Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Sodium metal crystallises in a body centred cubic lattice with a unit cell edge of 4.29 A. The radius of Na atom is approximately

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`1.86 A`
`3.22 A`
`5.72 A`
`0.93 A`

ANSWER :A
2.

Sodium metal crystalizes in a body centred cubic lattice with the cell edge a =4.29overset@A.The radius of sodium atom is :

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`1.8574overset@A`
`2.8574overset@A`
`3.8574overset@A`
None

Answer :A
3.

Sodium metal can be stored under

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Benzene
Kerosene
Alcohol
Toluene

ANSWER :B
4.

Sodium metal cannot be stored under :

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benzene
kerosene
alcohol
toluene

Answer :C
5.

Sodium metal cannot be stored under:

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Benzene
Kerosene
Alcohol
Toluene

Answer :C
6.

Sodium, Magnesium and Aluminium can be obtained from their are by

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Electrometallurgy
Pyrometalurgy
Hydrometallurgy
Smelting

Answer :A
7.

Sodium lauryl sulphate is used as _____.

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SOLUTION :DETERGENT
8.

Sodium iso-propoxide + A oversetDeltato 2-ethoxy propene + NaCl The compound A is

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`C_2H_5ONa`
`C_2H_5COCl`
`C_2H_5Cl`
`CH_3ONa`

ANSWER :C
9.

Sodium is used in nuclear reactor as :

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a moderator
a coolant
a REDUCING agent
an OXIDISING agent

Answer :C
10.

Sodium hypophosphite represented as

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`Na_(3)PO_(4)`
`Na_(3)P`
`NaH_(2)PO_(2)`
`Na_(2)PO_(3)`

ANSWER :C
11.

Sodium iauryl sulphate is

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Bio-DEGRADABLE, CATIONIC dertergent
Bio-degradable, ANIONIC detergent
Non-bio degradable, non-ionic detergent
Non-bio degradable, anionic detergent

Answer :B
12.

Sodium hydroxide is produced on a large scale

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by the hydrolysis of `Na_(2)CO_(3)`
by the ELECTROLYSIS of an aqueous solution of NaCl
by ADDING water to sodium oxide
by REACTING sodium with water

Answer :B
13.

Sodium hydroxide may be prepared by any of the following methods except :

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NELSON cell
Castner KELLNER cell
Solvay process
Bell process

Answer :C
14.

Sodium ordinarily does not show an oxidation state of +2, because of its

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HIGH FIRST ionisation potential
High second ionization potential
large ionic radius
high electronegativity

Answer :B
15.

Sodium forms two oxides (A) and (B) having 25.81 % and 41.03% oxygen respectively. What is the reaction of (A) and (8) with H_(2)O:

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SOLUTION :`AtoNa_(2)O`,`Na_(2)O+H_(2)Oto2NaOH`
`BtoNa_(2)O_(2)+2H_(2)Oto2NaOH+H_(2)O_(3)`
16.

Sodium formate solution on electrolysis gives ................. at anode.

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METHANE + `CO_2`
ETHANE + `CO_2`
`H_2 + CO_2`
FORMIC ACID

SOLUTION :`H_2 + CO_2`
17.

Sodium formate on heating with soda lime give:

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`CH_4`
`H_2O`
`H_2`
All

Answer :D
18.

Sodium extract of Lassaigne's solution is treated with FeSO_4 , FeCl_3 and dil. H_2 SO_4 to get a blood red colour . Which of the following is probable organic compound ?

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SOLUTION :The COMPOUND (a) has both NITROGEN and SULPHUR.
19.

Sodium extract prepared by using thiourea contains which ion in the solution ,mainly responsible for a characteristic test:

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NACN
`Na_2S`
NACNS
`Na_2SO_4`

ANSWER :C
20.

Sodium extract of Lassaigne's solution is treatedwith FeSO_4, FeCl_3 and dil. H_2SO_4 to get a blood red colour. Which of the following is probable organic compound?

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SOLUTION :The COMPOUND (a) has both NITROGEN and SULPHUR.
21.

Sodium extract is heated with concentrated HNO_(3) before testing for halogens because :

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Ag reacts faster with halides in ACIDIC medium.
Silver halides are totally INSOLUBLE in nitric acid.
`Ag_(2)S` and AgCN are SOLUBLE in acidic medium.
`S(2-) " and" CN^(-)`, if PRESENT, are decomposed by conc. `HNO_(3)` and hence do not interfere in the test.

Answer :D
22.

Sodium ethoxide reacts with ethyl iodide to yield:

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`CH_3CH_3`
`C_2H_5OCH_3`
`C_2H_5OC_2H_5`
None

Answer :C
23.

Sodium ethoxide reacts with ethanoyl. The compound that is produced in the above reaction is

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2-butanone
ethyl chloride
ethyl ethanoate
diethyl ether

Solution :`underset("ETHANOYL chloride")(CH_(3)COCl)+C_(2)H_(5)ON a to underset("Ethyl ethanoate")(CH_(3)COOC_(2)H_(5))+NACL`
24.

Sodium ethoxide is specific reagent for:

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Dehydration
Dehydrohalogenation
Dehydrogenation
Dehalogenation

Answer :C
25.

Sodium ethoxide is obtained by the reaction of ethyl alcohol with :

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NaOH
Na
NaCl
`NaHCO_3`

ANSWER :B
26.

Sodium ethoxide has reacted with ethanoyl chloride . The compound that is produced in the above reaction is

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DIETHYL ether
2-butanone
Ethyl chloride
Ethyl ethanoate

Solution :
27.

Sodium ethoxide (C_(2)H_(5)ONa) is a specific reagent for

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Dehydration
Dehydrohalogenation
Dehydrogenation
Dehalogenation

Answer :C
28.

Sodium ethoxide is a specific reagent for

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dehydration
dehydrogenation
DEHYDROHALOGENATION
dehalogenation

Solution :
ETHOXIDE ion is a strong base which ABSTRACTS proton from CARBOCATION to form alkene.

Thus, there is a loss of hydrogen and halogen both leading to dehydrohalogenation.
29.

Sodium ethoxide and ethyl chloride on heating will give :

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ETHER
ETHYL alcohol
Acetaldehyde
ACETIC acid

Answer :A
30.

Sodiumcyanideis sometimesaddedinthefrothfloatationprocess asa depressantwhen the ore contains amixtureofZnS +PbS because

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Pb `(CN)_2 `getsprecipitatedwithoutanyeffecton ZNS
ZnS fromssolublecomplex, `Na_2 [Zn(CN)_4] `while PBS formsthe froth
PbS formssolublecomplex,` Na_2[Pb(CN)_4]`while ZnS formsfroth
` Zn(CN)_2 `getsprecipitatedwithoutany EFFECTON PbS.

Answer :B
31.

Sodium dodecyl benzene sulphonate is used as a:

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Pesticide
Soap
Fertilizer
Detergent

Answer :D
32.

Sodium cyanidesolution isusedextract ………..or………. Fromitsores.

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ANSWER :SILVER, GOLD
33.

Sodium cyanide solution is used to extract _______ from its ores.

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copper
silver
gold
both (B) and (C )

ANSWER :D
34.

Sodium crystallizes in a face centred cubic lattice. The approximate number of unit cells in 5.0 g of sodium is (Atomic mass of sodium = 23 amu)

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`32.7 × 10^(22)`
`3.27 X 10^(22)`
`6.54 × 10^(22)`
`65.4 × 10^(22)`

ANSWER :B
35.

Sodium cyanide is added to depresses the floatation property of ZnS by forming a layer of …….

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Solution :`Na_(2)[Zn(CN)_(4)]`-SODIUM ZINCATE complex
36.

Sodium crystallizes in the cubic lattice and the edge of the unit cell is 430 pm. Calculate the number of atoms in a unit cell. (Atomic mass of Na = 23.0 density = 0.9623g cm^(-3), N_A = 6.023 xx 10^(23) mol^(-1)).

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Solution :Length of edge = 430 pm = `430 xx 10^(-12) m=430 xx 10^(-10)` cm
Volume of unit CELL = `a^3 =(430 xx 10^(-10))^3 cm^3 = 79.5 xx 10^(-24) cm^3`
Mass of one atom= `("Atomic mass")/("Avogadro.s No.") = (23)/(6.023xx10^(23))=3.82 xx 10^(-23)` g
Mass of unit cell = `"Volume" xx "density" = 79.5 xx 10^(-24) xx 0.9623 = 76.5 xx 10^(-24)` g
No. of atoms in unit cell = `("Mass of unit cell")/("Mass of an atom") =(76.5 xx 10^(-24))/(3.82 xx 10^(-23)) = 2`
37.

Sodium crystallises in a bcc unit cell. Calculate the approximate number of unit cells in 9.2 g of sodium ? "[Atomic Mass of Na = 23 u]"

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Solution :No. of moles of sodium `=("Mass of sodium")/("Atomic mass of sodium")`
`=(9.2)/(23)=0.4`
ONE MOLE of sodium metal contains `=6.022xx10^(23)" atoms"`
0.4 mole of sodium metal contains `=0.4xx6.022xx10^(23)" atoms "=2.4088xx10^(23)" atoms"`
One bcc UNIT cell contains = 2 atoms
No. of unit cells in 9.2 g of sodium `=(2.4088xx10^(23))/(2)=1.2044xx10^(23)`
38.

Sodium crystallizes in a bcc lattice, hence the coordination number of sodium in sodium metal is

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0
4
6
8

Answer :D
39.

Sodium chloride when heated with conc. H_(2)SO_(4) and solid potassium dichromate gives

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Chromic chloride
Chromyl chloride
Chromous chloride
NONE of these

Solution :`4NaCl+K_(2)Cr_(2)O_(7)+3H_(2)SO_(4)rarrunderset("Chromyle chloride")(K_(2)SO_(4)+2Na_(2)SO_(4))+2Na_(2)SO_(4)+2CrO_(2)+3H_(2)O`
40.

Sodium chloride, NaCl usually crystallizes in a face centred cubic lattice. How many ions are in contact with any single Na^(+) ion ?

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4
6
8
1

Solution :COORDINATION NUMBER of `NA^(+)` is 6.
41.

Sodium chromite is:

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`Na_2CrO_4`
`Na_2Cr_2O_4`
`Na_2Cr_2O_7`
`CR(SO_4)_3`

ANSWER :B
42.

Sodium chloride is soluble in water not in benzene because

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`Delta H_("hydration") lt Delta H_("LATTICE energy in water") and Delta H_("solvation") GT Delta H_("lattice energy in BENZENE")`
`Delta H_("hydration") gt Delta H_("lattice energy in water") and Delta H_("solvation") lt Delta H_("lattice energy in benzene")`
`Delta H_("hydration") = Delta H_("lattice energy in water") and Delta H_("solvation") lt Delta H_("lattice energy in benzene")`
`Delta H_("hydration") lt Delta H_("lattice energy in water") and Delta H_("solvation") = Delta H_("lattice energy in benzene")`

ANSWER :B
43.

Sodium chloride is soluble in water but not in benzene because

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`DeltaH_("hydration")ltDeltaH_("lattice ENERGY in water")and`
`DeltaH_("hydration")gtDeltaH_("lattice energy in benzene")`
`DeltaH_("hydration")gtDeltaH_("lattice energy in water")and`
`DeltaH_("hydration")ltDeltaH_("lattice energy in benzene")`
`DeltaH_("hydration")=DeltaH_("lattice energy in water")and`
`DeltaH_("hydration")ltDeltaH_("lattice energy in benzene")`
`DeltaH_("hydration")ltDeltaH_("lattice energy in water")d`
`DeltaH_("hydration")=DeltaH_("lattice energy in benzene")`

Solution :For a SUBSTANCE to dissolve, the energy evolved when the ions are HYDRATED (hydration energy) must be larger than the energy required to BREAK the crystal lattice (lattice energy). Conversely if the solid insoluble, the hydration energy is less than the lattice energy.
44.

Sodium chloride is prepared in the lab by burning sodium metal in the atmosphere of chlorine. The staff produced has a slightly yellowish colour. The cause of yellow colour is due to

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presence of `NA^(+)` ions in the CRYSTAL LATTICE.
presence of electrons in anion VACANCIES in the crystal lattice.
Presence of F-centre in the crystal lattice.
none of these

Answer :C
45.

Sodium chloride is known as:

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ROCK salt
Common salt
Table salt
All of these

Answer :D
46.

Sodium chloride is an ionic compound whereas hydrogen chloride is a gas because

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SODIUM is reactive
COVALENT bond is weaker than ionic bond
HYDROGEN CHLORIDE is a gas
covalent bond is stronger than ionic bond

Answer :B
47.

Sodium chloride is an ionic compound where as hydrogen chloride gas is mainly convalent because

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A) electronegativity difference in the CASE of hydrogen is less 2.1
B) hydrogen chloride is a gas
C) hydrogen is a non-metal
D) SODIUM is reactive.

Solution :NaCl is an ionic compound. The electronegativity difference between Na and CL is 2.1. In HCl gas the electronegativity difference between H and Cl is less than 2.1 so it is mainly covalent compound.
48.

Sodium chloride crystallizes in face-centred cubic (f.c.c.) structure. Its density is 2.165 g cm^(-3). If the distance between Na^+ and its nearest Cl^(-) ions is 281 pm, find out the Avogadro's number (Na = 23 g "mol"^(-), Cl = 35.5 g "mol"^(-)).

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Solution :For a cubic unit CELL,
`d=(ZM)/(a^3 10^(-30)N_A) G cm^(-3)` or `N_A=(ZM)/(10^(-30)d a^3)`
When .a. is in pm.
Where M=Molar MASS of NACL = 23 + 35.5 = 58.5 g `mol^(-)`
`N_A`=Avogadro.s number = ?
d= density = 2.165 g `cm^(-3)`
Z= number of atoms per unit cell = 4 (f.c.c.)
a=edge length of the unit cell in pm.
For NaCl type crystal, edge length (a) = `2 xx "interionic distance"` = 2 (281) = 562 pm
`:. N_A=(4 xx 58.5 g mol^(-))/(10^(-30) xx 2.165 g cm^(-3) xx (562)^3 cm^3)`
`=(234.0 g mol^(-1))/(8 xx 22188041 xx 10^(-30) xx 2.165 g) = 6.09 xx 10^(23) mol^(-)`
49.

Sodium chloride contains 60.68% chlorine by mass. If 7.1 g chlorine is made to react with 5.2 g of sodium, the number of moles of sodium which reacted with Cl_(2) is

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`0.2`
`0.1`
`0.21`
`0.12`

Solution :Percentage of sodium `= 100 -60.68 = 39.32`
60.68 CHLORINE react with sodium
= 39.32 g
7.1 g of chlorine react with sodium
`= ((39.32g)XX(7.1g))/(60.68)`
`= 4.60 g`
Moles of sodium ` = (4.60g)/(23 g MOL^(-1)) = 0.2 mol`
50.

Sodium carbonated is manufactured by solvay process, the products that are hydrated are

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`CO_(2)` and `NH_(3)`
`CO_(2)` and `NH_(4)Cl`
`NaCl, CaO`
`CaCl_(2),CaO`

Answer :A