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A cell Ag|`Ag^+||Cu^(++)|Cu` initially contains `2M Ag^+` and `2M Cu^(++)` ions. The change in cell potential after the passage of 10 amp current for 4825 sec is:A. `-0.0074 V`B. `-1.00738 V`C. `-0.0038 V`D. none |
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Answer» Correct Answer - A Q=10x4825 =48250 C no. of mole of `Ag^+ =48250/96500=0.5` `Ag+1/2 Cu^(++)toAg^+ +1/2 Cu` `{:(2.00,2.00),(2-0.25,2+0.50):}` `E_"cell"=E_"cell"^@-0.0591/1 "log" ([Ag^+])/([Cu^(++)]^(1//2)) implies E_1=E_"cell"^@-0.0591/1"log"2.00/((2.00)^1//2)` `E_2=E_"cell"^@-0.0591/1 "log" (2.50)/(1.75)^((1//2)) implies DeltaE=E_2-E_1=0.0591/1["log"sqrt2-"log"2.50/sqrt(1.75)]` `=0.0591/1["log"1.41-"log"1.88]=0.0591/1[0.1492-0.2742]=-0.0591/2xx0.125=-0074 V` |
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