94420 + Interview Questions in Chemistry in Class 12

1.	One of the following is the chief source of water and soil pollution
Answer» AGRO industry Mining Thermal POWER stations All of these Answer :D

Discussion

2.	One of the following is an incorrect statement , point it out,
Answer» Temporary HARDNESS is due to bicarbonates of Ca and MG. Hardness of WATER affects soap consumption. Hardness of water affects soap consumption. Permanent hardness is due to the soluble, `SO_(4)^(2-), Cl^(-), NO_(3)` of Ca and Mg. SOLUTION :No, permanent hardness cannot be removed by boiling water.

Discussion

3.	One of the following is false for Hg
Answer» it can EVOLVE hydrogen from `H_(2)S` It is a metal It has high specific heat It is LESS REACTIVE than hydrogen Solution :It cannot evolve `H_(2)` from `H_(2)S` `Hg+H_(2)Sto"No REACTION"`.

Discussion

4.	One of the following has O-O Bond
Answer» `H_2S_2O_6` `H_2S_2O_7` `H_2S_2O_5` `H_2S_2O_8` SOLUTION :`HO-UNDERSET(O)underset(\|\|)OVERSET(O)overset(\|\|)(S)-O-O-underset(O)underset(\|\|)overset(O)overset(\|\|)(S)-OH`.

Discussion

5.	One of the following is an essential amino acid.
Answer» CYSTEINE SERINE TYROSINE Isoleucine Answer :B

Discussion

6.	One of the following conversion results in the change of hybridization and gemetry :
Answer» `NH_(3)toNH_(4)^(+)` `H_(2)O to H_(3)O^(+)` `CH_(4) to C_(2)H_(6)` `BF_(3) to BF_(4)^(-)` Solution :`NH_(3) to NH_(4)^(+)` `sp^(3) " HYBRIDIZATION" sp^(3) " hybridization "` `"Tetrahedral geometryTetrahedral geometry "` `CH_(4)to C_(2)H_(6)` `sp^(3)"hybridized C" sp^(3) "hybridizedC"` `"Tetrahedral geometryTetrahedral geometry "` `H_(2) Oto H_(3)O ` `sp^(3) " hybridization" sp^(3) " hybridization "` `"Tetrahedral geometryTetrahedral geometry "` `BF_(3) to BF_(4)^(-)` `sp^(3) " hybridization" sp^(3) " hybridization "` ` "TRIGONAL plaanar geometryTetrahedral geometry "`

Discussion

7.	One of the following cannot be prepared by Kolbe's electrolytic process?
Answer» `CH_4` `C_2 H_6` `C_2 H_2` `C_2 H_4` ANSWER :A

Discussion

8.	One of the following amides will not undergo Hofmann bromamide reaction:
Answer» `CH_(3)CONHCH_(3)` `CH_(3)CH_(2)CONH_(2)` `CH_(3)CONH_(2)` `C_(6)H_(5)CONH_(2)` Solution :Only `1^(@)` amides undergo HOFMANN bromamide reaction. `CH_()CONHCH_(3)` being a `2^(@)` AMIDE does not undergo this reaction.

Discussion

9.	One of the following amide will not undergo Hoffmann bromamide reaction :
Answer» `C_(6)H_(5)CONH_(2)` `CH_(3)CONH_(2)` `CH_(3)CH_(2)CONH_(2)` `CH_(3)CONHCH_(3)` ANSWER :D

Discussion

10.	One of the fertilizer is :
Answer» `CaC_2` `CaCO_3` `CaCN_2` `CaSO_4` ANSWER :C

Discussion

11.	One of the essential alpha amino acids is:
Answer» Lysine Glycine Serine Proline Answer :A

Discussion

12.	One of the distinguishing reactions of aliphatic and aromatic primary amines is
Answer» Carbylamine reaction reaction with RED fjtmus paper Hofmann bromamide reaction COUPLING reaction. Solution :AROMATIC `1^(@)`AMINES give coupling REACTIONS but aliphatic `1^(@)`amines do net.

Discussion

13.	One of the constituents of German silver is
Answer» Cu Al Mg Ag Answer :A

Discussion

14.	One of the best photovoltaic material fur the conversion of sunlight into electricity is
Answer» iron zinc amorphous silicon aluminium Answer :C

Discussion

15.	one of the components of stainless steel is :
Answer» Cr Mg Sn W Answer :A

Discussion

16.	One of the characteristic of transition metals to from the complex ion is
Answer» Having unpaired ELECTRON in d-subshell Having paired ELECTRONS in d-subshells Providing EMPTY d-orbitals Having small charge/size ratio Answer :C

Discussion

17.	One of the approach to the study of real gases involves the analysis of a parameter Z called the compressibility factor Z=(PV_(m))/(RT) where P is pressure, V_(m) is molar volume, T isabsolute temperature and R is the universal gas constant . Such a relation can also be expressed as Z =((V_("m real"))/(V_("m ideal")))(where V_("m ideal ") and V_("m real") are the molar volume for ideal and real gas respectively) . Gas corresponding Z gt 1 have repluive tendenciesamong constituent particles due to their size factor, among constitutent particles . As the pressure is lowered or temperature is increased the value of Z approaches 1. ( reaching the ideal behaviour) For a real gas 'G'Z gt 1 at STP then for 'G' which of the following is true
Answer» 1 MOLE of the gas occupies 22.4 L at NTP 1 moleof the gas occupies 22.4 L atpressure HIGHER than that at STP (keeping temperature constant) 1 mole of the gas occupies 22.4 L at pressure lower than that at STP ( keeping temperature constant) None of the above Solution :`Z=(PV_(m))/(RT) gt 1` `(PV_(m))/(RT)= (1xx22.4)/(R xxT ) ` At same pressure `=1` atm `(1xxV_(m))/(RT) gt (1 xx 22.4)/(R xx T ) implies V_(m) gt 22.4 L ` at STP for real gas. For `V_(m) = 22.4 L` of real gas , we have to increase the pressure.

Discussion

18.	One of the acid listed below is formed from P_2O_3. The rest are formed from P_2O_5. The acid formed from hydrolysis is
Answer» `HPO_(3)` `H_4P_2O_7` `H_(3)PO_(4)` `H_(3)PO_(3)` ANSWER :D

Discussion

19.	One ,odel is obtained from scu water 11.9 C^(14) atoms disssociate from 1 gm carbon 15.3 C^(14) atoms dissociate from live model then model was how many years old ?t_((1)/(2))=5730 years
Answer» SOLUTION :2079 YEARS

Discussion

20.	one of an idealgas is expanded isothermally at 298 K unit its volume is tripled. Findthe values ofDelatS_("gas") and DeltaS_("total") under the followingconditions.(i) Expansion is carried outreversiby .(ii)Expansion is carried out irreversiblywhere836.8J of heatis less absorbed than in (i) (iii) Expansionis free.
Answer» Solution :(i) `DeltaS_(SURR)=0""DeltaS_(gas)=0` `DeltaS_("TOTAL")= 0` (ii)`DeltaS_(surr)= (-q_(sys))/(T)` `q_(IRR) = q_(rev)- 836.8` `DeltaS_(surr)= -[(q_(rev)-836.8)/(298)]` `DeltaS_("total")= 2.808 J//K`

Discussion

21.	One molecule of which of the following ligands form only two rings towards a particular central atom?
Answer» en bn dien trien Solution :

Discussion

22.	One moles of an ideal monoatomic gas undergo the state change as shown in following graph (ln 2 = 0.7) Efficiency of the cycle will be :
Answer» `50%` `25%` `13.63%` `12%` ANSWER :D

Discussion

23.	One molecule of haemoglobin will combine with four molecules of oxygen. If 1.0 gof haemoglobin combines with 1.53 mL of O, at body temperature (37^@C)and a pressure of 743 torr, what is the molar mass of haemoglobin?
Answer» SOLUTION :`6.8 XX 10^4 G "MOL"^(-1)`

Discussion

24.	One molecule of an olefinic compound, on ozonolysis, produces one molecule of acetone,one molecule of glyoxal and one molecule of formadehyde. Identify the compound and write its IUPAC name.
Answer» Solution :The structure of the olefinic hydrocarbon MAY be obtained by arranging the carbonyl compounds obtained on ozonolysis properly (each of the two oxygen atoms of acetone and formaldehyde is PLACED in front of the 2 oxygen atoms of GLYOXAL) followed by eliminating the four oxygen atoms and joining the carbonyl carbons by double BONDS. Thus, the IUPAC name of the starting olefinic compound is 4-methylpenta -1,3-diene.

Discussion

25.	One moleculeof H_(2)SO_(4) forms how many no of series of salt's
Answer» SOLUTION :There are (1) -ous seriesof SALTS , (2) -ic SERIES of salt.

Discussion

26.	One mole of CO_2 contains
Answer» `6.02 xx 10^23` ATOMS of C `6.02 xx 10^23` atoms of O `18.1 xx 10^23` MOLECULES of `CO_2` 3G atoms of `CO_2` Answer :A

Discussion

27.	One mole of which of the following has the highest entropy
Answer» Mercury Diamond Liquid nitrogen Hydrogen gas Solution :ENTROPY of a gas is greater than liquid and solid because gaseous PARTICLES are quite apart from each other and are in RANDOM motion.

Discussion

28.	One mole on non-volatile solute is dissolved in two mole of water. The vapour pressure of the solution relative to that of water is:
Answer» 2/3 1/3 1/2 3/2 Answer :A

Discussion

29.	One mole of which o the following has the highest entropy?
Answer» Liquid nitrogen Hydrogen gas Mercury Diamond Solution :GREATER the disorder in a system, the HIGHER is the ENTROPY. Hence, entropy is HIGHEST for hydrogen gas.

Discussion

30.	One mole of which of the following has the highest entropy ?
Answer» mercury diamond LIQUID nitrogen hydrogen gas Solution :Entropyof a gas is greater than liquid and solid because GASEOUS particles ar QUITE apart from each other and are in random MOTION.

Discussion

31.	One mole of water at 100^@C is converted into steam at 100^@C at a constant pressure of 1 atm. The change in entropy is ____________. (heat of vaporization of water at 100^@C=540cal/g)
Answer» 8.74 18.76 24.06 26.06 Solution :The ENTROPY change = `("heat of vaporization")//("temperature")` Here, heat of vaporisation = 540 cal/gm `=540xx18 cal mol^(-1)` Temperature of WATER = 100 + 273 = 373 K `THEREFORE` entropy change = `(540xx18)/(373) = 26.06 cal mol^(-1) K^(-1)`.

Discussion

32.	One mole of unsaturated hydrocarbon on ozonolysis gives one mole each of CH_3. CHO, HCHO and OHC. CHO. The hydrocarbon is
Answer» `CH_3.CH_2C-=C.CH_3` `CH-=C.CH_2.CH_2.CH_3` `CH_3.CH=CH.CH=CH_2` `CH_2=CH.CH_2CH-=CH_2` ANSWER :C

Discussion

33.	One mole of the complex compound Co(NH_(3))_(5)Cl_(3), gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with two moles of AgNO_(3) solution to yield two moles of AgCl (s). The structure of the complex is
Answer» `[CO(NH_(3))_(3)Cl_(3)]2NH_(3)` `[Co(NH_(3))_(4)Cl_(2)]ClNH_(3)` `[Co(NH_(3))_(4)Cl]Cl_(2)*NH_(3)` `[Co(NH_(3))_(5)Cl]Cl_(2)` Answer :D

Discussion

34.	One mole of the complex compound Co(NH_3)_5Cl_3 , gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with two moles of AgNO_3 solution to yield two moles of AgCl_((s)) . The structure of the complex is _________.
Answer» `[CO(NH_3)_3Cl_3]2NH_3` `[Co(NH_3)_4Cl_2]Cl.NH_3` `[Co(NH_3)_4Cl]Cl_2.NH_3` `[Co(NH_3)_5Cl]Cl_2` ANSWER :D

Discussion

35.	One mole of the complex compound Co(NH_(3))_(5)Cl_(3)gives 3 moles of ion on dissolution in water. One mole of the same complex reacts with two moles ofAgNO_(3) solution to yield two moles ofAgCl(s). The structure of the complex is–
Answer» `[CO(NH_(3))_(4)CL]Cl_(2).NH_(3)` `[Co(NH_(3))_(5)Cl].Cl_(2)` `[Co(NH_(3))_(3)Cl].2NH_(3)` `[Co(NH_(3))_(4)Cl_(2)]Cl.NH_(3)` Answer :B

Discussion

36.	One mole of the complex compound CoCl_3 xNH_3 gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with two moles of AgNO_3 solution to yield two moles of AgCl. The value of x is
Answer» 5 4 3 2 Answer :A

Discussion

37.	One mole of stachyose on hydrolysis yields
Answer» 1 MOLE of glucose + 1 mole of fructose + 2 MOLES of galactose 2 moles of glucose + 1mole of fructose + 1 mole of galactose 1 mole of glucose + 2 moles of fructose + 1 mole of galactose 2 moles of glucose + 2 moles of fructose Solution :One mole of STACHYOSE on HYDROLYSIS YIELDS one mole of glucose, one mole of fructose and two moles of galactose.

Discussion

38.	One mole of solid Zn is placed in excess of dilute H_(2)SO_(4)" at "27^(@)C in a cylinder fitted with a piston. Find the value of DeltaE, q and w for the process if the area of piston is 500cm^(2) and it moves out by 50 cm against a pressure of 1 atm during the reaction. The heat given to surrounding is 36.5 KJ. Zn(s)+2H^(-)(aq)hArrZn^(2+)(aq)+H_(2)(g)
Answer» SOLUTION :`DeltaE=-39.03KJ//"MOLE",q=-36.5kJ:w=-2.53kJ`

Discussion

39.	One mole of SO_(3) was placed in a litre reacton vesel at a certain temperaturee. The following equilibrium was established 2SO_(3)hArrSO_(2)+O_(2) At equlibrium 0.6 moles of SO_(2) were formed. The equlibrium constant for the reaction will be
Answer» `0.36` `0.45` `0.54` `0.675` Solution :`underset((1-0.6))(2SO_(3))hArrunderset((0.6))(2SO_(2))+underset((0.3))(O_(2))` `K_(C)=([SO_(2)]^(2)[O_(2)])/([SO_(3)])=(0.6xx0.6xx0.3)/(0.4xx0.4)=0.675.`

Discussion

40.	One mole of SO_(3) was placed in a vessel of 1 litre capacity at a certain temperature when the following equilibrium was established. 2SO_(3)iff2SO_(2)+O_(2) At equilibrium, 0.6 moles of SO_(2) were formed. The equilibrium constant of the reaction will be
Answer» `0.36` `0.45` `0.54` `0.675` SOLUTION :`{:(,2SO_(3),iff,2SO_(2),+,O_(2)),("Initial","1 MOLE",,0,,0),("At EQM.",1-0.6=0.4,,0.6,,0.3):}` `K=((0.6)^(2)(0.3))/((0.4)^(2))=0.675`

Discussion

41.	One mole of radioactive nuclide , X with half life of ten days decays as ""_(Z)^(A) X to ""_(Z- 4) ^(A - 8) Y + 2 ""_(2) ^(4) He . If the no. of moles of Helium formed in 20 days is 0.25 x then x = …..
Answer» Solution :`1 (""_(Z) X^(A)) to ( Z- A) Y ^((A - 8)) + 2 ( ""_(2) He^(4)) `, 1 mole of `X overset(10 "days")(to) (1)/(2)` mole of X `overset(10 "days")(to)` t = 20 days , `n_x` consumed = `(1 - (1)/(4)) = (3)/(4)` mole of X, 1 mole of .X. from `to` 2 mole of He GAS `(3)/(4)` mole of .X. from `to 2 xx (3)/(4)` mole of He gas , `V_(He) = 2 xx (3)/(4) xx 22.4 = 33.6I`, `n_(He "gas") to 2 xx (3)/(4) = (3)/(2)` MOLES , `0.25 xx = (3)/(2) , x = (3)/(2 xx 0.25)= (3)/(0.50) = 6`

Discussion

42.	One mole of propanone and one mole of formaldehyde are the products of ozonolysis of one mole of an alkene. The alkene may be
Answer» 2-methylpropene 2,2-dimethyl-1-butene Propene 2-butene Solution :`underset"2-methylprop ENE"(CH_3-oversetoverset(CH_3)(\|)C=CH_2)underset((II)Zn//H_2O)overset((i)O_3//CH_2Cl_2, 196-200 K)tounderset"proponone "(CH_3-oversetoverset(CH_3)(\|)C=O)+underset"formaldehyde""HCHO"`

Discussion

43.	One mole of Phenols is warmed with sodium metal. If we assume 100% yield, volume of H gas liberated at S.T.P is
Answer» 11.2L 22.4L 33.6L 44.8L Answer :A

Discussion

44.	One mole of potassium dichromate completely oxidises the following number of moles of ferrous sulphate in acidic medium
Answer» 1 3 5 6 Solution :`{:(Cr_(2)O_(7)^(--) rarr CR^(3+), Fe^(++) rarr Fe^(+++)),(" n=6n=1"):}` eq. of `K_(2)Cr_(2)O_(7)=` eq. of `FeSO_(4)` `1xx6=x xx1`

Discussion

45.	One mole of potassium chlorate is thermally decomposed and excess of aluminium is burnt in the gaseous product. How many moles or aluminium oxide are formed?
Answer» `1` `2` `1.5` `3` Solution :`2KClO_(3)to2KCl+3O_(2)` `4Al+3O_(2)to2Al_(2)O_(3)` 2 moles of `KClO_(3)` gives 2 moles of `Al_(2)O_(3)` `:.` 1 MOL of `KClO_(3)` gives 1 mol of `Al_(2)O_(3)`

Discussion

46.	One mole of phenol is warmed with sodium metal . If we assume 100% yield , volume of H_2 gas liberated at S.T.P is
Answer» `11.2L ` ` 22.4L` ` 33.6L ` ` 44.8L ` ANSWER :A

Discussion

47.	One mole of oxygen gas at STP is equal to ………..
Answer» `6.022xx10^(23)` molecules of oxygen `6.022xx10^(23)` ATOMS of oxygen 16 g of oxygen 32 g of oxygen SOLUTION :`"1 mole of O"_(2)" GAS at STP"=6.022xx10^(23)" molecules of O"_(2)="32 g of O"_(2).`

Discussion

48.	One mole of nitrogen gas at 0.8 atm takes 38 seconds to diffuse through a pinhole, whereas one mole of an unknown compound of xenon with fluorine at 1.6 atm takes 57 seconds to diffuse through the same hole. Calculate molecular formula of the compound.
Answer» <P> Solution :`(r_(1))/(r_(2))=sqrt((M_(2))/(M_(1)))xx(P_(1))/(P_(2))` or `(n_(1))/(t_(1))xx(t_(2))/(n_(2))=sqrt((M_(2))/(M_(t)))xx(P_(1))/(P_(2))` or `(1)/(38)xx(57)/(1) =sqrt((M)/(28))xx(0.8)/(1.6)` `therefore M=252`

Discussion

49.	One mole of nitrogen is mixed with 3 mole of hydrogen in a closed 3 litre vessel 20 % of nitrogen is converted into NH_3 .Then what is the K_C for (1)/2(N_2) + (3)/2(H_2) ⇌ NH_3
Answer» 0.36 LITRE `MOL^(-1)` 0.46 litre `mol^(-1)` 0.5 litre `mol^(-1)` 0.2 litre `mol^(-1)` ANSWER :A

Discussion

50.	One mole of oxygen at 273 K and one mole of sulphur dioxide at 546 K are taken in two separate containers, then
Answer» kinetic energy of both are equal kinetic energy of `O_(2) lt` kinetic energy of `SO_(2)` kinetic energy of `O_(2) gt` kinetic energy of `SO_(2)` none of these. Solution :For OXYGEN, n = 1 mole, T = 273 K Molecular mass of `O_(2) = 2 XX 16 = 32` For SULPHUR DIOXIDE, n = 1 mole. T = 546 K = 2(273)K Molecular mass of `SO_(2) = 32 + 2(16) = 64` Kinetic energy = (3/2)RT `(K.E_(I))/(K.E_(II)) = ((3)/(2) xx Rxx T)/((3)/(2) xx R xx 2T) = 1/2` `therefore` Kinetic energy of `SO_(2) gt` Kinetic energy of `O_(2)`.

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

One of the following is the chief source of water and soil pollution

One of the following is an incorrect statement , point it out,

One of the following is false for Hg

One of the following has O-O Bond

One of the following is an essential amino acid.

One of the following conversion results in the change of hybridization and gemetry :

One of the following cannot be prepared by Kolbe's electrolytic process?

One of the following amides will not undergo Hofmann bromamide reaction:

One of the following amide will not undergo Hoffmann bromamide reaction :

One of the fertilizer is :

One of the essential alpha amino acids is:

One of the distinguishing reactions of aliphatic and aromatic primary amines is

One of the constituents of German silver is

One of the best photovoltaic material fur the conversion of sunlight into electricity is

one of the components of stainless steel is :

One of the characteristic of transition metals to from the complex ion is

One of the acid listed below is formed from P_2O_3. The rest are formed from P_2O_5. The acid formed from hydrolysis is

One ,odel is obtained from scu water 11.9 C^(14) atoms disssociate from 1 gm carbon 15.3 C^(14) atoms dissociate from live model then model was how many years old ?t_((1)/(2))=5730 years

One molecule of which of the following ligands form only two rings towards a particular central atom?

One moles of an ideal monoatomic gas undergo the state change as shown in following graph (ln 2 = 0.7) Efficiency of the cycle will be :

One molecule of haemoglobin will combine with four molecules of oxygen. If 1.0 gof haemoglobin combines with 1.53 mL of O, at body temperature (37^@C)and a pressure of 743 torr, what is the molar mass of haemoglobin?

One molecule of an olefinic compound, on ozonolysis, produces one molecule of acetone,one molecule of glyoxal and one molecule of formadehyde. Identify the compound and write its IUPAC name.

One moleculeof H_(2)SO_(4) forms how many no of series of salt's

One mole of CO_2 contains

One mole of which of the following has the highest entropy

One mole on non-volatile solute is dissolved in two mole of water. The vapour pressure of the solution relative to that of water is:

One mole of which o the following has the highest entropy?

One mole of which of the following has the highest entropy ?

One mole of water at 100^@C is converted into steam at 100^@C at a constant pressure of 1 atm. The change in entropy is ____________. (heat of vaporization of water at 100^@C=540cal/g)

One mole of unsaturated hydrocarbon on ozonolysis gives one mole each of CH_3. CHO, HCHO and OHC. CHO. The hydrocarbon is

One mole of the complex compound Co(NH_(3))_(5)Cl_(3), gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with two moles of AgNO_(3) solution to yield two moles of AgCl (s). The structure of the complex is

One mole of the complex compound Co(NH_3)_5Cl_3 , gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with two moles of AgNO_3 solution to yield two moles of AgCl_((s)) . The structure of the complex is _________.

One mole of the complex compound Co(NH_(3))_(5)Cl_(3)gives 3 moles of ion on dissolution in water. One mole of the same complex reacts with two moles ofAgNO_(3) solution to yield two moles ofAgCl(s). The structure of the complex is–

One mole of the complex compound CoCl_3 xNH_3 gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with two moles of AgNO_3 solution to yield two moles of AgCl. The value of x is

One mole of stachyose on hydrolysis yields

One mole of SO_(3) was placed in a litre reacton vesel at a certain temperaturee. The following equilibrium was established 2SO_(3)hArrSO_(2)+O_(2) At equlibrium 0.6 moles of SO_(2) were formed. The equlibrium constant for the reaction will be

One mole of SO_(3) was placed in a vessel of 1 litre capacity at a certain temperature when the following equilibrium was established. 2SO_(3)iff2SO_(2)+O_(2) At equilibrium, 0.6 moles of SO_(2) were formed. The equilibrium constant of the reaction will be

One mole of radioactive nuclide , X with half life of ten days decays as ""_(Z)^(A) X to ""_(Z- 4) ^(A - 8) Y + 2 ""_(2) ^(4) He . If the no. of moles of Helium formed in 20 days is 0.25 x then x = …..

One mole of propanone and one mole of formaldehyde are the products of ozonolysis of one mole of an alkene. The alkene may be

One mole of Phenols is warmed with sodium metal. If we assume 100% yield, volume of H gas liberated at S.T.P is

One mole of potassium dichromate completely oxidises the following number of moles of ferrous sulphate in acidic medium

One mole of potassium chlorate is thermally decomposed and excess of aluminium is burnt in the gaseous product. How many moles or aluminium oxide are formed?

One mole of phenol is warmed with sodium metal . If we assume 100% yield , volume of H_2 gas liberated at S.T.P is

One mole of oxygen gas at STP is equal to ………..

One mole of nitrogen gas at 0.8 atm takes 38 seconds to diffuse through a pinhole, whereas one mole of an unknown compound of xenon with fluorine at 1.6 atm takes 57 seconds to diffuse through the same hole. Calculate molecular formula of the compound.

One mole of nitrogen is mixed with 3 mole of hydrogen in a closed 3 litre vessel 20 % of nitrogen is converted into NH_3 .Then what is the K_C for (1)/2(N_2) + (3)/2(H_2) ⇌ NH_3

One mole of oxygen at 273 K and one mole of sulphur dioxide at 546 K are taken in two separate containers, then