Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.	Lucas reagent is a mixture of :
Answer» CONC. `HCl +` ANHYDROUS `ZnCl_2` Conc. HCI + HYDROUS `ZnCl_2` Conc.`HNO_3 `+hydrous `ZnCl_2` Conc. `HNO_3` +anhydrous `ZnCl_2` Answer :A

2.	Lucas reagent is a...
Answer» Concentrated HCl + Anhydrous `ZnCl_(2)` Concentrated `HNO_(3)` + Anhydrous `ZnCl_(2)` Concentrated HCl + Hydrated`ZnCl_(2)` Concentrated `HNO_(3)`+ Concentrated`ZnCl_(2)` Solution :Concentrated HCl + Anhydrous `ZnCl_(2)`

3.	Lucas reagent is:
Answer» ANHYDROUS `CaCl_(2)` and CONC. `HCL` anhydrous `ZnCl_(2)` and conc. `HCl` anhydrous `AlCl_(3)` and conc. `HCl` anhydrous `PdCl_(2)` and conc. `HCl` Solution :N//A

4.	Lucas reagent is
Answer» anhydrous `ZnCl_2` DISSOLVED in CONC. `HNO_3` hydrous `ZnCl_2` dissolved in conc. HCL anhydrous `ZnCl_2` dissolved in conc. HCl anhydrous `ZnCl_2` dissolved in dil. HCl ANSWER :C

5.	Lucas reagent is _________.
Answer» `ZnCl_(2)` CONC. `H_(2)SO_(4)` and anydrous `ZnSO_(4)` `ZnSO_(4)` conc. HCL and ANHYDROUS `ZnCl_(2)` Answer :D

6.	Lubricating properties of graphite are diminished in presence of:
Answer» HIGH PRESSURE LOW pressure Vacuum None Answer :C

7.	Lubricant used in which is :
Answer» COCONUT oil Pine oil Amimal oil Glycerol Answer :D

8.	Lu (OH)_(3) is less basis than La (OH)_(3). This is due to
Answer» DECREASE in IONIC character of M-OH bond ionic SIZE decrease due to LANTHANIDE contraction increase in covalent character of M-OH bond all of these ANSWER :D

9.	ltBRgt
Answer» SOLUTION :`(a)Cu_(2)S+CuO to CU+SO_(2)` `(b) Cu_(2)SO_(4) to Cu+SO_(2)` `(c ) Cu_(2)S+Cu_(2)O to Cu+SO_(2)` `(d) PbSO_(4)+PBS to Pb+SO_(2)`

10.	ltBrgt What is 'A' in the following reaction?
Answer» SOLUTION :It is the CORRECT ANSWER.

11.	LTA is known as…………………. .
Answer» SOLUTION : LEAD TETRA ACETATE

12.	lt. Of a hydrocarbon weighs as much as one litre of CO_(2) .The molecular formula of the hydrocarbon is :-
Answer» `C_(3)H_(8)` `C_(2)H_(6)` `C_(2)H_(4)` `C_(3)H_(6)` ANSWER :A

13.	overset(H^o+//H_(2)O)underset(Delta)rarr
Answer» SOLUTION :

14.	overset)(E^(+))to major product major product will be
Answer»

15.	Major product :
Answer» SOLUTION :N//A

16.	LPG is an mixture of _____&_____ .
Answer» ANSWER :n-butane and iso-butane.

17.	LPG is a mixture of
Answer» `C_6H_12+C_6H_6` `C_4H_10+C_3H_8` `C_2H_4+C_2H_2` `C_2H_4+CH_4` Solution :LIQUEFIED PETROLEUM gas is a MIXTURE of ETHANE, PROPANE and butane. The main component is butane.

18.	Lowest I^(st) IP is of : -
Answer» PB SI SN C ANSWER :C

19.	Lowest IP will be shown by the element having the configuration ?
Answer» `[He] 2S^(2)` `1S^(2)` `[He] 2s^(2) 2P^(2)` `[He] 2s^(2) 2p^(6)` ANSWER :A

20.	Lowering of vapour pressure of 1.00 m solution of a non-volatile solute in a hypothetical solvent of molar mass 40 g/mole at its normal boiling point is:
Answer» 29.23 TORR 30.4 torr 35.00 torr 40.00 torr Answer :A

21.	Lowering of vapour pressure on dissolving a non-volatile solute in a liquid is a colligative property.
Answer»

22.	Lowering of vapour pressure is highest for
Answer» UREA 0.1 M glucose `0.1 M MgSO_(4)` `0.1 M BaCl_(2)` SOLUTION :`(P^(@)-P_(s))/(P^(@))` = molality `XX(1-alpha + x alpha + y alpha)` the VALUE of `P^(@)-P_(s)` is MAXIMUM for `BaCl_(2)`.

23.	Lowering of vapour pressure is determined by Ostward and Walner dynamic method. It is based on the principle, when air is allowed to pass through a solvent or solution, it takes up solvent vapour with it to get itself saturated with vapours at that temperature. dry ari to solution overset(P_(A)) to underset(A)("solvent") overset(P_(A)^(+)) to "Anhy".CaCl_(2) to air. A and B are weighted separately before and after passing dry air. Loss in weight of each set, gives the lowering of vapour pressure. The temperature of air, the solution and the solvent is kept constant. Loss in weight (w_(1)) of solution will be proportional to
Answer» <P>`P_(A)` `P_(A)^(@)` `P_(B)` `P_(B)^(@)` ANSWER :A

24.	Lowering of vapour pressure is determined by Ostward and Walner dynamic method. It is based on the principle, when air is allowed to pass through a solvent or solution, it takes up solvent vapour with it to get itself saturated with vapours at that temperature. dry ari to solution overset(P_(A)) to underset(A)("solvent") overset(P_(A)^(+)) to "Anhy".CaCl_(2) to air. A and B are weighted separately before and after passing dry air. Loss in weight of each set, gives the lowering of vapour pressure. The temperature of air, the solution and the solvent is kept constant. Dry air was passed through 5 g of solute iini 80 g of water and then through pure water. The loss in weight of solution was 2.5 g and that of pure water was 0.04 g. The molecule weight of solute is:
Answer» 7.143 71.43 74.3 `714.3 G "MOL"^(-1)` ANSWER :B

25.	Lowering of vapour pressure is determined by Ostward and Walner dynamic method. It is based on the principle, when air is allowed to pass through a solvent or solution, it takes up solvent vapour with it to get itself saturated with vapours at that temperature. dry ari to solution overset(P_(A)) to underset(A)("solvent") overset(P_(A)^(+)) to "Anhy".CaCl_(2) to air. A and B are weighted separately before and after passing dry air. Loss in weight of each set, gives the lowering of vapour pressure. The temperature of air, the solution and the solvent is kept constant. (P_(A)^(@) - P_(A))/(P_(A)^(@)) is equal to
Answer» `W_(1)/(W_(1) + W_(2))` `W_(2)/(W_(1) + W_(2))` `W_(1)/(W_(1)-W_(2))` `W_(2)/(W_(2)-W_(1))` ANSWER :B

26.	Lowering of vapour pressure is determined by Ostward and Walner dynamic method. It is based on the principle, when air is allowed to pass through a solvent or solution, it takes up solvent vapour with it to get itself saturated with vapours at that temperature. dry ari to solution overset(P_(A)) to underset(A)("solvent") overset(P_(A)^(+)) to "Anhy".CaCl_(2) to air. A and B are weighted separately before and after passing dry air. Loss in weight of each set, gives the lowering of vapour pressure. The temperature of air, the solution and the solvent is kept constant. Loss in weight of solvent W_(2) will be proportinal to:
Answer» <P>`P_(A)^(@) - P_(A)` `P_(A)- P_(A)^(@)` `P_(A)/P_(A)^(@)` `P_(A) XX P_(A)^(@)` ANSWER :A

27.	Lowering of vapour pressure is determined by Ostward and Walner dynamic method. It is based on the principle, when air is allowed to pass through a solvent or solution, it takes up solvent vapour with it to get itself saturated with vapours at that temperature. dry ari to solution overset(P_(A)) to underset(A)("solvent") overset(P_(A)^(+)) to "Anhy".CaCl_(2) to air. A and B are weighted separately before and after passing dry air. Loss in weight of each set, gives the lowering of vapour pressure. The temperature of air, the solution and the solvent is kept constant. Gain in weight of anyhdrous CaCl_(2) is proportinal to
Answer» <P>`P_(A)` `P_(A)^(@)` `P_(A)-P_(A)^(@)` `P_(A)^(@)-P_(A)` ANSWER :B

28.	Lowering of vapour pressure in 1 motal aqueous solution at 100^@C is
Answer» <P>13.44 mm Hg 14.12 mm Hg 31.2 mm Hg 35.2 mm Hg Solution :MOLALITY and mole fraction are RELATED as follows : `m = (x_B XX 1000)/((1-x_B)m_A), 1 = (x_B xx 1000)/((1-x_B) xx 18)` `x_B` = mole fraction of solute, `m_A` = molar mass of solvent `x_B` = 0.0176, `x_A` = 0.9824, p=p `x_A` `=p 760 xx 0.9824=746.624 , Delta p = p-p= 760 -746.624` `~~` 13.4 mm Hg

29.	Lower oxidation state in transition metals are stabilized by
Answer» CO <BR>O I Br ANSWER :A

30.	Lowering in vapour pressure is the highest for:
Answer» 0.2 m Urea 0.1 m GLUCOSE `0.1 m MgSO_4` 0.1 m `BaCl_2` ANSWER :D

31.	Lower molecular weight optically active ether is reacted with cold HI gives
Answer» butan-1-ol and iodomethane butan-2-ol and iodomethane propan-1-ol and iodoethane propan-2-ol and iodoethane Answer :B

32.	Lower members of carboxylic acid family are
Answer» WAXY solids. pleasant SMELLING liquids. foul smelling liquids. inert gases. Answer :B

33.	Lower members of aliphatic carboxylic acid are soluble in water. This is due to
Answer» FORMATION of HYDROGEN BONDS with WATER London forces water is non-electrolyte van der-Waals' INTERACTION with water molecules. Answer :A

34.	Lower members of aldehydes are soluble in water where as the higher members are not. Give reasons.
Answer» Solution :The lower members are soluble in water, as the carbonyl group is polar and it can FORM intermolecular hydrogen BONDING with water. This .SOLUBILITY decreases with increase in the size of alkyl group. This is because BIGGER alkyl groups increase the non-polar character of the molecule and prevent hydrogen bonding with water.

35.	Lower halogenated ethers can be converted into higher ethers by using _______ reagent.
Answer» GRIGNARD Tollen's Fehling's NONE of the above ANSWER :A

36.	Lowerethers are volatileliquidswhich on evaporation produce cooling. Therefore , they are used in _____________.
Answer» MOTORS REFRIGERATORS . HEATERS washing MACHINE ANSWER :B

37.	Loweraminesare soluble inwater.Thisstatementsis
Answer» False 1 Either ( a) or( B) Cannotsay Solution :Loweraminescan formH - bondwith WATER

38.	Lower aliphatic carboxylic acids are soluble in water where as higher ones are insoluble. Given reason.
Answer» Solution :(i) Lower aliphatic carboxylic acids (up to four carbon) are MISCIBLE with water due to the formation of hydrogen bonds with water. (ii) Higher carboxylic acid are insoluble in water due to increased HYDROPHOBIC INTERACTION of hydrocarbon PART.

39.	Lower aliphatic carboxylic acids are miscible with water but higher carboxylic acids are insoluble in water. Give reason. (or) Acetic acid is soluble in water but hexanoic acid in insoluble in water. Why?
Answer» Solution :Aliphatic ACIDS are miscible with WATER due to the formation of hydrogen bonds with water. Higher carboxylic acids are insoluble in water due to increased hydrophobic interaction of hydrocarbon part. THATS why acetic ACID is soluble in water whereas hexanoic acid is insoluble in water.

40.	Lower aliphatic amines are gases withfishy odour.
Answer» ANSWER :1

41.	Lower alcohols like ethanol and methanol are miscible in water due to ___________
Answer» their ACIDIC character VANDERWAALS force of attraction dipole-dipole inter ACTION inter MOLECULAR hydrogen bonding Answer :D

42.	Loweralcohols are miscible with waterbecauseof the fact that ___________ .
Answer» alcohols undergo solvolysis with WATERMOLECULES alcohols undergo intermolecularhydrogen BONDING with water alcohols undergo intramolecularhydrogen bonding with water alcohols undergo REDUCTION with WATERMOLECULE Answer :B

43.	Lower alcohols are soluble in water, higher alcohols are not. Why ?
Answer» SOLUTION :DUE to FORMATION of HYDROGEN BONDS.

44.	Lower alcohols are highly soluble in water due to_____.
Answer» SOLUTION :H-bonding.

45.	Low volatile nature of H_2SO_4 is due to:
Answer» HYDROGEN bonding van DER WAALS forces Strong bonds None of these Answer :A

46.	Low spin complex of d^6- cation in an octahedral field willhave the following energy. (Delta_0 = crystal field splitting energy in an octahedral field, P= Electron pairing energy)
Answer» <P>`(-12)/5 Delta_0 + P` `(-12)/5 Delta_0 + 3P` `(-2)/5 Delta_0 + 2P` `(-2)/5 Delta_0 + P` Answer :B

47.	Low spin complex is formed by :
Answer» `SP^(3)d^(2)` HYBRIDIZATION `sp^(3)d` hybridization `d^(2)sp^(3)`hybridization `sp^(3)`hybridization ANSWER :D

48.	Low reactivity of ketones with respect to aldehydes is due to
Answer» greater + I EFFECT of alkyl group greater STERIC HINDRANCE of alkyl group both 'a' and 'b' less steric hindrance of alkyl group Answer :C

49.	Low molecular weight alcohols are
Answer» SOLUBLE in water soluble on heating insoluble in water insoluble in all solvent Answer :A

50.	Low molar conductivity at high concentration is due to ________.
Answer» High attractive FORCE between oppositively CHARGED ions Viscous drag DUE to greater solvation both (a) and (B) Neither (a) nor (b) ANSWER :C