Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

SOCl_(2) can act as Lewis acid as well as Lewis base because

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sulphur has a PAIR of ELECTRONS to DONATE
it has empty d-orbital to ACCEPT electrons
sulphur is a non metal
chlorine is more electronegative

SOLUTION :Due to the presence of empty d-orbitals. It accept `e^((-))s` and the central atom S contains along pair of electrons.
2.

Soda ash has the chemical formula :

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`Na_(2)CO_(3)`
`NaHCO_(3)`
NaOH
`Na_(2)O`

ANSWER :A
3.

Soaps essentially form a colloidal solution in water and remove the greasy matter by:

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coagulation
emulsification
adsorption
ABSORPTION.

ANSWER :B
4.

Soaps do not from froths easily from hard water because :

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Of formation of insoluble SALTS
Of formation of complex salts
Of lower solubility of SOAPS in HARD water
None

Answer :A
5.

Soaps are anionic detergents.

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ANSWER :T
6.

Soaps and detergents are kept in the for which of the following types of compounds?

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SURFACE ACTIVE
Surface inactive
Water soluble
Water insoluble

Answer :A
7.

Explain cationic and anionic detergents with suitable examples.

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ANSWER :T
8.

Soaps.

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Solution :Soaps are sodium or potassium saltsof higher FATTY acids which contain more than twelve carbon ATOMS. Potassium soaps are SOFTER than sodium soaps and are USED in shampoo, SHAVING cream and bathing soaps. Sodium soaps are toilet soaps used for washing purposes.
9.

Soap removes grease by

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ADSORPTION 
EMULSIFICATION 
COAGULATION 
NONE of these 

SOLUTION :Emulsification
10.

Soap molecule has two parts, a polar part and a non-palar part. When soap added to water:

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Both parts dissolve in water
Non-POLAR PART DISSOLVES in water
Polar part dissolves in water
Both parts remain UNDISSOLVED in water and form a hydrocarbon layer

Answer :C
11.

Soap is reacted with hard water gives

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insoble `(RCOO)_(2)` Ca and soluble `(RCOO)_(2)Mg`
SOUBLE `(R-COO)_(2)`Ca and insoble `(R-COO)_(2)Mg`
Insouble `(R-COO)_(2)Ca` and `(R-COO)_(2)Mg`
soluble`(R-COO)_(2)Ca` and `(R-COO)_(2)Mg`

ANSWER :C
12.

Soap is an example of an associated colloid.

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13.

Soap is a weak antiseptic. What may be added to soaps to improve its antiseptic action?

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SOLUTION :Bithional is ADDED to SOAPS to improve its ANTISEPTIC action.
14.

Soap is a weak antiseptic. What may be added to soaps to improve its antiseptic action ?

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Solution :BITHIONAL is added to SOAPS to IMPROVE its antiseptic properties.
15.

Soap is____

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 SODIUM stearate
calcium stearate
sodium acetate
sodium benzoate

Answer :A
16.

Soap emulsifies

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OIL in WATER TYPE
Water in oil type
Oil in oil type
Gel in oil

Answer :A
17.

Soap cannot form foam with hard water because ......

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insoluble salt FORM 
insoluble salt of `Ca & Mg` form in water 
more TDS in HARD water 
DENSITY of hard water is more 

Solution :insoluble salt of `Ca & Mg` form in water
18.

SO_(3)^(2-)+S^(***) overset("boil")to S S^(***)O_(3)^(2-),S S^(***)O_(3)^(2-)+2H^(+)toH_(2)SO_(3)+S^(***) The above reaction sequence proves:

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Two sulphur atoms of THIOSULPHATE are not equivalent
Both are equivalent
Both of the above are correct
None of these

Solution :`O^(-)-UNDERSET(O)underset(||)overset(S)overset(||)(S^(6+))-O^(-)`
19.

SO_3 on reacting with conc. HCL gives:

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Chlorosulphuric ACID
`Cl_2 + H_2SO_3`
`Cl_2 + H_2SO_4`
None

Answer :A
20.

SO_(3) gas is entering the environment at a constant rate of 6.93xx10^(-6) gm//L//day due to the emission of polluting gases from thermal powerplant, but at the sane time it is decomposing and following first order kinetic with half lif e of 100 days. Based on above infromation, select the true statement (s)

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Concentration of `SO_(3)` in Kota is `1.25xx10^(-5)` M (ASSSUME `SO_(3)` present in Kota with constant concentration means rate of formation and dissociation of `SO_(3)` are equal).
If `SO_(3)` emission is STOPPED then after `1000` days its concentration will REDUCE to `~~ 1.2xx10^(-8)` M.
If `10^(3)` L of air passed throught 1 L pure water (assuming all `SO_(3)` to dissolved in it) and resulting solution is titrated against 1 N NaOH solution of which 15 ml is CONSUMED.
An industry is manufacturing `H_(2)SO_(4)` at the rate of 980 kg per day with the use of `SO_(3)` in air itshould use `8xx10^(5)` Litre aid /day.

Answer :A::B
21.

SO_(3) gas is entering the environment at a constant rate of 6.93 xx 10^(–6) gm/L/day due to the emission of polluting gases from thermal power plant, but at the same time it is decomposing & following first order kinetics with half life of 100 days. Based on above information select the true statement(s).

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Concentration of `SO_(3)` in Kota is `1.25 xx 10^(–5) M`
(Assume `SO_(3)` present in air reaches STEADY state)
If `10^(3)` L of air is passed through 1 L pure water
(assuming all `SO_(3)` to be dissolved in it) & resulting solution is titrated against 1 N NaOH solution, 15 ml is required to reach end POINT.
An INDUSTRY is manufacturing `H_(2)SO_(4)` at the rate of980 kgper DAY with the use of `SO_(3)` in air it should use `8 xx 10^(5)` Litre air /day.
If `SO_(3)` emission is stopped then after 1000 days its concentrations will reduce to `~~ 1.2 xx10^(–8) M`.

ANSWER :A::D
22.

SO_(3) (g) is produced as : SO_(2) (g) + (1)/(2) O_(2) (g) hArr SO_(3) (g) At 900 K, 0.2 mol of SO_(2) and 0.4 mol of O_(2) are taken in 2L vesset. When equilibrium is reaches by concentration of SO_(3) (g) is 0.08 M. Then K_(C)^(0) for reaction is :

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`(10)/(sqrt2)`
`10^(-1)`
`10`
`100`

Solution :`{:(,SO_(2) (g),+,(1)/(2)O_(2) (g),hArr,SO_(3) (g),T = 900 K,),("Concentration",(0.2)/(2),,(0.4)/(2),,,,),("initially",,,,,,,),("concentration",0.1 - x,,0.2 - (1)/(2) x,,x,,),(,x = 0.08 M,,,,,,),(,,,,,,,):}`
`K_(C) = ([SO_(3)])/([SO_(2)] [O_(2)]^(1//2)) = (0.08)/(sqrt(0.16) XX 0.02) = 10`
23.

SO_(3) can be prepared by which of the following reactions ?

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`CaSO_(4) C OVERSET ("HEAT") to `
`Fe_(2)(SO_(4))_(3) overset("heat") to`
`S+H_(2)SO_(4) overset("heat") to`
`H_(2)SO_(4) + PCl_(5) overset("heat") to`

Solution :`Fe_(2)(SO_(4))_(3) overset("heat") to Fe_(2)O_(3)+3SO_(3)`
24.

SO_3 gas can be identified by exposing it to the

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Glass rod dippend in CONC HCl
Filter paper dipped in acidified `K_2Cr_2O_7`
Filter paper dipped in lead acetate SOLUTION
Glass rod dippend in `NH_4OH`

ANSWER :B
25.

Sulphur troxide can be obtained by which of the following reaction ?

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`CaSO_(4)+C OVERSET(Delta)to`
`Fe_(2)(SO_(4))_(3) overset(Delta)to`
`S+H_(2)SO_(4) overset(Delta)to`
`H_(2)SO_(4)+PCl_(5) overset(Delta)to`

Solution :Except `SO_(2)` other gases are collected over water. Because `SO_(2)` soluble in `H_(2)O`.
26.

SO_3 can be obtained by heating:

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S + `H_2SO_4`
`CaSO_4 + C`
`FeSO_4`
`H_2SO_4 + PCl_5`

ANSWER :C
27.

SO_(2(g))+2H_(2)S_((g))rarr3S_((s))+2H_(2)O_((l)) which will be the method to obtain sulphur sol by reaction shown above?

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Double decomposition 
Oxidation 
REDUCTION 
HYDROLYSIS 

SOLUTION :Oxidation
28.

SO_(2)Cl_(2)hArrSO_(2)+Cl_(2) is the first order gas reaction with k=2.2xx10^(-5)sec^(-1) at 320^(@)C. The percentage of SO_(2)Cl_(2) decomposed on heating for 90 minutes is

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`1.118`
`0.1118`
`18.11`
`11.30`

Solution :`k=(2.303)/(t)log.(a)/((a-x))implieslog.(a)/((a-x))=(k.t)/(2.303)`
`implieslog.(a)/(a-x)=(2.2xx10^(-5)xx60xx60)/(2.303)=0.0516`
HENCE, `(a)/((a-x))=1.127implies(a-x)/(a)=0.887`
`implies1-(x)/(a)=0.887implies(x)/(a)=0.113=11.3%`
29.

SO_2Cl_2 to SO_2 +Cl_2 is a first order gas reaction with k = 2.2 xx 10^(-5) sec^(-1)" at " 320^@C Percentage of SO_2Cl_2 decomposed on heating for 90 minutes is

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0.0887
0.887
0.0113
0.113

Solution :`k = 2.303/tlog.(a)/ (a-x)or log.([A])_0/[A]_t= (KT)/2.303`
`=(2.2 xx 10^(-5)xx 60 xx 90)/2.303 = 0.0516`
Hence, `[A]_0/[A]_t=AL(0.0516) = 1.127`
`or [A]_t/[A]_0= 1/1.127=0.887`
AMOUNT decomposed `=1-[A]_t/[A]_0`
`=1-0.887 = 0.113`
% Amount decomposed = 11.3%
30.

SO_2 reacts with Cl_2 to yield:

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Thionyl chloride
Carbonyl chloride
Sulphuryl chloride
Sulphur monochloride

Answer :C
31.

SO_(2), reacts with Cl_(2), to form

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`SOCl_(2)`
`SO_(2)Cl_(2)`
`SCl_(2)`
`S_(2)Cl_(2)`

SOLUTION :`SO_(2)+Cl_(2) to SO_(2)Cl_(2)`
32.

SO_2 reduces cupric ion to cuprous ion in presence of:

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`KOH`
`H_2O`
`KCNS`
`H_2SO_4`

ANSWER :C
33.

SO_2 reduces:

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`MG`
`H_2S`
`KMnO_4`
`All`

ANSWER :C
34.

SO_2 pollution affects which part of the plant

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Chloroplast
Mitochondria
ER
Lysosome

Answer :A
35.

SO_2 reacts with chlorine to form

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SULPHUR monochloride
Sulphur dichloride
Sulphuryl chloride
Sulphur trichloride

Answer :C
36.

SO_2 oxidises

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MG
`K_2Cr_2O_7`
`KMnO_4`
All

Answer :A
37.

SO_(2) is reducing while TeO_(2) is an oxidising agent. Give reasons.

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Solution :Since +6 oxidation state of S is more STABLE than +4, therefore, it can readily donate electrons an hence acts as a reducing AGENT. For example, it reduces ferric to FERROUS salts.
`underset("Ferric sulphate")(Fe_(2)(SO_(4))_(3)) + SO_(2) + 2H_(2)O rarr underset("Ferrous sulphate")(2FeSO_(4)) + 2H_(2)SO_(4)`
Since due to inert pair effect, the stability of +6 oxidation state DECREASES while the stability of +4 and +2 oxidation states increases down the group. Thus, +4 oxidation state of `TiO_(2)` is less stable than its +2 oxidation state. As a result, it accepts electrons and thus acts an oxidising agent.
38.

SO^(2) is used as

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preservation
antioxidant
sweetening agent
both 'a, and 'b'

Answer :D
39.

SO_(2) is obtained when the following are heated in air

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S
`FeS_(2)`
HI
`HIO_(3)`

Solution :`S+O_(2) to SO_(2), 4FeS_(2)+11O_(2) to 2Fe_(2)O_(3) to 8SO_(2)`
40.

SO_(2) is more powerful reducing agent in

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ACID medium
Basic medium
Neutral medium
None

ANSWER :B
41.

SO_(2) is dried by

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<P>`P_(2)O_(5)`
`HNO_(3)`
Anhyd. `CaCl_(2)`
`CuO`

ANSWER :A
42.

SO_2 is dried by:

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CUO
`HNO_3`
`P_2O_5`
ANHYD. `CaCl_2`

ANSWER :C
43.

SO_(2) is a strong reducing agent however it also act as an oxidising agent Which of the following reactions shows its oxidising nature ?

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Bleaching flower petals
Decolourising ACIDIFIED `KMnO_(4)` solution
Reaction with `H_(2)S` to give COLLOIDAL sulphur
Turning acidified dichromate paper green

ANSWER :C
44.

SO_2 is considered as an air pollutant because

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Its concentration increases with temperature increases of atmosphere.
It is USED as an insecticide which is air POLLUTANT
It reacts with `O_2 and H_2O` to produce ACID RAIN
It is a strong oxidant and oxidant oxidizes other components of atmosphere

ANSWER :C
45.

SO_(2) gas was prepared by (i) burning sulphur in oxygen, (ii) reacting sodium sulphite with dilute H_(2)SO_(4) and (iii) case sulphur and oxygen combined in the ratio of 1:1. the data illustrates the law of:

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CONSERVATION of mass
multiple PROPORTIONS
CONSTANT proportions
RECIPROCAL proportions

Answer :C
46.

SO_2 + H_2 S toproduct. The final product is

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`H_(2)O + S`
`H_(2)SO_(4)`
`H_(2)SO_(3)`
`H_(2)S_(2)O_(3)`

Solution :`SO_(2)` ACTS as an oxidizing agent PARTICULARLY when treated with stronger reducing AGENTS. `SO_(2)` oxidizes `H_(2)S` into S.
47.

SO_2 is:

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Acidic
Basic
Amphoteric
Neutral

Answer :A
48.

SO_(2) gas used as a bleaching agent. Its bleaching action is :

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temporary and DUE to its oxidising nature
temporary and due to its REDUCING nature
permanent and due to its oxidising nature
permenent and due to its reducing nature

Answer :B
49.

SO_(2) forms an addition compound sulphuryl chloride with Cl_(2) in presence of

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CHARCOAL
`C Cl_(4)`
`H^(+)//K_(2)Cr_(2O_(7)`
`H^(+)//KMO_(4)`

ANSWER :A
50.

SO_(2) gas can be identified by exposing it to the

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Glass ROD dippend in conc HCl
Filter paper dipped in ACIDIFIED `K_(2)Cr_(2)O_(7)`
Filter paper dipped in lead acetate solution
Glass rod dippend in `NH_(4)OH`

Answer :B