% Ne is passed through a diffusion tube, if the amount of He is recovered is 20% of the input, what is the percentage of He in the product?(a) 25 %(b) 33.3 %(c) 50 %(d) 66.6 % |
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Answer» Right option is (a) 25 % Explanation: Let the amount of input be F, He balance: 0.4(F) = 1(0.2F) + x(F – 0.2F), => x = 0.25, => Percentage of He in the product = 25%. |
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| 1972. |
An aqueous solution with chlorine 30 g/L and an organic compound with no chlorine at the rate 50 L/min were put into an extraction machine and produced aqueous solution with chlorine 5 g/L and organic compound with chlorine 10 g/L, what is the rate of aqueous solution?(a) 10 L/min(b) 20 L/min(c) 30 L/min(d) 40 L/min |
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Answer» Correct answer is (c) 30 L/min The best I can explain: Let the rate of an aqueous solution be x. Chlorine balance equation, x(30) + 50(0) = x(5) + 50(10), => x = 20 L/min. |
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| 1973. |
What is the molecular weight of a mixture that contains 25% CO2, 40% O2 and 35% N2?(a) 11.2 g(b) 22.4 g(c) 33.6 g(d) 44.8 g |
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Answer» Correct choice is (c) 33.6 g Easy explanation: Molecular weight = (25*44 + 40*32 + 35*28)/100 = 33.6 g. |
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| 1974. |
What is the total pressure of a system having 40% O2 with 5 atm partial pressure and 60% N2 with 10 atm partial pressure?(a) 2 atm(b) 6 atm(c) 8 atm(d) 10 atm |
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Answer» The correct choice is (c) 8 atm To elaborate: P = 0.4*5 + 0.6*10 = 8 atm. |
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| 1975. |
A 1000 ml solution has 0.25 gms of solute. What is the concentration(gm/L)?(a) 0.25(b) 2.5(c) 25(d) 250 |
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Answer» The correct choice is (a) 0.25 To elaborate: Concentration = Mass / Volume. |
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| 1976. |
A reactor is supplied with a 100 mole feed of composition 46% C3H7O4, 44% O2 and 10% N2, if 50% of the limiting reagent is converted into product, what is the extent of reaction?(a) 1(b) 2(c) 3(d) 4 |
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Answer» Correct answer is (b) 2 The explanation is: The reaction is 4C3H7O4 + 11O2 -> 12CO2 + 14H2O, => limiting reagent is O2, => Extent of reaction = (44*0.5 – 44)/(-11) = 2. |
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| 1977. |
The quantity of solute per unit volume is __________(a) Mole(b) Concentration(c) Density(d) None of the mentioned |
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Answer» The correct answer is (b) Concentration For explanation: The quantity of solute per unit volume is concentration. |
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| 1978. |
A gas mixture input is given to a membrane with 40% O2 and 60% N2, the waste contains 80% of the input and the product contains 25% O2 and 75% N2, what is the percentage of O2 in the waste?(a) 0.22(b) 0.44(c) 0.66(d) 0.88 |
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Answer» Correct answer is (b) 0.44 For explanation: Let the input is 100 Kg mol, => waste = 0.8(100) = 80 Kg mol, => Product = 20 Kg mol. Equation of material balance, O2: 0.4(100) = 0.25(20) + y(80), => y = 0.4375 ≈ 0.44. |
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| 1979. |
100 Kg of a gas mixture of 40% He and 60% Ne is passed through a diffusion tube and the product has 20% He and 80% Ne, what is the amount of He recovered?(a) 25 Kg(b) 45 Kg(c) 50 Kg(d) 75 Kg |
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Answer» The correct choice is (a) 25 Kg The explanation is: Let the amount of He recovered be D, He Balance: 0.4(100) = 1(D) + 0.2(100 – D), => D = 25 Kg. |
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| 1980. |
_____________ is used for the measurement of gauge pressure.(a) Manometer(b) Barometer(c) Hydrometer(d) None of the mentioned |
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Answer» Correct answer is (a) Manometer To elaborate: Manometer is used for the measurement of gauge pressure. |
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| 1981. |
The _______ is computed by dividing the total process cost by number of units produced in that particular process. |
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Answer» The Cost per unit is computed by dividing the total process cost by number of units produced in that particular process. |
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| 1982. |
What is mole percentage of H2O?(a) 0.2(b) 0.4(c) 0.6(d) 0.8 |
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Answer» The correct choice is (b) 0.4 Best explanation: Mole percentage = Moles of the component / Total moles. |
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| 1983. |
A cube of ice is floating on water surface and when it completely melts, the level of water would _______(a) Increase(b) Decrease(c) Remains unchanged(d) None of the mentioned |
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Answer» The correct option is (c) Remains unchanged The best I can explain: There is no change in the volume of the water as the space occupied by the ice inside the water body is filled with it. |
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| 1984. |
Properties that do not depend on the quantity of material present, are called(a) Intensive properties(b) Extensive properties(c) Variable properties(d) None of the mentioned |
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Answer» Right answer is (a) Intensive properties Easiest explanation: Properties that do not depend on the quantity of material present are called intensive properties. |
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| 1985. |
50 Kg of a solid liquid mixture containing 20% solid and 80% water is left open in the atmosphere, after some time the water is 60%, how much water is evaporated?(a) 15 Kg(b) 25 Kg(c) 35 Kg(d) 45 Kg |
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Answer» Right option is (b) 25 Kg To elaborate: Let the weight of the water evaporated be W. Water Balance: 0.8(50) = 1(W) + 0.6(50 – W), => W = 25 Kg. |
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| 1986. |
A static column of height h is filled with a liquid of density D. What is the static pressure at the bottom if the column is placed in open.(a) P* + Dgh(b) Dgh(c) P*(d) None of the mentioned |
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Answer» Right choice is (a) P* + Dgh To explain I would say: Static pressure at the bottom = P* + Dgh. |
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| 1987. |
A pseudo molecular weight computed by dividing the mass in a mixture or solution by the number of moles in the mixture or solution is called(a) Molecular weight(b) Average molecular weight(c) Atomic weight(d) None of the mentioned |
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Answer» Right answer is (b) Average molecular weight For explanation: A pseudo molecular weight computed by dividing the mass in a mixture or solution by the number of moles in the mixture or solution is called average molecular weight. |
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| 1988. |
What is the molar flow rate of sodium solution if 80 gms of solution is collected in 20 seconds.(a) 0.1(b) 0.2(c) 0.3(d) 0.4 |
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Answer» The correct answer is (a) 0.1 The explanation: Molar flow rate = moles/time. |
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| 1989. |
Suppose at a place A the level of mercury in the mercury barometer touches 76cm. What may be the atmospheric pressure then? Calculate the atmospheric pressure experienced at a height of 50 metres over the same. place. |
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| 1990. |
56 in Hg equals(a) 13.76 psia(b) 27.52 psia(c) 28.56 psia(d) 57.12 psia |
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Answer» Correct choice is (b) 27.52 psia The best explanation: 56 in Hg = (56*14.7)/29.92 = 27.52 psia. |
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| 1991. |
One mole of H2O equals(a) 22.4 litre at 1 atm and 250C(b) 6.02 x 10^23 atoms of hydrogen and 6.02 x 10^23 atoms of oxygen(c) 18 g(d) 1 gal |
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Answer» The correct option is (c) 18 g The explanation: One mole of H2O = 18 gms. |
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| 1992. |
Using the proper number of significant figures 6 X 6 equals to(a) 3(b) 4(c) 36(d) 40 |
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Answer» Correct choice is (d) 40 Explanation: Significant figure in 40 is only one that is same as 6. |
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| 1993. |
Which one is the most concentrated solution?(a) 20 g of NaOH in 100 mL of water(b) 150 g of NaOH in 200 mL of water(c) 180 g of NaOH in 300 mL of water(d) 250 g of NaOH in 600 mL of water |
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Answer» The correct answer is (b) 150 g of NaOH in 200 mL of water Explanation: Concentration = Mass / Volume. |
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| 1994. |
40 psia equals(a) 175.64 kPa(b) 275.64 kPa(c) 375.64 kPa(d) 475.64 kPa |
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Answer» The correct answer is (b) 275.64 kPa To elaborate: 40 psia = (40*101.3)/14.7. |
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| 1995. |
_________ variable does depend on how much material you have.(a) Intensive(b) Extensive(c) Both intensive and extensive(d) Neither intensive nor extensive |
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Answer» Right choice is (b) Extensive The best explanation: Extensive variable does depend on how much material you have. |
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| 1996. |
50 Kg of a solid liquid mixture containing 10% solid and 90% water is left open in atmosphere, after some time the water is 80%, what is the weight of the mixture now?(a) 10 Kg(b) 25 Kg(c) 35 Kg(d) 50 Kg |
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Answer» Right option is (b) 25 Kg Best explanation: Make solid and water balance. |
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| 1997. |
A material have a mass of 2 gms and volume of 4 cm3. The material would _____ on water surface.(a) Completely Float(b) Completely Sink(c) Partially Sink(d) None of the mentioned |
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Answer» Correct answer is (b) Completely Sink For explanation: Specific gravity of the material is less than one. |
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| 1998. |
1 atm pressure equals to(a) 29.92 in Hg(b) 25.65 in Hg(c) 27.68 in Hg(d) 24.74 in Hg |
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Answer» Right answer is (a) 29.92 in Hg To elaborate: 1 atm = 29.92 in Hg. |
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| 1999. |
Heating a liquid at constant pressure can definitely cause____________(a) Vaporization(b) Condensation(c) Boiling(d) None of the mentioned |
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Answer» Correct option is (a) Vaporization Easiest explanation: Heating a liquid at constant pressure can definitely cause Vaporization. |
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| 2000. |
If HCl is present in excess and the amount of NaOH is doubled, number of moles of NaCl will be ____________(a) Doubled(b) Half(c) Four times(d) None of the mentioned |
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Answer» Right choice is (a) Doubled To explain I would say: 1 mole of NaOH is equivalent to 1 mole of NaCl. |
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