Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Sodium salts of some acids are used as food preservatives. Suggest a few such acids.

Answer»

SOLUTION :BENZOIC ACID, sorbic acid and PROPANOIC acid.
2.

Sodium salt of long chain allyl benzene sulphonic acids are called ..

Answer»

soap
DETERGENT
disinfectant
antiseptic

Solution :detergent
3.

Sodium salt of which acid is used as food preservative ?

Answer»

Phthellic ACID
Adipic acid
Formic acid
BENZOIC acid

Answer :D
4.

Sodium salt of benzene sulphonic acid on fusion with caustic soda gives:

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`C_6H_5OH`
`C_6H_6`
`C_6H_5COOH`
None

Answer :A
5.

Sodium salt of formic acid on strong heating followed by acid hydrolysis yields:

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HCHO
HCOOH
COOH-COOH
`CH_3CHO`

ANSWER :C
6.

Sodium salt of benzene sulphonic acid on fusion with caustic soda followed by acidification gives

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Benzene
Phenol
Thiophenol
Benzenesulfonic acid

Answer :B
7.

Sodium salt of benzene sulphonic acid on fusion with caustic soda and followed by treatment with HCI gives

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ACETIC acid
cumene
phenol
picric acid

Answer :C
8.

Sodium salt of an organic acid 'X' produces effervescence with conc. H_2SO_4. 'X' reacts with the acidified aqueous CaCl_2 solution to give a white precipitate which decolourises acidic solution of KMnO_4. 'X' is :

Answer»

`C_6H_5COONa`
HCOONA
`CH_3COONa`
`Na_2C_2H_4`

SOLUTION :
9.

Sodium salt of an organic acid 'X' produces effervescence with conc. H_2SO_4 . 'X' reacts with the acidified aqueous CaCl_2 solution to give a white precipitate which decolourises acidic solution of KMnO_4.'X' is -

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HCOONA
`CH_3COONa`
`Na_2C_2O_4`
`C_6H_5COONa`

ANSWER :C
10.

Sodium salt of alpha-halo carboxylic acid is heated with sodium nitrite and followed by hydrolysis gives

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AMIDES
nitroparaffins
AMINES
ALCHOLS

ANSWER :B
11.

Sodium saltof aci- formof nitroalkanewhentreatedwith 50% H_(2)SO_(4) gives- CHO orgt C=O compounds. Thisisknown as

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NEF CARBONYL SYNTHESIS
Sandmeyersynthesis
Balz sysnthsis
Gattermannsysthesis

ANSWER :A
12.

Sodiumsaltof acidformof ethyl methylnitromicacids is treatedwith 50%H_(2)SO_(4) gives

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`CH_(3) - CH_(2) - CH_(2) - COOH`
`CH_(3) - CO - CH_(2)- CH_(3)`
`CH_(3) - CO -CH_(3)`
`CH_(3) - CH_(2)- CHO`

Answer :B
13.

Sodium rosinate is generally added in the soap because it :

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Prevents RAPID drying of SOAP
PRODUCES rich lather
Gives ANTISEPTIC property
Acts as a perfume.

Answer :B
14.

Sodium reacts with water less vigorously thann potassium because:

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It has HIGHER ATOMIC weight
It is LESS electropositive
It is more electronegative
It is a metal

Answer :B
15.

Sodium reacts with alcohol as given below 2R-OH + 2Na to 2R - O Na + H_2Place the type of alcohol into decreasing order of reactivity towards sodium.

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`3^@gt 2^@ gt 1^@`
`1^@gt 3^@ gt 2^@`
`2^@gt 3^@ gt 1^@`
`1^@gt 2^@ gt 3^@`

Solution :Reactivity of ALCOHOL toward sodium depends upon the ACIDIC NATURE of the alcohol. More the acidic nature of alcohol, the faster is the reaction between alcohol and sodium.The electron RELEASING alkyl groups decrease the acidic nature of alcohol. DECREASING order of acidity of alcohol is `CH_3OH gt 1^@ gt 2^@ gt 3^@` . The same is the order of reactivity towards sodium metal.
16.

Sodium reacts with alcohol as given below 2Na+ 2ROH rarrH_2+2[Na^(+) bar(O)R] place the types of alcohol into decreasing order of reactivity towards Na

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`1^@ GT 2^@ gt 3^@`
`1^@ gt 3^@ gt 2^@`
`2^@ gt 3^@ gt 1^@`
`3^@ gt 2^@ gt 1^@`

ANSWER :A
17.

Sodium phenoxide reacts with CO_2 at 400 K and 4 - 7bar pressure to give …………………. .

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SODIUM SALICYLATE
Salicylaldehyde
Cate CHOL
PYROGALLOL

SOLUTION :Sodium salicylate
18.

Sodium potassium citrate is one of the components of the following reagent :

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Fehling.s SOLUTION
Tollen.s REAGENT
Benedict.s solution
Baeyer.s reagent

ANSWER :C
19.

Sodium phthalamide overset(Br_(2).KOH)toXoverset(H_(3)O^(+))toYThe product Y is :

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ANTHRANILIC acid
o- PHENYLENE diamine
terephthalic acid
adipic acid

Solution :
20.

Sodium phenoxide on reaction with methyl iodide produces compound X, which on Friedel-Craft's acylation produces compounds Y and Z. Mention compounds X, Y and Z.

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X= Methoxy Benzene,
Y = 0-methoxy TOLUENE,
Z = p-methoxy toluene
X = Methoxy Benzene,
Y=o-chloro anisole,
Z= p-chloro anisole
X = Anisole,
Y= 1(2-methoxy phenyl) ethan 1 - one,
Z=1(4-methoxy phenyl) ethan - 1 - one
X = Anisole, Y= o - NITRO Anisole,
Z= p-nitro anisole

Solution :X = Anisole,
Y= 1(2-methoxy phenyl) ethan 1 - one,
Z=1(4-methoxy phenyl) ethan - 1 - one
21.

Sodium pheoxide reacts with CO_(2) at 400K and 4-7 atm pressure to give

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SODIUM SALICYLATE
salicyladehyde
catechol
BENZOIC acid

Answer :A
22.

Sodium phenoxide is reacted with ethyl chloride gives

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o-ethyl SODIUM phenoxide
p-ethyl sodium phenoxide
ethoxy benzene
m-ethyl sodium phenoxide

Answer :C
23.

Sodium oxalate on heating with conc. H_(2)SO_(4) gives

Answer»

CO only
`CO_(2)` only
CO and `CO_(2)`
`SO_(2)` and `SO_(3)`

SOLUTION :Sodium OXALATE react with conc. `H_(2)SO_(4)` to form CO and `CO_(2)` GAS.
24.

Sodium palmitate is a major constituent in soap. When an aqueous solution of sodium palmitate having 1 kg of solvent is analysed for its boiling point, following data is obtained. Identify the option(s) which is/are correct.

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Aqueous mixture of SODIUM palmitate having concentration EQUAL to 0.07 M will be heterogeneous.
The CMC value of sodium palmitate should be LESS than 0.06M.
Osmotic pressure at 0.08 M at 300 K will be 1.9704 atm.
At 0.4 M concentration, the SOLUTION is homogeneous.

Answer :A::B
25.

Sodium peroxide in contact with moist air turns white due to the formation of:

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`Na_2O`
`Na_2CO_3`
`NaHCO_3`
NaOH

Answer :D
26.

Sodium nitroprusside when added to an alkanie solution of sulphide ions produces purple colourations due to the formation of

Answer»

`Na[FE(H_(2)O)_(5)NOS]`
`Na_(4)[(CN)_(5)NOS]`
`Na_(3)[(CN)_(5)NOS]`
`[Cr(NH_(3))_(6)CI_(6)`

Solution :(b) `Na_(2)S+Na_(2)[Fe(CN)_(5)NOrarrNH_(4)[Fe(CN)_(5)NOS]`
27.

Sodium or potassium salts of higher fatty acids are called

Answer»

SOAPS
Terpenes
Sugars
Alkaloids

Solution :Soaps are the sodium or POTASSIUM salts of higher FATTY ACIDS.
28.

Sodium nitroprusside, when added to an alkaline solution of sulphide ions, produces purple colour ion due to the formation off

Answer»

`NA[Fe(H_(2)O)_(5)NOS]`
`Na_(2)[H_(2)O)_(5)NOS]`
`Na_(3)[Fe(CN)_(5)NOS]`
`Na_(4)[Fe(CN)_(5)NOS]`

Solution :`Na_(4)[Fe(CN)_(5)NO]+S^(2-)to UNDERSET("Sodium thio-nitroprusside (VIOLET)")(Na_(4)[Fe(CN)_(5)NOS])`
29.

Sodium nitroprusside, when added to an alkaline solution of sulphide ions, produces purple colour ion due to the formation of

Answer»

`NA[Fe(H_(2)O)_(5)NOS]`
`Na_(2)[Fe(H_(2)O)_(5)NOS]`
`Na_(3)[Fe(CN)_(5)NOS]`
`Na_(4)[Fe(CN)_(5)NOS]`

Solution :`Na_(4)[Fe(CN)_(5)NO]+S^(2-)rarr Na_(4)[Fe(CN)_(5)NOS]`
Sodium thio-nitroprusside (violet)]
30.

Sodium nitroprusside whenadded to an alkaline solution ions produces a colouration which is :

Answer»

red
BLUE
brown
purple

Solution :`NH_(4)[Fe(CN)_(5)NO_(5)]` blue
31.

Sodiumnitroprusside reacts with sulphide ion give a purple colour due to the formation of

Answer»

`[Fe(CN)_(5)NO]^(3-)`
`[Fe(NO)_(5)CN]^(-)`
`[Fe(CN)_(5)NOS]^(4-)`
`[Fe(CN)_(5)NOS]^(3-)`

Solution :`underset("Sodium nitroprusside")([Fe(CN)_(5)NO]^(2-))+S^(2-)rarrunderset("PURPLE COMPLEX")([Fe(CN)_(5)NOS]^(4-))`
32.

Sodium nitroprusside test is used to distinguish between

Answer»

alcohols and phenols
aldehydes and ketones
formic ACID and other carboxylic acids
`1^@ , 2^@` and `3^@` amines.

SOLUTION :Sodium nitroprusside test is used to DISTINGUISH between aldehydes and ketones . Alkaline solution of ketone react with nitroprusside to form coloured ion.
`CH_(3) underset("(Acetone)") (COCH_(3)) + OH^(-) to CH_(3) COCH_(2) + H_(2)O`
`underset("Nitroprusside ion")([Fe(CN)_(5) NO]^(2-)) + CH_3 COCH_(2)^(-) to [Fe (CN)_(5) underset("(red coloured)")(NO * CH_(3) CO) CH_(2)]^(3-)`
Aldehydes do not show this reaction .
33.

Sodium nitrophrusside when added to an alkaline solution of sulphide ions produce as

Answer»

RED colouration
Blue colouration
Purple colouration
Brown colouration

Solution :`Na_(2)S+underset("SODIUM nitroprusside")(Na_(2)[Fe(NO)(CN)_(5)])to underset("Violet coloured complex")(Na_(3)[Fe(ONSNa)(CN)_(5)])` or `underset("Purple colour complex")(Na_(4)[Fe(CN)_(5)NOS])`
34.

Sodium nitroprusside Na_(2)[Fe(CN)_(5)NO] is used as a reagent for the detection of

Answer»

sulphur
nitrogen
BROMINE
iodine.

Answer :A
35.

Sodium nitrate decomposes above 800^@C to give

Answer»

`N_2`
`O_2`
`NO_2`
`Na_2O`

ANSWER :B
36.

Sodium nitrate used in …………….. .

Answer»

Photography
FIREARMS
Royal water
Cryosurgery

Solution :Firearms
37.

Sodium nitrate on reduction with Zn in presence of NaOH solution produces NH_(3). Mass of sodium nitrate nitrate absorbing 1 mole of electron will be

Answer»

`7.750`
`10.625`
`8.000`
`9.875`

Solution :AMMONIA is formed by reduction of nitrates and nitrites with Zn and NaOH. Zn and caustic soda produce nascent hydrogen which reacts with nitrates to FORM ammonia.
`NaNO_(3)+8H^(+)+8e OVERSET(Zn//NaOH)(RARR) NaOH+NH_(3)+2 H_(2)O`
From the equation
Mass of `NaNO_(3)` absorbing 8 moles of electron `=85 g`
`:.` Mass of `NaNO_(3)` absorbing 1 mole of electron `=85/8=10.625 g`.
38.

Sodium nitrate on heating with zinc dust and caustic soda gives

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`NaNO_2`
`NH_3`
`NO_2`
`N_2O`

ANSWER :B
39.

Sodium metal reacts readily with

Answer»

R-CHO
`R-CH_2OH`
ESTER
`R-NH_2`

ANSWER :B
40.

Sodium metal is soft but Iron is a hard metal. This difference arises due to.

Answer»

Sodium has lesser atomic MASS than IRON
Sodium has only ONE valence ELECTRON where as iron has more
There is one unpaired electron is sodium but four unpired electrons in iron
Sodium reacts readily with air and moisture but iron is resistanct to action of water

ANSWER :C
41.

Sodium metal is obtained by:

Answer»

The ELECTROLYSIS of concentrated NaCl (AQ)
HEATING `Na_2O` with `H_2`
Heating FUSED sodium chloride
Electrolysis of fused sodium chloride

Answer :D
42.

Sodium metal is extracted by

Answer»

Electrolysis of AQUEOUS SOLUTION of sodium chloride
Electrolysis of fused sodium chloride
Heating sodium oxide with carbon
Heating sodium oxide with hydrogen

Answer :B
43.

Sodium metal exists in bcc unit cell. The distance between nearest sodium atoms is 0.368 nm. The edge length of unit cell is .........

Answer»

0.368 nm 
0.184 nm 
0.425 nm 
0.575 nm 

Solution :In bcc structure, the closest DISTANCE (d)
between two ATOMS `= (sqrt(3)a)/2`
`THEREFORE` distance `(d) = 0.368 = (sqrt(3)a)/(2)`
`IMPLIES a = 0.425`.
44.

Sodium metal in liquid ammonia is

Answer»

an IONIC CONDUCTOR
an ELECTRONIC conductor
a MIXED conductor
NON - conductor

45.

Sodium metal crystallizes in bcc structure with the edge length of the unit cell 4.3 xx 10^(-8) cm. Calculate the radius of sodium atom.

Answer»


Solution :Edge length of theunit CELL `(a)=4.3xx10^(-8)`cm
Radius of SODIUM atom (r) `=?`
For bcc structure, `r=sqrt(3)/4 a`
`=(sqrt(3))/(4)(4.3xx10^(-8)cm)`
`=(1.732xx4.3xx10^(-8))/(4)`
`=(7.4476)/(4)xx10^(-8)`cm
`=1.86xx10^(-8)cm=1.86 Å`
46.

Sodium metal crystallizes in bee structure with the edge length of the unit cell 4.3 xx10^(-) cm. Caleulate the radius of sodium atom.

Answer»

SOLUTION :`"Edge LENGTH of the UNIT cell (a)"=4.3xx10^(-8)CM`
`"Radius of sodium atom (r )"=?`
`"for bcc structure, r"=(sqrt3)/(4)a`
`=(sqrt3)/(4)(4.3xx10^(-8)cm)`
`=(1.732xx4.3xx10^(-8))/(4)`
`=(7.4476)/(4)xx10^(-8)cm`
`=1.86xx10^(-8)cm=1.86Å`
47.

Sodium metal crystallizes in B.C.C. lattice with edge length of 4.29A^(@). The radius of sodium atom is

Answer»

`2.857 A^(@)`
`1.601 A^(@)`
`2.145 A^(@)`
`1.857 A^(@)`

ANSWER :D
48.

Sodium metal crystallizers in B.C.C. lattice with edge length of 4.29 A^o. The radius of sodium atom is

Answer»

`2.145 Å`
`2.857Å`
`1.857Å`
`1.601Å`

SOLUTION :EDGE length `a = 4.29Å`
For B.C.C. lattice
`R = ( SQRT( 3) a )/( 4) = ( sqrt( 3))/( 4) xx 4.29`
`= 1.857 Å`
49.

Sodium metal crystallizes in a body-centred cubic lattice with a unit cell edge of 4.29 A^@. The radius of sodium atom is approximately…...

Answer»

`5.72 A^@`
`0.93 A^@` 
`1.86 A^@` 
`3.22 A^@` 

Solution :For bcc structure `R = (SQRT3)/4 a`
`r = (sqrt3)/(4) XX 4.29`
`r = 1.86 A^@`.
50.

Sodium metal crystallizes in a body centred cubic lattice with a unit cell edge of 4.29Å. The radius of sodium atom is approximately :

Answer»

`1.86Å`
`3.22Å`
`5.72Å`
`0.93Å`

Solution :For body CENTRED cubic LATTICE,
Radius, `R = ( SQRT( 3))/( 4) a `
`a = 4.29 Å`
`:. r = ( 1.732)/( 4) xx 4.29 = 1.86 Å`