94420 + Interview Questions in Chemistry in Class 12

1.	Starch is turned to disaccharide in presence of
Answer» Maltase Zymase Diastase LACTASE ANSWER :C

Discussion

2.	Starch is of which type polymer ?
Answer» SYNTHETIC NATURAL SEMI Synthetic NONE of these SOLUTION :Natural

Discussion

3.	Starch is polymer of:
Answer» Fructose Glucose Lactose None Answer :B

Discussion

4.	Starch is mixture of:
Answer» amylon amylopectin maltase LACTOSE ANSWER :B::C

Discussion

5.	Starch is made up of :
Answer» `alpah`-GLUCOSE PYRANOSE `beta`-FRUCTOSE pyranose `beta`-fructose furanose both (1) and (3) Answer :D

Discussion

6.	Starch is made up of:
Answer» GLUCOSE and fructose Amylose and amylopectin Amylose and glycogen Amylopectin and glycogen Answer :B

Discussion

7.	Starch is composed of :
Answer» AMYLOSE and GLYCOGEN amylose and amylopectin amylopectin and glycogen GLUCOSE and glycogen. ANSWER :B

Discussion

8.	Starch is changed into disaccharides in presence of:
Answer» Diastage Maltase Lactase Zymase Answer :C

Discussion

9.	Starch is a mixture of two components , a water soluble component amylose(15-20%)and a water insoluble component amylopectin (80-85%). The aqueous solution of amylose gives a blue colour with iodine solution due to the formation of
Answer» amylose IODIDE amylose IODATE INCLUSION complex amylose TETRAIODIDE complex SOLUTION :Inclusion Complex.

Discussion

10.	Starch is an example of ………………………… colloids.
Answer» ANSWER :lyophillic COLLOIDS

Discussion

11.	Starch is changed into disaccharides in presence of
Answer» DIASTASE MALTASE LACTOSE ZYMASE. ANSWER :A

Discussion

12.	Starch is a mixture of amylopectin and
Answer» pyran amylase lactose D-ribose Answer :B

Discussion

13.	Starch iodide paper is used to test for the presence of :
Answer» Iodine Iodine ion Oxidant Reductant Answer :C

Discussion

14.	Starch dispersed in hot water is an example of ..........
Answer» emulsion hydrophobic SOL LYOPHILIC sol associated COLLOID SOLUTION : lyophilic sol

Discussion

15.	Starch composed of
Answer» AMYLOSE and amylopectin sucrose and maltose maltose and lactose amylose and cellobiose Answer :A

Discussion

16.	Starch can be used as an indicator for the detection of traces of
Answer» GLUCOSE in AQUEOUS solution PROTEIN in BLOOD Iodine in aqueous solution Urea in blood Answer :C

Discussion

17.	Starch contains about 20%............and about 80% of ……………..
Answer» SOLUTION :AMYLOSE , AMYLOPECTIN

Discussion

18.	Starch contains 20% of___________ and 80% of ______.
Answer» RIBULOSE, AMYLOSE mylopectin, amylose amylose, AMYLOPECTIN amylopectin, ribulose SOLUTION :amylose, amylopectin

Discussion

19.	Starch can be used as an indicator for the detection of the traces of
Answer» GLUCOSE in AQUEOUS solution Proteins in blood Iodine in aqueous solution Urea in blood Answer :C

Discussion

20.	Starch and cellulose possess the same molecular formula, but starch is water soluble and cellulose is water insoluble. Why?
Answer» Solution :Starch has two forms, one is a LINEAR polymer and the other is a cross LINKED polymer. Both forms of starch are soluble in water. Cellulose is a network polymer stabilized with HYDROGEN BONDING. So it is insoluble in water.

Discussion

21.	Stannous chloride gives a white precipitate with a solution of mercuric chloride. In this process nercuric chloride is:
Answer» Oxidised Reduced Converted into a complex COMPOUND CONTAINING Sn and Hg Converted into a CHLORO complex of Hg Answer :B

Discussion

22.	Standard zinc electrode is coupled with a standard electrode to form a cell, whise emf was found to be 1.60V , reduction taking place at Zinc electrode . If standard reduction potential of zinc electrode is -0.76V, then the standard reduction potential of the standard electrode will be______ V.
Answer» `-2.36` `+0.84` 2.36 `-0.84` Solution :`{:(1.6=-0.76 + (-X) therefore x =-2.36),([E_("CELL")^(0) = E_("Zn(red)")""+(-E_("electrode")^(0))]):}`

Discussion

23.	Standard reduction potentials of three metalselectrodes A,B, and C are 0.34V,-0.40V and -0.47V respectively . Which is the best reducingagent ?
Answer» A B C None Answer :C

Discussion

24.	Standard reduction potentials of Zn, Cu and Cr is increasing order can be represented as
Answer» `ZN lt Cu lt Cr` `Zn lt Cr lt Cu` `Cr lt Zn lt Cu` `Cu lt Zn lt Cr` ANSWER :B

Discussion

25.	Standard reduction potentials of the half reactions are given below: F_(2)(g)+2e^(-)to2F^(-)(aq),E^(@)=+2.85V Cl_(2)(g)+2e^(-)to2Cl^(-)(aq),E^(@)=+1.36V Br_(2)(s)+2e^(-)to2Br^(-)(aq),E^(@)=+1.06V I_(2)(s)+2e^(-)to2I^(-)(aq),E^(@)=+0.53V The strongest oxidizing and reducing agents respectively are:
Answer» `Cl_(2) and Br^(-)` `Cl_(2) and I_(2)` `F_(2) and I^(-)` `Br_(2) and Cl^(-)` Solution :Higher the reduction potential, more easily it is reduced and hence STRONGER is the oxidizing agent. `F_(2)` has highest reduction potential. Hence, `F_(2)` is strongest oxidizing agent. CONSIDERING the reverse reaction (oxidation reaction), higher the oxidation potential, more easily it is oxidized and hence stronger is the REDUCING agent. oxidation potential of `I^(-)` ion `(-0.53V)` is highest out of -2.85,-1.36,,-1.06 and -0.53. hence, `I^(-)` is strongest reducing agent.

Discussion

26.	Standard reduction potentials of the half reactions are given below : {:(F_(2) (g) + 2e^(-) rarr 2F^(-) (aq) , ""E^(@) = + 2.85 V),(Cl_(2)(g) + 2e^(-) rarr 2Cl^(-)(aq)," "E^(@) = +1.36 V),(Br_(2)(l) + 2e^(-) rarr 2Br^(-) (aq)," "E^(@) = +1.06 V),(I_(2) (s) + 2e^(-) rarr 2I^(-)(aq), ""E^(@) = + 0.53 V):} The strongest oxidising and reducing agents respectively are
Answer» `F_(2) and I^(-)` `Br_(2) and Cl^(-)` `Cl_(2) and Br^(-)` `Cl_(2) and I_(2)` Solution :Since `F_(2)` has the HIGHEST electrode potential, therefore, it is the strongest OXIDISING AGENT and `F^(-)` is the WEAKEST reducing agent. Further, since `I_(2)` has the lowest electrode potential, therefore, it is the weakest oxidising agent and CONVERSELY `I^(-)` is the strongest reducing agent. Thus, option (a) is correct.

Discussion

27.	Standard reduction potentials at 25^(@) C of Li^(+) abs(Li,Ba^(2+))Ba,Na^(+) abs(Na and "Mg"^(2+)) Mg are -3.05 V, - 2.90V, - 2.71V and -2.37V respectively. Which one of the following is the strongest oxidising agent?
Answer» `Na^(+)` `LI^(+)` `BA^(2+)` `Mg^(2+)` Answer :D

Discussion

28.	Standard reduction potentials for the half reactions are given below : F_(2)(g)+2e^(-) to 2F^(-)(aq) , E^(@)=+2.85" V " Cl_(2)(g)+2e^(-) to 2Cl^(-)(aq) , E^(@)=+1.36" V " Br_(2)(g)+2e^(-) to 2Br^(-)(aq) , E^(@)=+1.06" V " I_(2)(g)+2e^(-) to 2I^(-)(aq) , E^(@)=+0.53" V " The strongest oxidising and reducing agents respectivity are :
Answer» `F_(2)` and `I^(-)` `Br_(2)` and `Cl^(-)` `Cl_(2)` and `Br^(-)` `Cl_(2)` and `I_(2)`. SOLUTION :(a) More negative (or less positive) the VALUE of reduction potential, stranger will be the reducing agent. Thus `L^(-)` is the STRONGEST reducing agent. More positive is the values of reduction potential, stronger will be the oxidising agent. Thus, `F_(2)` is the strongest oxidising agent.

Discussion

29.	Standard reduction potential ofI_(3)^(-), I^(-) and Fe^(3+), Fe^(2+) are 0.54 and 0.77 V, respectively . Calculate the equilibrium constant for the reaction. 2Fe^(3+) + 3I^(-)
Answer» ANSWER :`6.25xx10^(7)`

Discussion

30.	Standard reduction potential of Zn^(2+)//Zn,Ni^(2+)//Ni and Fe^(2+)//Fe are -0.76 V, -0.23 V and -0.44 V respectively. So in which condition reaction X+Y^(2+) to Y+X^(2+) would be spontaneous ?
Answer» `X=Ni,Y=Fe` `X=Ni,Y=ZN` `X=Fe,Y=Zn` `X=Zn,Y=Ni` SOLUTION :`Zn_((S))+Ni_((AQ))^(2+) to Zn_(Ni^(2+)//Ni)^(@)-E_(Zn^(2+)//Zn)^(@)` `=-0.23-(-0.76)=+0.52V`.

Discussion

31.	Standard reduction potential (SRP) of fluorine is highest. Comment
Answer» Solution :Standard potential for the reaction, `F_(2)+2e^(-)rarr2F^(-)` is highest, `+2.87 V`. This is because, fluoride is the EASIEST formed ANION from its element and hydration enthalpy is highest for fluoride. Highest SRP suggests that fluorine is the BEST oxidant.

Discussion

32.	Standard reduction potential of the half reaction are given below F_(2)(g)+2e^(-)to2F^(-)(aq),""E^(@)=+2.85V Cl_(2)(g)+2e^(-)to2Cl^(-)(aq),""E^(@)=+1.36V Br_(2)(l)+2e^(-)to2Br^(-)(aq),""E^(@)=+1.06V I_(2)(s)+2e^(-)to2I^(-)(aq),""E^(@)=+0.53V the strongest oxidising and reducig agents respectively are
Answer» `F_(2) and I^(-)` `Br_(2) and CL^(-)` `Cl_(2) and Br^(-)` `Cl_(2) and I_(2)` Solution :`E^(o)` more positive, REDUCING AGENT will be GREATER.

Discussion

33.	Standard reduction potential of the half reactions are given below: {:(F_(2("g"))+2e^(-)rarr 2F_(aq)^(-),,E^(o)= + 2.85 V ),(Cl_(2("g"))+2e^(-)rarr 2Cl_(aq)^(-),,E^(0)= + 1.36 V),(Br_(2(l))+2e^(-)rarr 2Br_(aq)^(-),,E^(0)=1.06V),(I_(2(s))+2e^(-)rarr 2I_(aq)^(-),,E^(0)=+0.53V):} The strongest oxidising and reducing agents respec-tively are:
Answer» `Cl_(2) and BR^(-)` `Cl_(2) and I_(2)` `F_(2) and I^(-)` `Br_(2) and CL^(-)` Answer :C

Discussion

34.	Standard reduction potential of x,y and z are 0.75,-0.80 and -.25 volt respectively. Then which of the following statement is not true ?
Answer» OXIDATION of y is CARRIED out by X and y. Oxidation of x and REDUCTION of Z is carried out by y. Reduction of x and oxidation of y is carried out by z. Reduction of x is carried out by y and z. Solution :Oxidation of x and reduction of z is carried out by y.

Discussion

35.	Standard reduction potential of most of the transition elements is generally
Answer» negative positive zero None of the above Answer :A

Discussion

36.	Standard reduction potential of metals X,Y and Z are 0.34 V, 0.80 V and -0.45V then give their order of strength of reduction potential.
Answer» `Z GT Y gt X` `Z gt X gt Y` `X gt Y gt Z` `Y gt Z gt X` Solution :`Z gt X gt Y` Reduction potential values are `Y gt X gt Z`. As reduction potential value is higher than tendency to GET reduced it increases but REDUCING NATURE get decreases. So order for sterngth of reducing nature is in of `Z gt X gt Y`.

Discussion

37.	Standard reduction potential of most of the transition elements is generally :
Answer» NEGATIVE Positive Zero None Answer :A

Discussion

38.	Standard reduction potential of following reactions is given below : Mn^(2+)+2e^(-) to Mn","E^(o)=-1.18V and Mn^(3+)+e^(-) to Mn^(2+),""E^(o)=1.51V, then what is the redox potential of reaction Mn^(3+)+3e^(-) to Mn ?
Answer» `0.33V` `1.69V` `-0.28V` `-0.85V` Solution :(i) `MN^(2+)+2E^(-) to Mn` (reduction) `DeltaG^(@)=-nFE^(@)=2.36F`. . . (1) (II) `Mn^(3+)+e^(-) to Mn^(2+)` (reduction) `DeltaG^(@)=-nFE^(@)=--1.51F` . . . (2) Sum of equation (1) and (2), (iii) `Mn^(3+)+3e^(-) to Mn` (reduction) `DeltaG^(@)=2.36F+(-1.51F)` `=0.85F` `DeltaG^(@)=-nFE^(@)` `THEREFORE 0.85F=-3xxFxxE^(@)` `therefore E^(@)=(0.85)/(3)=-0.28V`

Discussion

39.	Standard reduction potential of half-cells are given as follows : Zn^(2+)+2e^(-) to Zn,E^(o)=-0.76V Fe^(2+)+2e^(-) to Fe,E^(o)=-0.44V What is the emf of following reactions ? Zn_((S))+Fe_((aq))^(2+) to Zn_((aq))^(+2)+Fe_((S)).
Answer» `-1.20V` `+1.20V` `+0.32V` `-0.32V` Solution :`E_(CELL)^(o)=E_("Reduction (CATHODE)")^(o)-E_("Reduction (anode)")^(o)` `=E_(FE^(2+)\|Fe)^(o)-E_(Zn^(2+)\|Zn)^(o)` `=-0.44-(-0.76)` `+0.32V`

Discussion

40.	Standard reduction potential of an element is equal to:
Answer» `+1xx` its REDUCTION POTENTIAL `-1XX` its STANDARD oxidation potential `0.00V` `+1xx` its standard oxidation potential Answer :B

Discussion

41.	Standard reduction potential of an element equal to
Answer» `+ 1 xx` its reductionpotential `- 1 xx ` its standard OXIDATION potential `0.00`V `+ 1 xx ` its standard oxidation potential SOLUTION :`E_(OP)^(@) = - E_(RP)^(@)` for any element .

Discussion

42.	Standard reduction potential at 25^(@)C of Li^(+)\|Li,Ba^(2+)\|Ba,Na^(+)\|Na and Mg^(2+)\|Mg are -3.05,-2.90,-2.71 and -2.37 volt respectively. Which one of the following is the strongest oxidising agent
Answer» `NA^(+)` `LI^(+)` `Ba^(2+)` `Mg^(2+)` SOLUTION :The oxidizing character i.e., acceptance of electrons increases with the reduction potential.

Discussion

43.	Standard reduction potential for,Li^+Li, Zn^(2+) Zn, H^+ H_2 and Ag^+ Agis -3.05,-0.762,0.00 and +80V. Which has highest reducing capacity?
Answer» AG `H_2` Zn Li Answer :D

Discussion

44.	Standard potentials (E^(@)) for some half-reactions are given below : Sn^(4+) + 2e to Sn^(2+) , E^(@) = +0.15 V 2 Hg^(2+) + 2e to Hg_(2)^(2+) , E^(@) = 0.92 V PbO_(2) + 4 H^(+) + 2e to Pb^(2+) + 2H_(2)O , E^(@) = +1.45 V Based on the above , which one of the following statements is correct ?
Answer» `Sn^(4+)` is a strongest OXIDISING agent than `Pb^(4+)` `Sn^(2+)` is a strongest reducing agent than `Hg_(2)^(2+)` `Pb^(2+)` is a strongest oxidising agent than `Pb^(4+)` `Pb^(2+)` is a strongest reducing agent than `Sn^(2+)` Solution :GREATER the REDUCTION potential , stronger is the oxidizing agent or WEAKER is the reduction agent .

Discussion

45.	Standard reduction electrode potentials of three metals A, B and C are respectively + 0.5V, –3.0V and –1.2 V. The reducing powers of these metals are:
Answer» `B GT C gt A` `A gt B gt C` `C gt BGT A ` `A gt C gt B` ANSWER :A

Discussion

46.	Stadard reduction electrode potentials of three metals A,B and C are respectively +0.5V, -3.0V and -1.2V. The reducing powers of these metals are:
Answer» `AGTBGTC` `CgtBgtA` `AgtCgtB` `BgtCgtA` ANSWER :D

Discussion

47.	Standard reduction electrode potential of three metals A, B and C are respectively +0.05 V, -3.0 and -1.2 V. The reducing powers of
Answer» ` B GT C gt A ` `A gt B gt C ` `C LT B lt A` `A gt C gt B` ANSWER :A

Discussion

48.	Standard molar enthalpy of formation of CO_2 is equal to:
Answer» Zero The standard molar enthalpy of combustion of GASEOUS CARBON The sum of standard molar enthalpies FORMATION of CO and `O_2` The standard molar enthalpy of combustion of carbon (graphite) ANSWER :D

Discussion

49.	Standard molar enthalpy of formation of CO_(2) is equal to
Answer» zero standard molar enthalpy of combustion the sum of standard molar ENTHALPIES of formation of CO and `O_(2)` the standard molar enthalpy of combustion of CARBON (graphite) Answer :D

Discussion

50.	Standard Gibb's energy of reaction (Delta_(r)G^(@)) at a certain temperature can be computed as Delta_(r)G^(@)=Delta_(r)H^(@)-T.Delta_(r)S^(@) and the change in the value of Delta_(r)H^(@) and Delta_(r)S^(@) for a reaction with temperature can be computed as follows Delta_(r)H_(T_(2))^(@)-Delta_(r)H_(T_(1))^(@)=Delta_(r)C_(p)^(@)(T_(2)-T_(1))Delta_(r)S_(T_(2))^(@)-Delta_(r)S_(T_(1))^(@)=Delta_(r)C_(p)^(@)ln((T_(2))/(T_(1)))Delta_(r)G^(@)=Delta_(r)H^(@)-T.Delta_(r)S^(@) "andby "Delta_(r)G^(@)=-RT lnK_(eq)Consider the following reaction : CO(g)+2H_(2)(g)subCH_(3)OH(g)Given :Delta_(f)H^(@)(CH_(3)OH),g=-201 kJ//mol Delta_(f)H^(@)(CO, g)=-114 kJ//mol S^(@)(CH_(3)OH, g)=240 J//K-mol, S^(@)(H_(2),g)=29 JK^(-1)mol^(-1)S^(@)(CO, g)=198 J//mol-K, C_(p,m)^(@)(H_(2))=28.8J//mol-KC_(p,m)^(@)(CO)=29.4 J//mol-K, C_(p,m)^(@)(CH_(3)OH)=44 J//mol-Kand ln((320)/(300))0.06,all data at 300 KDelta_(r)H^(@) at 300 K for the reaction is
Answer» `-87 kJ//mol` `87 kJ//mol` `-315 kJ//mol` `-288 kJ//mol` SOLUTION :`Delta_(r)H^(@)" at 300 K = "Delta_(F)H_((CH_(3)OH))^(@)-Delta_(f)H_((CO))^(@)-2.Delta_(f)H_((H_(2)))^(@)` `=-201-(-114)-2xx0` `=-87 KJ//mol`.

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Starch is turned to disaccharide in presence of

Starch is of which type polymer ?

Starch is polymer of:

Starch is mixture of:

Starch is made up of :

Starch is made up of:

Starch is composed of :

Starch is changed into disaccharides in presence of:

Starch is a mixture of two components , a water soluble component amylose(15-20%)and a water insoluble component amylopectin (80-85%). The aqueous solution of amylose gives a blue colour with iodine solution due to the formation of

Starch is an example of ………………………… colloids.

Starch is changed into disaccharides in presence of

Starch is a mixture of amylopectin and

Starch iodide paper is used to test for the presence of :

Starch dispersed in hot water is an example of ..........

Starch composed of

Starch can be used as an indicator for the detection of traces of

Starch contains about 20%............and about 80% of ……………..

Starch contains 20% of___________ and 80% of ______.

Starch can be used as an indicator for the detection of the traces of

Starch and cellulose possess the same molecular formula, but starch is water soluble and cellulose is water insoluble. Why?

Stannous chloride gives a white precipitate with a solution of mercuric chloride. In this process nercuric chloride is:

Standard zinc electrode is coupled with a standard electrode to form a cell, whise emf was found to be 1.60V , reduction taking place at Zinc electrode . If standard reduction potential of zinc electrode is -0.76V, then the standard reduction potential of the standard electrode will be______ V.

Standard reduction potentials of three metalselectrodes A,B, and C are 0.34V,-0.40V and -0.47V respectively . Which is the best reducingagent ?

Standard reduction potentials of Zn, Cu and Cr is increasing order can be represented as

Standard reduction potentials of the half reactions are given below: F_(2)(g)+2e^(-)to2F^(-)(aq),E^(@)=+2.85V Cl_(2)(g)+2e^(-)to2Cl^(-)(aq),E^(@)=+1.36V Br_(2)(s)+2e^(-)to2Br^(-)(aq),E^(@)=+1.06V I_(2)(s)+2e^(-)to2I^(-)(aq),E^(@)=+0.53V The strongest oxidizing and reducing agents respectively are:

Standard reduction potentials at 25^(@) C of Li^(+) abs(Li,Ba^(2+))Ba,Na^(+) abs(Na and "Mg"^(2+)) Mg are -3.05 V, - 2.90V, - 2.71V and -2.37V respectively. Which one of the following is the strongest oxidising agent?

Standard reduction potential ofI_(3)^(-), I^(-) and Fe^(3+), Fe^(2+) are 0.54 and 0.77 V, respectively . Calculate the equilibrium constant for the reaction. 2Fe^(3+) + 3I^(-)

Standard reduction potential of Zn^(2+)//Zn,Ni^(2+)//Ni and Fe^(2+)//Fe are -0.76 V, -0.23 V and -0.44 V respectively. So in which condition reaction X+Y^(2+) to Y+X^(2+) would be spontaneous ?

Standard reduction potential (SRP) of fluorine is highest. Comment

Standard reduction potential of x,y and z are 0.75,-0.80 and -.25 volt respectively. Then which of the following statement is not true ?

Standard reduction potential of most of the transition elements is generally

Standard reduction potential of metals X,Y and Z are 0.34 V, 0.80 V and -0.45V then give their order of strength of reduction potential.

Standard reduction potential of most of the transition elements is generally :

Standard reduction potential of following reactions is given below : Mn^(2+)+2e^(-) to Mn","E^(o)=-1.18V and Mn^(3+)+e^(-) to Mn^(2+),""E^(o)=1.51V, then what is the redox potential of reaction Mn^(3+)+3e^(-) to Mn ?

Standard reduction potential of half-cells are given as follows : Zn^(2+)+2e^(-) to Zn,E^(o)=-0.76V Fe^(2+)+2e^(-) to Fe,E^(o)=-0.44V What is the emf of following reactions ? Zn_((S))+Fe_((aq))^(2+) to Zn_((aq))^(+2)+Fe_((S)).

Standard reduction potential of an element is equal to:

Standard reduction potential of an element equal to

Standard reduction potential at 25^(@)C of Li^(+)|Li,Ba^(2+)|Ba,Na^(+)|Na and Mg^(2+)|Mg are -3.05,-2.90,-2.71 and -2.37 volt respectively. Which one of the following is the strongest oxidising agent

Standard reduction potential for,Li^+Li, Zn^(2+) Zn, H^+ H_2 and Ag^+ Agis -3.05,-0.762,0.00 and +80V. Which has highest reducing capacity?

Standard potentials (E^(@)) for some half-reactions are given below : Sn^(4+) + 2e to Sn^(2+) , E^(@) = +0.15 V 2 Hg^(2+) + 2e to Hg_(2)^(2+) , E^(@) = 0.92 V PbO_(2) + 4 H^(+) + 2e to Pb^(2+) + 2H_(2)O , E^(@) = +1.45 V Based on the above , which one of the following statements is correct ?

Standard reduction electrode potentials of three metals A, B and C are respectively + 0.5V, –3.0V and –1.2 V. The reducing powers of these metals are:

Stadard reduction electrode potentials of three metals A,B and C are respectively +0.5V, -3.0V and -1.2V. The reducing powers of these metals are:

Standard reduction electrode potential of three metals A, B and C are respectively +0.05 V, -3.0 and -1.2 V. The reducing powers of

Standard molar enthalpy of formation of CO_2 is equal to:

Standard molar enthalpy of formation of CO_(2) is equal to

Starch contains 20% of_____ and 80% of .