Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

State any three advantages of charcoal over wood.

Answer»

Advantages of charcoal over wood It has higher calorific value, i.e. higher heat generating efficiency. Charcoal does not produce smoke on burning so it is a clean fuel. It is easier to transport and ready to use in a convenient dry and broken-up form.

2.

State any three advantages of using charcoal over wood?

Answer»

(i) It produces large amount of heat energy.

(ii) It is smokeless and pollution free.

(iii) It is easy to store and transport.

3.

Which of the following is not obtained by the destructive distillation of wood?A. Wood gas B. Coal C. Acetic acid D. Tar

Answer»

Destructive distillation is a process in which a solid is heated in a completely closed container & all it fumes which contains various volatile substances are collected. So destructive distillation of wood does not show any sign of coal. Thus, the answer is option (b).

4.

Why do two magnetic field lines of force never intersect each other?

Answer»

Two magnetic field lines of force never intersect each other. If the lines intersect, then at the point of intersection there would be two directions (the needle would point towards two directions) for the same magnetic field, which is not possible.

5.

Amount of charcoal produced on the destructive distillation of 1 kg of wood is about: A. 0.50 kg B. 0.75 kg C. 0.25 kg D. 1 kg

Answer»

Destructive distillation is a process in which a solid is heated in a completely closed container & all it fumes which contains various volatile substances are collected. So, when destructive distillation of wood is performed & its volatile constituents are studied, 0.25 kg of charcoal was found.

6.

How is charcoal prepared ? Explain why, charcoal is a better fuel than wood.

Answer»

Charcoal is prepared by burning wood in a limited supply of air, so that water and other volatile materials present in it get removed. Charcoal is a better fuel than wood because it has a higher calorific value than wood, and it burns without producing smoke wheras wood produces a lot of smoke on burning. 

7.

In a village people burn wood and cow dung as fuel for basic necessity. In another nearby village, people have a bio-gas plant in which bio waste is used ta prepare bio gas which is supplied to all the houses of the village.Answer the following questions based on the situation given above.(i) If we compare the situation of both villages, which practice is the best and why?(ii) What values are promoted by each village?(iii) Suggest some other ways that can be employed for saving resources?

Answer»

(i) The practice of the second village is the best because they are employing a less polluting and less expensive way of fuel generation.
(ii) The first village is promoting no concern for the environment, ignorance and no technological development. The second village is promoting environmental concern, judicious use of resources and sharing.
(iii) Renewable sources of energy like CNG (Compressed Natural Gas) can be used in vehicles, solar energy can be used in place of electricity.

8.

Why is charcoal considered a better fuel than wood? What are the disadvantages of converting wood into charcoal?

Answer»

Charcoal is considered a better fuel than wood because:
(i) It has high calorific value.
(ii) It does not produce any smoke.
Disadvantages:
(i) 1 kg of wood on destructive distillation produces only 0.25 kg of charcoal making it an expensive fuel.
(ii) For production of charcoal, more and more trees would have to be cut down which causes deforestation and disturbs the ecological balance of the Earth.

9.

Ranbir lives in a village and uses wood as a fuel. He studied in this school that charcoal is a better fuel than wood. He decided to use charcoal instead of wood. (i) How can Ranbir obtain charcoal from wood ? (ii) Why is charcoal considered as better fuel than wood ? Give two reasons.(iii) State the values that prompted this action of Ranbir.

Answer»

(i) Charcoal can be produced by cutting trees, 1 kg of wood on destructive distillation produces only 0.25 kg of charcoal.

(ii) (a) Charcoal has high calorific value.

(b) Charcoal does not produce any smoke.

(iii) No regard for environment, disregard for health.

10.

Gadolinium belongs to 4f series. It’s atomic number is 64. Which of the following is the correct electronic configuration of gadolinium?(i) [Xe] 4f75d16s2(ii) [Xe] 4f65d26s2(iii) [Xe] 4f86d2(iv) [Xe] 4f95s1

Answer»

(i) [Xe] 4f75d16s2

11.

 Following are the transition metal ions of 3d series: Ti4+,V2+, Mn3+, Cr3+(Atomic number :Ti = 22,V= 23, Mn = 25, Cr = 24)Answer the following : (a) Which ion is most stable in an aqueous solution and why? (b) Which ion is a strong oxidizing agent and why? (c) Which ion is colourless and why?

Answer»

(a) Cr3+, half filled t32g

(b) Mn3+, due to stable d5 configuration in Mn2+

(c) Ti4+, No unpaired electrons 

12.

The electronic configuration of Cu(II) is 3d9 whereas that of Cu(I) is 3d10. Which of the following is correct?(i) Cu(II) is more stable(ii) Cu(II) is less stable(iii) Cu(I) and Cu(II) are equally stable(iv) Stability of Cu(I) and Cu(II) depends on nature of copper salts

Answer»

(i) Cu(II) is more stable

13.

An ammeter and a milliammeter are converted from the galvanometer. Out of the two, Which current measuring instrument has higher resistance?

Answer»

Higher is the range lower will be the value of shunt, so milliammeter will be having higher resistance.  

14.

Electronic configuration of a transition element X in +3 oxidation state is [Ar]3d5. What is its atomic number?(i) 25(ii) 26(iii) 27(iv) 24

Answer»

Its atomic number is  26

15.

Define current sensitivity of the galvanometer?

Answer»

It is defined as deflection per unit current of Moving coil galvanometer.  

16.

Explain the following observations: Copper atom has completely filled d orbitals (3d10) in its ground state, yet it is regarded as a transition element.

Answer»

Because it has incompletely filled d orbitals in one of its oxidation state (Cu2+).

17.

What is the value of Bohr magneton? 

Answer»

The value of Bohr magneton :

μl = 9.27×10-27 Am2 

18.

 Account for the following : Atomic radii of 4d and 5d series elements are nearly same.

Answer»

 Due to lanthanoid contract.

19.

What is lanthanoid contraction? What are its two consequences?

Answer»

The steady decrease in the size of lanthanoid ions (M3+) with the increase in atomic number is called lanthanoid contraction. 

Consequences of lanthanoid contraction :

(i) Separation of lanthanoids is difficult due to lanthanoid contraction because due to this contraction their ionic radii is very small.

(ii) The basic strength of hydrofdes decreases from La(OH)3 to Lu(OH)3. Due to lanthanoid contraction, the size of M3+ ions decreases and there is increase in the covalent character in M - OH bond.

20.

Explain why:Ce3+ can be easily oxidised to Ce4+. (At. No. Ce = 58).

Answer»

Ce3+, ions having the configuration 4f15d06d0 can easily lose electron to acquire the configuration 4f05d06s0 and form Ce4+ ion.

21.

On the basis of Lanthanoid contraction, Radii of 4d and 5d block elements.

Answer» Radii of 4d and 5d block elements will be almost same.
22.

Although + 3 oxidation states is the characteristic oxidation state of lanthanoids but cerium shows + 4 oxidation state also. Why?

Answer»

Electronic configuration of Ce : [Xe] 4fd 5d1 6s2. Generally 5d1 and 6s2 electrons are lost by the lanthanoids in their reactions i.e., they exhibit +3 oxidation states. But Ce exhibit + 4 oxidation state also because it gains extra stability by losing 4f1 electron because it will give rise to completely filled orbitals.

23.

Although Zirconium belongs to 4d transition series and Hafnium to 5d transition series even then they show similar physical and chemical properties because___________. (i) both belong to d-block. (ii) both have same number of electrons. (iii) both have similar atomic radius. (iv) both belong to the same group of the periodic table.

Answer»

(iii) both have similar atomic radius. 

24.

Although +3 oxidation states is the characteristic oxidation state of lanthanoids but cerium shows +4 oxidation state also. Why?

Answer»

It is because after losing one more electron Ce acquires stable 4f0 electronic configuration.

25.

On the basis of Lanthanoid contraction, Trends in the stability of oxo salts of lanthanoids from La to Lu.

Answer»

As the size decreases from La to Lu, stability of oxosalts also decreases.

26.

Although Zr belongs to 4d and. Hf belongs to 5d transition series but it is quite difficult to separate them. Why?

Answer»

Zr, a member of 4d series and Hf, a member of 5d series, belong to same group. They are chemically quite similar yet their separation is difficult. The reason is that both have same size due to lanthanoid contraction. The radii of these elements are 160 pm (h) and 159 pm (Hf).

27.

Explain the following observations :The numbers of the actinoid series exhibit a larger number of oxidation states than the corresponding members of the lanthanoid series.

Answer»

Actinoids exhibit a large number of oxidation states because 5f ,6d and 7s levels have almost comparable energies (very small energy difference between sub-shells than the energy difference between 4f and 5d orbitals in case of Lanthanoids.

28.

KMnO4 acts as an oxidising agent in alkaline medium. When alkaline KMnO4 is treated with KI, iodide ion is oxidised to ____________.(i) I2(ii) IO–(iii) IO3–(iv) IO4–

Answer»

KMnO4 acts as an oxidising agent in alkaline medium. When alkaline KMnO4 is treated with KI, iodide ion is oxidised to  IO3–

29.

In the following questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices. (i) Both assertion and reason are true, and reason is the correct explanation of the assertion.(ii) Both assertion and reason are true but reason is not the correct explanation of assertion.(iii) Assertion is not true but reason is true.(iv) Both assertion and reason are false.Assertion : Separation of Zr and Hf is difficult.Reason : Because Zr and Hf lie in the same group of the periodic table.

Answer»

(ii) Both assertion and reason are true but reason is not the correct explanation of assertion.

30.

Match the properties given in Column I with the metals given in Column II.Column I (Property)Column II (Metal)(i) An element which can show +8 oxidation state(a) Mn(ii) 3d block element that can show upto +7 oxidation state(b) Cr(iii) 3d block element with highest melting point(c) Os(d) Fe

Answer» (i) → (c) (ii) → (a) (iii) → (b)
31.

Match the statements given in Column I with the oxidation states given in Column II.Column IColumn II(i) Oxidation state of Mn in MnO2 is(a) + 2(ii) Most stable oxidation state of Mn is(b) + 3(iii) Most stable oxidation state of Mn in oxides is(c) + 4(iv) Characteristic oxidation state of lanthanoids is(d) + 5(e) + 7

Answer» (i) → (c) (ii) → (a) (iii) → (e) (iv) → (b)
32.

In the following questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices. (i) Both assertion and reason are true, and reason is the correct explanation of the assertion.(ii) Both assertion and reason are true but reason is not the correct explanation of assertion.(iii) Assertion is not true but reason is true.(iv) Both assertion and reason are false.Assertion : Cu2+ iodide is not known.Reason : Cu2+ oxidises I– to iodine.

Answer»

(i) Both assertion and reason are true, and reason is the correct explanation of the assertion.

33.

Match the properties given in Column I with the metals given in Column II.Column I (Property)Column II (Metal)(i) Element with highest second ionisation enthalpy(a) Co(ii) Element with highest third ionisation enthalpy(b) Cr(iii) M in M (CO)6 is(c) Cu(iv) Element with highest heat of atomisation(d) Zn(e) Ni

Answer» (i) → (c) (ii) → (d) (iii) → (b) (iv) → (a)
34.

Match the property given in Column I with the element given in Column II.Column I (Property)Column II (Element)(i) Lanthanoid which shows +4 oxidation state(a) Pm(ii) Lanthanoid which can show +2 oxidation state(b) Ce(iii) Radioactive lanthanoid(c) Lu(iv) Lanthanoid which has 4f7 electronic configuration in +3 oxidation state(d) Eu(v) Lanthanoid which has 4f14 electronic configuration in +3 oxidation state(e) Gd(f) Dy

Answer» (i) → (b) (ii) → (d) (iii) → (a) (iv) → (e) (v) → (c)
35.

Match the catalysts given in Column I with the processes given in Column II.Column I (Catalyst)Column II (Process)(i) Ni in the presence of hydrogen(a) Zieglar Natta catalyst(ii) Cu2Cl2(b) Contact process(iii) V2O5(c) Vegetable oil to ghee(iv) Finely divided iron(d) Sandmeyer reaction(v) TiCl4 + Al (CH3)3(e) Haber’s Process(f) Decomposition of KClO3

Answer» (i) → (c) (ii) → (d) (iii) → (b) (iv) → (e) (v) → (a)
36.

State whether the following statements are true or false. Correct the false statements.(1) Bleaching powder is used in preparation of chloroform which is used as an anaesthetic. (2) On addition of universal indicator the colour of table salt changes to pink. (3) Borax is Na2B4O7.9H2O. (4) Boron -10 is used to cure bone cancer.(5) Clinical deo contains 20 to 25% of aluminium.

Answer»

(1) True 

(2) False. On addition of universal indicator the colour of table salt changes to green.

(3) False. Borax is Na2B4O7.9H2O 

(4) False. Boron – 10 is used in treatment of brain tumour. 

(5) True

37.

Mention any three processes where transition metals act as catalysts.

Answer»

(i) Vanadium (V) oxide in contact process for oxidation of SO2 to SO3.

(ii) Finely divided iron in Haber’s process in conversion of N2 and H2 to NH3.

(iii) MnO2 in preparation of oxygen from KClO3.

38.

In what respects the Mendeleev's classification is superior to the other classification given earlier?

Answer»

Mendeleev's classification is superior to the earlier classifications: 

(i) Mendeleev's developed a periodic table of elements wherein the elements were arranged on the basis of their atomic mass and also on the similarity in chemical properties. 

(ii) Among chemical properties, he took the formulae of the hydrides and oxides formed by an element as one of the basic properties of an element for classification.

39.

Which of the following on treatment with `XeF_6`gives Xe ?A. `H_2`B. `HCl`C. `OH^-` (conc)D. All of these

Answer» Correct Answer - D
`XeF_6 + 3H_2 to Xe + 6HF`
`XeF_6 + 6HCl to Xe + 6HF + 3Cl_2`
40.

Which behave like pseudohalide in followingA. `(CN)_2`B. `(SCN)_2`C. `N_3^-`D. `I_3^-`

Answer» Correct Answer - C
`N_3^-` is pseudohalide
`(CN)_2 and (SCN)_2` behave like pseudohalogen
`I_3^-` is polyhalide
41.

Which of the following can be obtained by hydrolysis of `XeF_6`A. `XeO_3`B. `HF`C. `XeO_2F_2`D. `Xe`

Answer» Correct Answer - A::B::C
`XeF_6+3H_2O to XeO_3 + 6HF` Complete hydrolysis
`XeF_6 + 2H_2O to XeO_2F_2 + 4HF` (Partical hydrolysis)
42.

(i)`(r)+(p)to NaClO_2 + O_2` (ii)`IO_3^(-) + I^(-) overset(H^+)to (q)` (iii)Acidic solution of `ClO_2^(-) to (s) + (r)` (disproportionation reaction ) (p)used as air purifier and `CO_2` absorber (q) estimated by hypo and it forms violet colour vapour (it self) (r)is yellow colour gas (s) gives chromylchloride test. which option is correct .A. (p)=`Na_2O_2 , (q) =l_2`B. `(q)=I_2 O_5 , (r)=Cl^-`C. `(p)=Na_2O, (r) =Cl_2O`D. `(r)=Cl_2 , (s)=Cl_2 O_3`

Answer» Correct Answer - A
`ClO_2+Na_2O_2to NaClO_2+O_2`
`IO_3^(-) + I^(-) to l_2 + H_2O`
`underset((+3))(5ClO_2^(-))overset(H^+)to underset((+4))(4ClO_4) + underset((-1))(Cl^-) + H_2O`
`A=Na_2O_2 , B=I_2 , C=ClO_2 , Cl^-`
43.

Consider following properties of the noble gases. I. They readily form compounds which are colourless. II: They generally do not form ionic compounds. III: Xenon has variable oxidation states in its compounds IV : the smaller He and Ne do not form clathrate compounds. Select correct properties.A. I,II,IIIB. II,III,IVC. I,III,IVD. All

Answer» Correct Answer - B
(I)They do not form compounds readily as they are chemically inert on account of stable electron configuration.
(II),(III),(IV) are correct statement
44.

When a rubber sheet is rubbed with woolen carpet, the carpet is found to acquire a positive charge of 8 × 10-7 C 1. In the above process charging is byconductionfrictioninductionpolarization2. Among Rubber shoe and woolen carpet which one acquire both mass and charge during rubbing? Explain.

Answer»

1. In the above process charging is by:

  • Friction

2. Carpet is found to be positive body which means that electrons are lost from carpet to rubber shoe. Hence rubber shoe acquires charge and mass.

45.

Electrostatic force is a ...... force(i) Conservative(ii) non conservative(iii) medium independent(iv) dissipative Conservative

Answer»

(i) Conservative

46.

How many of the following compounds from HCl on hydrolysis as one of the products (major or minor) (i)`BCl_3` , (ii)`BiCl_3` , (iii)`SO_2Cl_2` (iv)`NCl_3` (v)`PCl_5` (vi)`CrO_2Cl_2` (vii)`CH_3Cl` (viii)NaCl

Answer» Correct Answer - 5
(i),(ii),(iii),(v),(vi),(ix)
47.

What are the products formed in the reaction of xenon hexafluoride with silicon dioxide?A. (1) `XeSiO_4 + HF`B. (2) `XeF_2+ SiF_4`C. (3)`XeOF_4 + SiF_4 `D. (4)`XeO_3 + SiF_2`

Answer» Correct Answer - C
`2XeF_6 +SiO_2 to SiF_4 + 2XeOF_4`
48.

`[HXeO_4]^(-) + OH^(-) to [X] + [Y] + O_2 +H_2O` The products [X] and [Y] in unbalanced reaction are:A. `[XeO_6]^(4-) & Xe`B. `[XeO_6]^(4-) & XeO_3`C. `XeO_3 & Xe`D. `H_2XeO_4 & Xe`

Answer» Correct Answer - A
`2[HXeO_4]^(-) + 2OH^(-) to [XeO_6]^(4-) + Xe + O_2 + 2H_2O`
49.

It is safe to be inside a vehicle rather than outside, even when there is lightning and thunder. Comment on this.

Answer»

Inside a spherical shell electrical field is zero. This is called electrostatic shielding. Hence it is safe to be inside a vehicle rather than outside.

50.

A cubical iron block is given a charge of +40m C and placed in vacuum.1. Give the direction of electric field at the centre of one face.2. Calculate the net flux due to the charged cube through one face.3. Will there be any change in the flux if it is placed underwater of dielectric constant 81. Justify.

Answer»

1. Normally outwards from the surface.

Total flux = \(\frac{40\times10^{-3}}{8.85\times10^{-12}}\) = 4.51 x 109Nm2C-1

2. Through one face = \(\frac{4.51\times10^9}{6}\) = 0.75 x 109Nm2C-1

3. Electric flux decreases because flux depends on permittivity of medium.