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`[HXeO_4]^(-) + OH^(-) to [X] + [Y] + O_2 +H_2O` The products [X] and [Y] in unbalanced reaction are:A. `[XeO_6]^(4-) & Xe`B. `[XeO_6]^(4-) & XeO_3`C. `XeO_3 & Xe`D. `H_2XeO_4 & Xe` |
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Answer» Correct Answer - A `2[HXeO_4]^(-) + 2OH^(-) to [XeO_6]^(4-) + Xe + O_2 + 2H_2O` |
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