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98801.

sulphur containing amino acid is

Answer»

Answer: Homocysteine

98802.

the power house of a cell is

Answer»

The power house of the cell is Mitochondria.

98803.

cholestrol is transported from the liver to extrahepatic tissues by

Answer»

Cholesterol is transported from liver to extrahepatic tissues by LDL.

98804.

oxidation of fatty acids occurs

Answer»

Answer: In the matrix of mitochondria.

98805.

NH3 is detoxified in the brain as

Answer»

Answer:  Glutamine.

98806.

Explain the following: a). ICl is more reactive than I2 b). NaBiO3 is stronger oxidizing agent c). Noble gases have very low boiling point.

Answer»

(a) I ‐Cl bond is weaker than I‐I and Cl – Cl bond. 

(b) Bi has +5 oxidation state in NaBiO3. +3 O.S of Bi is more stable than +5 due to inert pair effect 

(c) Noble gases are monoatomic and their atoms are held together by weak dispersion forces.

98807.

Define the following as related to proteins. a). Peptide linkage b). Primary structure c). Denaturation

Answer»

(a) Peptide linkage: 

It is an amide linkage formed between ‐COOH group and ‐NH2 group of alpha aminoacids in proteins. 

(b) Primary structure: 

The specific sequence in which various amino acids are linked to one another in a Protein molecule is called its primary structure. 

(c) Denaturation: 

A process in which secondary and tertiary structures of proteins are destroyed but Primary structure remains the same is called denaturation of protiens. It is caused by change in temp, change in pH etc.

98808.

Expain the majar drought prone areas of India.

Answer»

On the basis of severity of droughts, India can be divided into three drought prone areas.

a. The Extreme drought prone areas: This is the most important drought prone areas of the country which has been recording continuous drought for many years. The regions are western parts of Rajasthan, Kutch regions of Gujarat and semi-arid regions of Western and North western parts of India.

b. The Severe drought prone areas: This is the second important drought prone areas of the county. The eastern parts of Rajasthan, western parts of Madhya Pradesh, Parts of Maharashtra, interior parts of Andhra Pradesh. North and northeastern parts of Karnataka and Tamil nadu.

c. The Moderate drought prone areas: This region is mainly found in regions of U.P, parts of Gujarat, Maharashtra, Jharkhand, Tamil Nadu and interior parts of Karnataka.

98809.

Study the given paragraph and answer the questions. A rare and magnificient fossil of the dinosaurs, ketosaures belonging to the lower Jurassic age going back to about 160 million years as collected from Yamanapalli of Adilabad district. (i) Name the branch of Science that deals with the study of fossils. (ii) In which place, the fossil of ketosaures was collected from ?

Answer»

(i) Palaeonotology. 

(ii) It was collected from Yamanapalli of Adilabad district.

98810.

Palaeontology is the study of?1. Bones2. Primates3. Fossils4. Birds

Answer» Correct Answer - Option 3 : Fossils

The correct answer is Fossils.

  • Palaeontology is the study of the history of life on Earth as based on fossils.
  • Fossils are the remains of plants, animals, fungi, bacteria, and single-celled living things that have been replaced by rock material or impressions of organisms preserved in rock. 
  • Palaeontology is the scientific study of the life of the geologic past that involves the analysis of plant and animal fossils, including those of microscopic size, preserved in rocks.

  • Osteology is the study of Bones.
  • Primatology is the scientific study of primates.
  • The study of Birds is known as Ornithology.
  • The study of plants is known as Botany.
98811.

"Migration may enhance or blurr the effects of selection". Comment.

Answer»

Migration can enhance the process of natural selection by bringing in the alleles and traits within a population that are selected by nature. Hence, providing advantage to a particular group. 
Migration can blur the effect of natural selection by removing the useful traits or genes from the population.

98812.

"Migration may enhance or blurr the effects of selection".Comment.

Answer»

Migration can enhance the process of natural selection by bringing in the alleles and traits within a population that are selected by nature. Hence, providing advantage to a particular group.
Migration can blur the effect of natural selection by removing the useful traits or genes from the population.

98813.

You have studied the story of pepper moths in England. Had the industries been removed, what impact could it have had on the moth population? Discuss.

Answer»

In the population of Peppermoth, 2 variants were already existing in the population, the black and the grey. In the absence of Industrialisation, the grey moths were prevalent because they blended very well with the lichen and moss covered trees camouflage and the predators cannot spot them. The Black ones were easily spotted and killed by predators and therefore, were fewer in numbers. With Industrialisation, the stems got covered with black soot. This provided better camouflage to the black variant and their number increased. If the industries had been removed the population of black moths would have declined because as stated earlier they would have been spotted better by predators and therefore be eaten more frequently.

98814.

All of the following statements about uric acid are true except (A) It can be formed from allantoin (B) Formation of uric acid stones in kidneys can be decreased by alkalinisation of urine (C) Uric acid begins to dissociate at pH above 5.8 (D) It is present in plasma mainly as monosodium urate

Answer»

(A) It can be formed from allantoin

98815.

In mammals other than higher primates uric acid is converted by (A) Oxidation to allantoin(B) Reduction to ammonia (C) Hydrolysis to ammonia (D) Hydrolysis to allantoin

Answer»

(A) Oxidation to allantoin

98816.

An atmosphere is

Answer»

An atmosphere is the layers of gases surrounding a planet or other celestial body. Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases.

98817.

What do you mean by electrostatic potential energy

Answer»

Electric potential energy is the energy that is needed to move a charge against an electric field. You need more energy to move a charge further in the electric field, but also more energy to move it through a stronger electric field.

98818.

Point P is 5m towards the South of Point M. Point Q is 3m towards the East of Point P . Point O is 3m towards the East of Point M. Point N is 2 m towards the South of Point Q. How far and towards which direction is Point O from point N ?A. 5 m towards SouthB. 7 m towards NorthC. 8 m towards WestD. 7 m towards West

Answer» Correct Answer - B
Points O is 7 metres towards. North of Point N.
98819.

Plane angle and solid angle have : (1) Dimensions but no units (2) No units and no dimensions (3) Both units and dimensions (4) Units but no dimensions

Answer»

(4) Units but no dimensions

Plane angle and solid angle are dimensionless but have units.

98820.

If a soap bubble expands, the pressure inside the bubble : (1) increases (2) remains the same (3) is equal to the atmospheric pressure (4) decreases

Answer»

Correct option is (4) decreases

P = P+ 4T/R

 R increases and P decreases

98821.

Consider circuit as shown in figure. The current through wire AB is A. `1A`B. `2A`C. `3A`D. None

Answer» Correct Answer - B
98822.

Consider the circuit as shown in figure. The equivalent resistance between A and B is A. `(9)/(7)Omega`B. `(1)/(9)Omega`C. `(7)/(9)Omega`D. None

Answer» Correct Answer - C::D
98823.

In the circuit shown in the figure, the value of maximum rate of heat production in resistance R is A. `(25)/(12)W`B. `(38)/(12)W`C. `(35)/(12)W`D. None

Answer» Correct Answer - A
98824.

Consider circuit as shown . Which of the graph best represent V-l relationship across the variable resistance R. A. B. C. D.

Answer» Correct Answer - A
98825.

While measuring length of small iron rod, following five reading wee obtained. `12.66 mm, 12.58 mm, 12.62 mm, 12.80 mm and 12.72mm` The experimenter reported the result of the experiment based on the obove readings.A. Number of significant figures in the length reported will be `3`.B. Number of significant figures in the lenth reported will be `4`.C. Number of significant figure in the error reported will be `1`.D. Number of significant figures in the error reported will be `2`.

Answer» Correct Answer - B
98826.

A resistance R is to be measured using a meter bridge. Student chooses the standared resistance S to be `100 Omega`. He finds the null point at `l_(1)=2.9cm`. He is told to attempt to improve the accuracy. Which of the folllowing is a useful way?A. He should measure `l_(1)` more accurately.B. He should change S to `1000 Omega` and repeat the experiment.C. He should chandge S to `3 Omega` and repeat the experiment.D. He should give up hope of a more accurate measurement with a meter bridge.

Answer» Correct Answer - C
98827.

Procedure to solve Block Diagram Reduction Problems

Answer»

Block Diagram Reduction Problems : 

• Step 1: Reduce the blocks connected in series 

• Step 2: Reduce the blocks connected in parallel 

• Step 3: Reduce the minor feedback loops 

• Step 4: Try to shift take off points towards right and Summing point towards left 

• Step 5: Repeat steps 1 to 4 till simple form is obtained 

• Step 6: Obtain the Transfer Function of Overall System

98828.

A current of 5 A flows in a resistor of resistance 8 Ω. Determine the rate of heat dissipation and also the heat dissipated in 30s.

Answer»

Solution:  P = I2 R = 52 × 8 = 200 W

W = Pt = 200 × 30 = 6000 J

98829.

What are the advantages/disadvantages of Block Diagram Representation ?

Answer»

Advantages of Block Diagram Representation 

• Very simple to construct block diagram for a complicated system 

• Function of individual element can be visualized 

• Individual & Overall performance can be studied 

• Over all transfer function can be calculated easily

Disadvantages of Block Diagram Representation

• No information about the physical construction

• Source of energy is not shown

98830.

How current flow in a circuit.

Answer»

For most practical applications, it is necessary that current flow continues for as long as it is required; this will not unless the following conditions are fulfilled:

1. There must be a complete path around which the electrons may move. If the electrons cannot return to the point of starting, then eventually they will all congregate together and the flow will cease.

2. There must be a driving influence to cause the continuous flow. This influence is provided by source which causes the current to leave at a high potential and to move round the circuit until it returns to the source at a low potential.

The driving influence is termed as the electromotive force, hereafter called the e.m.f

The direction of an electric current is by convention the direction in which a positive charge would move. Thus, the current in the external circuit is directed away from the positive terminal and toward the negative terminal of the battery. Electrons would actually move through the wires in the opposite direction.

98831.

What is ampere?

Answer»

The ampere is defined as that current which, if maintained in two straight parallel conductors of infinite length, of negligible circular cross-section, and placed 1 meter apart in a vacuum, would produce between these conductor a force of 2 × 10-7 Newton per meter of length.

 An ampere is a unit of measure of the rate of electron flow or current in an electrical conductor.

1 ampere is defined as 1 coulomb of charge per second.

 

98832.

What is the Block diagram reduction technique ?

Answer»

Block diagram reduction technique

Because of their simplicity and versatility, block diagrams are often used by control engineers to describe all types of systems. A block diagram can be used simply to represent the composition and interconnection of a system. Also, it can be used, together with transfer functions, to represent the cause‐ and‐effect relationships throughout the system. Transfer Function is defined as the relationship between an input signal and an output signal to a device

98833.

The focal length of a concave mirror is of its radius of curvature—(A) Double (B) Half(C) One fourth (D) Equal

Answer»

The focal length of a concave mirror is of its radius of curvature Half.

98834.

An object is placed of at a distance of 30 cm from a convex lens. A real image is formed at the same distance from the lens. The focal length of the lens is —(A) 30 cm (B) 20 cm(C) 15 cm (D) 10 cm

Answer»

The correct option is:

(C) 15 cm 

98835.

Which eye-defect arises due to decreasing of focal length of eye lens—(A) Myopia (short sightedness) (B) Hypermotropia (far shightedness)(C) Presbyopia (D) None of these

Answer»

Myopia (short sightedness) eye-defect arises due to decreasing of focal length of eye lens.

98836.

Discuss the law of transverse vibrations In stretched string?

Answer»

Laws of transverse vibrations in stretched strings: 

There are three laws of transverse vibrations of stretched strings which are given as follows:

(I) The law of length: 

For a given wire with tension T (which is fixed) and mass per unit length p (fixed) the frequency varies inversely with the vibrating length. 

Therefore, 

f ∝ \(\frac{1}{l}\) ⇒ f = \(\frac{C}{2}\)

⇒1 × f = C, where C is constant

(II) The law of tension: 

For a given vibrating length I (fixed) and mass per unit length p (fixed) the frequency varies directly with the square root of the tension T,

f ∝ \(\sqrt T\)

⇒f = A\(\sqrt T\), Where A is constant

(III) The law of mass: 

For a given vibrating length l (fixed) and tension T (fixed) the frequency varies inverely with the square root of the mass per unit length µ,

f = \(\frac{1}{\sqrt μ}\)

⇒f = \(\frac{B}{\sqrt μ}\), Where B is constant

98837.

During short circuit an electric current in the circuit becomes —(A) very low (B) unchanged(C) very high (D) changes constantly

Answer»

During short circuit an electric current in the circuit becomes very high.

98838.

Which of the following expression does not represent electric power in an electric circuit ?(A) I2R (B) IR2(C) VI (D) V2/R

Answer»

IR2 does not represent electric power in an electric circuit.

98839.

Write full form of ‘LASER’ and ‘MASER’ ?

Answer»

‘LASER’ stands for light Amplication by stimulated emission of radiation.

‘MASER’ stands for microwave Amplication by stimulated emission of radiation.

98840.

a capacitor of capacitance `C` is connected to two voltmeter `A` and `B`. `A` is ideal , having infinite resistance, while `B` has resistance `R`. The capcitor is charged and then switch `S` is closed. The reading of `A` and `B` will be equal A. at all timesB. after time RCC. after time RC in 2D. only after a very long time

Answer» Correct Answer - A
a.A and B are effectively in parallel and hence give the same reading every time.
98841.

In the given circuit in which case will the ammeter reading not change when `R_2` is varied? A. `R_1= r`B. `R_1 = 2r`C. `R_1gtR_2`D. `r =0`

Answer» Correct Answer - D
d. When r = 0 the terminal potential difference in the arm
containing `R_1` remains unchanged, so the ammeter reading does
not change.
98842.

A screw gauge having `100` equal division and a pitch of length `1mm` is used to measue the diameter of a wire of length `5.6cm`. The main scale reading is `1mm and 47^(th)` circular division coincides with the scale. Find the curved surface area of wire in `cm^(2)` to appropriate significant fihure. `(use pi = (22)/(7)`

Answer» Correct Answer - 2.6
Least count`=(1mm)/(100)=0.01mm`
`Diameter=MSR+CSR`
`=1mm+47(0.01)mm=1.47mm`
Surface are
`piDl=(22)/(7)xx1.47xx56mm^(2)`
`=2.58724cm^(2)=2.6cm^(2)`
98843.

A constant voltage dc source is connected, as shown in Fig. A2.7, across two resistors of resistances `400 kOmega` and `100 k Omega`. What is the reading of the voltmeter, also of resistance `100 kOmega`, when connected across the second resistor as shown? A. 111 VB. 250 VC. 125 VD. 333 V

Answer» Correct Answer - A
a. Effective resistance across voltmeter is `50kOmega`. Total resistance
across the dc supply is `450 kOmega`.
Current drawn from supply `1000 V//450 kOmega = 1//450A`. Potential difference across voltmeter is
`(50 xx 1000)/450 V = (1000)/9 V = 111V` .
98844.

Define current density. Write its SI unit and dimension

Answer»

Current density—Current density of a conductor is defined as the amount of current passing per unit area of the conductor held to the flow of chares :

It can be expressed as— 

J = I/A

It is a vector quantity.

The S.I. unit of current density is ampere/ metre2 (Am–2)

The dimension of current density is [MºL–2TºA]

98845.

State two properties of nuclear force.

Answer»

Two properties of nuclear forces are as follows : 

(1) It is mainly an attractive force.

(2) It is strong fundamental force in nature.

98846.

Ampere-hour is a unit ofA. Quantity of electricityB. Strength of electric currentC. PowerD. Energy

Answer» Correct Answer - A
charge`=`current`xx`time
98847.

Which of the following teams is the champion of 2018-19 Premier Badminton League, Played during 22 December to 13 January?A. Hyderabad huntersB. Pune 7 acesC. Mumbai rocketsD. Bangaluru Raptors

Answer» Correct Answer - D
98848.

Which of the following Nation has won 2018 Hockey World Cup, held in India?A. NetherlandsB. BelgiumC. IndiaD. Australia

Answer» Correct Answer - B
98849.

2018 Hockey Wold Cup was held in?A. IndiaB. PakistanC. AustraliaD. Netherlands

Answer» Correct Answer - A
98850.

A mixture of plane polarised and unpolarised light falls normally on a polarising sheet. On rotating the polarising sheet about the direction of the incident beam, the transmitted intensity varies by a factor 4. Find the ratio of the intensities `I_(P)` and `I_(0)` respectively of the polarized and unpolarised components in the incident beam. Next the axis of polarising sheet is fixed at an angle of `45^(@)` with the direction when the transmitted intensity is maximum. Then obtain the total intensity of the transmitted beam in terms of `I_(0)`. `[(3)/(2),(5I_(0))/(4)]`A. `(2)/(1)`B. `(3)/(2)`C. `(4)/(3)`D. `(4)/(1)`

Answer» Correct Answer - 2
Intensity of polarised light
`I__(p) = I_(p) cos ^(2) theta//2`
`theta I_(p) ={ {:(,"max" =I_(p)),(,"min"=0):}`
But intensity of unpolarised light remains const.
`therefore I_(0) = I_(0)//2`
`therefore I_("max")= I_(p) + I_(0)//2`
`I_("min") = I_(0)//2`
but problem `I_(p) +(I_(0))/(2) = 4(I_(0))/(2)`
`therefore (I_(p))/(I_(0)) =(3)/(2)`