Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Pure benzene freezes at 5.3^(@)C. A solution of 0.223 of phenylacetic acid (C_(6)H_(5)CH_(2)COOH) in 4.4 g of benzene (K_(f) = 5.12 Kg mol^(-1)) freezes at 4.47^(@)C. From this observation, one can conclude that

Answer»

Phenylacetic ACID exists as such in benzene
Phenylacetic acid undergoes partial ionization in benzene
Phenylacetic acid undergoes complete ionization in benzene
Phenylacetic acid dimerizes in BENZEN

Solution :`Delta T_(f)=T_(0)-T_(f)=5.3-4.47=0.83`
molality of solvent `m = (0.223)/(136)xx(1000)/(4.4)=0.373`
(Molecular weight of phenylacetic acid = 136)
`K_(f)=5.12`
`Delta T_(f) =i. K_(f)m`
`i=(Delta T_(f))/(K_(f)m)=(0.83)/(5.12xx0.373)=0.45`
i is NEARLY equal to 0.5 it MEANS phenylacetic acid undergoes dimerization in benzene.
Discussion
2.

Pure benzene freezes at 5.3^(@)C. A solution of 0.223 g of phenylacetic acid (C_(6)H_(5)CH_(2)COOH) in 4.4 g of benzene (K_(f)="5.12 K kg mol"^(-1)) freezes at 4.47^(@)C. From this observation, one can conclude that

Answer»

phenylacetic acid exists as such in benzene
phenylacetic acid UNDERGOES partial ionization in benzene
phenylacetic acid undergoes COMPLETE ionization in benzene
phenylacetic acid dimerizes in benzene

Solution :Observed molecular mass of phenylacetic acid
`=(1000xx5.12xx0.223)/((5.3-4.47)xx4.4)=312.6`
Calculated molecular mass of `C_(6)H_(5)CH_(2)COOH`
`=72+5+12+2+12+32+1=136`
As observed molecular mass is nearly double of the theoretical value, it dimerizes in benzene.
Discussion
3.

Pure aniline is a

Answer»

Colourless SOLID
Brown COLOURED solid
Colourless LIQUID
Brown coloured liquid

ANSWER :D
Discussion
4.

Pure aniline is a :

Answer»

colourlesssolid
brown COLOURED solid
colourless liquid
brown coloured liquid

Answer :C
Discussion
5.

Pure ammonia is placed in a vessel at temperature where its dissociation constant (alpha) is appreciable. At equlibrium

Answer»

`K_(p)` does not CHANGE significantly with pressure
`alpha` does not change with pressure
CONCENTRATION of `NH_(3)` does not change with pressure
Concentration of `H_(2)` is less than that of `N_(2)`

Solution :`K_(p)` is constant and does not change with pressure.
Discussion
6.

Pure and dry Air is passed over soda lime and potash solution and then through a long tube containing red hot copper. The remaining air is passed over heated magnesium ribbon Which of the following are removed when air is passed through soda lime and potash

Answer»

`O_2`
`N_2`
`CO_2`
`CO_2` and WATER vapour

SOLUTION :`2Cu + O_2 to 2CuO`
`3Mg+ N_2 to Mg_3 N_2`
for COMPLETE REMOVAL of `O_2 and N_2` the AIR obtaned after removal of `CO_2 and H_2O` is repeatedly passed over heated Cu and Mg.
`C + O_2 to CO_2`
Discussion
7.

Pure ammonia is placed in a vessel at a temperature where its dissociation appreciable. At equilibrium

Answer»

`K_p` does not CHANGE significantly with pressure
`ALPHA` does not change with pressure
concentration of `NH_3` does not change with pressure
concentration of `H_2` is less than that of `N_2`

ANSWER :A
Discussion
8.

Punderset(2.H_(3)O^(+))overset(1.CH_(3)MgBr)toR underset(2.Delta)overset(1.dil.NaOH)to4-methylpent-3-en-2-one P is

Answer»

PROPANONE
ethanamine
ETHANENITRILE
ethanal

Solution :`underset("Ethanenitrile")(CH_(3)CN) underset(2.H_(3)O^(+))overset(1.CH_(3)MgBr)to underset("Propanone")(CH_(3)-overset(O)overset(||)(C)-CH_(3)) underset(("ALDOL condensation"))overset(1." dil. NaOH")to CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)(C)-CH_(2)COCH_(3) underset(-H_(2)O)overset(Delta)to underset("4-Methylpent-3-en-2-one")(CH_(3)-underset(CH_(3))underset(|)overset(4)(C)=overset(3)(C)H-overset(2)(C)OCH_(3))`
Discussion
9.

Pure (+) 2- chlorobutane gives how many different dichlorbutanes?

Answer»


SOLUTION :
Discussion
10.

Pure alky chloride can be obtaned from alkanol by the eaction of

Answer»

`PCl_(5)`
`PCl_(3)`
`SOCl_(2)`
`HCL`

ANSWER :C
Discussion
11.

Pure acetylene has sweet ethereal smell while impure smells like garlic due to presence of:

Answer»

`NH_3`
`PH_3`
`AsH_3`
`H_2S`

ANSWER :B
Discussion
12.

Pudding process is used in the manufacture of:

Answer»

Steel
Cast-iron
Wrought iron
Pig iron

Answer :C
Discussion
13.

[Pt(Ox)(py)_(2)(O_(2))(H_(2)O)] Select correct statement about this complex :

Answer»

Oxidation state of `O_(2)` is `-1`
EAN of PT is 86
Complex will SHOW GEOMETRICAL as well as OPTICAL isomerism
Both (b) and (C )

ANSWER :D
Discussion
14.

[Pt(NH_(3))(NH_(2)OH)(NO_(2))(py)]^(+) will form how many geometrical isomers ?

Answer»

2
3
4
5

Solution :`[M(ABCD)] to (AC)(BD),(ab)(CD),(AD)(bc)`
Discussion
15.

[Pt("trien")]^(2+) is a ……. Ligand on the basis of its denticity.

Answer»

SOLUTION :tetradentate
Discussion
16.

[Pt(NH_(3))_(4)][PtCl_(4)] is called as ……………..

Answer»

ZEIGLER NATTA Catalyst
Zeises' salt
Magnus's GREEN salt
Mohr's salt

Answer :A::C
Discussion
17.

[Pt(NH_(3))_(2)Cl_(2)]^(2+) shows……………… isomerism.

Answer»


ANSWER :Cis-trans ISOMERISM
Discussion
18.

Pt|H_(2)(1 atm )|H^(+)(0.001M)||H^(+)(0.1M)|H_(2)(1atm)|Pt what will be the value of E_(cell) for this cell

Answer»

0.1182V
`-0.1182V`
0.0591 V
`-0.0591 V`

ANSWER :A
Discussion
19.

Pt(H_(2),"x atm")abs(0.0MH^(+))abs(0.1MH^(+))Pt(H_(2),"y atm"). ifE^(o) "" (cell) = 0.00V,then x/y is :

Answer»

100
10
`0.01`
`0.1`

ANSWER :D
Discussion
20.

Pthalic acid overset(Delta)to underset(x)("product") . No of sp^2 carbons in 'x' are

Answer»


SOLUTION :
Discussion
21.

Pt, O_(2)(1atm.) OH^(-)_((aq)) 2OH_((aq))^(-) hArr H_(2)O_((l))+?+2e^(-)

Answer»

`1//2 O_(2)`
`1//2 O_(2(g))`
`O_(2(g))`
`2O_(2(g))`

Solution :`2OH_((aq))^(-) HARR H_(2)O_((l))+(1)/(2)O_(2(g))+2e^(-)`
Discussion
22.

Pt|Cl_(2)(P_(1)atm)|HCl(0.1M)|Cl_(2)(P_(2)atm)|Pt, cell reaction will be spontaneous if

Answer»

`p_(1)=p_(2)`
`p_(1)gtp_(2)`
`p_(2)gtp_(1)`
`P_(1)=P_(2)=1atm`

Solution :`E_(cell)=E_(cell)^(0)-(0.591)/(2)log_(10)((P_(Cl_(2)_(anode)))/(P_(Cl_(2)(cathode))))=0-(0.0591)/(2)log_(10)((P_(1))/(P_(2)))`
if `P_(1)ltP_(2),E_(cell)=+ve` (SPONTANEOUS)
Discussion
23.

[Pt (NH_(3))(NH_(2)OH) (NO_(2))(Py)]^(+) will form how many geometrical isomers :-

Answer»

2
3
0
5

Answer :B
Discussion
24.

[PtBrCl(NO_(2))(NH_(3))] I on ionisation gives the ion

Answer»

`CL^(-)`<BR>`Br^(-)`
`I^(-) `
`NO_2^(-)`

ANSWER :C
Discussion
25.

Psi_420 represents

Answer»

`4 p_z`
`4d_(z^2)`
4s
`5 P_x`

ANSWER :B
Discussion
26.

Psycotherapeutic drugs are also called

Answer»

antacidis
tranquilizers
antioxidant
analgesic and antipyretic

Answer :B
Discussion
27.

Pseudonitrol is formedfromnitrousacidand what ?

Answer»

`CH_(3) - CH_(2) - CH_(2) - NO_(2)`
`CH_(3) - CH_(2) - NO_(2)`
`CH - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)- NO_(2)`
`CH_(3) - overset(NO_(2))overset(|)(CH) - CH_(3)`

Answer :D
Discussion
28.

Pseudo halides are anions having resemblance with halide ions. Group I metals can form salts with pseudo halides. Pseudo halogens can acts as ligands and form coordinate complexes. Their hydrides are weakly acidic and can be prepared in analogous way as halogen hydrides are prepared. Azides, cyanides, selonocyanides are example of pseuda halides. When sodium pseudo halides are dissolved in water, it resembles with:

Answer»

(A) NACI
(B) NABR
(C) NAF
(D) Nal

Answer :C
Discussion
29.

Pseudo first order rate for the reaction, A+B toProduct, when studied in 0.1M of B is given by -(d[A])/(dt)=k[A], where , k=1.85xx10^(4)sec^(-1), calculate the value of second orderrate constant.

Answer»

Solution :`A+B to `Product
`-(d[A])/(DT)=K[A]`
`-(d[A])/(dt)=1.85xx10^(4)XX[A]`…………………..`(i)`
Assuming the reaction to be of second ORDER
`-(d[A])/(dt)=k.[A][B]`
`-(d[A])/(dt)=k.[A][0.1]` …………..`(ii)`
Dividing Eq. `(i)` by `(ii)`, we get
`1=(1.85xx10^(4))/(k.xx(0.1))`
`:.k.=1.85xx10^(5)Lmol^(-1)s^(-1)`
Discussion
30.

Prussionblue is formedwhen :

Answer»

Ferroussulphatereacts with `FeCI_(3)`
Forric sulphatee REACTSWITH `K_(4)[Fe(CN)_(6)]`
Ferrousammoniumsulphatee REACTS with `FeCI_(3)`
Ammoniumsulphate reacts with `FeCI_(3)`

SOLUTION :`2Fe_(2)(SO_(4))_(3) + 3K_(4)[Fe(CN)_(6)] rarr underset("Prussian blue")(Fe_(4)[Fe(CN)_(6)]_(3))+6K_(2)SO_(4)`
Discussion
31.

Prussian'sblueisformed when Fe^(+2) ions are added to K_(4)[Fe(CN)_(6)]_(2) Turnbull'sblue is

Answer»

`Fe_(4)[Fe(CN)_(6)]_(3)`
`Fe_(3)[Fe(CN)_(6)]_(2)`
`Fe_(2)[Fe(CN)_(6)]`
All

Answer :a
Discussion
32.

Prussian blue is obtained by mixing together aqueous solution of Fe^(3+) salt with

Answer»

Ferricyanide
Ferocyanide
Hydrogen cyanide
Sodium cyanide

Solution :`Fe^(3+)+K_(4)overset("II")("["Fe)(CN)_(6)"]"tounderset("Prussian blue (deep blue COLOUR)")(Koverset(III)(Fe)overset(II)("["Fe)(CN)_(6))"]"+3K^(+)`
Discussion
33.

Prussian blue is a complex with the formula "…...............".

Answer»


ANSWER :`K OVERSET(III)(FE) [ overset(II) (Fe)(CN)_(6)]`
Discussion
34.

Prussian blue is formed when

Answer»

Ferrous sulphate REACTS with `FeCl_(3) `
ferric sulphate reacts with `K_(4)[Fe(CN)_(6)]` 
 forrous ammonium sulphate reacts with `FeCl_(3)`
ammonium sulphate reacts with `FeCl_(3)`

ANSWER :B
Discussion
35.

Prussian blue is

Answer»

`K_(3)[Fe(CN)_(6)]`
`K_(4) [Fe(CN)_(6)]`
`KFE[Fe(CN)_(6)]`
`Fe_(4)[Fe(CN)_(6)]`

Solution :Prussian BLUE in `K overset(III)(Fe)[overset(II) (Fe) (CN)_(6)]`
Discussion
36.

Prussian blue is formed when :

Answer»

`Na_4Fe(CN)_6`
`Na_3Fe(CN)_6`
`Fe_4[Fe(CN)_6]_3`
NONE of these

Answer :C
Discussion
37.

Prussian blue is :

Answer»

`K_3[FE(CN)_6]`
`Fe_4[[Fe(CN)_6]_3`
`K_2Fe[Fe(CN)_6]`
`K_4[Fe(CN)_6]`

ANSWER :B
Discussion
38.

Provided detailed curved arrow mechanisms for the following reactions:

Answer»

Solution :
In the fourth MECHANISM step, the nitrogen atom is protonated in preference to the oxygen atoms because nitrogen electronegative, and THUS more readily WILLING to share its LONE pair.
Discussion
39.

Provided detailed curved arrow mechanisms for the following reactions:

Answer»

SOLUTION :
Fragmentation of the tetrahedral INTERMEDIATE with an amide anion leaving group (in this case RNH) is the obvious RATE determining step, because an amide anion is a POOR leaving group (An amide anion is a poorer leaving group than a hydroxide ion.) One could combine this step with the nitrogen anion protonation to avoid having an amide anion leaving group. This is reasonable, as the solvent is WATER, and the amine will he hydrogen bonded before it departs. However, in this reaction, the amide anion leaving group problem cannot be solved by protenation with `H_(3) O` because `H_(3)O.` is simply not present. The reaction medium is strongly basic, so any strong acid such as hydronium ion will be immediately neutralized.
Discussion
40.

Provided detailed curved arrow mechanisms for the following reactions:

Answer»

SOLUTION :
Discussion
41.

Provided detailed curved arrow mechanisms for the following reactions:

Answer»

Solution :Two reasonable mechanisms can be written for this reaction: a traditional FISCHER esterification or a carbonyl carbon cation capture mechanism. Both are ACCEPTABLE, although the traditional Fischer esterification mechanism is probably the minor pathway as an alcohol is more basic than a carboxylic acid. Fischer esterification mechanism is as follows:

Mechanism involving carbocation capture of carbonyl

The carbocation captures the carbonyl oxygen of the OC-CH, group INSTEAD of the OH oxygen, because it LEADS to the more stable oxonium ion intermediate. The resulting oxonium ion enjoys RESONANCE stabilization, whereas the oxonium ion formed by OH capture does not.
This carbocation-carbonyl capture mechanism for acid-catalyzed esterification of a carboxylic acid can only be a possibility when the carbocation derived from the alcohol is sufficiently stable (secondary or better).
Discussion
42.

Provided detailed curved arrow mechanisms for the following reactions:

Answer»

SOLUTION :
Discussion
43.

Provided detailed curved arrow mechanisms for the following reactions:

Answer»

SOLUTION :
The last TWO stpes of this mechanism show loss of water in an `E_(1)` fashion, An `E_(2)`- type of DEHYDRATION is also ACCEPTABLE. As explaianed below.

Discussion
44.

Provide the structure of the major organic product which results in the following reaction.

Answer»




Solution :`Beta-H` at the BRIDGING CARBON is anti to LEAVING group LOST in `E_(2)` reaction .
Discussion
45.

Provide the organic product(s) of the reaction. Pay careful attention to stereochemistry. If more than one product is formed, indicate which product (if any) is the major product. If no reaction occurs, write "NR"

Answer»

SOLUTION :
Discussion
46.

Provide the organic product(s) of the reaction. Pay careful attention to stereochemistry. If more than one product is formed, indicate which product (if any) is the major product. If no reaction occurs, write "NR"

Answer»

SOLUTION :
Discussion
47.

Provide the organic product(s) of the reaction. Pay careful attention to stereochemistry. If more than one product is formed, indicate which product (if any) is the major product. If no reaction occurs, write "NR"

Answer»

SOLUTION :
Discussion
48.

Provide the organic product(s) of the reaction. Pay careful attention to stereochemistry. If more than one product is formed, indicate which product (if any) is the major product. If no reaction occurs, write "NR"

Answer»

SOLUTION :
Discussion
49.

Provide the organic product(s) of the reaction. Pay careful attention to stereochemistry. If more than one product is formed, indicate which product (if any) is the major product. If no reaction occurs, write "NR"

Answer»

SOLUTION :
Discussion
50.

Provide the organic product(s) of the reaction. Pay careful attention to stereochemistry. If more than one product is formed, indicate which product (if any) is the major product. If no reaction occurs, write "NR"

Answer»

SOLUTION :
Discussion