1.

100 Kg of a gas mixture of 40% He and 60% Ne is passed through a diffusion tube and the product has 20% He and 80% Ne, what is the amount of He recovered?(a) 25 Kg(b) 45 Kg(c) 50 Kg(d) 75 Kg

Answer» The correct choice is (a) 25 Kg

The explanation is: Let the amount of He recovered be D, He Balance: 0.4(100) = 1(D) + 0.2(100 – D), => D = 25 Kg.


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