Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Nitrobenzene is a versatile compound that may be converted inot a wide variety of subsituted benzenes. Five such synthesis are shown below. In each reaction box above an arrow write letters designating the reagents and conditions, selected from the list at the bottom of the page, that would effect the transformation. The reagents must be written in the answer box in the correct order of their use. You may assume appropriate heating or cooling takes place, and more than one equivalent of the reagent may be used if needed. {:(,"Reagents",,"Reagents",),(A,H_(2)","Ni "catalyst",F,Cl_(2) " & " FeCl_(3),),(B,KBr " & " Cu_(2) Br_(2),G,NaOH 10 % " solution",),(C,KCN " & " Cu_(2) (CN)_(2),H,(CH_(3)CO)_(2)O", pyridine",),(D,HNO_(2) 0^(@)C,I,HNO_(3)//H_(2)SO_(4),),(E,CH_(3)I " & pyridine",,,):}

Answer»


SOLUTION :BASIC INFORMATION
Discussion
2.

Nitrobenzene does not undergo Friedel - Crafts reaction - Give reason.

Answer»

Solution :NITROBENZENE does not UNDERGO Friedel - Crafts REACTIONS due to the strong DEACTIVATING nature of `-NO_2` GROUP.
Discussion
3.

Nitrobenzene combines with hydrogen in the presence of platinum to produce.

Answer»

Toluene
BENZENE
ANILINE
Azobenzene

Solution :`UNDERSET("Nitro benzene")C_(6)H_(5)NO_(2)+6Hoverset(Pt//H_(2))rarrC_(6)underset("Aniline")H_(5)NH_(2)+2H_(2)O`
Discussion
4.

Nitrobenzene can be prepared from benzene diazonium chloride by using the reagents

Answer»

`HBF_(4)//NaNO_(2)`
`HNO_(3)//H_(2)SO_(4)`
`HBF_(4)//HNO_(3)`
Fuming `HNO_(3)`

ANSWER :A
Discussion
5.

Nitrobenzene does not undergo Friedel-Crafts alkylation. Give reasons.

Answer»

Solution :Due to POWERFUL electron WITHDRAWING effect of the `-NO_(2)` group, the benzene ring in `C_(6)H_(5)NO_(2)` is deactivated towards Friedel CRAFT’s alkylation and hence it is USED as a solvent in MANY Fridel-Craft’s reaction.
Discussion
6.

Nitrobenzene can be prepared from benzene by using a mixture of cone. HNO_3 and conc. H_2SO_4 . In the nitrating mixture HNO_3acts as a

Answer»

base
acid
REDUCING agent.
catalyst

Answer :A
Discussion
7.

Nitrobenzene can be prepared from benzene by using a mixture of conc. HNO_3 and conc. H_2SO_4. In the nitrating mixture, HNO_3 acts as a

Answer»

Base
Acid
Reducing agent
Catalyst

Solution :
Discussion
8.

Nitrobenzene can be prepared from benzene by using a mixture of conc. HNO_(3) and conc. H_(2)SO_(4). In the nitrating mixture HNO_(3) acts as a

Answer»

base
acid
reducing agent
catalyst

Answer :A
Discussion
9.

Nitrobenzene can be prepared from benzene by using a mixture of conc. HNO_(3) and conc. H_(2)SO(4). In the nitrating mixture, HNO_(3) acts as a

Answer»

base
acid
reducing agent
catalyst

Answer :A
Discussion
10.

Nitrobenzene can be prepared from benzene by using a mixture of conc. HNO_(3) and conc. H_(2)SO_(4). In the nitrating mixture, nitric acid acts as a

Answer»

base
acid
reducing agent
catalyst.

Solution :`HNO_(3)+H_(2)SO_(4) RARR NO_(2)^(+)+HSO_(4)^(-)+H_(2)O`
In this reaction nitric acid acts like a base.
Discussion
11.

Nitrobenzenen can be prepared from benzene by using a mixture of conc HNO_(3) and conc. H_(2)SO_(4) in the nitrating mixture. Nitric acid acts as a

Answer»

BASE
ACID
Reducing AGENT
Catalyst

ANSWER :A
Discussion
12.

Nitrobenzene can be converted to aniline by the following reagents :

Answer»

`H_(2)//PD`
`Sn//HCl`
`Fe//HCl`
All of the above.

Answer :D
Discussion
13.

Nitrobenze on electrolytic reduction in strongly acidic medium gives

Answer»

aniline
p-aminophenol
m-nitroaniline
nitrosobenzene.

Solution :
Discussion
14.

Nitroaniline is subjected to the treatement of various reagents in the following sequence (i) NaNO_(2)//HCl (1280 K) (ii) KI (iii) Cu Powder. The product is

Answer»

3, 3' Diaminobiphenyl
3-Iodoaniline
3-Nitroiodobenzene
3, 3'-Dinitrobiphenyl.

Solution :
Discussion
15.

Nitroation of nitrobenzene results in

Answer»

o-dinitrobenzene
1,2,3 trinitrobenzene
m-dinitrobenzene
p-dinitrobenzene

Answer :C
Discussion
16.

Nitroalkanes are reduced by Zn+ NH_(4)Cl gives

Answer»

`1^(@)`- amines
N-alkyl HYDROXYL amine
oxime
amide

Answer :B
Discussion
17.

Nitroalkanes can be reduced by using __________.

Answer»

`LiAlH_(4)`
`Fe`/CONC. `HCl`
`H_(2)`/Raney `NI`
all of these

Answer :D
Discussion
18.

Nitroalkane is reduced by stannous chloride and HCl gives

Answer»

` 2^(@)` - amine
only oxime
only N-alkyl HYDROXYL amine
MIXTURE of oxime and N-alkyl hydroxyl amine

ANSWER :D
Discussion
19.

Nitroalkane is acidic only towards

Answer»

Liquid `NH_(3)`
NaOH
Alcohol
`Na_(2)CO_(3)`

ANSWER :B
Discussion
20.

Nitroalkane is acidic only towards :

Answer»

`Na_2CO_3`
NaOH
Alcohol
Liquid `NH_3`

ANSWER :B
Discussion
21.

Nitroalkane condensedwithaldehydeandketoneto fromnitroalchol. The maincondition ofnitroalkane is

Answer»

absenceof `ALPHA` -H atoms
absenceof `beta` - H atoms
presenceof ` alpha` - H atoms
it MUST be tetrary

Answer :C
Discussion
22.

Nitroalkane and alkyl nitrite can be distinguished by the action of:

Answer»

alkali
nitrous acid
mineral acids
reduction of Sn/HCl

Answer :A::B::D
Discussion
23.

Nitroalkaneare acidiconlytowards

Answer»

`NaCO_(2)`
`C_(2)H_(5)-OH`
NaOH
`NH_(3)`

Answer :C
Discussion
24.

Nitro group in nitrobenzene is :

Answer»

ORTHO director
meta director
PARA director
ortho and para director

Answer :B
Discussion
25.

Nitrocompounds are reduced to amines by

Answer»

PASSING HYDROGEN GAS in the presence of FINELY divided Ni.
reduction with metals in acidic medium.
passing hydrogen in the presence of platinum.
all of the above.

Answer :D
Discussion
26.

Nitro benzene cannto be prepared from Bromo benzene by direct nitration. Give reason.

Answer»

SOLUTION :Nitro benzene cannot be PREPARED from Bromo benzene because the BROMINE directly attached to the benzene ring cannot be CLEAVED easily.
Discussion
27.

Nitro benzene on reduction with SnCl_(2)+KOH gives………………

Answer»


ANSWER :AZOBENZENE
Discussion
28.

Nitro benzene cannot be prepared from Bromo benzene by direct nitration. Give reason.

Answer»


SOLUTION :NITRO benzene cannot be PREPARED from Bromo benzene because the BROMINE directlyattached to the benzene ring cannot be cleaved easily.
Discussion
29.

Nitro-acinitro tautomerism is exhibited by…………..

Answer»

NITRO methane
nitrobenzene
chloropicrin
o-toluidine

Answer :A
Discussion
30.

Nitrite (NO_(2)^(Θ)) interfers in the ring -test of nitrate (NO_(3)^(Θ)) some of the following reagent can be used for the removed of nitrate

Answer»

`AgF`
`(NH_(2))_(2) CS`(thiourea)
`NH_(2)SO_(3)H` (sulphanitlic ACID)
NONE of these

Answer :a,b,c
Discussion
31.

Nitrite and mitrate bothrespond toring test Nitrate areremoved bymeating with

Answer»

CONC `HNO_(3)`
`NH_(4)CI`
Conc `H_(2)SO_(4)`
`MnO_(2)`

ANSWER :b
Discussion
32.

Nitriles react with SnCl_(2) and HCl followed by hydrolysis give aldeyhydes. What is this reaction known as ?

Answer»

SOLUTION :Stephen.s REACTION
Discussion
33.

Nitric oxide reacts with hydrogen to give nitrogen and water (2" NO"+2" H"_(2)to"N"_(2)+2" H"_(2)"O"). The kinetics of this reaction is explained by the following steps : (i) 2 "NO"+"H"_(2)to"N"_(2)+"H"_(2)"O"_(2)("slow")"""(ii) ""H"_(2) "O"_(2)+"H"_(2)to2" H"_(2)"O"("fast") What is the predicted rate law ?

Answer»


ANSWER :RATE `=K["NO"]^(2)[H_(2)]`
Discussion
34.

Nitrile rubber is a copolymer of :

Answer»

isobutylene and isoprene
isobutylene and acrylonitrile
BUTADIENE and acrylonitrile
STYRENE and butadiene

ANSWER :C
Discussion
35.

The process of nitriding used in the treatment of steel is :

Answer»

O
`N_2`
NH_3`
`CO_2`

ANSWER :C
Discussion
36.

Nitric oxidereacts withH_(2)accordingto thereaction 2NO_((g))+ 2H_(2(g)) to N_(2(g))+ 2H_(2)O_((g)) What isthe relationshipamong (d[NO])/(dt) = (d[H_(2)])/(dt) = (d[N_(2)])/(dt)" and" (d[H_(2)O])/(dt)?

Answer»

Solution :GIVEN :`2NO_((G)+ 2H_(2(g)) toN_(2(g))+ 2H_(2)O_((g))`
Therelationshipamong therate ofconsumption of thereactants and therate offormationof products isas follows:
Rateof reaction`:R= - (1)/(2) (d[NO])/(dt) = (1)/(2) (d[H_(2)])/(dt) = (d[N_(2)])/(dt)= (1)/(2) (d[H_(2)O])/(dt)`
Discussion
37.

Nitric oxide reacts with bromine as :2NO(g)+Br_(2(g))hArr 2NOBr(g)When 0.087 mol of NO and 0.0437 mol of Br_(2) are mixed in a closed container at constant temperature, 0.0518 mol of NaBr is obtained at equilibrium. The equilibrium constant is :

Answer»

`12.86`
`121.66`
`2.1xx10^(4)`
`1.6xx10^(3)`

ANSWER :B
Discussion
38.

Nitric oxide (NO) reacts with oxygen to produce nitrogen dioxide 2NO_((g))+O_(2(g))rarr 2NO_(2(g)) If the mechanism of reaction is NO+O_(2)overset(K)hArr NO_(3) (fast) NO_(3)+NOoverset(K_(1))hArr NO_(2)+NO_(2) (slow)

Answer»

Rate `K'[NO][O_(2)]`
Rate `=K'[NO][O_(2)]_(2)`
Rate `= K'[NO]^(2)[O_(2)]`
Rate `K'[NO]^(3)[O_(2)]`

ANSWER :C
Discussion
39.

Nitricoxide, NO reacts with oxygen to produce nitrogen dioxide : 2" NO"(g)+"O"_(2)(g)to2"NO"_(2)(g) What is the predicted rate law, if the mechanism is : "NO"+"O"_(2)overset(k)iff"NO"_(3)("fast") "NO"_(2)+"NO"overset(k_(1))to"NO"_(2)+"NO"_(2)("slow")

Answer»


Solution :From the slow step, RATE `=k_(1)[NO_(3)][NO]""…(i)`
From fast step, EQM. CONST. `k=([NO_(3)])/([NO][O_(2)])""…(ii)`
Substituting the value of `[NO_(3)]" from (ii) in (i), we get: Rate"=k'[NO]^(2)[O_(2)]`
Discussion
40.

Nitric oxide (NO) reacts with oxygen to produce nitrogen dioxide : 2NO(g)+O_(2)(g)to2NO_(2)(g) What is the predicated rate law if the mechanism is {:(NO(g)+O_(2)(g)hArrNO_(3)(g),,("fast")),(NO_(3)(g)+NO(g)to2NO_(2)(g),,("slow")):}

Answer»

Solution :From the slow step,
Rate `=k_(1)[NO_(3)][NO]`…………`(i)`
From fast step
EQULIBRIUM constant `(K)=([NO_(3)])/([NO][O_(2)])`…………`(II)`
Substituting the VALUE of `[NO_(3)]` from equation `(ii)` into equation `(i)`, we get
Rate `=k.[NO]^(2)[O_(2)]`
Discussion
41.

Nitric oxide (NO) is paramagnetic in gaseous state

Answer»

GASEOUS state
solid state
liquid state
polymeric state

Answer :A
Discussion
42.

Nitric oxide is prepared by the action of cold dil. HNO_3 on:

Answer»

Fe
Cu
Sn
Zn

Answer :B
Discussion
43.

Nitric oxide is prepared by the action of cold dil. HNO_3 on

Answer»

Cu
Sn
Zn
Fe

ANSWER :A
Discussion
44.

Nitric oxide becomes brown when released in air. Why ?

Answer»


SOLUTION :Nitric OXIDE combines with oxygen when exposed AIR to give nitrogen DIOXIDE which is brown in COLOUR.
`2NO+O_(2) rarr 2NO_(2)`
Discussion
45.

Nitric oxide is:

Answer»

ACIDIC TOWARDS litmus
Basic towards litmus
Neutral towards litmus
Amphoteric

Answer :C
Discussion
46.

Nitric acid whether dilluted or concentrated :

Answer»

REACTS with AL to GIVE `H_2`
Reacts with Al to give `NO_2`
Reacts with Al to give `NH_4NO_3`
HARDLY AFFECTS Al

Answer :D
Discussion
47.

Nitric acid prepared in large scales using, ……………… .

Answer»

OSTWALD's PROCESS
Haber's process
Contact process
Deacon's process

Solution :Ostwald.s process
Discussion
48.

Nitric acid is the most important oxi-acid formed by nitrogen. It is one of the major idustrial chemicals and is widely used. Nitric is manufactured by ostwald process in which catalytic oxidation of ammonia is done in following sequence as shown by reactions 4 NH_(3) (g)+50_(2)(g) overset("Pt/Rh")underset("Catalyst")(rarr) 4 NO(g)+6 H_(2)O(g) ...(i) 2NO(g)+O_(2)(g) overset(1120 K)(rarr) 2NO_(2)(g) ...(ii) 3 NO_(2)(g)+H_(2)O(l) rarr 2 HNO_(3)(aq)+NO(g) ...(iii) In this process the aqueous nitric acid is obtained which can be concentrated by distillation to ~ 68.5% by weight. Then concentration to 98% acid can be achieved by dehydration with concentrated sulfuric acid. If 170 kg of NH_(3) is heated in excess of oxygen, then the volume of H_(2)O(l) produced in 1st reaction at STP is (rho_(H_(2)O)=1 g//mL)

Answer»

`33.6xx10^(3) L`
`270 L`
`224xx10^(3) L`
`170 L`

Solution :Moles of `NH_(3)=170/17=10xx10^(3)`
`:.` moles of `H_(2)O` formed `=6/4xx10xx10^(3)`
`:.` mass of `H_(2)O` formed `=6/4xx10xx10^(3)xx18`
`:.` volume of `H_(2)O` formed `=15xx18L =270 L`
Discussion
49.

Nitric acid is the most important oxi-acid formed by nitrogen. It is one of the major idustrial chemicals and is widely used. Nitric is manufactured by ostwald process in which catalytic oxidation of ammonia is done in following sequence as shown by reactions 4 NH_(3) (g)+50_(2)(g) overset("Pt/Rh")underset("Catalyst")(rarr) 4 NO(g)+6 H_(2)O(g) ...(i) 2NO(g)+O_(2)(g) overset(1120 K)(rarr) 2NO_(2)(g) ...(ii) 3 NO_(2)(g)+H_(2)O(l) rarr 2 HNO_(3)(aq)+NO(g) ...(iii) In this process the aqueous nitric acid is obtained which can be concentrated by distillation to ~ 68.5% by weight. Then concentration to 98% acid can be achieved by dehydration with concentrated sulfuric acid. If 180 L of water completely reacts with NO_(2) produced to form nitric acid according to the above reactions, then the volume of air required at STP containing 20% of NH_(3) is (rho_(H_(2)O)=1 g//mL)

Answer»

`1.56xx10^(6) L`
`6.72 xx10^(4) L`
`3.36xx10^(6) L`
NONE of these

Solution :MOLES of WATER REACTED `=(180xx10^(3))/18=10^(4)`
`:.` moles of `NO_(2)` required `=30xx10^(3)=` mole of `NH_(3)` required
`:.` volume of air at `STP=(30xx10^(3)xx22.4)/0.2=3.36xx10^(6) L`.
Discussion
50.

Nitric acid oxidises sulphur to:

Answer»

`SO_2`
`SO_3`
`H_2SO_3`
`H_2SO_4`

ANSWER :D
Discussion