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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Identify positive or normative statements from the following : There are inequalities in the distribution of income and wealth in India |
| Answer» Correct Answer - Positive statements | |
| 2. |
Identify positive or normative statements from the following : 5% population of India is below poverty line |
| Answer» Correct Answer - Positive statements | |
| 3. |
Identify positive or normative statements from the following : Free education should be given to the poor till class XII |
| Answer» Normative statements | |
| 4. |
Explain how the following problems of an economy be solved with the help of price mechanism: (i) What to produce ? (ii) How to produce ? |
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Answer» (i) Price mechanism automatically solves the problems of what to produce. Profit motive is the main motive od producers. If demand for a commodity increases, it would increase profit of producers and encourage them to produce more of this commodity. Therefore automatically, the commodity that is more in demand would get produced. The opposite happens when demand of the commodity falls. So (a) `uarr` Demand `- uarr` Price, `- uarr` Profits `- uarr` Production (b) `darr` Demand `- darr` Price, `- darr` Profits `- darr` Production (ii) Is the price of labour (wages) and price of capital (interest) that would help the producers in deciding between labour intensive and captial intensive technique. In a labout surplus economy, wages would be low, which means less cost of production implying more profits to the producers so he would choose labour intensive technique. In a capital surplus economy, price of capitial being low, the profits would be more, so the producers would choose capital intensive technique. |
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| 5. |
State whether the following statements are true/false PPC is cancave due to increasing MOC_________. |
| Answer» true because MOC increase then ppc will be concave | |
| 6. |
Identify positive or normative statements from the following : Accommodation of Refugees is posing a big problem for the Europe |
| Answer» Correct Answer - Positive statements | |
| 7. |
State whether the following statements are true/false An economy can operate outside PPC with available production capacity___________ . |
| Answer» false because an economy cannot produce above the PPC curve because they have limited resources | |
| 8. |
The central problems of an economy areA. what to produce and how muchB. how to produceC. for whom to produceD. all of these |
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Answer» Correct Answer - D The central problems of an economy are what to produce and how much,for whom to produce |
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| 9. |
Identify positive or normative statements from the following : India government should design new polices to control inflation |
| Answer» Normative statements | |
| 10. |
What is meant by economising of resources ? |
| Answer» Economising of resources means best possible use of available resources. . | |
| 11. |
I regret _____ you that you are to be dismissed next month. A) inform B) to inform C) informing D) having informed |
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Answer» Correct option is B) to inform |
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| 12. |
She would sit for hours listening _____ the songs of the birds. A) to B) from C) at D) with |
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Answer» Correct option is A) to |
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| 13. |
To "call it a day" means _____. A) to quit B) it becomes evening C) to say good morning |
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Answer» Correct option is A) to quit |
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| 14. |
To "carry off" means _____. A) to move B) to kill C) to drop |
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Answer» Correct option is A) to move |
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| 15. |
Why was there no tear in buttoo's eye |
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Answer» Buttoo did this for Arjuna's sake and to keep his own promise to Arjuna.
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| 16. |
Directions : Each of these questions contain two statements, Assertion and Reason. Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select one of the codes (a), (b), (c) and (d) given below.(a) Assertion is correct, reason is correct; reason is a correct explanation for assertion.(b) Assertion is correct, reason is correct; reason is not a correct explanation for assertion(c) Assertion is correct, reason is incorrect(d) Assertion is incorrect, reason is correct.Assertion : Bond angle of H2S is smaller than H2O.Reason : Electronegativity of the central atom increases, bond angle decreases. |
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Answer» (c) Bond angle of H2S (92°) < H2O (104°31). As the electronegativity of the central atom decreases, bond angle decreases. In the present case, S is less electronegative than oxygen. Thus bond pairs in H2S are more away from the central atom than in H2O and thus repulsive forces between bond pairs are smaller producing smaller bond angle. |
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| 17. |
Which one of the following is not an use of ammonia ?(a) To produce various nitrogenous fertilizers.(b) In manufacture of nitric acid(c) As a refrigerate(d) In the pickling of stainless steel |
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Answer» (d) NH3 is not used in the pickling of stainless steel. |
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| 18. |
PH3, the hydride of phosphorus is(a) metallic (b) ionic (c) non-metallic (d) covalent |
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Answer» (d) PH3 is covalent hydride |
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| 19. |
One mole of calcium phosphide on reaction with excess water gives(a) one mole of phosphine(b) two moles of phosphoric acid(c) two moles of phosphine(d) one mole of phosphorus pentoxide |
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Answer» (c) Ca3 P2 + 6H2O →3Ca(OH)2 + 2PH3 ; i.e 2 moles of phosphine are produced from one mole of calcium phosphide Ca3P2+6H2O⇒3Ca(OH)2+2PH3 1 mol of Ca3P2=2 moles of PH3 It shows that one mole of calcium phosphide on reaction with excess of water gives 2 moles of phosphine. Hence, Option C is Correct |
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| 20. |
Which statement is incorrect ?A. `Pb^(4+)` salts are batter oxidising agent.B. `Tl^(3+)` salts are better reducing agent.C. `BiF_(5)` and `TlI_(3)` both compounds exist.D. `PbI_(4)` is less stable than `PbI_(2)` |
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Answer» Correct Answer - B Which statement is ……….. On the basis of inert pair effect. |
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| 21. |
Which of the following is diamagnetic ?A. `(Ni(CN)_(4))^(2-)`B. `(NiCl_(4))^(2-)`C. `(CoCl_(4))^(2-)`D. `(CoF_(6))^(2-)` |
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Answer» Correct Answer - A `(Ni(CN)_(4))^(2-)` is `dsp^(2)` hybridised ad diamagnetic. |
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| 22. |
A certain amount of reducing agent reduces x mole of `KMnO_(4)` & y mole of `K_(2)Cr_(2)O_(7)` in difference experiments in acidic medium. If the change in oxidation state of reducing agent is same in both experiments then `x:y` isA. `5:3`B. `3:5`C. `5:6`D. `6:5` |
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Answer» Correct Answer - D Equivalent of `KMnO_(4)=5x` Equivallent of `K_(2)Cr_(2)O_(7)=6y` Equivalents of oxidising agent must be same `5x=6y` `x:y=6:5` |
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| 23. |
Which of the following element will form acidic oxides of type E2O3?(a) As (b) Sb (c) Bi (d) P |
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Answer» (d) The oxides of the type E2O3 of nitrogen and phosphorus are purely acidic |
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| 24. |
Which of the following exhibit both Frenkel & Schottky defect? (1) AgBr (2) KCl (3) CsCl (4) ZnS |
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Answer» Answer: (1) AgBr Only AgBr can exhibit both Schottky and Frenkel defect. |
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| 25. |
Which of the following is the strongest reducing agent ?(a) NH3 (b) PH3 (c) BiH3 (d) SbH3 |
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Answer» (c) BiH3 is the strongest reducing agent while NH3 is the weakest reducing agent. |
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| 26. |
An alkaline earth metal 'M' readily forms water soluble sulphate and water insoluble hydroxide. Its oxide MO is very stable to heat and does not have rock-salt structure. M is :- (1) Ca (2) Be (3) Mg (4) Sr |
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Answer» [Be] BeSO4 is water soluble Be(OH)2 is water insoluble BeO is stable to heat |
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| 27. |
What is the IUPAC name of [Cr(NH3)2(H2O)3]Cl3? |
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Answer» Triaquatriammine Chromium (iii) Chloride. |
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| 28. |
Which of the following is used as anaesthetic ? (A) Chloroform (B) Iodoform (C) Acetylene (D) Methane |
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Answer» Correct answer is (A) Chloroform |
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| 29. |
Isopropyl alcohol on oxidation forms – (A) Acetone (B) Ether (C) Acetaldehyde (D) Ethylene |
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Answer» Correct answer is (A) Acetone |
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| 30. |
Graphite is a good conductor of electricity.Reason?A. Due to presence of free ElectronsB. due to its sheet like structureC. both of theseD. none of these |
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Answer» Correct Answer - A |
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| 31. |
Covalency of nitrogen molecule isA. 1B. 2C. 3D. 6 |
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Answer» Correct Answer - C |
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| 32. |
(a) Vomiting(b) Salivation(c) Heart beat(d) Chewing |
| Answer» (d) Chewing, is The correct option | |
| 33. |
(a) differentiate the taste of an apple from that of an ice cream(b) differentiate the smell of a perfume from that of an agarbatti(c) differentiate red light from green light(d) differentiate a hot object from a cold object |
| Answer» (b) differentiate the smell of a perfume from that of an agarbatti | |
| 34. |
1 g of a monobasic acid dissolved in 200 g of water lowers the freezing point by `0.186^@ C`.On the other hand when 1 g of the same acid is dissolved in water so as to make the solution 200 mL , this solution requires 125 mL of 0.1 N NaOH for complete neutralization. If `alpha` for the acid is `x xx10`. Find x: |
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Answer» Correct Answer - 60 Let molar mass of acid be m. then 0.186=`ixx1/mxx1000/200xx1.86` Also, `1/m=125xx0.1xx10^(-3) so m=10000/125=400/5=80` so `i=80/50=8/5=1.6=1+ alpha implies alpha=60%` |
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| 35. |
25 ml of `FeC_2O_4` dissolved in 186 gm of water calculate depression in freezing point. It 10 ml of same `FeC_2O_4` titrated with 30 ml of 0.4 M `KMnO_4` in acidic medium (`k_f` for `H_2O=1.86`,Assume 100% ionisation of `FeC_2O_4`). |
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Answer» Correct Answer - 1 `x_(FeC_2O_4)=x_(KMnO_4) " " undersetn(FeC_2O_4)toundersetn(Fe^(+2))+undersetn(C_2O_4^(-2))` `x_(Fe^(+2))+x_(C_2O_4^(-2))=x_(KMnO_4) " " n_(FeC_2O_4)=(MV)/1000` `1xxn+2xxn=(0.4xx5xx30)/1000 " " 0.02=(Mxx10)/1000` `n=(2xx10)/1000=0.02 " " M=2` n=no . of mole of substance x=equivalent of substance `DeltaT_f=i K_fm=2xx1.86xx((25xx2)/1000xx1000/186)=100/100=1` |
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| 36. |
`{:("Column-I","Column-II"),("Quantities","Factors on which dependency exist"),((A)"Molar conductance", (p)"Temperature"),((B)"emf of a cell in operation",(q)"Concentration of species involved"),((C )"Electrode potential ",(r)"Nature of substance involved "),((D)"Standard reduction potential ",(s)"No . of electrons lost or gained in the reaction "),(,(t)"is on additive property"):}` |
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Answer» Correct Answer - A`to`p,q,r,t , B`to` p,q,r ; C`to` p,q,r ; D`to`r (A)`lambda_M=(1000K)/M` `lambda_M` depend upon T,M, nature of substance and have additive property. (B)& ( C) `E_(cell)=E_(cell)^@-(2.0303 RT)/(nF)` log Q `E_(cell)` depend upon T,Q,n & nature of substance. (D) `E_("red")^(@)` depend upon nature of substance. |
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| 37. |
Match the column : `{:("Column-I","Column-II"),((A)"Molten" PbCl_2 "using inert electrode", (p)"Metal of salt will reduced"),((B)"Sodium chloride solution using inert electrode ",(q)H_2O+2e to H_2(g)+2OH^(-)),((C )"Silver nitrate solution with silver electrode",(r)"Solution become basic after electrolysis"),((D)"Sodium nitrate solution using inert electrode",(s)"Solution become neutral after electrolysis "),(,(t)"Solution become acidic after electrolysis"):}` |
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Answer» Correct Answer - A-p,s , B-q,r , C-p,s , D-q,s (A)`PbCl_2, "Cathode" : Pb^(2+)+2e^(-)to Pb(s)` Anode : `2Cl^(-)to Cl_2(g)+2e^(-)` (B)`"Cathode" : H_2O+2eto H_2(g)+2 OH^(-)` Anode : `2Cl^(-)to Cl_2(g)+2e^(-)` ( C)`"Cathode" : Ag^(+)+e^(-)to Ag(s)` Anode : `Ag(s)underset("Neutral solution")(to Ag^(+)+e^(-))` ( D)`"Cathode" : H_2O+2eto H_2(aq)+2OH^(-)` Anode : `H_2Ounderset("Neutral solution")(to 1//2O_2+2H^(+)+2e^(-))` |
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| 38. |
The process of using an electric current to bring about chemical change is called electrolysis.Electrolysis is a processes of oxidation and reduction at the respective electrodes due to external current passed in the electrolyte. The product obtained during electrolysis depends on following factors. The nature of the electrolyte The concentration of electrolyte The nature of the electrode. Consider the electrolysis of following cell containing aq. solution of `CuSO_4,ZnCl_2` and `MBr_2` by using pure silver rod as a cathode and Pt electrode as anode.Assume that `M^(2+)` does not further oxidise and can not form complex with `NH_3` Assume no hydrolysis of any ion. `E_(Cu^(2+)//Cu)^(0)=0.35 V, E_(M^(2+)//M)^(0)=-0.10 V, E_(Zn^(2+)//Zn)^(0)=-0.76 V, E_(H_(2)O // H_2)^(0)=-0.828 V, E_(Ag^(+)//Ag)^(0)=0.80 V, (2.303RT)/F=0.06` What will be the volume of gases formed at anode at STP by electrolysis of above solution after passing 20 amp current for 28950 sec. (Assume current efficiency to be 100% and one mole of gas occupies 22.4 L volume at STP). A. `44.8 L Br_2`B. `22.4 L Br_2`C. `22.4 L Cl_2`D. `44.8 L Cl_2` |
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Answer» Correct Answer - A,C Total charge =`(20xx28950)/96500 =6F` Mole of `Br_2` formed =2 Mole of `Cl_2` formed =1 |
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| 39. |
The molar conductance of NaCl varies with the concentration as shown in the following table and all values follows the equation. `lambda_(m)^(c)=lambda_(m)^(oo)-bsqrt(C)` where `lambda_(m)^(c)`= molar specific conductance `lambda_(m)^(oo)=` molar specific conductance at infinite dilution C=molar concentration When a certain conductivity cell (C) was filled with 25`xx10^(-4)(M) NaCl` solution, the resistance of the cell was found to be 1000 ohm. At infinite dilution, conductance of `Cl^(-)` and `SO_(4)^(2-)` are `80ohm^(-1) cm^(2) "mole"^(-1)` and `160ohm^(-1) cm^(2) "mole"^(-1)` respectively. What is the cell constant of the conductivity cell (C)?A. `0.385 cm^(-1)`B. `3.85 cm^(-1)`C. `38.5 cm^(-1)`D. `0.1925 cm^(-1)` |
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Answer» Correct Answer - D For `25xx10^(-4)(M)` NaCl solution `lambda_m=lambda_m^oo-bsqrtC` `lambda_m=127-10^3(25xx10^(-4))^(1//2)` `lambda_m=127-10^3xx5xx10^(-2)` `lambda_m=77` `lambda=(1000.G.sigma)/M` so, `sigma=(Mlambda)/(1000 G)=(Mlambda)/(1000 G)=(25xx10^(-4)xx77xx1000)/1000=0.1925 cm^(-1)` |
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| 40. |
A cell Ag|`Ag^+||Cu^(++)|Cu` initially contains `2M Ag^+` and `2M Cu^(++)` ions. The change in cell potential after the passage of 10 amp current for 4825 sec is:A. `-0.0074 V`B. `-1.00738 V`C. `-0.0038 V`D. none |
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Answer» Correct Answer - A Q=10x4825 =48250 C no. of mole of `Ag^+ =48250/96500=0.5` `Ag+1/2 Cu^(++)toAg^+ +1/2 Cu` `{:(2.00,2.00),(2-0.25,2+0.50):}` `E_"cell"=E_"cell"^@-0.0591/1 "log" ([Ag^+])/([Cu^(++)]^(1//2)) implies E_1=E_"cell"^@-0.0591/1"log"2.00/((2.00)^1//2)` `E_2=E_"cell"^@-0.0591/1 "log" (2.50)/(1.75)^((1//2)) implies DeltaE=E_2-E_1=0.0591/1["log"sqrt2-"log"2.50/sqrt(1.75)]` `=0.0591/1["log"1.41-"log"1.88]=0.0591/1[0.1492-0.2742]=-0.0591/2xx0.125=-0074 V` |
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| 41. |
For the cell (at 298K) `Ag(s) | AgCl(s) | Cl^(-)(aq)|| AgNO_(3)(aq) | Ag(s)` Which of the following is correct?A. The cell emf will be zero when `[(Ag^(+))]` in anodic compartment =`[Ag^(+)]` in cathodic compartmentB. The amount of AgCl(s) precipitate in anodic compartment will decrease with the working of the cellC. The concentration of `[Ag^(+)]`=constant, in anodic compartment during working of cellD. `E_(cell)=E_(Ag^(+)|Ag)^(0)-E_(Cl^(-)|AgCl|Ag)^(0)-0.059/1"log"1/[Cl^(-)]_(a)` |
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Answer» Correct Answer - A `E_(cell)=E_(Ag|Ag^+)^0+0.0591/1."log"([Cl^(-)])/([ksp])+E_(Ag^+|Ag)-0.0591/1."log"1/[Ag^+]_c` `E_cell=0+0.0591/1 "log" ([Ag^+]_c[Cl^(-)])/([Ag^+]_a[Cl^(-)])=0.0591 "log" ([Ag^+]_c)/([Ag^+]_a)` If `[Ag^+]_c=[Ag^+]_a` then `E_cell=0` |
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| 42. |
Matct the following : `{:("Column-I","Column-II"),((A)"Working concentration cell", (p)H_2+1/2 O_2toH_2O + "electrical energy"),((B)"Spontaneous cell reaction",(q)E_(cell)^@=0),((C )"Non-working Daniel cell",(r)E_(cell) gt 0),((D)"Working fuel cell",(s)"Galvanic cell"),((t)"For working of concentration cell, concentration of cation in anodic compartment should be less than the cathodic compartment"):}` |
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Answer» Correct Answer - A-q,r,t , B-r, C-s, D-p,r A: Conc cell : `E_("cell")^@=0, E_("cell")=-0.0591/n "log" (["cation"]_("Anode"))/(["cation"]_("cathode"))` B: spontaneous cell reaction `E_("cell")^@ gt 0` C: Daniell cell : Galvanic cell D: Fuel cell `H_2+1//2 O_2 to H_2O+`Electrical energy |
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| 43. |
Given : `E_(cu^(+2)//cu)^0=0.34 V` `E_(Cl_2//Cl^(-))^0`=1.36 V `E_(Br_2//Br^(-))^0=1.08 V` `E_(l_2//l^(-))^0=0.54 V` `{:("Column-I","Column-II"),((A)Cu^(+2)+2Cl to Cu+Cl_2, (p)"Can produce electricity in the galvanic cell"),((B)Cl_2+CutoCu^(+2)+2Cl^(-),(q)"Can be made to occur in electrolysis cell"),((C )2I^(-)+"starch solution + chlorine water",(r)"Appearance of brown colour"),((D)2Br^(-)+C Cl_4+"Chlorine water",(s)"Appearance of violet colour"):}` |
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Answer» Correct Answer - A`to`q , B`to`q , C-`to` s , D`to`r `(A)toq " " (E_("red")^(@))Cl_2//Cl^(-) gt (E_("red")^(@))Cu^(+2)//cu` so reduction of `Cl_2` to `Cl^(-)` will occur at cathode and oxidation of Cu to `Cu^(+2)` will occur at anode.So reverse reaction is possible it means such reverse reaction can be made to occur in an electrolysis cell. `(B)to p` As mentioned in (a) the reaction is feasible and hence can produce electricity in the galvanic cell `( C)tos " " 2I^(-)toCl_2 to I_2 ("violet")+2Cl^(-)` `(E_("red")^@)_(Cl_2//Cl^(-)) gt (E_("red")^@)_(l_2//l^(-))` `(D)to r " " 2Br^(-)toCl_2 to Br_2 ("Brown")+2Cl^(-)` `(E_("red")^@)_(Cl_2//Cl^(-)) gt (E_("red")^@)_(Br_2//Br^(-))` |
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| 44. |
When our target is asked to make this ether startint from alkyl halides. First we recall that ethers can be prepared by substitution reactions of alkoxide anion nucleophiles with alkyl halide electrophiles- The William ether synthesis. The two ways to prepare the target ether are as follows Next we examine the two reactions to determine whether both are expected to give a good yield of the target compound. Since route A combines a strongly basic nucleophile a secondary `(2^(@))` alkayl halide we expect the major product to result from elimaination by `E_2` mechanism. Route B on the other hand, employs a primary alkylhalide that can not give elimination (It has no hydrogen on the `beta`-carbon) and that is excellent. Substrate for an `S_N2`substitution because it is benzylic Route B is the obvious choice. Benzyl ether reacts with HI to formA. p-iodotoluene and ethyl alcoholB. Benzyl alcohol and ethyl iodideC. Benzyl iodide and ethyl alcoholD. Iodobenzene and ethyl alcohol. |
| Answer» Correct Answer - C | |
| 45. |
Hybridization of S in SO3 is(a) sp2 (b) sp3 (c) sp2d (d) sp3d2 |
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Answer» (a) In SO3 , sp2 hybridisation |
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| 46. |
Bleaching action of SO2 is due to its(a) oxidising property (b) acidic property (c) reducing property (d) basic property |
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Answer» (c) SO2 + 2H2O → H2SO4 + 2H . Bleaching action is due to reduction. |
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| 47. |
By which of the following SO2 is formed ?(a) Reaction of dil. H2SO4 with O2(b) Hydrolysis of dil. H2SO4(c) Reaction of conc. H2SO4 with Cu(d) None of these |
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Answer» (c) Cu +2H2 SO4 (conc) →CuSO4 +SO2 +2H2O |
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| 48. |
Number of bonds in SO2 are(a) two σ and two (b) two σ and one π (c) two σ and three π (d) None of these |
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Answer» (b) two σ and one π |
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| 49. |
Name the most catenating element of group 16. |
| Answer» Amongst group 16 elements the most catenating element is sulphur. | |
| 50. |
Among the hydrides of group 15 elements which has highest boiling point? |
| Answer» Correct Answer - Water `H_2O` | |