Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

One the basis of intermolecular forces predict the correct order of decreasing boiling to that of sugar solution is:

Answer»

`CH_3OH GT H_2 gt CH_4`
`CH_3OH gt CH_4 gt H_2`
`CH_4 gt CH_3OH gt H_2`
`H_2 gt CH_4 gt CH_3OH`

ANSWER :B
Discussion
2.

One strand of DNA has the sequence. ATGCTT, the sequence of complementary strand would be:

Answer»

TCCGAA
TACGTA
TACGAA
TAGCTA

Answer :C
Discussion
3.

One that marks the paper like lead is :

Answer»

Ga
Ti
B
Tl

Answer :D
Discussion
4.

One solution contains Fe^(2+),Fe^(3+) and I^(-) ions. Such solution is reacted with iodine solution at 35^(@)C. If E^(@) of Fe^(3+)//Fe^(2+) is +0.77V and for I_(2)//2I^(-),E^(@)=0.535V. So what is probable redox reaction ?

Answer»

`I^(-)` will be REDUCED in `I_(2)`
There will be no redox reaction.
`I^(-)` will be oxidized in `I_(2)`
`Fe^(2+)` will be oxidized in `Fe^(3+)`.

Solution :`Fe^(+3)|Fe^(2+)=0.77V and I_(2)|2I^(-)=0.536V` is given
`2(e^(-)+Fe^(+3)toFe^(+2))" "E_(RED)^(@)=0.77V(Fe^(3+)|Fe^(2+))`
`underline(2I^(-) to I_(2)+2E^(-)""E_(red)^(@)=0.536V(I_(2)|I^(-)))`
`2Fe^(+3)+2I^(-) to 2Fe^(+2)+I_(2)`
`E^(@)=E_(Fe^(3+)|Fe^(2+))^(@)-E_(I_(2)|I^(-))^(@)`
`=0.77-0.536=0.164V`
So reaction will OCCUR.
Discussion
5.

one species has the longest bond length ?

Answer»

`NO^+`
`O_2^-`
`O_2^+`
`N_2^+`

ANSWER :B
Discussion
6.

One sample of air is found to have 0.03% carbon dioxide and another sample 0.02%. This illustrate that:

Answer»

AIR is a compound
air is an element
air does not FOLLOW the law of CONSTANT proportions
air is a MIXTURE.

Answer :D
Discussion
7.

One quantum is absorbed per gaseous molecules of Br_(2) for converting into Br atoms. If light absorbed has wavelength 5000 Å, calculate energy required in kJ//mol.

Answer»


ANSWER :`239.4 KJ//mol`
Discussion
8.

One pink solid (X) has the formula CoCl_3. 5NH_3. H_2O.A solution of this salt (X) in water is also pink and precipitates 3 moles AgCl on treatment with silver nitrate solution..When the pink solid (X) is heated, it loses 1 mole H_2O to yielda purple solid (Y) with the same molar ratio of NH_3:Cl:Co.The purple solid releases two of its chlorides rapidly on dissolution and after treatment with AgNO_3 solution.The coordination number of cobalt in complexes (X) and (Y) is six. The IUPAC name of pink (X) and purple (Y) complexes respectively are :

Answer»

Tetraamminechloridoaquacobalt(III) chloride and pentaamminechloridocobalt(III) chloride
Pentaammin echloridocarbalt(III) chloride and pentaammineaquacobalt (III) chloride
Pentaammineaquacobalt(III) chloride and pentaamminechloridocobalt(III)chloride
Pentaammineaquacobaltate(III) chloride and pentaamminechloridocobaltate (III) chloride

Solution :`underset(1:5:1)([CO(NH_3)_5H_2O])Cl_3("pink")overset(aq.)HARR[Co(NH_3)_5H_2O]^(3+)+3Cl^(-)`
`3Ag^(+)+3 Cl^(-)to3AgCldarr`(white)
The following complex is obtained on HEATING and losing 1 mole of `H_2O`
`underset(1:5:1)([Co(NH_3)_5Cl]Cl_2)("purple")overset(aq.)hArr[Co(NH_3)_5Cl]^(2+)+2Cl^(-)`
`2Ag^(+)+2Cl^(-)to2AgCldarr`(white)
So, pink (X) is `[Co(NH_3)_5(OH_2)]Cl_3` and IUPAC name would be pentaammineaquacobalt(III) chloride and purple (Y) is `[Co(NH_3)_5Cl]Cl_2` and IUPAC name would be pentaamminechloridocobalt(III)chloride.
Discussion
9.

One poise is equal to :

Answer»

1 DYNE `SEC^(-2)`
1 dyne `sec cm^(-2)`
dyne `sec^(-1) cm^(-2)`
dyne `sec^(-1) cm^(-1)`

ANSWER :B
Discussion
10.

One part of an element A combines with two parts of B (another element). Six parts of element C combine with four parts of elementB. If A and C combine together, the ratio of their masses will be governed by

Answer»

law of definite PROPORTIONS
law of MULTIPLE proportions
law of reciprocal proportions
law of conservation of mass

ANSWER :C
Discussion
11.

One part of an element A combines with two parts of another B. Six parts of the element C combine with four parts of the element B. If a and C combine together the ratio of their weights will be governed by

Answer»

LAW of definite proportion
Law of multiple proportion
Law of RECIPROCAL proportion
Law of conservation of mass

Solution :The weights of two elements COMBINING with a fixed amount of the third element will bear the same RATIO (or simple multiple of it) in wgich they themselves react.
Discussion
12.

One of them contributes maximum to air pollution

Answer»

India
USA
Russia
Britain

Answer :B
Discussion
13.

One of the statements of Dalton's atomic theory is given below : ''Compounds are formed when atoms of different elements combine in a fixed ratio'' Which of the following laws is not related to this statement?

Answer»

LAW of conservation of mass
Law of definite proportions
Law of multiple proportions
AVOGADRO law

Solution :Law of conservation of mass is simply the law of indestructibility of matter during physical or chemical changes. Avogadro law states that equal volume of DIFFERENT gasses contain the same number of molecules under SIMILAR conditions of temperature and pressure.
Discussion
14.

One of the reasons that solidCuSO_4 dissolves in water is

Answer»

The ion-DIPOLE forces between the ions and WATER molecules
The electrostatic force of attraction between`Cu^(2+)` and the `SO_4^(2-)` ions
Instantaneous dipole-induced dipole forces (DISPERSION or London forces) between the `Cu^(2+)` and `SO_4^(2-)` ions
The HYDROGEN bonding between the water molecules

Answer :A
Discussion
15.

One of the reasons of the flame test of metal salts is ……..

Answer»

Metal EXCESS DEFECTS 
Metal deficiency defects 
SCHOTTKY defects 
Frenkel DEFECT 

ANSWER :A
Discussion
16.

One of the reactive intermediates of organic reactions contains a divalent carbon surrounded by six electrons but bearing no electrical charge. The species is called

Answer»

Carbene
Carbenium ION
CARBOCATION
METHYLENE group

Solution :The description refers to carbene.
Discussion
17.

One of the reasons for greater reactivity of finely divided platinum catalyst is that it has :

Answer»

Particles which are almost atomic in dimensions
Particle size which can spread EASILY through WHOLE reactants
Much larger SURFACE area
A PHYSICAL state only in which it can react quickly

Answer :C
Discussion
18.

One of the products of the following reactions is P. Structure of P is

Answer»




SOLUTION :
Discussion
19.

One of the products of radiation fall out from atmospheric bomb testing or nuclear accidents at Chernobyl is iodine-131 . People living in a region where Iodine-131 was known to have been deposited were encouraged to use table salt enriched with non-radioactive isotope of iodine . By use of non-radioactive iodine isotope in common salt :

Answer»

rate of iodine - 131 UPTAKE is sharply reduced compared to uptake of iodine -127
a new non-radioactive isotope is formed
taste of table salt BECOMES better
iodine -131 being water soluble is eliminated from TISSUE .

Solution :Displacement of `I^(127)` leads to EXCREATION of `I^(131)` from HUMAN body .
Discussion
20.

One of the products of the following reaction KCNO+(NH_4)_2SO_4oversetDeltato is:

Answer»

`NH_4CO_2`
`NH_4NO_5`
`NH_2 - CO - NH_2`
both `N_2` and `NO_2`

SOLUTION :`KCNO+(NH_4)_2SO_4 OVERSET(DELTA)to NH_4CNOoversetDeltaNH_2CO NH_2`
Discussion
21.

One of the products of radiation fall out from atmospheric bomb testing or nuclear accidents at Chernobyl is iodine-131 . People living in a region where Iodine-131 was known to have been deposited were encouraged to use table salt enriched with non-radioactive isotope of iodine . Non-radioactive isotope prescribed in the table salt is :

Answer»

I-131
I-127
I-132
I-129

Solution :Table SALT = (NACL + `I^(127)`)
Discussion
22.

One of the products of radiation fall out from atmospheric bomb testing or nuclear accidents at Chernobyl is iodine-131 . People living in a region where Iodine-131 was known to have been deposited were encouraged to use table salt enriched with non-radioactive isotope of iodine . The rate of iodine uptake by the thyroid is :

Answer»

dependent upon the iodine concentration
dependent upon PRESSURE of iodine
follows second - order kinetics
independent of iodine concentration

SOLUTION :RATE `alpha` CONC. , of Iodine up take
Discussion
23.

One of the products of a reaction between solid KMNO_4 and conc. HCl is

Answer»

a red liquid
a greenish yellow GAS
`MnO_(2)`
`HClO_(4)`

Answer :B
Discussion
24.

One of the products formed due to the reaction between KMnO_(4) and HCl is

Answer»

RED liquid
`MnO_(2)`
greenish yellow gas
`HClO_(4)`

SOLUTION :A greenish yellow gas is FORMED.
`2KMnO_(4)+3H_(2)O_(4)+10HCl rarr K_(2)SO_(5)+2MnSO_(4)+8H_(2)O+underset("yellow")underset("Greenish")(5Cl_(2))uarr`
Discussion
25.

One of the point intresting and useful aspects on stereochemisty isthe stuyd of what happens to optically active molecules when they react. The product isolated from the reaction of a chiral starting mterial can tell us a great deal about the reaction mechanism. The given reaction is an example of which type of reaction ? D-underset(C_(6)H_(5)) underset(|)overset(C_(3)H_(7)) overset(|)C-ONa+Cl-overset(O)overset(||)S-Cloverset("ether")toD-underset(C_(6)H_(5))underset(|)overset(C_(3)H_(7))overset(|)C-Cl+SO_(2)+HCl

Answer»

`SN2`
`SN1`
`SNI`
`SN1`

ANSWER :C
Discussion
26.

One of the product of the following reaction is KCNO+(NH_(4))_(2)SO_(4)overset(Delta)rarr

Answer»

`NH_(4)NO_(3)`
`NH_(2)CONH_(2)`
`N_(2)`
`NO_(2)`

Solution :`KCNO+(NH_(4))_(2)SO_(4)rarrNH_(4)CNOoverset(Delta)rarrNH_(2)CONH_(2)`
Discussion
27.

One of the product formed in the electrolysis of sodium salt of succinic acid is

Answer»

Ethane
Butene
Ethylene
Acetylene

Answer :C
Discussion
28.

One of the product formed when adipic acid is heated with P_2O_5 is

Answer»




ANSWER :B
Discussion
29.

One of the processes used for concentration of ores is Froth floatation process. This process is generally used for concentration of sulphide ores. Sometimes in this process we add NaCN as a depressant. NaCN is generally added in case of ZnS and PbS minerals. what is the purpose of addition of NaCN during the process of Froth floatation?

Answer»

NaCN CAUSES reduction by precipitation
A soluble COMPLEX is formed by reactio between NaCN and ZNS while PbS forms froth
A soluble complex is formed by REACTION between NaCN and PbS while ZnS forms froth
A precipitate of `Pb(CN)_(2)` is produced while ZnS REMAIN unaffected.

Answer :B
Discussion
30.

One of the point intresting and useful aspects on stereochemisty isthe stuyd of what happens to optically active molecules when they react. The product isolated from the reaction of a chiral starting mterial can tell us a great deal about the reaction mechanism. In which is inversion of configuration ?

Answer»

`H-UNDERSET(C_(6)H_(13)) underset(|) overset(C_(3))overset(|)C-Br overset(Nal) underset("acetone")to`
`CH_(3)-underset(C_(3)H_(7)) underset(|) overset(C_(2)H_(5))overset(|)C-Br overset(Nal) underset("acetone"//"water")to`
`H-underset(C_(3)) underset(|) overset(C_(2)H_(5))overset(|)C-OH+Cl-overset(O) overset(||)S-Cl to`
`H-underset(HC=CH_(2)) underset(|) overset(C_(3)H_(7))overset(|)C-OH+ H_(2) overset(Pt)to`

Answer :A
Discussion
31.

One of the nuclides in each of the following pairs is radioactive, the other is stable. Which one is radioactive and which is stable? Explain (a) ""_(84)^(208)Po, ""_(83)^(209)Bi (b) ""_(19)^(39)K, ""_(19)^(40)K (c ) ""_(31)^(71)Ga, ""_(31)^(76)Ga

Answer»

Solution :(a) PO has an atomic number greater than 83 and so it is radioactive. Bi-209 has 126 neutrons (a magic no), so it is expected to be stable.
(b) `""_(19)^(39)K` has a magic no .of neutrons, (20), so it is expected to be stable. The isotope `""_(19)^(40)K` has an odd number of protons (19) and an odd number of neutrons (21). Since stable odd-odd nuclei are RARE, `""_(19)^(40)K` is expected to be radioactive
(c ) Of the two isotopes `""_(31)^(76)Ga` LIES farther from the centre of the stability belt, so it is expected to be radioactive and `""_(31)^(71)Ga` to be stable.
Discussion
32.

One of the oxidants used with liquid propellants is

Answer»

Ammonium perchlorate
Nitrocellulose
Sulphuric acid
DINITROGEN tetraoxide `(N_(2)O_(4))`

Solution :Dinitrogen tetraoxide is USED as an oxidant with LIQUID propellant.
Discussion
33.

One of the most widely used drug in medicine,iodex is:

Answer»

METHYL salicylate
Ethyl salicylate
Acetyl SALICYLIC ACID
o-hydroxy BENZOIC acid

Answer :A
Discussion
34.

One of the most widely used drug in medicine, iodex is

Answer»

Methyl salicylate
ETHYL salicylate
ACETYL SALICYLIC acid
o-hydroxyl benzoic acid

SOLUTION :Mathyl salicylic also known as oil of wintergreen is USED as medicine iodex in treatment of rehumatic pains areremedy for aches, sprains and bruises.
Discussion
35.

One of the most fascinating developments in Modern chemistry has been the synthesis of Buckminister fullerence, C_(60) Identify the correct options about C_(60)

Answer»

It cosists of fused `5` and `6` membered CARBON RINGS.
All atoms are not-equivalent
All bonds are not-equivalent
`C-C` BOND lengths at the FUSION of two `6`-membered rings are shorter with the `C-C` bond length at the fusion of `5`-and `6`-membered rings.

Solution :N//A
Discussion
36.

One of the most important uses of HO is:

Answer»

In dyes
In creams
In PLANT nutrition
As ROCKET fuels

Answer :D
Discussion
37.

One of the major requirements of atomic structure is determination of location of electron inside an atom. The wave mechanical model establishes this in accordance with Heisenberg uncertainity principal thorugh the concept of orbitals. The orbitals are defined as that 3d's space in which probability of finding electron maximum and are represented by wavefunctions psi_(n,l,m) where n, l and m are quantum numbers. the variation of Psi is analysed in terms of polar coordinates and hence psi=f(r, theta , phi) where r' representes radius vector and theta and phi represents angle (angle) which the radius vector makes with z-axis and its projection in x-y plane makes with x-axis respectively. the expression phi_(r,theta,phi) are often given in terms of sigma instead of r where sigma =(2zr)/(na_(0)) and z=atomic number of n=shell number Which of the followings statements is incorrects with respect to psi_((r)) vs r graph for H-atoms ?

Answer»

For a 3d orbital, the graph will not intersect the x-axis at any finite, non-zero value
For a 4s orbital, the graph will intersect at exactly three DISTINCT, non zero finite POINTS
For 1s orbital the SIGN of the `psi_((R))` will not CHANGE after at any radial distance.
For 3p orbital, the graph will intersect x-axis at two non-zero distinct points

Answer :D
Discussion
38.

One of the important use of quick lime is:

Answer»

As a purgative
In BLEACHING silk
In drying gases and alcohol
In DYEING cotton

Answer :C
Discussion
39.

One of the important uses of ferrous sulphate is in the:

Answer»

MANUFACTURE of blue-black ink
Manufacture of chalks
Preparation of HYDROGEN sulphide
Preparation of SULPHUR dioxide

Answer :A
Discussion
40.

One of the important approach to the study of real gases involves the analysis of parameter Z called the compressibility factor Z = (PV_(m))/(RT) where P is pressure, V_(m) is molar volume, T is absolute temperature and R is the universal gas constant. such a relation can also be expressed as Z = ((V_(m)real)/(V_(m)ideal)) (where V_(m ideal) and V_(m real) are the molar volume for ideal and real gas respectively). Gas corresponding Z lt 1 have attractive forces amoung constituent particles. As the pressure is lowered or temperature is increased the value of Z approaches 1. (reaching the ideal behaviour) Following graph represents a pressure (P) volume (V) relationship at a fixed temperature (T) for n moles of a real gas. The graph has two regions marked (I) and (II). Which of the following options is true.

Answer»

`Z LT 1` in the REGION (II)
`Z = 1` I the region (II)
`Z =1` for the curve
`Z` approaches 1 as we MOVE from region (II) to region (I)

SOLUTION :N//A
Discussion
41.

One of the important use of ferrous sulphate is in the

Answer»

Manufacture of blue ink
Manufacture of chalks
Preparation of HYDROGEN sulphide
Preparation of ANHYDROUS FERRIC chloride

Solution :Manufacture of blue BLACK ink.
Discussion
42.

One of the important approach to the study of real gases involves the analysis of parameter Z called the compressibility factor Z = (PV_(m))/(RT) where P is pressure, V_(m) is molar volume, T is absolute temperature and R is the universal gas constant. such a relation can also be expressed as Z = ((V_(m)real)/(V_(m)ideal)) (where V_(m ideal) and V_(m real) are the molar volume for ideal and real gas respectively). Gas corresponding Z lt 1 have attractive forces amoung constituent particles. As the pressure is lowered or temperature is increased the value of Z approaches 1. (reaching the ideal behaviour) {:("Observation",,"Conclusion"),(I.Z =1,,I."The gas need not be showing the ideal behaviour"),(II. Zgt1,, II. "On applying pressure the gas will respond by"),(,,"increasing its volume"),(III. Z lt 1,, III. "The gas may be liquefied"),(IV. Z rarr1 "for low" P,, IV. "The gas is approaching the ideal behaviour") :}

Answer»

All conclusions are TRUE
Conclusions I, II & IV ar true
Conclusions I, III & IV are true
Conclusion III & IV are true

Solution :N//A
Discussion
43.

One of the important approach to the study of real gases involves the analysis of parameter Z called the compressibility factor Z = (PV_(m))/(RT) where P is pressure, V_(m) is molar volume, T is absolute temperature and R is the universal gas constant. such a relation can also be expressed as Z = ((V_(m)real)/(V_(m)ideal)) (where V_(m ideal) and V_(m real) are the molar volume for ideal and real gas respectively). Gas corresponding Z lt 1 have attractive forces amoung constituent particles. As the pressure is lowered or temperature is increased the value of Z approaches 1. (reaching the ideal behaviour) For a real gas G Z gt 1 at STP Then for 'G': Which of the following is true:

Answer»

1 mole of the gas occupies 22.4 L at `NTP`
1 mole of the gas occupies 22.4 L at pressure higher than that at `STP` (keeping TEMPERATURE constant)
1 mole of the gas occupies 22.4 L at pressure LOWER than that at `STP` (keeping temperature constant)
None of the above

Solution :N//A
Discussion
44.

One of the important postulates of Dalton's atomic theory is :

Answer»

an atom is MADE up electrons , PROTONS ND neutrons
atom can neither be CREATED nor be destroyed
atoms of same element are not like
All the ELEMENTS naturally as atoms only

Answer :B
Discussion
45.

One of the important approach of the study of real gases involves the analysis of a parameter Z called the compressibility factor Z=(PV_(m))/(RT) where P is pressure, V_(m) is molar volume ,T is absolute temperature and R is the universal gas constant .Such a relation can also be expressed as Z=((V_(" m real"))/(V_("m ideal"))) (where V_("m ideal") and V_("m real") are the moler volume for ideal and real gas respectively tendencies among constituent particles.As pressure is force among is lowered or temperature is increased the value of Z approaches ideal behaviour Following graph represents a pressure (P) volume (V) relationship at a fixed temperature (T) for moles of a real gas.The graph has two regions masked (I) and (II). Which of the folloingoption true ?

Answer»

`Zlt1` in the region (II)
Z = 1 in the region (II)
Z = 1 for the curve
Zapproaches 1 as we MOVE from region (II) region(I)

ANSWER :D
Discussion
46.

One of the important approach of the study of real gases involves the analysis of a parameter Z called the compressibility factor Z=(PV_(m))/(RT) where P is pressure, V_(m) is molar volume ,T is absolute temperature and R is the universal gas constant .Such a relation can also be expressed as Z=((V_(" m real"))/(V_("m ideal"))) (where V_("m ideal") and V_("m real") are the moler volume for ideal and real gas respectively tendencies among constituent particles.As pressure is force among is lowered or temperature is increased the value of Z approaches ideal behaviour For a realgas 'G', Zgt1 at STP, then for 'G' which of the following is true ?

Answer»

1mole of the GAS occupies 22.7 L at STP
1 mole of the gas occupies 22.7 L at PRESSURE higher then that at STP (Keeping temperature CONSTANT )
1 Mole of the gas occupies 22.7 L at pressure lower then that at STP (keeping temperature constant )
NONE of the above

Answer :B
Discussion
47.

One of the important approach of the study of real gases involves the analysis of a parameter Z called the compressibility factor Z=(PV_(m))/(RT) where P is pressure, V_(m) is molar volume ,T is absolute temperature and R is the universal gas constant .Such a relation can also be expressed as Z=((V_(" m real"))/(V_("m ideal"))) (where V_("m ideal") and V_("m real") are the moler volume for ideal and real gas respectively tendencies among constituent particles.As pressure is force among is lowered or temperature is increased the value of Z approaches ideal behaviour Choose the conslusions which are appropriate for the observation stated

Answer»

All conclusions are TRUE
Conclusions I, II and IV are TURE
Conclusions I,III and IV are true
Cinclusions III and Iv are true

ANSWER :D
Discussion
48.

One of the hazards of nuclear explosion is the generation of Sr^90 and its subsequent incorporation in bones. This nuclide has a half life of 28.1 year. Suppose one microgram wasabsorbed by a new born child, how much Sr90 will remain in his bones after 20 years.

Answer»

Solution :GIVEN `t_(1//2) = 28.1 "year," m_0 = 10^(-6)g, t= 20` year, m = ?
`:. T = 2.303/lambda log""m_0/m`
`:. 20 = (2.303 xx 28.1)/(0.693) log"" 10^(-6)/m`
`:.m = 6.1 xx 10^(-7)g`
Discussion
49.

One of the hazards of nuclear explosion is the generation of ""^90Srand its subsequent incorporation in bones. The nuclide has a half-life of 28.1 years. Suppose one microgram was absorbed by a newborn child, how much ""^90Srwill remain in his bones after 20 years?

Answer»

SOLUTION :0.61 `MUG `
Discussion
50.

One of the following named reaction is an example of "disproportionation reaction". Identify it

Answer»

BIRCH reduction
Aldol condensation
Reimer-Tiemann reaction
Cannizzaro reaction

Solution :
Discussion