Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Libermannreactionis givenonlyby :

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PRIMARY amine
SECONDARY amine
Tetiary amine
NONE of these

Answer :B
2.

Libermann's test used for identification of which functional group in organic compounds

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ALCOHOL
`1^(0)` - amine
Phenolic
aldehyde

Answer :C
3.

Liberation of iodine which gives a …………….colouration with starch.

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SOLUTION :BLUE - BLACK
4.

_____liberates oxygen from water.

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P
Na
`F_2`
`I_2`

ANSWER :C
5.

LiAlH_(4)andNaBH_(4) are

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`H^(+)` DONOR
`H^(-)` donor
`H^(-)` acceptor
None

Answer :B
6.

LiAlH_4is a best reagent to prepare unsaturated alcohol. Prove it.

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Solution :`LiAlH_4` (LITHIUM Aluminium HYDRIDE) does not reduce the carbon-carbondouble BOND present in the carbonyl compound and hence it is the BEST reagent to prepare UNSATURATED alcohol.
`underset(("Prop - 2- enal"))underset("Crotanaldehyde")(CH_3-CH=CH-CHO)underset(H_2O)overset(LiAlH_4)tounderset(("but-2-en-1-ol"))underset("Crotyl alcohol")(CH_3-CH = CH - CH_2OH)`
7.

LiAlH_(4) is a best reagent to prepare unsaturated alcohol. Prove it.

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Solution :`LiAlH_(4)` (Lithium Aluminium Hydride) does not reduce the carbon - carbon double bond present in the CARBONYL compound and hence it is the best reagent to prepare unsaturated alcohol.
`underset("(PROP -2- enal)")underset("Crotanaldehyde")(CH_(3)-CH=CH-CHO)overset(LiAlH_(4))underset(H_(2)O)rarrunderset("(but -2- EN -1- ol)")underset("Crotyl alcohol")(CH_(3)-CH=CH-CH_(2)OH)`
8.

LiAlH_4 is used as :

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An OXIDISING agent
A REDUCING agent
A mordant
A WATER softener

Answer :B
9.

LiAlH_(4) converts acetic acid into-

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Acetaldehyde
Methane
Ethyl alcohol
Methyl alcohol

Solution :`CH_(3)COOH + 4H OVERSET(LiAIH_(4))to CH_(3)CH_(2)OH + H_(2)O`
10.

LiAIH_4 is used as :

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OXIDISING agent
Reducing agent
A mordant
Water softner

Answer :B
11.

Li occupies higher position in the electrochemical series of metals as compared to Cu since

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the standard REDUCTION POTENTIAL `Li^+`/Li is lower than that of `CU^(2+)`/Cu
the standard reduction potential of `Cu^(2+)` /Cu is lower than that of `Li^(2+)`/Li
the standard oxidation potential of `Li^(2+)`/LIT is lower than that of `Cu//Cu^(2+)`
Li is sinaller in size as compared to Cu.

Solution : the standard reduction potential `Li^+`/Li is lower than that of `Cu^(2+)`/Cu
12.

Li occupies higher position in the electrochemical series of metal as compared to Cu, since

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the STANDARD reduction POTENTIAL of `Li^(+)//Li` is lower than that of `Cu^(2+)//Cu`.
the standard reduction potential of `Cu^(2+)//Cu` is lower than that of `Li^(+)//Li`
the standard oxidation potential of `Li//Li^(+)` is lower than that of `Cu//Cu^(2+)`
Li is SMALLER in size as COMPARED to Cu.

Answer :A
13.

Li and Mg both combine with N_(2) at high temp. This suggest that the two metalshave

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HORIZONTAL RELATIONSHIP
vertical relationship
diagonal relationship
no relationship

ANSWER :C
14.

Lewis -structure SO_(4)^(2-)

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15.

The reaction quotient ‘Q.’ is useful in predicting the direction of the reaction. Which of the following is incorrect?

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If `Q_(C) GT K_(c)` , the reverse reaction is favoured
If`Q_(C) lt K_(c)` the forward reaction is favoured.
If`Q_(C) gt K_(c)`forward reaction is favoured.
If `Q_(c) = K_(c)`, no reaction occur.

Solution :(a) If `Q_(c) gt K_(c)`, the reaction will proceed from RIGHT to left i.e., reverse reaction is favoured.
(b) If `Q_(c) lt K_(c)` the reaction will proceed from left to right i.e., forward reaction is favoured.
(d) If `Q_(c) = K_(c)` the reaction is ALREADY at equilibrium and no reaction occurs.
16.

Lewis -structure SO_(3)

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17.

Lewis -structure SO_(2)

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18.

Lewis -structure SiF_(4)

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19.

Lewis -structure SnCl_(3)^(-)

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20.

Lewis -structure SCN^(-)

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21.

Lewis -structure PO_(3)^(-3)

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22.

Lewis -structure OCN^(-)

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23.

Lewis -structure O_(3)

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24.

Lewis -structure NOCl

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25.

Lewis -structure NO_(3)^(-)

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26.

Lewis -structure NO_(2)Cl

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27.

Lewis -structure NO_(2)^(-)

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28.

Lewis -structure NH_(4)^(+)

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29.

Lewis -structure N_(3)^(-)

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30.

Lewis -structure NH_(2)Cl

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31.

Lewis -structure HNC

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32.

Lewis -structure HCN

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33.

Lewis -structure H_(3)O^(+)

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34.

Lewis -structure F_(2)O

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35.

Lewis -structure COCl_(2)

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36.

Lewis -structure CO_(2)

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37.

Lewis -structure CO_(3)^(2-)

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38.

Lewis -structure CN^(-)

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39.

Lewis -structure CO

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40.

Lewis -structureCH_(3)Cl

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41.

Lewis -structure C Cl_(3)

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42.

Lewis -structure BH_(4)^(-)

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43.

Lewis -structure BeF_(4)^(2-)

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44.

Lewis concept of ccovalency of an element involved octet rule. Later on it was found that may elements in their compounds e.g. BeF_(2),BF_(3) etc, have incomplete octet whereas PCl_(5), SF_(6) etcc. Have expanded octet. This classical concept also failed in predicting the geometry of molecules. Modern concept of covalence was proposed in terms of valence bond theory. Hybridization concept along with v.B. Theory successfully molecules was explained by VSEPR concept. Finally molecular orbital theory was proposed to explain many other molecules. Which statements are correct for CO^(+) and N_(2)^(-) according to M.O. Theory: (I) Both have same configuration. (II) Bond order for CO^(+) and N_(2)^(+) are 3.5 and 2.5 (III) Bond order of CO^(+) and N_(2)^(+) are same. (IV) During the formation of N_(2)^(@) from N_(2) bond length increases. (V) During the formation of CO^(+) from CO, the bond length decreases.

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II, IV, V
I, III, IV,V
I,III
I,II,III

Answer :A
45.

Lewis -structure BF_(4)^(-)

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46.

Lewis concept of ccovalency of an element involved octet rule. Later on it was found that may elements in their compounds e.g. BeF_(2),BF_(3) etc, have incomplete octet whereas PCl_(5), SF_(6) etcc. Have expanded octet. This classical concept also failed in predicting the geometry of molecules. Modern concept of covalence was proposed in terms of valence bond theory. Hybridization concept along with v.B. Theory successfully molecules was explained by VSEPR concept. Finally molecular orbital theory was proposed to explain many other molecules. Which are true statements among the following? (i) I_(3)^(+) has bent structure. (ii) P_(pi) - P_(pi) bonds are present in SO_(2). (III) SeF_(4) and CH_(4) has same shape. (IV) XeF_(2) andd CO_(2) has same shape. (V) SF_(4) is sea-saw structure whereas ICl_(3) is T-shaped.

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I,II,IV,V
I,II,III,IV
II,III,IV,V
I,III,IV,V

Solution :`SeF_(4)` is SEA -saw shaped whereas `CH_(4)` is tetrahedral.
47.

Lewis concept of ccovalency of an element involved octet rule. Later on it was found that may elements in their compounds e.g. BeF_(2),BF_(3) etc, have incomplete octet whereas PCl_(5), SF_(6) etcc. Have expanded octet. This classical concept also failed in predicting the geometry of molecules. Modern concept of covalence was proposed in terms of valence bond theory. Hybridization concept along with v.B. Theory successfully molecules was explained by VSEPR concept. Finally molecular orbital theory was proposed to explain many other molecules. The bond angles NO_(2)^(+), NO_(2) and NO_(2)^(-) are respectively.

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`180^(@), 134^(@), 115^(@)`
`115^(@), 134^(@), 180^(@)`
`134^(@), 180^(@), 115^(@)`
`115^(@), 180^(@), 130^(@)`

Solution :Greater the no. of LONE pair on N-atom, SMALLER will be the bond angle.
48.

Lewis base is

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`CO_(2)`
`SO_(3)`
`SO_(2)`
ROH

Solution :ROH is a LEWIS base because it has an lone pair of ELECTRON.
49.

Lewis acids are

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ELECTRON ACCEPTORS
PROTON acceptors
electron donors
proton donors

Answer :A
50.

Lewis acid character of boron trihalides is as a follows :

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`BF_(3) GT BCl_(3) gt BBr_(3) gt BI_(3)`
`BCl_(3)gt BF_(3) gt BBr_(3)gt BI_(3)`
`BI_(3)gt BBr_(3)gt BCl_(3)gt BF_(3)`
`BI_(3) gt BF_(3)gt BCl_(3) gt BBr_(3)`

Answer :C