Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Oxygen can be obtained from bleaching powder by:

Answer»

ADDING DILUTE acid
Passing CARBON dioxide
Heating with a COBALT salt
Adding alkalies

Answer :C
2.

Oxygen can be absorbed by :

Answer»

Sodium hydroxide
`CuSO_(4)(AQ)`
PYROGALLOL
`C_(3)H_(5)OH.`

Answer :A
3.

Oxygen can obtained by heating:

Answer»

`Na_2O`
`Fe_2O_3`
`Fe_3O_4`
`BaO_2`

ANSWER :D
4.

Oxygen balance in the atmosphere maintained through the process of:

Answer»

Photosynthesis
Protein SYNTHESIS
Amino ACID synthesis
FAT synthesis

Answer :A
5.

Oxygen atom of ether is _________

Answer»

very active
replacable
OXIDISING
COMPARATIVELY INERT

ANSWER :D
6.

Oxygen atom in ether is

Answer»

very ACTIVE
replacable
COMPARATIVELY INERT
LESS active

SOLUTION :comparatively inert
7.

Oxygen and sulphur have difference in their melting point and boiling points. Give reason.

Answer»

Solution :DUE to their atomaticity - oxygen exists as diatomic molecule `(O_(2))` where as sulphur exists as polyatomic molecules `(S_(8))`.
8.

Oxygen and Sulphur have same

Answer»

OUTER electronic configuration
ATOMIC size
electronic configuration
electron affinity

ANSWER :A
9.

Oxygen and sulphur both are the members of the same group in periodic table but H_(2)O is liquid while H_(2)S is gas because

Answer»

molecular WEIGHT of water is more.
electronegativity of sulphur is more.
`H_(2)S` is weak acid.
water molecules are having weak hydrogen bonds between them.

Solution :`H_(2)O` is LIQUID but `H_(2)` is a gas. This can be attributed to the PRESENCE of INTERMOLECULAR hydrogen BONDING in case of `H_(2)O`.
10.

Oxygen differs from sulphur in:

Answer»

EXIST in DIATOMIC state
Have ATOMS of same size
Form covalent hydrides
Form covalent COMPOUNDS with metals

Answer :C
11.

Oxygen and Ozone are____of each other.

Answer»

Isomers
ALLOTROPES
Isotopes
Isobars

Solution :allotropes
12.

Oxygen and hydrogen gases are produced at the anode and cathode during the electrolysis of fairly concentrate aqueous solution of :

Answer»

`K_2SO_4`
`AgNO_3`
`H_2SO_4`
`NAOH`

SOLUTION :Anode : `2H_2O to O_2 +4e^(-) + 4H^(+)` , Cathode :`2H_2O + 2e^(-) to H_2 + 2OH^(-)`
Anode : `4OH^(-) to 2H_2O + O_2 + 2e^(-)` , Cathode : ` 2H^(+) + 2e^(-) to H_2`
13.

Oxygen and hydrogen are at same temperature . The kinetic energy of oxygen molecules will be

Answer»

16 times
4 times
equal to k.E of HYDROGEN
`1//4`the of the K.E. of hydrogen molecules

Answer :C
14.

Oxyacid of chlorine with + 5 state of the central atom is

Answer»

HYPOCHLOROUS acid
chlorous acid
chloric acid
Perchloric Acid

Answer :C
15.

Oxyacid of phosphorus that can reduce AGNO_3 to silver is

Answer»

`H_3PO_(4)`
`H_4P_2O_7`
`H_3PO_3`
`HPO_3`

Solution :`H_(3)PO_(3)+2AgNO_(3)+H_2O to H_(3)PO_(4)+underset(2 AG )(2HNO_(3^(+)))`
16.

OXY-haemoglobin contains:

Answer»

LESS OXYGEN than haemoglobin
More oxygen than haemoglobin
Contains more CARBON dioxide
Contains less carbon dioxide

Answer :B
17.

"Oxoanion" + H_(2)Orarr "oxoacid"+OH^(-) Oxoanion is converted into oxoacid by abstraction of proton from water which is initiated by H-bond formation. The increasing strength of H-bond of the given oxoanion is :

Answer»

`ClO_(4)^(-)ltSO_(4)^(2-)ltPO_(4)^(3-)ltSiO_(4)^(4-)`
`SO_(4)^(2-)ltSO_(4)^(2-)ltPO_(4)^(3-)ltSiO_(4)^(4-)`
`ClO_(4)^(-)ltSO_(4)^(2-)ltSiO_(4)^(4-)ltPO_(4)^(4-)`
`ClO_(4)^(-)ltPO_(4)^(3-)ltSO_(4)^(2-)ltSiO_(4)^(4-)`

Solution :Tendency of `pi`-bond formation is maximum in `ClO_(4)^(-)`, hence, `SiO_(4)^(4-)` will more easily form STRONG H-bond.
18.

Oxo process:

Answer»

is simply carbonylation or hydroformylation reaction
use COBALT CARBONYL hydride `[COH(CO)_(4)]`
both statements are correct
both statements are INCORRECT

19.

Oximes are formed by the action of aldehydes and ketones with:

Answer»

`NH_3`
`NH_2OH`
`NH_2-NH_2`
`NH_2CONHNH_2`

ANSWER :B
20.

Oxidizing and reducing property of elements depends upon

Answer»

IONISATION potential
oxidation potential
electron affinity
all of these

Solution :All these PROPERTIES are related with electron GAIN or LOSS.
21.

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below : (1)/(2)Cl_(2)(g)overset((1)/(2)Delta_(diss)H^(Theta))rarrCl(g)overset(Delta_(eg)H^(Theta))rarrCl^(-)(g)overset(Delta_(hyd)H^(Theta))rarrCl^(-)(aq)The energy involved in the conversion of(1)/(2)Cl_(2)(g) " to " Cl^(-)(aq)(Using the data,Delta_(diss)H_(Cl_(2))^(Theta)=240 kJ mol^(-1),Delta_(eg)H_(Cl)^(Theta)=-349 kJ mol^(-1),Delta_(hyd)H_(Cl)^(Theta)=-381 kJ mol^(-1)) will be

Answer»

`-610 kJ mol^(-1)`
`-850 kJ mol^(-1)`
`+120 kJ mol^(-1)`
`+152 kJ mol^(-1)`

Solution :`DeltaH=(240)/(2)-349-381`
`=120-349-381=-610kJ//mol`.
22.

Oxidising product of substance Na_(3)AsO_(3) would be

Answer»

`As_(2)O_(3)^(3-)`
`AsO_(3)^(-3)`
`AsO_(2)^(-4)`
`AsO_(4)^(-3)`

ANSWER :D
23.

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below : 1/2Cl_(2)(g) overset(1/2 Delta_("diss")H^(Θ))(rarr)Cl(g) overset(Delta_(eg)H^(Θ))(rarr)Cl^(-)(g) overset(Delta_("hyd")H^(Θ))(rarr)Cl^(-)(aq) The energy involved in the conversion of 1/2 Cl_(2)(g) to Cl^(-)(aq) (using the data, Delta_("diss")H_(Cl_(2))^(Θ)=240" kJ mol"^(-1), Delta_("eg") H_(Cl)^(Θ)=-349" kJ mol"^(-1), Delta_("hyd")H_(Cl^(-))^(Θ)=-381" kJ mol"^(-1)) will be -

Answer»

`-610" kJ MOL"^(-1)`
`-850" kJ mol"^(-1)`
`+ 120" kJ mol"^(-1)`
`+ 152" kJ mol"^(-1)`

SOLUTION :`DeltaH_(1/2 Cl_(2) rarr CL^(-))=1/2 DeltaH_("Diss")^(Θ)+Delta_(Eg)H^()+Delta_("hyd")H^(Θ)=1/2 xx240+(-349)+(-381) =-610" kJ/mol"`
24.

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below :1/2Cl_(2(g))overset(1/2Delta_(diss)H^(odot))(rarr) Cl_(g)overset(Delta_(cg)H^(odot))(rarr)Cl_((g))^(-) overset(Delta_(hyd)H^(odot))(rarr)Cl^(-)_(aq) The energy involved in the conversion of 1/2Cl_(2(g)) to Cl_((aq))^(-) (using the data,Delta_(diss)H_(CL_(2))^(odot)=240" "KJ" "mol^(-1),Delta_(eg)H_(Cl)^(odot)=-349 KJ" "mol^(-1),Delta_(hyd)H_(Cl^(-))^(odot)=-381KJ" "mol^(-1)) will be

Answer»

`-610 KJ" "MOL^(-1)`
`-850" "KJ" "mol^(-1)`
`+120" "KJ" "mol^(-1)`
`+152" "KJ" "mol^(-1)`

Answer :A
25.

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below (1)/(2)CL_(2)(g)overset((1)/(2)Delta_(diss)H^(Theta))(rarr)Cl(g)overset(DeltaH_(Eg)^(Theta))(rarr) Cl^(-)(g)overset(Delta_(hyd)H^(Theta))(rarr)Cl^(-)(aq) The energy involved in the conversion of (1)/(2)Cl_(2)(g) to Cl^(-)(aq) (Using the data Delta_(diss)H_(Cl_(2))^(Theta)=240KJ mol^(-1)) Delta_(Eg)H_(Cl)^(Theta)=-349KJmol^(-1) , Delta_(Eg)H_(Cl)^(Theta)=-381KJmol^(-1)) will be

Answer»

`+152 kJ MOL^(-1)`
`-610 kJ mol ^(-1)`
`850 kJ mol ^(-1)`
`+ 120 kJ mol ^(-1)`

Answer :B
26.

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below : (1)/(2) Cl_(2) (g) overset((1)/(2) Delta_("diss") H^(Theta))(to) Cl (g) overset( Delta_(eg) H^(oplus))(to) Cl^(-) (g) overset(Delta_(hyd) H^(Theta))(to) Cl^(-) (aq) The energy involved in the conversion of (1)/(2) Cl_(2)(g) to Cl^(-) (aq) (using the data , Delta_("diss") H_(Cl_(2))^(Theta) = 240 kJ mol^(-1) , Delta_(eg) = - 349 kJ mol^(-1) , Delta_(hyd) H_(Cl^(-))^(Theta) = -381 kJ mol^(-1)) will be -

Answer»

`-610 kJ MOL^(-1)`
`-850 kJ mol^(-1)`
`+120 kJ mol^(-1)`
`+152 kJ mol^(-1)`

Answer :A
27.

Oxidising power depends on:

Answer»

REDUCTION potential
Electrons affinity
lonisation energy
None of the above

Answer :A
28.

Oxidising agent in Etard oxidation is

Answer»

`K_(2)Cr_(2)O_(2) +dil.H_(2)SO_(4)`
`KOH+KMNO_(4)`
`dil.NHO_(3)`
`CrO_(2)Cl_(2)" in "CS_(2)`

Answer :D
29.

Oxidising action increases from left to right in the following order

Answer»

`Cl_2ltBr_2ltI_2ltF_2`
`Cl_2ltI_2ltBr_2ltF_2`
`I_2ltF_2ltCl_2ltBr_2`
`I_2ltBr_2ltCl_2ltF_2`

ANSWER :D
30.

Oxides of which of the following metals show oxidation state of +8 ?

Answer»

Ru
Os
Mn
Zn

ANSWER :A::B
31.

Oxides of which of the following melals show oxidation state of +8 ?

Answer»

`RU`
Os
Mn
Zn

Solution :`RuO_4 : OsO_4`
32.

Oxides of sulphur and nitrogen are important pollutants of

Answer»

AIR and water
Air
Water
Soil

Answer :B
33.

Oxides of sulphur and nitrogen

Answer»

`H_(2)S`
`H_(2)Te`
`H_(2)SE`
`H_(2)O`

Solution :All hydrides except H0 acts as reducing agents, The reducing nature INCREASES as the atomic NUMBER of the central ATOM increases. This is due to weakening of M-H bond as the bond LENGTH increases with increase in size of sulphur and nitrogen.
34.

Oxides of silicon are:

Answer»

Liquids
Solids
Gases
None

ANSWER :B
35.

Oxides of group 13 elements are:

Answer»

Acidic
Basic
Amphoteric
All of these

Answer :D
36.

Oxide that is prepared by dehydration of strongest oxidising agent is

Answer»

`Cl_2O`
`ClO_2`
`Cl_2O_6`
`Cl_2O_7`

ANSWER :D
37.

Oxide ores are concentrated by………

Answer»

HAND picking
hydraulic washing
froth FLOATATION process
Magnetic SEPRATION process

Answer :B
38.

Oxide of nitrogen which is soluble in alcohol is:

Answer»

`NO_2`
`N_2O`
`N_2O_3`
`NO`

ANSWER :B
39.

Oxide of nitrogen which acts as oxidising as well as reducing agent is

Answer»

NO
`N_2O_5`
`NO_2`
`N_2O`

ANSWER :A
40.

Oxide of nitrogen used as catalyst in lead chamber process for the manufacture of H_2SO_4 is:

Answer»

`NO`
`N_2O`
`N_2O_3`
`N_2O_5`

ANSWER :A
41.

Oxide of nitrogen used as catalyst in lead chamber process for the manufacture of sulphuric acid is:

Answer»

NO
`N_2O`
`N_2O_3`
`N_2O_5`

ANSWER :A
42.

Oxide of nitrogen used as a catalyst in the lead chamber process for the manufacture of sulphuric acid is

Answer»

NO
`N_(2)O`
`N_(2)O_(3)`
`N_(2)O_(5)`

ANSWER :A
43.

Oxide of metal cation which is not amphoteric?

Answer»

`AL^(3+)`
`Cr^(3+)`
`Fe^(3+)`
`Zn^(2+)`

ANSWER :C
44.

Oxide of metal cation which is not amphoteric ?

Answer»

`AL^(+3)`
`CR^(+3)`
`FE^(+3)`
`Zn^(+2')`

SOLUTION :`Fe_(2)O_(3)` basic OXIDE
45.

Oxide of boron dissolves is strong alkalies to give :

Answer»

boric acid
borates
meta borates
boron hydroxide.

Solution :`B_(2)O_(3)+2NaOH rarr underset("SOD. Metaborate")(2NaBO_(2)+H_(2)O)`
46.

Oxide of a non-metal possesses the following characteristics: It is both a proton donor and proton acceptor It is poor conductor of electricity It reacts readily with basic and acidic oxides It oxidises Fe at boiling point. The oxide is:

Answer»

`H_2O`
`CO_2`
`H_2O_2`
NO

Answer :A
47.

..........oxide is linear.

Answer»

`N_(2)O`
`N_(2)O_(3)`
`N_(2)O_(4)`
`NO_(2)`

SOLUTION :Structure of `N_(2)O` is N-N- O type.
48.

Oxidation takes place at _______ and reduction takes place at __________.

Answer»

ANODE, cathode
cathode, anode
anode
cathode

Answer :A
49.

Oxidationstatesofthe metalin theminerals heamatiteandmagnetite,respectively, are

Answer»

II, III inhaematiteandIII in magnetite
II,III in haematiteandII in magnetite.
II in haematiteandII ANDIII in magnetite.
III in haematiteandIIand III in magnetite.

SOLUTION :Haematite :` Fe_2(III)O_3` , Magnetite:` Fe_ 3 O _ 4= FeO. Fe_2 O _ 3-= Fe (II) O. Fe_ 2(III) O _3.`
50.

Oxidation states of the metal in the minerals haematite and magnetite, respectively, are....

Answer»

II, III haematite and III in MAGNETITE
II, III in haematite and II in magnetite. 
II in haematite and II, III in magnetite. 
III in haematite and II, III in magnetite. 

SOLUTION :(i) Haematite `Fe_(2)O_(3) :Fe`
`:. 2x + 3 (-2) = 0`
`:.x = 3`
(ii) Magnetite `(Fe_2O_4)` is MIXTURE of `FeO` and `Fe_2O_3`
`:. FeOFe = 2`
`Fe_2 O_3 Fe = 3`