Explore topic-wise InterviewSolutions in Current Affairs.

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1.

m-nitro benzoic acid can be obtained by

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none

Answer :A
Discussion
2.

M = molarity of the solutionm = molality of the solutiond = density of the solution(in g. ml^(-1))M^(-1)=gram molecular weight of solute Which of the following relations is correct

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`m=(M)/(1000d-MM^(1))`
`m=(M xx 1000)/(d + MM^(1))`
`m=(M xx 1000)/((1000xxd)-MM^(1))`
`M=(m xx 1000)/((1000 xx d)-MM^(1))`

Answer :C
Discussion
3.

m-Methoxybenzoic acid is a________acid than p-methoxybenzoic acid due to____of the OCH_(3) group at m-position.

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SOLUTION :STRONGER,-I-effect.
Discussion
4.

M-L bonds in carbonyl compounds posses

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only `SIGMA` CHARACTER
only `PI` character
both `sigma` and `pi` chracter
NONE of the above

Answer :C
Discussion
5.

M' is the molecular weight of KMnO_(4). The equivalent weight of KMnO_(4) when it reacts acoording to the equation 2KMnO_(4)+3H_(2)SO_(4)+5H_(2)C_(2)O_(4)rarrK_(2)SO_(4)+2MnSO_(4)+8H_(2)O+10CO_(2)

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`M//2`
`M//2`
M
`M//5`

ANSWER :D
Discussion
6.

M is molecular weight of KMnO_(4). The equivalent weight of KMnO_(4) when it is converted into K_(2)MnO_(4) is

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Molecular weight /10
M/3
M/5
M/7

Solution :`Koverset(+7)(Mn)O_(4) rarr K_(2) overset(+6)(Mn)O_(4)`
Change in 0.5 per atom `=7-6=1`
`:.` Equivalent weight of `KMnO_(4)`
`=("Molecular weight of "KMnO_(4))/("Change of 0.5 per atom")=M/1=M`
Discussion
7.

M g of a substance when vaporised occupy a volume of 5.6 litre at NTP. The molecular mass of the substance will be

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M
2M
3M
4M

Answer :D
Discussion
8.

m-Dihydroxybenzene is called as

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Resorcinol
Catechol
Quinol
Cresol

Answer :A
Discussion
9.

m-Chlorobenzaldehyde on reaction with conc. KOH at room temperature gives:

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POTASSIUM m- chlorobenzoate andm-hydroxybenzaldehyde
m-hydroxybenzaladehyde and m-chlorobenzylalcohol
m -chlorobenzyl ALCOHOL andm-hydroxybenzylalcohol
Potassium m-chlorobenzote and m-chlorobenzyl alcohol.

ANSWER :D
Discussion
10.

m-Chlorobenzaldehyde on reaction with conc. KOH at room temperature gives

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POTASSIUM m-chlorobenzoate and m-hydroxybenzaldehyde
m-hydroxybenzaldehyde and m-chlorobenzyl alcohol
m-chlorobenzyl alcohol and m-hydroxybenzyl alcohol
potassium m-chlorobenzoate and m-chlorobenzyl alcohol

Solution :m-Chlorobenzaldehyde does not CONTAINS a-H ATOM. It is an EXAMPLE of Cannizzaro reaction
Discussion
11.

m-chlorobenzaldehyde on reaction with conc. KOH at room temperature gives :

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POTASSIUM m-chlorobenzoate and m-hydroxybenzaldehydes
m-hydroxybenzaldehyde and m-chlorobenzyl alcohol
m-chlorobenzyl and m-hydrozybenzyl alcohol
potassiumm-chlorobenzoate and m-chlrobenzyl alcohol.

Solution :It is CANNIZARO REACTION.
Discussion
12.

m-Bromoaniline can be prepared by

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`C_(6)H_(6) underset(H_(2)SO_(4))OVERSET(HNO_(3))to underset(2.NAOH,H_(2)O)overset(Sn-HCl)to underset(H_(2)O)overset(Br_(2))to`
`C_(6)H_(6)underset(FeBr_(3))overset(Br_(2))to underset(H_(2)SO_(4))overset(HNO_(3))to underset(Pt)overset(H_(2))to`
`m-BrC_(6)H_(4)COOH overset(SOCl_(2))to overset(NH_(3))to overset(Br_(2),NaOH)to`
`C_(6)H_(5)NH_(2) underset(Cu_(2)Br_(2))overset(NaNO_(2),HCl)to overset(SOCl_(2))to overset(NaNH_(2))to`

Answer :C
Discussion
13.

m-Bromoaniline can be prepared by :-

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`C_(6)H_(6) underset(H_(2)SO_(4)) overset(HNO_(3))to underset(2." "NaOH,H_(2)O)overset(1." "Sn-HCL)to underset(H_(2)O)overset(Br_(2))to`
`C_(6)H_(6) underset(FeBr_(3)) overset(Br_(2)) to underset(H_(2)SO_(4)) overset(HNO_(3)) to underset(Pt) overset(H_(2))to`
`m-BrC_(6)H_(4)COOH overset(SOCl_(2)) to overset(NH_(3))to underset(H^(+)) overset(Br_(2),NaOH)to`
`C_(6)H_(5)NH_(2) underset(Cu_(2)Br_(2)) overset(NaNO_(2)//HCl)to overset(NaNH_(2))to`

SOLUTION :
Discussion
14.

m-Bromo benzamide reacts with Br_(2) and KOH to give :

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m - Bromoaniline
3, 5 - DIBROMO benzamide
m - Bromobenzylamine
m - Bromophenol.

Answer :A
Discussion
15.

Lysol is solution of cresol in

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Soaphy WATER
SIMPLE water
Acid
Heavy water

Solution :Soaphy water.
Discussion
16.

Lysine has 2 amino groups so it will have three PK_a VIZ-pk_(a_1)=2.2, pk_(a_2)=8.5 and pk_(a_3)=10.5 : overset((1))H_2overset(+)NCH_2CH_2CH_2overset(+(2))overset(NH_3)overset(|)CHCO_2overset((3))H (A) at pH=4 the hydrogen atom (H^(+)) is lost form- (B)At pH=9.5 the hydrogen atom (H^(+)) is lost from- (C ) At pH=13 the hydrogen atom (H^(+)) is lost form-

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Solution :`{:(A,B,C),(3,2,1):}`
At LOWER PH VALUES `H^+` is lost from more ACIDIC site.
Discussion
17.

Lysine is least soluble in water in the p H range

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3 to 4
5 to 6
6 to 7
8 to 9

Solution :LYSINE is a basic AMINO ACID , therefore , its isoelectric point LIES in the basic range 8-9. At the isoelectric point, an amino acid has the lowest solubility.
Discussion
18.

Lysine is least soluble in the pH range

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3 to 4
5 to 6
6 to 7
8 to 9

Solution :AMINO acids are least SOLUBLE at isoelectric point i.e. PH 5.5 (5 to 6) at which positive and negative charges on zwitter ion are equal.
Discussion
19.

Lysine, H_(2)N-(CH_2)_(4)-underset(NH_2)underset(|)(CH)-COOH is ...........

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`alpha`-amino acid
Basic amino acid
Amino acid synthesised in body
`BETA`-Amino acid

Solution :Lysine is a basic `alpha`-amino acid SINCE it has two `-NH_2` GROUPS and one `-COOH` group. It is not synthesized in body.
Discussion
20.

Lysine H_(2)N-(CH_(2))_(4)-underset(NH_(2))underset("|")"CH"-COOH is ……….

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`ALPHA`-amino ACID
Basic amino acid
Amino acid synthesized in BODY
`beta`-amino acid

Solution :(A) and (B)
Lysine is basic amino acid
Discussion
21.

Lysine at pH =3.5 exists as ……………………

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ANSWER :A
Discussion
22.

Lyophobic sol can be protected

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by addition of oppositely CHARGED SOL
by addition of an electrolyte
by addition of LYOPHILIC sol.
by boiling:

SOLUTION :by addition of lyophilic sol.
Discussion
23.

Lyophobic sol can be protecteda)by addition of oppositely charged solb) by addition of an electrolytec) by addition of lyophilic sol.d)by boiling:

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by ADDITION of oppositely CHARGED SOL
by addition of an electrolyte
by addition of LYOPHILIC sol.
by BOILING:

Solution :by addition of lyophilic sol.
Discussion
24.

Lyophilic sols are more stable than lyophobic sols because

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The colloidal PARTICLES have positive CHARGE
The colloidal particles have negative charge
The colloidal particles are SOLVATED
There are STRONG electrostatic repulsions between the NEGATIVELY charged colloidal particles

Answer :C
Discussion
25.

Lyophilic sols are more stable than lyophobic sols because :

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the COLLOIDAL particles have POSITIVE charge
the colloidal particles have no charge
the colloidal particles are more SOLVATED
there are strong electrostatic repulsions between the NEGATIVELY charged colloidal particles

Answer :C
Discussion
26.

Lyophilic sols are more stable than lyophobic sols because:

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the colloidal particles have POSITIVE charge
the colloidal particles have negative charge
the colloidal particles are solvated
there are strong ELECTROSTATIC repulsions between the NEGATIVELY CHARGED colloidal particles

Answer :C
Discussion
27.

Lyophilic sols are called reversible colloids. Explain

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Solution :Lyophilic sols are generally known as reversible colloids. In fact, if the dispersed phase is removed completely the colloidal solution can be formed again by mixing the dispersed phase (residue) left in a fresh SAMPLE of DISPERSION MEDIUM. for example, if a colloidal sol of starch in WATER is dried completely, it can be reformed by mixing the residue with fresh water.
Discussion
28.

Lyophilic sols are also called reversible colloids because

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they can be reformed by mixing residue (dispersed phase) in DISPERSION medium even after drying
they can be easily precipitated from the colloidal system
once FORMED, the disperison medium and dispersed phase cannot be separaed
special reversible reactions are USED to prepare them.

Answer :A
Discussion
29.

Lyophillic colloids are more stable than lyophobic colloids. Explain.

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Discussion
30.

Lyophilic sols are:

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Irreversible sols
Pre pared from inorganic componds
Coagulated by ADDING electroytes
SELF-stabilising

Solution :LYOPHILIC sols are self stabilising because these sols are reversible and are highly hydrated in the solution.
Discussion
31.

Lyophilic colloids are stable due to

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small SIZE of the particles
large size of particles
charge on the particles
layer of dispersion MEDIUM on the particles.

Solution :Lyophilic SOLS are more stable due to the fact that lyophilic colloids are extensively SOLVATED, which means the COLLOIDAL particles are covered by a layer of dispersion medium
Discussion
32.

Lunar caustic is chemically:

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SILVER chloride
Silver NITRATE
Sodium hydroxide
POTASSIUM nitrate

Answer :B
Discussion
33.

T/F Luminal and seconal are tranquilizers

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ANSWER :T
Discussion
34.

Lucas test is usedto make distinction between1^(@) 2^(@)"and"3^(@)alcohols ROH+underset("conc.")(Hcl)overset("Anhydrous"ZnCl_(2))rarrunderset("White turbidity")(RCIdownarrow)+H_(2)O This shows that :

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ROH behaves as a base
greater the value `pK_(a)`(alcohol), greater the reactivity with conc.HCLand THUS sooner the formation white turbidity
alcohol which reacts fastest with Na METAL, will give turbidity at fastest rate
alcohol which gives red COLOUR during Victor meyer test, will always give turbidity at slower rate than those giving BLUE or white colour during Victor Meyer test

Solution :N//A
Discussion
35.

Luminal, a barbiturate drug is used as a /an

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ANTIHISTAMINE
SLEEP producing
Antiseptic
ANTIMALARIAL

ANSWER :B
Discussion
36.

Lucas test is used to make distinguation between 1^(@), 2^(@) and 3^(@) alcohols. ROH+underset("conc.")(HCl)overset("anydrous ZnCl"_(2))rarr underset("whiteturvidity")(RCl darr)+H_(2)O This shown that -

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ROH behaves as a base GREATER the value of `pK_(a)` (alcohol), greater REACTIVITY with conc. HCl and thus sooner the formation of white TURBIDITY.
Alcohol which reacts fastest with Na metal, will give turbidity at fastest rate
alcohol which reacts fastest with Na metal, will give turbidity at fastest rate.
Alcohol which gives red colour during victor mayor test, will always give turbidity at slowerrate then those giving blu or white colour during victor mayor test.

Solution :`-`Proton act or lone pair donor are lewis base
-HCl is proton donor (ACID)

R-OH act as base, greater the pKa value of `R-OH` greater will basic nature, greater will tendency to donate lone pair a to take `H^(o+)`.
Discussion
37.

Lucas test is used to make distinction between 1^(@), 2^(@) and 3^(@) alcohols. This do not show that

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ROH behaves as a base
greater than value of `pK_(a)` (alcohol), greater the reactivity with cone. HCl and thus sooner the formation of white turbidity
alcohol which REACTS FASTEST with Na metal, will give turbidity at fastest rate
alcohol which gives RED colour during Victor Mayor test, will give turbidity AST slower rate then those giving blue or white colour during Victor Mayor test.

Answer :A::B::D
Discussion
38.

Lucas test is used to distingush between 1^@, 2^@ and 3^@ alcohols. This shows that

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R-OH BEHAVES as base
greater the Pka VALUE of alcohol, greater the reactivity of alcohol with HCI and thus sooner the formation of white turbidity
both are correct
none is correct

Answer :C
Discussion
39.

Lucas test is used for the determination of

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alcohols
alkyl halides
phenols
aldehydes

Solution :Lucas test - ALCOHOL reacts with concentrated hydrochloric acid in presence of anhydrous `ZnCl_(2)` to form alkyl halides. The three type of alcohols undergo this reaction at different rates. Order of RATE of reaction is : `"tertiary" gt "SECONDARY" gt "PRIMARY"`
`R-OH+HCl overset("anhy." ZnCl_(2))to R-Cl+H_(2)O`
Discussion
40.

Lucas test is used to distinguish between

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`1^(@)` , `2^(@)` and `3^(@)` ALCOHOLS
`1^(@) , 2^(@)` and `3^(@)` amines
Aldehydes and KETONES
ALKENES and alkynes

Answer :A
Discussion
41.

Lucas test is used for distinguishing primary, secondary and tertiary alchols as: ROH+"Conc."HCloverset(ZnCl_(2))rarrRCl(white turbidity)+H_(2)O The correct statement regarding the above test is/are

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ROH behaves as a base
Greater the VALUE of `pK_(a)` of alcohol, greater the reactivity with HCl and thus, sooner the formation of white turbidity.
Alcohols that reacts faster with Na metal, will give turbidity at fastest RATE.
Alcohols that do not change the orange colour of ACIDIC DICHROMATE solution produces immediate turbidity in this test.

Answer :a,B,d
Discussion
42.

Lucas test is used for the determination of :

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Alcohols
Phenols
Alkylhalides
Aldehydes

Answer :A
Discussion
43.

Lucas test is positive with

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`CH_3-O-CH_3`
`C_2H_5-OH`
`CH_3-Cl`
`CH_3-CHO`

ANSWER :B
Discussion
44.

Lucas test is used for

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Alcohols
Amines
Diethyl ether
Glacial acetic acid

Solution :Lucas TEST is USED for the DISTINCTION of PRIMARY secondary and tertiary alcohols.
Discussion
45.

Lucas test is done for:

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ANSWER :B
Discussion
46.

Lucas test is associated with

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Phenol
Carboxylic acid
Alcohols
Aldehydes

Solution :Lucas test is employed to distinguish between `1^(@),2^(@)` and `3^(@)` alcohols.
Lucas REAGENT i.e. conc. HCl and anhyd `ZnCl_(2)` is ADDED to alcohols and the appearance of turbidity due to formation of alkyl chloride HELPS in the distinction of alcohols.
If turbidity APPEARS immediately, alcohol is TERTIARY. If turbidity appears in 5 mins, alcohol is secondary.
If solution remains clear, i.e. no turbidity, alcohol is primary.
Discussion
47.

Lucas reagent produces cloudiness immediately with :

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n-butanol
Isopropanol
n-propanol
Tertiary butanol

Answer :D
Discussion
48.

Lucas reagent is used to distinguish among primary, secondary and tertiary

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ALKYL halides
ALCOHOLS
aliphatic amines
aromatic amines.

Solution :LUCAS reagent is the solution of anhydrous `ZnCI_2` in cone. HCI. `1^@` alcohols GIVES cloudiness not at all at room temperature `2^@` alcohols gives cloudiness within five MINUTES. `3^@` alcohols gives cloudiness immediately.
Discussion
49.

Lucas reagent is used to distinguish among primary, secondary and tertiary :

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ALKYL halides
Alcohols
Aliphatic amines
Aromatic amines

Answer :B
Discussion
50.

Lucas reagent is a mixture of conc. HCL and ZnCl_2.

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ANSWER :1
Discussion