Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Pick out the correct set of statements for Hl. 1. It reduces iodic acid to I_(2) 2. It reduces H_(2)SO_(4) to SO_(2) 3. It decolourises acidified KMnO_(4) 4. It liberates I_(2) withCuSO_(4) solution

Answer»

1, 2, 3
1, 2, 4
1, 3, 4
1, 2, 3, 4

Answer :D
Discussion
2.

Pick out the correct statement 1. The C-Cl bond in Chlorobenzene is shorter than methyl chloride. 2. The C-Cl bond in chlorobenzene has some double bond character 3. The C-Cl bond in chlorobenzene has some double bond character

Answer»

only 1, 2
only 1,3
only 1, 2, 3
only 1

Answer :C
Discussion
3.

Pick out the compound/s that gives effervescence with aqueous NaHCO_(3) I. C_(6)H_(5)OH""II.C_(6)H_(5)NH_(2) III. (CH_(3)CO)_(2)O""IV.CH_(3)COOH

Answer»

I and II
I and IV
III and IV
III and I

Answer :C
Discussion
4.

Pick out the complex compound in which the central metal atom obeys EAN rule strictly?

Answer»

`K_(4)[Fe(CN)_(6)]`
`K_(3)[Fe(CN)_(6)]`
`CR(H_(2)O)_(6)]Cl_(3)`
`[Cu(NH_(3))_(4)]SO_(4)`

Solution :In `K_(4)[Fe(CN)_(6)]`
EAN of `Fe=26-2+6xx2=36`. The above complex strictly obeys EAN RULE.
Discussion
5.

Pick out the alloy that contains a non-metal as constituent in it

Answer»

Brass
Bronze
Steel
Invar

Answer :C
Discussion
6.

Pick out the combination which show positive deviations from Raoult.s law:

Answer»

`C_2H_5OH + C Cl_4`
`H_2O + CH_2CH_2CH_2OH`
`C_2H_5OH + CHCl_3`
All are correct

Answer :D
Discussion
7.

Pick out the alkane which differs from the other members of the group.

Answer»

2,2-dimethyl propane
pentane
 2-methyl BUTANE
2,2-dimethyl butane.

Solution :
Discussion
8.

Pick out incorrect statemment about K_(2) Cr_(2)O_(7).

Answer»

It oxidazes KI to `I_(2)`
It oxidizes Ki to `I_(2)`
It oxidizes `SO_(2)` to ` K)_(2)SO_(4)`
It oxidizes `SO_(2)` to S

SOLUTION :It oxidises `SO_(2)` to `K_(2)SO_(4)`
Discussion
9.

Pick out incorrect statement with respect to methyl nitrite

Answer»

They are ALSO CALLED PSEUDO acid
High electrical conductivity
Decolourises `FeCl_3` solution
Dissolves in `NaOH` instantly

Answer :C
Discussion
10.

Pick out incorrect statement for H_2SO_3

Answer»

But-1-ene when HYDRATED in presence of conc. `H_2SO_4`, form butan-2-ol
Carbon or sulphur are oxidized by conc. `H_2SO_4` to their respective dioxides.
Cu is oxidized by conc. `H_2SO_4` to form only `H_2S`
Zn REDUCED conc. `H_2SO_4` to form `SO_2, and ZNSO_4`

Solution :`SO_2` is main reduction product with less electropositive metal having HIGH electrode potential.
`Cu+2H_(2)SO_(4) to CuSO_(4)+2H_(2)O+2SO_(2)`
(a). `CH_(3)-CH_(2)-CH=CH_(2)+H_(2)SO_(4) to CH_(3)-CH_(2) underset(OSO_(3)H)underset(|)(CH)-CH_(3) overset(H_(2)O)to CH_(3)-CH_(2)-underset(OH)underset(|)(CH)-CH_(3)+H_(2)SO_(4)`
(b). `C+underset(("Conc.""))(2H_(2)SO_(4))to 2H_(2)O+CO_(2)+2SO_(2)`
`(b) S+2H_(2)SO_(4) to 2H_(2)O+3SO_(2)`
`(d) underset(("98% )acid")) (Zn+H_(2)SO_(4)) to ZnSO_(4)+2H_(2)O+SO_(4)`
Discussion
11.

Pick out incorrect statement regarding ethers

Answer»

Ethers have HIGHER boiling points than alkanes of COMPANIES mass.
Ethers are miscible with water.
DIETHYL ether is used as refrigarant
ANISOLE is used as surgical anesthetic agent.

ANSWER :D
Discussion
12.

Pick out incorrect statement

Answer»

Colloidal sols are heterogeneous
Colloids carry + ve or - ve CHARGE
Colloidal sols show Tyndall effect
The SIZE RANGE of colloidal particles `10 - 2000Å`

ANSWER :D
Discussion
13.

Pick out incorrect statement.

Answer»

`NF_3` molecules has trigonal pyramidal structure
It is practically insoluble in water and is only HYDROLYZED, when an ELECTRIC spark is through a MIXTURE with water vapour
Dipole moment of `NF_3` is more than that of `NH_3`
Nitrogen (II) oxide `(N_2O_3)` is an acidic oxide. passed

Solution :Dipole moment of `NH_(3)(0.49 xx 10^(-29)c.m.)` is more than that of `NF_3 (0.07 xx 10^(-29)Cm)`. This is due to the fact that the directions of the dipole moments of the bonding N-H and non-bonding electron pairs COINCIDE in `NH_3` and, therefore, vector eddition of all dipole moments yield a large resultant dipole moment. In `NF_3` on the contrary, the dipole moments of N-F bonds and of the non- bonding electron pair are in opposite directions, No that they are partially compensated when Hummated.
a) From the above figure, it is clear that `NF_(3)`, has a trigonal pyramidal structure.
B). `N_(2)O_(3)(l)+H_(2)O(l) to underset("Acid")(2HNO_(2)(l))`
Discussion
14.

Pick out an incorrect statement from the following:

Answer»

Benzene cannot be iodinated with `l_(2)` directly
The product of the reaction between benzene and `(CH_(3)CH_(2)CH_(2)CO)_(2)O`in PRESENCE of anhydrous `aici_(3)` is `PhCOCH_(2)CH_(2)CH_(3)`
The electrophile formed with `HNO_(3)` & `H_(2)SO_(4)` IS `SO_(3)`
Iodination of Arene may occur with ICI also

Answer :C
Discussion
15.

Pick a poor electrolytic conductor complex in solution:

Answer»

`K_2[PtCI_6]`
`[CO(NH_3)_3](NO_2)_3`]
`K_4[FE(CN)_6]`
`[Co(NH_3)_4]SO_4`

ANSWER :D
Discussion
16.

Pich out the statement which is not relevant in the discussion of colloids

Answer»

SODIUM aluminium silicate is used in the softening of hard water
potash alum is used in shaving ROUNDS and as a styptic in medicine
artificial rain is caused by THROWING electrificied sand on the clouds from an aeroplane
deltas are FORMED at a place where the river pours its water into the sea.

Solution :Sodium aluminium silicate is used in the softening of hard water.
Discussion
17.

pi-bonding is not involved in :

Answer»

FERROCENE
Dibenzenechromium
Zeise's SALT
GRIGNARD's reagent

Solution :R-MgX has M-C `DELTA`-BOND.
Discussion
18.

Phytol is

Answer»

oils
fats
terpenes
glycolipids

Answer :C
Discussion
19.

Physisorption is reversible while chemisorption is irreversible. Why?

Answer»

Solution : Physisorption INVOLVES weak forces between the ADSORBENT and the adsorbate while chemisorption involves the FORMATION of a chemical bond between the adsorbent and adsorbate. Once a chemical bond is formed, it is difficult to break. Therefore physisorption is REVERSIBLE but chemisorption is irreversible
Discussion
20.

Physisorption and chemisorption are two types of adsorption. What is the effect of temperature on physisorption and chemisorption?

Answer»


ANSWER :When TEMPERATURE INCREASES physorption DECREASES. But CHEMISORPTION increases with increases in temperature.
Discussion
21.

Physical properties of :

Answer»

ALCOHOLS LIE between ALKANES and `H_2O`
`H_2O` lie between alcohols and alkanes
Alkanes lie between alcohols and `H_2O`
None

Answer :A
Discussion
22.

Physical and chemical adsorption respond differently to rise in temperature ? What is this difference and why is it so ?

Answer»
Discussion
23.

Physical adsorption of a gasous species may change to chemical adsorption with ___.

Answer»

DECREASE in temperature
increase in temperature
increase in SURFACE AREA of adsorbent
decrease in surface area of adsorbent

Answer :B
Discussion
24.

Physical adsorption of a gaseous species may change to chemical adsorption with

Answer»

DECREASE in temperature
increase in temperature
increase in surface area of adsorbent
decrease in surface area of adsorbent

Solution :At HIGHER temperature, gaseous MOLECULES may DISSOCIATE into atoms which are then chemisorbed, e.g., `N_2` GAS on iron surface at temperature above 773 K.
Discussion
25.

Physical adsorption of a gaseous species may change to chemical adsorption with ________ .

Answer»

decrease in temperature
increase in temperature
increase in surface AREA of adsorbent
decrease in surface area of adsorbent

Solution :At HIGHER temperature, gaseous molecules may dissociate into atoms which are then chemisorbed, e.g., `N_2` GAS on IRON surface at temperature above 773 K.
Discussion
26.

Physical adsorption of a gaseous species may change to chemical adsorption with .......

Answer»

decrease in temperature 
increase in temperature 
increase in surface area of adsorbent 
decrease in surface area of adsorbent 

SOLUTION :At a HIGHER temperature, the PHYSICAL ADSORPTION of the gases may change to CHEMICAL adsorption.
Discussion
27.

Physical adsorption of a gaseous species may change to chemical adsorption with…………

Answer»

DECREASE in temperature
increase in temperature
increase in surface area of ADSORBENT
decrease in surface area of adsorbent .

Solution :At high temperature, gaseous species MAY DISSOCIATE into atoms which are chemisorbed, e.g., `N_(2)` on iron surface at `ge 773K.`
Discussion
28.

Physical adsorption is inversly proportional to ....

Answer»

volume
concentration
TEMPERATURE
all of these

Solution :temperature
Discussion
29.

Physical adsorption of a gaseous speciesmay change to chemical adsorption with ……. .

Answer»

decrease in TEMPERATURE
INCREASE in temperature
increase in SURFACE area of adsorbent
decrease in surface area of adsorbent

SOLUTION :On increasing temperature PHYSISORPTION changes to chemisorption. As temperature increase , energy of activation of adsorbate particles increases which lead to Hence , physisorption transform into chemisorption.
Discussion
30.

Physical adsorption of a gaseous species may change to chemical adsorption with ____________

Answer»

decrease in temperature
INCREASE in temperature
increase in SURFACE AREA of ADSORBENT
decrease in surface area of adsorbent

Solution : increase in temperature
Discussion
31.

Physical adsorption is appreciable at

Answer»

Higher TEMPERATURE
Lower temperature
At ROOM temperature
`100^@C`

ANSWER :B
Discussion
32.

Physical adsorption is considerable at

Answer»

LOW TEMPERATURE
room temperature
high temperature
none of these

Solution : low temperature
Discussion
33.

Physical adsorption is:

Answer»

HIGHLY SPECIFIC
IRREVERSIBLE
CONSIDERABLE at HIGH temperature
Not very specific.

Answer :D
Discussion
34.

Physical adsorption is....

Answer»

INSTANTANEOUS and REVERSIBLE.
instantaneous and IRREVERSIBLE.
SPECIFIC and reversible.
non specific and irreversible. 

SOLUTION :instantaneous and reversible.
Discussion
35.

Physical adsorption is :

Answer»

HIGHLY specific
Reversible
Irreversible
Monolayer adsorption

Answer :B
Discussion
36.

Physical adsorption increases when :

Answer»

TEMPERATURE increases
Temperature decreases
Temperature REMAINS constant
None

Answer :B
Discussion
37.

Phthalic acid +NH_(3)toDoverset(Delta)toE

Answer»


SOLUTION :
Discussion
38.

Physical adsorption become appreciable at :

Answer»

HIGH temperature
Room temperature
Low temperature
None

Answer :C
Discussion
39.

Phthalic acid reacts with resorcinol in the presence of concentrated H_(2)SO_(4) to give:

Answer»

Phenolphthalein
Alizarin
Coumarin
Fluorescein

Solution :
Discussion
40.

Physical adsorption:

Answer»

Is reversible
Decreases with temperature
Is exothermic
All

Answer :D
Discussion
41.

Photosysthesis si a bio process by which plants make energy rich molecules from low energy molecules with the help of energy from sunlight . The photosysthesis of glucose can be represented as: 6CO_(2(g))+ 6H_(2)O_(g) + hv rarr C_(5)H_(12)O_(6(s)) + 6O_(2)(g)..........(i) The energy of one mole of a photon of wave lenght is known as one Einstein. A weight lifter lifts a weight of 160Kg through of 2.4 m . Assuming all the energy required for this task is obtained by the combustion of glucose , calculate the change in the current produced by a sample of blood of the weight lifter . Same volume of blood (5mL) is tested both before and after lifting the weight and the total volume of blood in his body is 5L. (1 g of glucose releases 15.58 KJ of energy )

Answer»


SOLUTION :N//A
Discussion
42.

Phthaldehyde has

Answer»

no CARBOXYLIC group
one carboxylic group.
two carboxylic groups
three carboxylic groups.

Answer :C
Discussion
43.

Photosynthesis in plants is brought about by chlorophyll. It involves :

Answer»

CONVERSION of CHEMICAL energy into radiant energy
Conversion of chemical energy into mechanical energy
Conversion of solar energy into chemical energy
Conversion of mechanical energy into solar energy

Answer :C
Discussion
44.

Photon having energy equivalent to the binding energy of 4th state of He^(+) atom is used to eject an electron from the metal surface of work function 1.4 eV. If electrons are further accelerated through the potential difference of 4V then the minimum value of De-brogile wavelength associated with the electron is:

Answer»


Solution :In the particular EXCITED state of H-atom, path length is five times the de-Broglie wavelength.
`:. 2pir=5lambda …(1)`
However, path length in a sate `n` is `n` times the de-Broglie wavelength.
`:. 2pir=nlambda …(2)`
From (1) & (2), principal quantum number (n) of the excited state `=5`. PHOTON having `2^(nd)` highest energy corresponds to back transition of electron from `n=4` to `n=1`
This photon will cause an already excited `Li^(2+)` electron to go some higher state. Let the initial excited state of `Li^(2+)` ION be `n_(1)` and final excited state of `Li^(2+)` ion be `n_(2)`
`:. (13.6(1)^(2)[1/1^(2)-1/4^(2)])/(("Photon having" 2^(nd) "highest energy"),("corresponding to transition n=4 to n=1 in H-atom"))=(13.6(3)^(2)[1/n_(1)^(2)-1/n_(2)^(2)])/(("Energy ABSORBED by" Li^(+) "ion to make"),("a transition from" n_(1) "to" n_(2)))`
`:. 13.6[1/1^(2)-1/4^(2)]=13.6[3^(2)/n_(1)^(2)-3^(2)/n_(2)^(2)]` or `13.6[1/1^(2)-1/4^(2)]=13.6[1/((n_(1)//3)^(2))-1/((n_(2)//3)^(2))]`
On cmparing both sides,
`n_(1)/3=1` & `n_(2)/3=4rArr n_(1)=3` & `n_(2)=12`
Thus, the final excited state of `Li^(2+)` ion electron is `n=12` Ans.
Discussion
45.

Photographic plates and films are prepared by coating an emulsion of light sensitive substance

Answer»

POTASSIUM BROMIDE.
SILVER fluoride.
silver chloride.
silver bromide.

Solution :silver bromide.
Discussion
46.

Photographic plates and films have an essential ingredient of

Answer»

silver nitrate
silver BROMIDE
sodium chloride
oleic acid

Solution :The PHOTOGRAPHIC plate of film consists of a glass plate or THIN STRIP of celluloid which is coated with the thin layer of an emulsion of silver bromide DISPERSED in getalin.
Discussion
47.

Photographic paper is developed with alkaline hydroquinone. selectthe correctstatements

Answer»

Hydroquinone is the OXIDANT.
`Ag^+` is the oxidant.
Br is the oxidant.
`Ag^(+)` is the reductant.

Solution :`Ag^+`isreduced HENCE, it isanoxidantHydroquinoneis oxidisedhence, it ISA reductant
Discussion
48.

Photographic films or plates have …… as an essential ingredient.

Answer»

SILVER Oxide
Silver Bromide
Silver Thiosulphate
Silver Nitrate

Answer :B
Discussion
49.

Photographic films or plates have ……… as an essential ingredient:

Answer»

SILVER bromide
Silver oxide
Silver thiosulphate
Silver nitrate

Answer :A
Discussion
50.

Photoelectrons are liberated by ultra violet light of wavelength 3000Å from a metallic surface for which the photoelectric threshold, is 4000Å. Calculate de Broglie wavelength of electrons emitted with maximum kinetic energy.

Answer»


ANSWER :`1.2xx10^(-5)m`
Discussion