Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Nuclear reactions accompained with emission of neutron (s)are

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`""_(13)^(27)Al+_(2)^(4)He to _(15)^(30)P`
`""_(6)^(12)C+_(1)^(1)H to _(7)^(13)N`
`""_(14)^(30)P+_(14)^(30)Si to _(+1)^(0)e`
`""_(98)^(241)Cm+_(2)^(4)He to _(97)^(244)Bk+_(+1)^(0)C`

ANSWER :A::D
2.

Nuclear hydroxy derivatives are called _____ and side chain substituted hydroxy derivatives are called _____.

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PHENOLS, phenols
ALCOHOLS, alcohols
alcohols, phenols
phenols, alcohols

Answer :Phenols, AROMATIC alcohols .
3.

Nuclear isomerism is exhibited by-

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MOLECULES H only
All diatomic molecule
All diatomic molecule having EVEN Z VALUE
All diatomic molecule having odd Z value.

Solution :All diatomic molecule having odd z value.
4.

Nuclear fusion produces:

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Argon
Deuterium
Helium
Krypton

Answer :C
5.

Nuclear energy is the result of conversion of :

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NEUTRONS to protons
protons to neutrons
protons to neutrons and electrons
mass into ENERGY.

ANSWER :C
6.

Nuclear energy is based on the conversion of:

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PROTONS into neutrons
Mass into ENERGY
Neutrons into protons
Uranium into radium

Answer :B
7.

Nuclear charge actually experienced by an electron is termed as effective nuclear charge. The effective nuclear charge Z^(**) actuall ydepends on type of shell and orbital in which electron is actually present. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is s gt p gt d gt f (for the same value of n) The phenomenon in which penultimate shell electrons act as screen or sheild in between nucleus and valence shell electrons and thereby reducing nuclear charge is known as shielding effect. the penultimate shell electrons repel the valence shell electron to keep them loosely held with nucleus. it is thus evident that more is the shielding effect, lesser is the effective nuclear charge and lesser is the ionization energy. Q. Which of the following is not concerned to effective nuclear charge?

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HIGHER ionization potential of carbon than boron
Higher ionization potential of magnesium than ALUMINIUM
Higher VALUES of successive ionization energy
Higher electronegativity of higher oxidation state

Solution :Magnesium having higher ionization potential DUE to more stable electronic arrangement `[Ne]3s^(2)` in comparison to aluminium `[Ne]3s^(2)3p^(1)`.
8.

Nuclear charge actually experienced by an electron is termed as effective nuclear charge. The effective nuclear charge Z^(**) actuall ydepends on type of shell and orbital in which electron is actually present. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is s gt p gt d gt f (for the same value of n) The phenomenon in which penultimate shell electrons act as screen or sheild in between nucleus and valence shell electrons and thereby reducing nuclear charge is known as shielding effect. the penultimate shell electrons repel the valence shell electron to keep them loosely held with nucleus. it is thus evident that more is the shielding effect, lesser is the effective nuclear charge and lesser is the ionization energy. Q. Ionzation enegy is not influenced by:

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Size of atom
Effective nuclear charge
Electrons PRESENT in inner shell
Change in ENTROPY

Solution :Ionization energy is not AFFECTED by entropy.
9.

Nuclear charge actually experienced by an electron is termed as effective nuclear charge. The effective nuclear charge Z^(**) actuall ydepends on type of shell and orbital in which electron is actually present. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is s gt p gt d gt f (for the same value of n) The phenomenon in which penultimate shell electrons act as screen or sheild in between nucleus and valence shell electrons and thereby reducing nuclear charge is known as shielding effect. the penultimate shell electrons repel the valence shell electron to keep them loosely held with nucleus. it is thus evident that more is the shielding effect, lesser is the effective nuclear charge and lesser is the ionization energy. Q. Which of the following valence electron experience maximum effective nuclear charge?

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`4S^(1)`
`4p^(1)`
`3D^(1)`
`2p^(3)`

Solution :ELECTRONS closer to NUCLEUS will experience higher effective nuclear charge. `2p^(3)` is closer to `4s^(1)` as principal quantum number is concerned FIRST.
10.

Nucelophilic aliphatic substitution reaction is given by those compounds which have nucleophiic groups as leaving. Less is the basicity of the leaving group. More is its leaving power. Leaving group in the form of nucleophile (charged of neutral) Leaving power of which groups is maximum ? Which one of the following compounds may NOT given SN rection ?

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`R-overset(o+)N-=N`
`R-O-SO_(2)-CH_(3)`
`R-NH_(2)`
`R-overset(o+)UNDERSET(H)underset(|)O-H`

Answer :C
11.

Nucelophilic aliphatic substitution reaction is given by those compounds which have nucleophiic groups as leaving. Less is the basicity of the leaving group. More is its leaving power. Leaving group in the form of nucleophile (charged of neutral) Leaving power of which grops is maximum ? Leaving power of which group is maximum ?

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`-O-UNDERSET(O) underset(||)overset(O) overset(||)S-CF_(3)`
`-O-underset(O) underset(||)overset(O) overset(||)S-C_(4)F_(9)`

`-overset(Theta)(Br)`

Answer :B
12.

ntoOrbit no , zto Atomic no implies r_(n.z)to Radiusv_(n.z)to Velocity T_(n.z)to Time period of Revolution implies K_(n.z)to kinetic energy of the electron {:("Column-I","Column-II"),("(for single electron species)","(Ratio)"),((A)r_(2,1):r_(1,2),(P)"9:1"),((B)V_(1,3):V_(3,1),(Q)"8:1"),((C )T_(1,2):T_(2,1),(R)"16:1"),((D)K_(1,2):K_(2,1),(S) "1:32"):}

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SOLUTION :(i)`r=0.521xxn^2/z A^@` , (II)`V=2.18xx10^6 z//n`, (III)`T PROP n^3//z^2` , (IV)`K.E prop z^2/n^2`
13.

Np^(7+) is

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OXIDISING agent
reducing agnet
COLOURED ion
all of these

Answer :C
14.

Now carbohydrates are regarded as :

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AROMATIC compounds
Polyfunctional compounds
Alicyclic compounds
Polysaccharide

Answer :B
15.

Now a days, how quantity of electricity Q can be measured in electrolytic cell ?

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Solution :* Now we have CONSTANT CURRENT (I) sources available and the quantity of electricity Q passed is GIVEN by :
`Q=It`
Where, I=current in AMPERE
t=time in second for PASSES of current.
Q=current in Coulomb.
16.

Now a days , the reagentused in Hinsberg method is _________

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p-tolueensulphonyl chloride
benzenesulphonic ACID
ETHYL oxalate
ACETIC acid

ANSWER :A
17.

Novolac, the linear polymer used in paints is

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copolymer of buta-1, 3-diene and styrene
obtained by the POLYMERIZATION of methyl methacrylate
initial PRODUCT obtained in the condensation of PHENOL and formaldehyde in the presence of acid catalyst
obtained by the polymerisation of caprolactam.

Solution :Novolac is initial product obtained in the condensation of phenol and formldehyde.
18.

Novolac,the linear polymer used in paintsis

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copolymer of 1,3-butadieneand styrene
obtained by the polymerisation methyl methacryalate
INITIAL product obtained in the condensation of phenol and formaldehyde in the presenceof ACIDCATALYST
obtained by the polymerisation of CAPROLACTUM

SOLUTION :Novolacis the initial product of the condensation reaction between phenol and fomaldehyde in the PRESENCE of acid catalyst.
19.

Novolac on heating with formaldehyde undergoes ___________ to form an infusible solid mass called ____________ .

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a. POLYMERISATION , MELAMINE
b. VULCANISATION , resin
C. cross-linking, bakelite
d. condensation, polystyrene

Answer :C
20.

Novolac is of which type polymer ?

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LINEAR
BRANCHED
Cross linked
NONE of these

Solution :Linear
Novolac is linear polymer, it can be SHOWN as below :
21.

Novolac is

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CROSS linked polymer
linear polymer
ADDITION polymer
SYNTHETIC rubber

ANSWER :B
22.

Novalgin is well known

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antipyretic
antibiotic
antiseptic
disinfectant

Answer :A
23.

Novalgin is a common:

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SOLUTION :ANALGESIC
24.

Note the following balanced chemical equation 2CO+O_(2)implies 2CO_(2) Which one of the following statement is significant in relation to the above chemical equation ?

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ONE can add to a VESSEL oly 2 mol of co for each mol of `O_(2)` added
no MATTER how much of these two reagents are added to a vessel 1 mol of `O_(2)` is consumed
when they react co reacts with `O_(2)` in 2:1 mol ratio
when 2 mol of co and1mol of `O_(2)` are placed in a vessel they will react to give I mol of `cO_(2)`

Solution :This is ACCORDING to law if definite proportion in this reaction CO reacts with `O_(2)` in 2:1 mol ratio option (c ) is the correct answer
25.

Note : log 2 = 0.3 : All data are at 25^(@)C

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ANSWER :a-r,t ; b-s,t ; c-p,Q,t ; d-p,t
26.

Note : Hints for Q. No. 10 are given on next Page

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SOLUTION :
27.

Not considering the electronic spin, the degeneracy of the second excited state (n = 3) of H atom is 9, while the degeneracy of the second excited state of H^(-) is :

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3
5
2
4

Solution :For `H^(-2)` ND EXCITED state is `2P`, thus degeneracy is 3.
28.

Normally FeCl_(3).6H_(2)O consists of

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TRANS `[FE(H_(2)O)_(2)Cl_(2)]CL.4H_(2)O`
trans`[Fe(H_(2)O)_(6)Cl]Cl_(2)`
trans `[Fe(H_(2)O)_(4)Cl_(2)]Cl.2H_(2)O`
trans`[Fe(H_(2)O)_(3)Cl_(3)]Cl.3H_(2)O`

Solution :It consistsof trans `[Fe(H_(2)O)_(4)Cl_(2)]Cl.2H_(2)O`
29.

Normally hydrogen is placed in

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IA
IVA
VIIA
All of these

Answer :A
30.

A solution is defined as a :

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NUMBER of eq/litre of SOLUTION
number of eq/litre of SOLVENT
number of mole/kg of solvent
number of mole/kg of solution

Answer :a
31.

Normality of pure sulphuric acid is:

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4 N
12 N
24 N
36 N

Answer :D
32.

Normality of 1 % H_(2)SO_(4) solution is nearly

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`2.5`
`0.1`
`0.2`
1

Answer :C
33.

Normality (N) of a solution is equal to

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`("No. of moles of solute")/("Volume of SOLUTION in litre")`
`("No. of gram EQUIVALENT of solute")/("Volume of solution in litre")`
`("No. of moles of solute")/("MASS of solvent in KG")`
None of these

Answer :B
34.

Normal melting point and boiling point of rhombic sulphur are 387.5 K and 717.6 K respectively. When sulphur is heated in a test tube to 455 K and the test tube in verted, the content which pour out is

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PLASTIC sulphur
molten sulphur
monoclinic sulphur
None of these

Solution :NOTHING will COME out of the TUBE
35.

Normal freezing point of a solvent is 5^(@)C A 0.5 nilal solution of urea in the this solvent causes freezing point depression of two degrees. Calculate the molal depression constant.

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Solution :`DeltaT_(F)=2^(@)C=2" K MOLALITY",m=0.5 m, DeltaT_(f)=K_(f)m`
`K_(f)=(DeltaT_(f))/m=(2K)/(0.5m)=4KM^(-1)`
36.

Normal freezing point of a solvent is 15^(@)C. A 0.5 molal solution of urea in the above solvent causes a freezing point depression of two degrees. Calculate the molal depression constant.

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SOLUTION :`"4 K m"^(-1)`
37.

Normal freezing of a solvent is 5^(@)C. A 0.5 molal solution of urea in this solvent causes a freezing point depression of two degree. Calculate molal depression constant. (K_(f))

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Solution :`K_(F)=(DeltaT_(f))/m=(2K)/(0.5m)=4KM^(-1)`
38.

Normal boiling of water is 373 K (at 760 mm). Vapour pressure of water at 298 K is 23 mm. If the enthalpy of evaporation is 40.656 kJ/mole, the boiling point of water at 23 mm pressure will be

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250 K
294 K
51.6 K
12.5 K

Solution :Applying CLAUSIUS clapeytron equation
`log.(P_(2))/(P_(1))=(Delta H_(V))/(2.303R)[(T_(2)-T_(1))/(T_(1)xxT_(2))]`
`log.(760)/(23)=(40656)/(2.303xx8.314)[(373-T_(1))/(373T_(1))]`
This gives `T_(1)=294.4 K`.
39.

Normal aluminium electrode coupled with normal hydrogen electrode gives an emf of 1.66V. So the standard electrode potential of aluminium is

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`-1.66V`
`+1.66V`
`-0.83V`
`+0.83V`

ANSWER :A
40.

Normal aluminium electrodecoupled with normal hydrogen electrode gives an e.m.f. of 1.66 volts. So the standard electrode potential of aluminium is:-

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`-1.66V`
`+1.66V`
`-0.83V`
`+0.83V`

Solution :`E_(CELL)^(o)=1.66=E_(H^(+)//H_(2))^(o)-E_(AL^(3+)//Al)^(o)`
`=O-E_(Al^(3+)//Al)^(o)` or `E_(Al^(3+)//Al)=-1.66V`
41.

Normal aluminium electrode coupled with normal hydrogen electrode gives an emf of 1.66 volts . So the standard electrode potential of aluminium is

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`-1.66` V
`+ 1.66` V
`-0.83` V
`+ 0.83` V

SOLUTION :AL undergoes oxidation w.r.t. N.H.E. Hence , its STANDARD electrode potential MUST be negative .
42.

Normal alkanes can undergo sulphonation if they contain:

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4 CARBON atoms
5 carbon atoms
Atleast 6carbon atoms
3 carbon atoms

Answer :C
43.

Normal aluminum coupled with normal hydrogen electrode gives an emf of 1.66 V. The standard electrode potential of aluminium is :

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`-1.66V`
`+1.66V`
`-0.83V`
`+0.83V`

ANSWER :B
44.

Norethindrone is which type of drugs?

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ANTIFERTILITY
Disinfectant
Antimicrobials
Antihistamine 

SOLUTION :Antifertility
45.

Norethindrone is an example of synthetic progesterone derivative which is most widely used as

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Antiseptics
Antifertility drugs
Antibiotics
Analgesics

Answer :B
46.

Norethindrone is an example of

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SYNTHETIC testosterone
synthetic progestrone DERIVATIVE
preservative
Birth CONTROLLING agent

Solution :Norethindrone is CONTRACEPTIVE, derivative of progestrone
47.

No.of 'f' electrons in ground state of Thorium

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SOLUTION :`Th=[Rn]6D^(2) 7s^(2)`
48.

Non-stoichiometry is shown 1) due to variable valency of transition metals 2) due to defect in solid structure 3) reducing nature Correct statemet (s) is /are

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1,2
1,3
2,3
1,2,3

Answer :A
49.

Non-stoichionmetric metal deficiency is shown in the salts of :

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all METALS
ALKALI metals only
ALKALINE earth metals only
Transition metals only .

SOLUTION :METAL deficiency defect is shown by transition metals because they possess variable valency.
50.

Non stoichiometric solid among the following

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MGO
cao
`na_(2)o`
TIO

ANSWER :D