Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Pick out the odd ones from the following sets:（i) Sulphur, Argon, Solid CO_2, Diamond ,. (ii) SiC, Quartz,BaO,Graphite

Answer»

SOLUTION :(i) Diamond because all others are molecular SOLIDS.
（ii) BaO because all others are COVALENT solids.
Discussion
2.

Pick out the one which does not belong to the family

Answer»

pepsin
cellulose
ptyalin
 LIPASE.

Solution :Among the GIVEN options pepsin, ptyalin and lipase are ENZYMES. HOWEVER, cellulose is polysaccharide.
Discussion
3.

Pick out the odd ones from among the following compounds on the basis of their medicinal properties. (i) Luminal, seconal, phenacetin, equanil (ii) Chloroxylenol, phenol, chloramphenicol, bithional.

Answer»

SOLUTION : (i) PHENACETIN is an ANTIPYRETIC while the remaining THREE are tranquillisers. (ii) Chloramphenicol is an antibiotic while the remaining three are ANTISEPTICS.
Discussion
4.

Pick out the odd one from amongst the following compounds on the basis of their medicinal properties mentioning the reason : luminal, seconal, phenacetin, equanil.

Answer»

SOLUTION :PHENACETIN,-an ANTIPYRETIC while OTHERS are TRANQUILLIZERS.
Discussion
5.

Pick out the odd one amongston the basis of their medicinal properties. Give suitable reason : Sucralose, aspartame, alitame, sodium benzoate.

Answer»

SOLUTION :SODIUM benzoate is a food preservative. Other THREE are artificialsweetners.
Discussion
6.

Pick out the odd one amongston the basis of their medicinal properties. Give suitable reason : Luminal, seconal, terfenadine, equanil.

Answer»

SOLUTION :TERFENADINE is antihistamine other THREE are used as TRANQUILIZERS.
Discussion
7.

Pick out the odd one.

Answer»

`._(92)U^(238)RARR ._(90)Th^(234)+._(2)He^(4)`
`SO_(2)Cl_(2)rarr SO_(2)+Cl_(2)`
`CH_(3)COOCH_(3)+H_(2)O overset(H^(+))rarr CH_(3)COOH+CH_(3)OH`
`C_(12)H_(22)O_(11)+H_(2)O overset(H^(+))rarr C_(6)H_(12)O_(6)+C_(6)H_(12)O_(6)`

Answer :C
Discussion
8.

Pick out the odd one amongston the basis of their medicinal properties. Give suitable reason : Chloroxylenol, phenol, chloamphenicol, bithional.

Answer»

Solution :Chloramphenicol is a BROAD spectrum antibiotic. Other THREE haveantiseptic PROPERTIES.
Discussion
9.

Pick out the odd one among the following:

Answer»

`CH_(3)CHOHCH_(3)`
`CH_(3)CH_(3)-underset(CH_(3))underset(|)CH-OH`
`(CH_(3))_(3)C-OH`
`C_(6)H_(5)CHOHC_(2)H_(5)`

ANSWER :C
Discussion
10.

Pick out the odd from amongst the following on the basis of their medicinal properties mentioning the reason. Chloroxylenol, phenol, chloramphenicol, bithional.

Answer»

SOLUTION :Chloramphenicol-an ANTIBIOTIC while OTHERS are ANTISEPTICS.
Discussion
11.

Pick out the more reactive metal

Answer»

Cu
Ag
Au
Na

Answer :D
Discussion
12.

Pick out the mononuclear carbonyl among the following

Answer»

` [Co_2(CO)_s]`
`[Mn_2(CO)_(10) ]`
`[CR(CO)_6]`
`[MNRE(CO)_(10) ]`

Answer :C
Discussion
13.

Pick out the incorrect staterment.

Answer»

`I_(2)O_(5)` is formed by heating `HIO_(3)", to "170^@C`
`I_(2)O_(5)` is stable to heat
`I_(2)O_(5)` is used in the estimation of CO
`I_(2)` combines with `O_(3)` to form `l_(4)O_(9)` When heated above `75^(@)C", it "(I_4O_5)` decomposes to form lOs

Solution :It decomposes when heated to `300^(@)C`.
`2I_(2)O_(5) overset(300^(@)C)to 2I_(2)+5O_(2)`
(a) `2HIO_(3) overset(170^(@)C)to I_(2)O_(5)+H_(2)O`
(c) `I_(2)O_(5)` oxidizes CO to `CO_(2)` quantitatively at room TEMPERATURE, liberating `I_(2)`, which can be tirated with SODIUM thoiosulphate. `I_(2)O_(5)+5CO to 5CO_(2)+I_(2)`
(d) `2I_(2)+3O_(3)to I_(4)O_(9)`
`4I_(4)O_(9) overset( GT 75^(@)C)to 6I_(2)O_(5)+2I_(2)+3O_(2)`
Discussion
14.

Pick out the incorrect statement regarding anisole.

Answer»

Anisole is not as reactive as phenol
The `-OCH_(3)` group is m-directing
Anisole is USED in perfumery
Nitration of anisole forms TWO SUBSTITUTED isomers.

Answer :B
Discussion
15.

Pick out the incorrect statement with regard to catalyst

Answer»

Presence of catalyst does not change the nature of products
A catalyst ALTERS the state of equilibrium
A catalyst is more effective in the FINELY divided form
all the above

Answer :B
Discussion
16.

Pick out the incorrect statement w.r.t. NH_3

Answer»

It contains a lone pair of ELECTRONS, which can bonds to a proton to form tetrahedra `NH_(4)^(+)` ions
`N_2` is FORMED, when `NH,_3` is passed over heated copper (II) oxide
`NH_3` burns in air to form `N_2` and steam
In Ostwald process for the manufacture of `HNO_3, NH_3,` is oxidized in presence of Pt/Rh catalyst to give `NO and H_2O`

Solution :`NH_3`, SHOWS no reaction towards air. It burns with a pale green flame in oxygen.
`4NH_3+3O_(2) to 2N_(2)+6H_(2)`
a) NH, molecule is trigonal pyramidal is shape with a lone pair of electron in one of the four `sp^3` hybridized orbitals. When it is bonded to `H^+`, it forms tetrahedral `NH_(4^(+))` ions, because all the four sp hybrid orbitals possess four bonded pairs of electrons.
b). `2NH_(3)+3CuO to N_(2)+3H_(2)O+Cu`
d). `4NH_(3)+5O_(2) overset(Pt//Rh)to 4NO+6H_(2)O`
Discussion
17.

Pick out the incorrect statement regarding hydrogen halides.

Answer»

Hydrogen chloride can be prepared by the reaction of NaCl with conc. `H_2SO_4`
Reactions of respective ionic halides, i.e., NaBr and KI with conc. `H_2SO_4` are employed to produce HBr and HI
Hdrogen halides (X=Cl, Br, I) are prepared by action of phosphorus trihalides with water.
A solution of hydrogen chlorides in toluene does affect blue litmus paper.

Solution :Reactions of NaBr and KI with conc. `H_2SO_4` cannot be used to prepare HBr and EI, SINCE these two HYDRIDES are reducing agents and are readily oxidized by conc. `H_2SO_4`
`2HX +H_(2)SO_(4)to SO_(2)+2H_(2)O+X_(2), X=Br,I`
(a) (i) `NaCl+H_(2)SO_(4) to NaHSO_(4)+HCl("in the cold")`
(ii) `NaHSO_(4)+NaCl to NaHSO_(4)+HCl("on heating")`
(c) `PX_(3)+3H_(2)O to H_(2)PO_(3)+3HX`
For example `PCl_(3)+3H_(2)O to H_(3)PO_(3)+3HCl`
`underset(("Red"))(2P)+3Br_(2) to 2PBr_(3)`
`underset(("Red"))(2P)+3I_(2) to 2PI_(3)`
`PBr_(3)+3H_(2)O to H_(3)PO_(3)+3HBr_(2)`
`and PI_(3)+3H_(2)O to H_(3)PO_(3)+3HI`
Discussion
18.

Pick out the incorrect statement regarding ozene

Answer»

`O_3` is an emetable, dark-blue diamagnetic gas
The central owygen im `O_(3)` IE `sp^(2)-` hybridized
It is oxidising agent
It does not react with `BaO_(2)`

Solution :`O_(3)` react with KOH to form potassium ozonide, `KO_(3)`, an orange colored solid containing paramagnetic `O_(3)`,
`BaO_(3) +O_(3) to BaO+2O_(2)`
(a). `O_(3)` is an unstable, because its decomposition is exothermic. The blue colour is due to intenstion absorption of red light. It also absorbs strongly in UV region `(lambda=255mm)`
b. In there are three electron pairs (all bonds pairs) AROUND central O atom. To accommodate three electron pairs in trigonal planar orientation (VSEPR THEORY), the central O atom is `sp^(2)-"hybridized"`.
c. In presence of `O_(3)`, Hg is oxidized to a suboxide. If then, starts sticking to glass and loss mobality. This is TERMED as TAILING of mercury.
Discussion
19.

Pick out the incorrect statement regarding H_2SO_4.

Answer»

When treated with `H_2SO_(4), HCOOH" form "CO and H_2O`
Glucose, when treated with conc. `H_(2)SO_(4)`, forms carbon
Conc. `H_(2)SO_(4)` cannot oxidize HBr and HI to form `Br_(2), and l_(2)`, respectively
Conc. `H_2SO_(4)`, reacts with `NaNO_(3)`

Solution :`2HBr+H_(2)SO_(4) to 2H_(2)O+SO_(2)+Br`
`8HI+H_(2)SO_(4) to 4H_(2)O+H_(2)S+4I_(2)`
Thus, `H_(2)SO_(4)` oxidises both HBr and HI.
(a). `HCOOH underset(-H_(2)O)overset(H_(2)SO_(4))to CO+H_(2)O`
`(b). C_(6)H_(12)O_(6) underset(-6H_(2)O)overset(H_(2)SO_(4))to 6C+6H_(2)O`
`(d) (a) NaNO_(3)+H_(2)SO_(4) overset("Warming")to NaHSO_(4)+HNO_(3)`
Discussion
20.

Pick out the incorrect statement about CO .

Answer»

In laboratory it is prepared by dehydrating HCOOH with conc. `H_2SO_4`
CO is neutral oxide and ACTS as a fuel
It REDUCES aqueous solution of `PdCl_2` to metallic Pd
Co forms COMPLEX with haemoglobin and this complex is less STABLE than oxyhaemoglobin

Answer :D
Discussion
21.

Pick out the incorrect statement for SO_2.

Answer»

It TURNS filter paper moistened with acidified `K_2Cr_2O_7` SOLUTION green
It turns starch IODATE paper blue
It does not react with CHLORINE in presence of charcoal
It decolourieses acidified `KMnO_4` solution

Answer :C
Discussion
22.

Pick out the incorrect statement for CIO_(3)

Answer»

`CIO_(2)` is a powerful oxidizing and chlorinating agent and is prepared in the laboratory from `NaCIO_(3)` and oxalic acid.
`CIO_(2)`, is used to manufacture `NaCIO_(2)` , which is also used for bleaching textiles and paper.
`CIO_(2)` COMBINES with `O_(3)` to FORM dichlorine HEXOXIDE, a dark red liquid.
`ClO_(2)` contains an odd number of ELECTRONS and therefore, it dimerizes like `NO_(2)`

SOLUTION :`CIO_(2)` molecules is paramagnetic and contains an odd number of electrons. Odd electron molecules often dimerize in order to pair the electrons, but `CIO_2` does not dimerize. This is because odd electrons is delocalized. The molecule is angular with O-Cl-O angle of `108^(@)`. The bond of lengths are both 147 pm and are shorter than for single bonds.
`2NaClO_(3)+2(COOH)_(2) overset(H_(2), 90^(@)C)to 2ClO_(2)+2CO_(2)+(COONa)_(2)+2H_(2)O`
`(b) 2ClO_(2)+2NaOH+H_(2)O_(3) to 2NaClO_(2)O_(3)+2H_(2)O`
(c) `2ClO_(3)+2O_(3) to Cl_(2)O_(6)+2O_(3)` .
Discussion
23.

Pick out the incorrect statement for CIF_(3)^(-)

Answer»

It has trigonal planar geometry
It is used to make gaseous `UF_(6)`, which is USEFUL in making enriched U-235 fuel
It is used as powerful fluorinating agent for inorganie COMPOUNDS
`CIF_(3)` has been used as fuel in short RANGE rockets reacting with hydrazine.

Solution :It has T-shaped geomertry.

`(B) 2ClF_(3)+U to UF_(6)+Cl_(2)`
(c) `4CIF_(3)+2Al_(2)O_(3) to 4AlF_(3)+2Cl_(2)+3O_(2)`
`(b) 2CIF_(3)+2NH_(3) to 6HF+Cl_(2)+N_(2)`
(d) `4ClF_(3)+3NH_(2)NH_(2) to 12HF+3N_(2)+2Cl_(2)`
Discussion
24.

Pick out the incorrect statement about glycolysis

Answer»

It is anaerobic respiration
During glycolysis glucose is converted into PYRUVATE or lactate with generation of 38 MOLECULES of ATP per molecule of glucose
Glycolysis provides energy to those cells which live without OXYGEN
It occursin the cytoplasm of the cell

Answer :B
Discussion
25.

Pick out the incorrect statement about ATP.

Answer»

It is a nucleotide
It contains the purine, adenine
The ENZYME - catalysed HYDROLYSIS ATP is ADP and AMP is accompanied by absorption of ENERGY
Energy is STORED in the cell in form of ATP

Answer :C
Discussion
26.

Pick out the incorrect statement:

Answer»

`MnO_(4)^(2-)` is quite strongly oxidizing and stable only in very strong alkalies, In dilute ALKALI, neutral solutions, it disproportionates
In acidic SOLUTION, `MnO_(4)^(-)` is reduced to `Mn^(2+)` and thus, `KMnO_(4)` is widely used as oxidising agent
`KMnO_(4)` does not ACTS as oxidising agent in alkaline medium
`KmnO_(4)` is manufactured by the fusion of pyrolusite ore with `KOH` in presence of air or `KNO_(3)`, followed by electrolytic OXIDATION in alkaline solution

Solution :N//A
Discussion
27.

Pick out the incorrect statement.

Answer»

Orthophosphorus acid can be obtained by reacting `P_O_6" wIth "H_O`
Orthophosphoric acid can be obtained by reacting `P_4O_10" with "H_O`
Pyrophosphoric can be obtained by HEATING orthophosphorus acid
Metaphosphoric acid is obtained by the dehydration of orthophosphoric acid at `316^@C.`

SOLUTION :Pyrophosphoric acid can be obtained by heating orthophosphoric acid.
`O-underset(OH)underset(|)overset(OH)overset(|)(P)-OH+H" "O+underset(OH)underset(|)overset(OH)overset(|)(P)=O to O-underset(OH)underset(|)overset(OH)overset(|)(P)-O-underset(OH)underset(|)overset(OH)overset(|)(P)=O+H_(2)O`
Although pyrophosphoric is tetrabais acid, yet only two sodium salts are known `Na_(2)P_(2)O_(7) and Na_2H_(2)P_(2)O_(7)`.
`P_(4)O_(6)+6H_(2)O to 4H_(3)PO_(3) `
It structure is `O=underset(OH)underset(|)overset(H)overset(|)P-OH`
Therefore, it is diabastic
(b) `P_(4)O_(10)+6H_(2)O to 4 [O=underset(OH)underset(|)overset(OH)overset(|)P-OH]`
This acid is tribasic.
(d) `H_(3)PO_(4) overset(316^(@)C)to HPO_(3)+H_(2)O`
The metaphosphate IONS up FORM `PO_(4)` units and are cyclic. The trimetaphosphate ion `(P_(3)O_(9)^(3-))` is shown below:
Discussion
28.

Pick out the incorrect match of intermolecular attraction between molecule/ion in the following pairs

Answer»

HBr and `H_(2)S`–DIPOLE-dipole attraction
`Cl_(2) and CBr_(4)`–Dispersion force (london force)
`NH_3 and C_(6)H_(6)`–Hydrogen bond
`12 and No_(3) ^(-) `​–Ion-induced dipole attraction

ANSWER :C
Discussion
29.

Pick out the incorrect statement :

Answer»

`MnO_4^(2-)` is quite STRONGLY oxidizing and stable only in very strong alkalies. In DILUTE ALKALI, neutral solutions, it disproportionates.
In acidic solutions, `MnO_4^–` is reduced to `Mn^(2+)` and thus, `KMnO_4` is widely used as oxidising AGENT
`KMnO_4` does not acts as oxidising agent in alkaline medium
`KMnO_4` is MANUFACTURED by the fusion of pyrolusite ore with KOH in presence of air or `KNO_3`, followed by electrolytic oxidation in alkaline solution.

Answer :C
Discussion
30.

Pick out the ideal conditions needed for the manufactor of H_(2)SO_(4) by contact process.

Answer»

Low temperature, high PRESSURE anid high CONCENTRATION of reactants
Low temperature, low concentration of reactants and low pressure
High temperature, high pressure and high concentration of reactants
Low temperature, low pressure and high concentration of reactants.

Answer :A
Discussion
31.

Pick out the ideal condition for H_(2)SO_(4) manufactured by Contact process

Answer»

Low TEMPERATURE, HIGH pressure and high CONCENTRATION of REACTANTS
Low temperature, low pressure and low concentration of reactants
High temperature, high pressure and high concentrationof reactants
Low temperature, low pressure and high concentrationof reactants

ANSWER :A
Discussion
32.

Pick out the false statement.

Answer»

Vapour pressure of a liquids is the MEASURE of the strength of intermolecular ATTRACTIVE forces
Liquid with stronger intermolecular interaction are more viscous than those with WEAKER intermolecular force
Vapour pressure of allliquids is same at their freezing POINTS
Both (a) and (b)

Solution :Vapour pressure of all liquids are different at their freezing points.
Discussion
33.

Pick out the equation in which the products formed is not correct ?

Answer»




Solution :The correct EQUATION (B) is
`CH_3CH_2CH_2overset(CH_3)overset(|)UNDERSET(CH_3)underset(|)(OC) CH_2CH_3+HIto`
`CH_3CH_2CH_2OH+I-overset(CH_3)overset(|)underset(CH_3)underset(|)(C)- CH_2CH_3`
This is because the ether contains a `3^(@)` group and in such a CASE `3^(@)` alkyl iodide is the major PRODUCT along with the `1^(@)` alcohol.
Discussion
34.

Pick out the correct statement(s) of the following.

Answer»

All atoms with an odd atomic number are NECESSARILY paramagnetic
All atoms with an even atomic number are necessarily paramagnetic
All atoms with an even atomic number may be diamagnetic or paramagnetic
Atoms with an odd atomic number may be paramagnetic and in some CASES diamagnetic

SOLUTION :There is no way to create all pairs with odd number of electrons, MANY atoms with even number of electrons can have ONE or more unpaired electrons.
Discussion
35.

Pick out the effect of catalyst on activation energy ?

Answer»

Catalyst lowers the activation energy
Catalyst PROVIDES alternate PATH to the reaction
Both (a) and (b)
None of these

Answer :C
Discussion
36.

Pick out the correct statements from the following. (I) Cobalt (III) is more stable in octahedral complexes. (II) Zinc froms coloured ion or complexes. (III) Most of the d-block elements and their compounds are ferromagnetic. (IV) Osmium show (VIII) oxidation sate.

Answer»

I and II
I and III
II andIV
I and IV

Solution :(I) `Co^(3+)` have higher charge density than `Co^(2+), So Co^(3+)` is more stable in octahedral COMPLEXES.
(II) Zn exhibits only `+2` oxidation STATE.So, `Zn^(2+)=[Ar]3d^(10),4s^(0)`
Since, iy does not contain any unpaired electron, its compounds are colourless.
(III) d-block elements are generally paramagnetic and sometime DIAMAGNETIC , but not ferromagnetic.
(IV) OSMIUM and ruthenium are VIII group elements, so can exibit the highest oxidation state`+8` in their oxides,
HENCE, statements I and IV are correct.
Discussion
37.

Pick out the correct statements from the following : 1. Cobalt (III) is more stable in octahedralcomplexes. 2. Zinc forms coloured ions or complexes. 3.Most of the d-block elements and their compounds are ferromagnetic . 4. Osmium shows (VIII)oxidation state. 5.Cobalt (II) is more stablein otahedral complexes.

Answer»

1 and2
1 and 3
2 and 4
1 and 4

Solution :Cobalt (III) is MUCH stable in OCTAHEDRAL compelxesand ALSO osmium shows (VIII) OXIDATION state.
Discussion
38.

Pick out the correct statements from the following 1. Cobalt (III) is more stable in octahedral complexes 2. Zinc forms coloured complexes 3. Most of the d-block elements and their compounds are ferromagnetic 4. Osmium show (VIII) oxidation state 5. Cobalt (II) is more stable in octahedral complexes

Answer»

1 and 2
1 and 3
2 and 4
1 and 4

Solution :Co(III) is more stable in OCTAHEDRAL complexes and Osmium SHOWS (VIII) oxidation STATE.
Discussion
39.

Pick out the correct statements among the following from inspection of standard reduction potentials (Assume standard state conditions). Cl_2(aq.)+2e

Answer»

`Cl_2` can oxidise `SO_4^(2-)` from SOLUTION<BR>`Cl_2` can oxidise `Br^-` and `I^-` from aqueous solution
`S_2O_8^(2-)` can oxidise `Cl^-,Br^-` and `I^-` from aqueous solution
`S_2O_8^(2-)` is added slowly, `Br^-` canbe REDUCE in presence of `Cl^-`

ANSWER :B::C
Discussion
40.

Pick out the correct statement(s):

Answer»

`MnO_(2)` dissolves in conc.HCl but does not form `Mn^(4+)` ions
Decomposition of acidic `KMnO_(4)` is not catalyst by sunlight
`MnO_(4)^(2-)` is stongly oxidising and stable only in very strong alkali. In DILUTE alkali, WATER or acidic solutions it DISPROPORTIONATES
`KMnO_(4)` does not act as oxidising agent in alkaline medium

Solution :(a)`MnO_(2)+4HCl to MnCl_(2)+Cl_(2)+2H_(2)O`
(b)Decomposition of acidic `KMnO_(4)` is catalyst by sunlight
`MnO_(4)^(-)+4H^(+) to 4MnO_(4)+2H_(2)O+3O_(2)`
(c)`underset("green")(3K_(2)MnO_(4))+2H_(2)O to underset("purple")(2KMnO_(4)^(-)+underset("dark brown")(MnO_(2))(darr)+4KOH`
(d) `KMnO_(4)` also acts as an OXIDIZING agent in alkaline medium.
`MnO_(4)^(-)+2H_(2)O +3E^(-) to MnO_(2)+4OH^(-), E^(@)=+1.23` volt
Discussion
41.

Pick out the correct Statements

Answer»

ACTIVATED complexis an unstable intermediate with MAXIMUM energy and normal bonds
Activated compled is an unstable intermediate with maximum energy and fractional bond orders
Transition state cannot exist independently, it has greater vibrational character than unstable intermediate
Transition state ISA state in which bonds are half broken and half formed

Solution :Activated complex has more P,.E. and less STALE than REACTANTS and products.
Discussion
42.

Pick out the correct statement(s)

Answer»

`MnO_(2)` dissolves in conc. `HCl`, but does not form `Mn^(4+)` ions
Decomposition of acidic `KMnO_(4)` is not CATALYSED by sunlight
`MnO_(4)^(2-)` is strongly oxidising and stable only in very strong alkalu. In dilute alkali, water or acidic solution it disproportionates
`KMnO_(4)` does not act as oxidising agent in alkaline medium

Solution :(a) `MnO_(2)+4HCl rarr MnCl_(2)+cl_(2)+2H_(2)O`
(b) Decomposition of acidic `KMnO_(4)` is catalysed by sunlight.
`4MnO_(4)^(-)+4H^(+)rarr 4MnO_(2)+2H_(2)O+3O_(2)`
(c) `underset("green")(3K_(2)MnO_(4))+2H_(2)Orarrunderset("purple")(2KMnO_(4)^(-))+underset("dark brown")(MnO_(2)DARR)+4KOH`
(d) `KMnO_(4)` also acts as an oxidizing agent in alkaline medium.
`MnO_(4)^(-)+2H_(2)O+3e^(-)rarrMnO_(2)+4OH^(-),E^(@)=+1.23" volt"`
Discussion
43.

Pick out the correct statement with respect to [Mn(CN)_6]^(3-)

Answer»

It is `dsp^2` hybridised and SQUARE planar
It is `sp^3d^2` hybridised and octahedral
It is `sp^3d^2` hybridised and tetrahedral
It is `d^2sp^3` hybridised and Octahedral

Answer :D
Discussion
44.

Pick out the correct statement with respect to [Mn(CN)_(6)]^(3-)

Answer»

It is `sp^(3)d^(2)`-hybridized and OCTAHEDRAL
It is `sp^(3)d^(2)`-hybridized and TETRAHEDRAL
It is `d^(2)sp^(3)`-hybridized and octahedral
Itis `dsp^(2)`-hybridized and square planar

Solution :In `[Mn(CN)_(6)]^(3-), Mn^(3+)=3d^(4)`

In presence of strong field LIGAND, `CN^(-)`,
`[Mn(CN)_(6)]^(3-)` =
ltbgt Thus, the COMPLEX is `d^(2)sp^(3)` hybridized having octahedral shape.
Discussion
45.

Pick out the correct statement with respect of lyophillic sol

Answer»

They are less stable
They will not be PRECIPITATED easily
There is no definite attractive FORCE existing between the DISPERSION medium and dispersed phase
They are called IRREVERSIBLE sols.

Answer :B
Discussion
46.

Pick out the correct statement set for transition metals 1. They form interstitial compounds 2. 5d- elements have higher energies than 3d 4d - elements

Answer»

1, 2
2, 3
1, 2, 3
1, 2, 3, 4

Answer :C
Discussion
47.

Pickout the correct statement (s):

Answer»

Goldenyellow `PbI_(2)` DISSOLVES in hot water to give is COLOURLESS solution
`Ba^(2+) and Ca^(2+)` ions can be sepuratedby adding `SO_(4)^(2-)` ion in acetic ACID MEDIUM
Salt of calcium copper and nickel give a green flame colour
The SULPHIDE ion gives with alkline sodium nitroprtasside ,a violet colour

Answer :a,b,d
Discussion
48.

Pick out the correct statement from the following and choose the correct answer from the codes given below (1) Hex-1,5-diene is a conjugated dience (2) Prop-1,2-diene is a conjugated dience (3)Hexa-1,3-diene is a conjugated dience (4) Buta-1,3, diene is an isolated dience (5) Prop-1,2-diene is a cummulative diene

Answer»

1,2
2,3
4,5
3,5

Solution :N/A
Discussion
49.

Pick out the correct statement regarding resistance of an electrolytic solution

Answer»

It is inversely PROPORTIONAL to the length (L)
It is inversely proportional to the cross sectional area (A)
It is DIRECTLY proportional to the cross sectional area (A)
Resistivity is denoted by `rho` (rho)

ANSWER :B
Discussion
50.

Pick out the correct statement.

Answer»

Both glycine and p - aminobenzoic ACID form DIPOLAR IONS
Both sulphanilic acid and p - aminobenzoic and form dipolar ions
Glycine does not form dipolar ion, but p - aminobenzoic acid FORMS dipolar ion
Both sulphanilic acid and glycine form dipolar ions, but p - aminobenzoic acid does not form dipolar ion

Answer :D
Discussion