Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Though nitrogen exhibit +5 oxidiation state, it does not form pentahalide. Why?

Answer»

Solution :NITROGEN dose not haved - orbitals to EXPAND thecovalent beyond four. HENCE it dose not FORM pentahalide .
Discussion
2.

Nitrogen dioxide (NO_(2)) reacts with fluorine (F_(2)) to from nitrul fluoride (NO_(2)F). 2NO_(2)(g)+F_(2)(g)to 2NO_(2)F(g) Write the rate of reaction in terms of (i) rate of formation of NO_(2)F (ii) rate of disappearance of NO_(2) (iii) rate of disappearance of F_(2)

Answer»


ANSWER :(i) `+(1)/(2)(d[NO_(2)F])/(DT)` (ii) `-(1)/(2)(d[NO_(2)])/(dt)` (III) `-(d[F_(2)])/(dt)`
Discussion
3.

Nitrogen does not form pentahalides. Give reason.

Answer»

Solution :NITROGEN does not FORM pentahalides because it does not possess d-orbitals and hence cannot EXPAND its octet.
Discussion
4.

Nitrogen does not form pentahalides as it does not have ............ .

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SOLUTION :d-orbitals
Discussion
5.

Nitrogen does not form any pentahalide like Phosphorus. Why?

Answer»

SOLUTION :NITROGEN does not FORM pentahalides due to NON - availability of the d - orbitals in its valence SHELL.
Discussion
6.

Nitrogen does not combine directly with:

Answer»

Ca
Al
Ag
Mg

Answer :C
Discussion
7.

Nitrogen dioxide is released by heating

Answer»

`PB(NO_(3))_2`
`KNO_3`
`NaNO_(2)`
`NaNO_(3)`

Solution :`2PB(NO_(3))_(2) to 2PbO +4NO_(2) +O_(2)`
Discussion
8.

Nitrogen dioxide is not produced on heation

Answer»

`KNO_(3)`
`Pb(NO_(3))_(2)`
`Cu(NO_(3))_(2)`
`AgNO_(3)`

Solution :`KNO_(3)` on heating gives `O_(2)` while all others GIVE `NO_(2)`
`{:(""2KNO_(3)overset(Delta)rarr 2KNO_(2) + O_(2)),(2 Pb(NO_(3))_(2)overset(Delta)rarr 2PbO + 4 NO_(2)+O_(2)),(2Cu(NO_(3))_(2) rarr 2 CuO + 4 NO_(2) + O_(2)),(" "2AgNO_(3) overset(Delta)rarr 2AG + 2NO_(2) + O_(2)):}`
Discussion
9.

Nitrogen dioxide cannot be obtained by heating :

Answer»

`KNO_(3)`
`N_(2)O_(4)`
`Pb(NO_(3))_(2)`
`N_(2)O_(5)`.

Answer :A
Discussion
10.

Nitrogen dioxide and sulphur dioxide have some properties in common. Which property is shown by one of these compounds, but not by the other ?

Answer»

Is soluble in water
Is used as a FOOD preservatives
FORMS 'acid rain'
Is a reducing agent

SOLUTION :`SO_(2)` inhibits the growth of yeasts, moulds and bacteria and hence acts as a food preservative but `NO_(2)` does not.
Discussion
11.

Nitrogen dioxide

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dissolves in water FORMING nitric ACID
does not DISSOLVE in water
dissolves in water to form nitrous acid and GIVES off oxygen
dissolves in water to form a mixture of nitrous and nitric acids

Answer :4
Discussion
12.

Nitrogen dioxide and sulphur dioxide have some properties in common. Which property is shown by one of these compounds, but not by the other?

Answer»

Is solubole in WATE
Is USED as a food PRESERVATIVE
Forms 'acid-rain'.
Is a reducing agent

SOLUTION :`NO_(2)` is not used as a food preservative.
Discussion
13.

Nitrogen differs from rest of the members on the account of various factors. Which of the following properties can be classified as anomalous properties of nitrogen ?

Answer»

BOND enthalpy of `N -= N` is 941.4 kJ/mol
Hydride of NITROGEN i.e., AMONIA has apperciable boiling point as compared to the other members like P, As.
`NH_(3)` can form unstable complexes by donating its lone pair
Molecular nitrogen comprises 78% by volume of the atmosphere

Answer :A::B
Discussion
14.

Nitrogen differs from other elements among the VA group, due to

Answer»

Small ATOMIC SIZE
HIGH ELECTRONEGATIVITY
Absence of 'd' orbitals
All of these

ANSWER :D
Discussion
15.

Nitrogen can combine directly at higher temperatures to give nitrides with

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 Mg
CI
 ZN
 FE .

ANSWER :A::B
Discussion
16.

Nitrogen containing organic compound when fused with sodium metal forms :

Answer»

`NaNO_(2)`
`NACN`
`NaNH_(2)`
`NANC`

Solution :N//A
Discussion
17.

Nitrogen can be purified from the impurities of oxides of nitrogen and ammonia by passing through:

Answer»

CONC. HCl
Alkaline SOLUTION of pyrogallol
A solution of `K_2Cr_2O_7` ACIDIFIED with `H_2SO_4`
A solution of KOH

Answer :D
Discussion
18.

Nitrogen can form..........type of oxides.

Answer»

4
5
6
7

Solution :`NO, N_(2)O, NO_(2), N_(2)O_(3), N_(2)O_(4),N_(2)O_(5)`
Discussion
19.

Nitrogen can form N^(3-) ion because of

Answer»

HIGH electronegativity
low electronegativity
high I.E.
Low I.E.

Answer :A
Discussion
20.

Nitrogen cannot form NCl_5 due to______.

Answer»

SOLUTION :The ABSENCE of d-orbitals(2D) in the VALENCY SHELL(L-shell) of N-atom.
Discussion
21.

Nitrogen can be purified from the impurities of oxides of nitrogen and ammonia by passing through :

Answer»


ANSWER :C
Discussion
22.

Nitrogen can be obtained from air by removing

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OXYGEN
HYDROGEN
carbon dioxide
both (a) and (C)

SOLUTION :Nitrogen can be obtained from air by REMOVING oxygen and hydrogen.
Discussion
23.

Nitrogenatomis amines is

Answer»

`SP^(2)` - hydridised
sp- hydridised
`sp^(3)` - hybridised
`sp^(2)` - hydbridised

ANSWER :C
Discussion
24.

Nitrogen atom in ammonia undergoes _______ hybridization and the geometry of the molecule is______ .

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SOLUTION :`sp^3` PYRAMIDAL
Discussion
25.

Nitrogen atom in ammonia undergoes .......... hybridization and the geometry of the molecule is ...............

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SOLUTION :`sp^3` PYRAMIDAL
Discussion
26.

Nitrogen and phosphorus are elements in the same group but property of catenation is shown only by phosphorus, why?

Answer»

Solution :NITROGEN has high bond dissociation energy and forms triple bond in `N-= N`. THEREFORE it cannot SHOW the PROPERTY of CATENATION. Phosphorus has low bond dissociation energy and forms P-P bond which can extend further to exhibit catenation.
Discussion
27.

Nitroethane can exhibit one of the following kind of isomerism

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Metamerism
Optical activity
TAUTOMERISM
Position isomerism

Solution :NITROALKANES exhibit tautomerism. In it, `ALPHA - H` - ATOM is labile and FORM nitrolic acid.
Discussion
28.

Nitrocompounds are

Answer»

DERIVATIVES of alkane
derivatives of benzene
NITRODERIVATIVE of AMMONIA
both a and B

Answer :D
Discussion
29.

Nitroethane on reduction by Sn//HCl gives nitrosoethane.

Answer»

SOLUTION :ETHANAMINE
Discussion
30.

Nitrocompound (A) on reaction with nitrous acid gives a compound (B). B gives a red solution with NaOH. The compound (A) is

Answer»

`CH_(3)CH_(2)NO_(2)`
`{:(CH_(3)-CH-CH_(2)NO_(2)),("|"),(""CH_(3)):}`
`CH_(3)CH_(2)CH_(2)NO_(2)`
NONE of these.

Solution :The compound is a primary nitro compound. All the three compounds give RED solution with `HNO_(2)//NaOH` as they are primary nitro compounds.
Discussion
31.

Nitrochalk is

Answer»

`CAN`
`CaNCN`
`(NH_4)_2 SO_4`
`CA(NO_3)_2. CAO`

ANSWER :A
Discussion
32.

Nitrobezene is formed as the major product along with a minor product in the reaction of benzene with a hot mixture of nitric acid and sulphuric acid. The minor product consists of carbon: 42.86%, hydrogen: 2.40%, nitrogen: 16.67%, and oxygen: 38.07% (i) Calculate the empirical formula of the minor product, (ii) when 5.5 gm of the minor product is dissolved in 45 gm of benzene, the boioling point of the solution is 1.84^(@)C higher than that of pure benzene. Calculate the molar mass of the minor product and determine its molecular its molecular and structural formula.(Molal boiling point elevation constant of benzene is 2.53 K kg mol^(-1).)

Answer»

Solution :The rations of atoms in the minor products are :
`C:H:N:O``{:( ::(42.86)/(12):(2.40)/(1):(16.67)/(14):(38.07)/(16)),( ::3.57: 2.40 : 1.19 : 2.38), ( :: 3 : 2: 1: 2):}`
Empirical formula of the minor PRODUCT: `C_(3)H_(2)NO_(2)` Molar empirical formula mass of the minor product is `(3xx12+2xx1+1xx14+2xx16)` gm `mol6(-1)` `= 84 gm mol^(-1)`
Let M be the molar mass of the minor product. For `5.5` gm of the minor product dissloved in 45 gm benzene, the molality of solution is given by
`m = (55gm//M)/0.045 kg)`
Subsituting this in the expression of ELEVATION of boiling point, we get`DELTA T_(a) = K_(b)m`
`1.84 K = (2.53K kg mol^(-1))` `((55gm//M)/(0.045kg))`
`M = ((2.53xx55)/(1.84xx0.045))gm mol^(-1)`
`=168gm mol^(-1)`
Number of unit of empirical formula in the moleculat formula `= (168gm mol^(-1))/(84gm mol^(-1))=2`
Hence, the molecular formula of the minor product is `2(C_(3)H_(2)NO_(2))`, i.e., `C_(6)H_(4)(NO_(2))` . The product is m-dinitrobenzene.
Discussion
33.

Nitrobenzene when reduced with Zn and NH_(4)OH yields a product (A). Identify (A). Will (A) reduce Tollen's reagent?

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Solution :The product (A) is PHENYL hydroxylamine. It reduces Tollen.s reagent.

This reaction is MULLIKEN Test for DISTINGUISHING `-NO_(2)` group.
Discussion
34.

Nitrobenzene to Hydrazobenzene. Here the reagent is

Answer»

`Sn+HCl`
`Zn+NH_(4)CL`
`Zn+Aq.NaOH`
`LiAlH_(4)`

ANSWER :C
Discussion
35.

Nitrobenzene to benzoic acid

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SOLUTION :
Discussion
36.

Which of the following reagent converts nitrobenzene to aniline?

Answer»

SOLUTION :ANILINE :
Discussion
37.

Nitrobenzene on reduction . With Al - Hg and water gives :

Answer»

Azobenzene
Aniline
Azoxy benzene
Phenylhydroxylamine

Answer :D
Discussion
38.

Nitrobenzene on reaction with HNO_(3)//H_(2)SO_(4) on 80^(@)-100^(@)C forms which one of the following products

Answer»

1,4-Dinitrobenzene
1, 2, 4-Trinitrobenzene
1, 2-Dinitrobenzene.
1, 3-Dinitrobenzene.

Solution :`NO_(2)` is a m-directing GROUP and HENCE 1, 3-dinitrobenzene is FORMED.
Discussion
39.

Nitrobenzene on reduction with Zn//NH_4 Cl gives

Answer»

ANILINE
Hydrozo BENZENE
NITROSO benzene
N-phenl hydroxylamine

Answer :D
Discussion
40.

Nitrobenzene on reaction with conc. HNO_(3)//H_(2)SO_(4) at 80-100^(@)C forms which one of the following products?

Answer»

1,4-Dinitrobenzene
1,2,4-Trinitrobenzene
1,2-Dinitrobenzene
1,3-Dinitrobenzene

Solution :`-NO_(2)` is a m-directing GROUP and HENCE 1,3-dinitrobenzene is FORMED.
Discussion
41.

Nitrobenzene on reaction with conc. HNO_3//H_2SO_4 at 80-100^@C forms which one of the following products

Answer»

TNT
1,3-dinitrobenzene
Picric acid
1,4-dinitrobenzene

SOLUTION :
Discussion
42.

Nitrobenzene on reaction with at 80-100^(@)C form which one of the following products?

Answer»

1,4-dinitrobenzene
2,4,5-tirnitrobenzene
1,2-dinitrobenzene
1,3-dinotrobenzene

Solution :
Discussion
43.

Nitrobenzene on reaction with conc. HNO_3//H_2SO_4 at 80 - 100^@C forms which one of the following products ?

Answer»

1,4- DINITROBENZENE
1, 2, 4 - Trinitrobenzene
1, 2 - Dinitrobenzene
1, 3 - Dinitrobenzene

Answer :D
Discussion
44.

Nitrobenzene on further excessive nitration gives

Answer»

Trinitrobenzene
m-Dinitrobenzene
p-Dinitrobenzene
nitration does not occur.

Solution :
Further substitution is checked because of two highly deactivating `- NO_(2)` GROUPS which DECREASE the reactivity of the RING TOWARDS electrophilic subtitution considerably.
Discussion
45.

Nitrobenzene is subjected to reduction with zinc dust and ammonium chloride. The main product formed will be:

Answer»

Benzenamine
Aniline
N-Phenylhydroxylamine
None of these

Solution :`PhNO_2overset(Zn_2+NH_4Cl)to UNDERSET(N-"PHENYL HYDROXYLAMINE")(PhNHOH)`
Discussion
46.

Nitrobenzene on electrolytic reduction is strongly acidic medium gives

Answer»

aniline
p - aminophenol
m - nitroaniline
nitrosobenzene

Answer :B
Discussion
47.

Nitrobenzene on alkaline medium reduction gives…………………..

Answer»


ANSWER :HYDRAZOBENZENE
Discussion
48.

Nitrobenzene is formed as the major product along with a minor product in thereaction of benzene with a hot mixture of HNO_3 and H_2SO_4. The minor product consists of C: 42.86%, H: 2.40%, N: 16.67% and 0:38.07%. (i) Calculate the empirical formula of the minor product, (ii) when 5.5 g of the minor product is dissolved in 45 g of benzene, the b.p. of the solution is 1.84^@Chigher than that of pure benzene. Calculate the molecular weight of the minor product and determine its molecular and structural formula. K_b(C_6H_6) = 2.53 K kg "mol"^(-1)

Answer»

SOLUTION :`C_3H_2NO_2`, 168, m-dinitrobenzene
Discussion
49.

Nitrobenzene on eelctrolutic reduction gies :.

Answer»

Azobebzene
Hydrazobebzene
Aminophenol
Aniline

Solution :`PhNO_2 UNDERSET ("WEAKLY ACIDIC medium" )OVERSET ("Electrolytic reduction")rarr PhNH_2`
Discussion
50.

Nitrobenzene is a set of the following reactions yielded a coloured product 'Z' The structure of Z would be

Answer»




SOLUTION :The REACTION involvesdiazotisation FOLLOWED by COUPLING reaction PHENOL
Discussion