Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Let's consider a hypothetical planet "pseudo Earth" which is similar to our earth in several aspects. The similarities are On pseudo earth: (i) There are same number of elements as on our earth and they are known by the same name. (ii) Pauli's exclusion principal, Hund's Rule and Aufbau principle are known to the people of pseudo earth in the same manner as we know on our earth. (iii) They classify elements as representative, transition and inner- transition elements in the same manner as we classify on our earth. However, there is one basic difference in understanding the electrons, spin on these two earths. On our earth the electron can have only two spin directions. clock wise (1) and anti-clockwise (2), while on pseudo earth there is an additional possible value of spin quantum number called neutral spin (3) in which electron is believed to be fluctuating harmonically between clockwise and anti-clockwise directions, about its axis. Answer the following three question based on the above information. The long form of periodic table on this pseudo earth will have how many groups?

Answer»

18
24
27
36

Solution :NA
Discussion
2.

Levonorgestrel is a commonly used contraceptive. The number of chiral centres present in this molecule is:

Answer»

4
5
6
7

Answer :C
Discussion
3.

Let's consider a hypothetical planet "pseudo Earth" which is similar to our earth in several aspects. The similarities are On pseudo earth: (i) There are same number of elements as on our earth and they are known by the same name. (ii) Pauli's exclusion principal, Hund's Rule and Aufbau principle are known to the people of pseudo earth in the same manner as we know on our earth. (iii) They classify elements as representative, transition and inner- transition elements in the same manner as we classify on our earth. However, there is one basic difference in understanding the electrons, spin on these two earths. On our earth the electron can have only two spin directions. clock wise (1) and anti-clockwise (2), while on pseudo earth there is an additional possible value of spin quantum number called neutral spin (3) in which electron is believed to be fluctuating harmonically between clockwise and anti-clockwise directions, about its axis. Answer the following three question based on the above information. On pseudo earth, atomic number of the first transition metal wouLd be

Answer»

21
26
29
31

Solution :NA
Discussion
4.

Let's consider a hypothetical planet "pseudo Earth" which is similar to our earth in several aspects. The similarities are On pseudo earth: (i) There are same number of elements as on our earth and they are known by the same name. (ii) Pauli's exclusion principal, Hund's Rule and Aufbau principle are known to the people of pseudo earth in the same manner as we know on our earth. (iii) They classify elements as representative, transition and inner- transition elements in the same manner as we classify on our earth. However, there is one basic difference in understanding the electrons, spin on these two earths. On our earth the electron can have only two spin directions. clock wise (1) and anti-clockwise (2), while on pseudo earth there is an additional possible value of spin quantum number called neutral spin (3) in which electron is believed to be fluctuating harmonically between clockwise and anti-clockwise directions, about its axis. Answer the following three question based on the above information. The first noble gas on pseudo earth would be

Answer»

`He`
`H`
`LI`
`NE`

SOLUTION :NA
Discussion
5.

Let us consider the gases: H_(2)S,CO_(2) and NH_(3) How many of these gases can be dried by conc H_(2)SO_(4) ?

Answer»


ANSWER :1
Discussion
6.

Let us consider emission of alphaparticle from uranium nucleus: ._(92)^(235)U - ._(2)He^(4) to ._(90)Th^(231) {:(e = 92, e = 0, e = 90),(p = 92, p = 2, p = 90),(n = 143, n = 2, n = 141):} shortage of two electorns in thorium is due to:

Answer»

CONVERSION of electrons to positron
combination with positron to evolve energy
annihilation
absorption in the nucleus

Answer :B,C
Discussion
7.

Let us consider a binary solution of two volatile liquids 'A' and B, when taken in a closed container.Both the components would evaporate and an equilibrium would be established between vapour phase and liquid phase .Let the total pressure at this stage be p_("total") and p_A and p_B are partial pressures of A and B. Mole fractions of these components in liquid solution are x_A and x_B, that of vapour phase and y_A and y_B respectively p_A^@ and p_B^@ are vapour pressure of pure A & pure B . Ideal liquid solution follow Raoult's law and non ideal liquid - liquid solution does not follow Raoult's law, deviation is measured in term of activity coefficient gamma gamma=p_("real")/p_("ideal") For water + alcohol solution correct set is :

Answer»

(ii)(b)(Q)
(ii)(c )(R)
(IV)(d)(S)
(iv)(c )(R)

Solution :water+alcohol`to` NON ideal solution with +ve derivation correct code for this solution are (ii),(iv),b,c,d,Q,S
Discussion
8.

Let us consider a binary solution of two volatile liquids 'A' and B, when taken in a closed container.Both the components would evaporate and an equilibrium would be established between vapour phase and liquid phase .Let the total pressure at this stage be p_("total") and p_A and p_B are partial pressures of A and B. Mole fractions of these components in liquid solution are x_A and x_B, that of vapour phase and y_A and y_B respectively p_A^@ and p_B^@ are vapour pressure of pure A & pure B . Ideal liquid solution follow Raoult's law and non ideal liquid - liquid solution does not follow Raoult's law, deviation is measured in term of activity coefficient gamma gamma=p_("real")/p_("ideal") For water + H_2SO_4 solution correct set is

Answer»

(i)(a)(P)
(II)(b)(Q)
(III)(d)(R)
(iv)(C )(P)

Solution :water`+H_2SO_4to` NON ideal solution with -ve deviation correct codes for this solution are (iii),iv,b,c,d,Q,R
Discussion
9.

Let us calculate the emf of the following cell at 25^@C using Nernst equation. Cu(s)|Cu^(2+)(0.25 aq. M)||Fe^(3+)(0.05 aq M)|Fe^(2+)(0.1 aq M)|pt(s)

Answer»

Solution :Given : `(E^@)_(Fe^(3+)|Fe^(2+)) = 0.77 V and (E^@)_(Cu^(2+)|cu) = 0.34V`
HALF reaction are `Cu(s) to Cu^(2+) (aq) + 2e^(-) "" ………(1)`
`2Fe^(3+) (aq) + 2e^(-) to 2Fe^(2+)(aq)"" ……..(2)`
the overall reaction is `Cu(s) + 2Fe^(3+)((aq)) to Cu^(2+)(aq) + 2Fe^(2+)(aq)`, and n = 2 APPLY NERNST equation at `25^@C`
`E_("cell") = E_("cell")^(@) - (0.0591)/(2) log ([Cu^2][Fe^(2+)]^2)/([Fe^(3+)]^(2)) "" [ :. Cu(S) = 1]`
`E_("cell")^(@) = (E_("OX")^(@))_(Cu|Cu^(2+)) + (E_("red")^(@))_(Fe^(3+)|Fe^(2+))`
Given standared reduction potential of `Cu^(2+)|Cu` is 0.34 V
`:. (E_("ox")^@)_(Cu|Cu^(2+)) = -0.34 V`
`(E_("cell")^(@))_(Fe^(3+)|Fe^(2+)) = 0.77 V`
`:. E_("cell")^(@) = -0.34 + 0.77 = 0.43 V`
`:. E_("cell") = 0.43- (0.0591)/2 xx log ((0.25)(0.1)^2)/((0.005)^2)`
`= 0.43 - (0.0591)/2 xx 2`
`= 0.43 - 0.0591`
`= 0.3709V`
`= log((0.25)(0.1)^2)/((0.005)^2)`
`= log(25 xx 10^(-2)xx 1 xx 10^(-2))/(25 xx 10^(-6))`
`= log 10^2`
`= 2 log_(10)10 = 2`.
Discussion
10.

Let us consider a binary solution of two volatile liquids 'A' and B, when taken in a closed container.Both the components would evaporate and an equilibrium would be established between vapour phase and liquid phase .Let the total pressure at this stage be p_("total") and p_A and p_B are partial pressures of A and B. Mole fractions of these components in liquid solution are x_A and x_B, that of vapour phase and y_A and y_B respectively p_A^@ and p_B^@ are vapour pressure of pure A & pure B . Ideal liquid solution follow Raoult's law and non ideal liquid - liquid solution does not follow Raoult's law, deviation is measured in term of activity coefficient gamma gamma=p_("real")/p_("ideal") For Hexane + neptane solution correct set is :

Answer»

(i)(a)(Q)
(II)(B)(P)
(ii)(d)(R)
(i)(d)(P)

Solution :Hexane+neptance `to` IDEAL solution correct code for ideal solution are `to (i)(a),(P)(d)`
Discussion
11.

Let the solubility of an aqueous solution of Mg(OH)_(2) be x then its K_(sp) is

Answer»

`4 x^(3)`
`108 x^(5)`
`27 x^(4)`
9x

Solution :`{:(Mg(OH)_(2)hArr,Mg^(++)+,,2OH^(-)),(,(X),,(2X)^(2)):}`
`K_(sp) = 4X^(3)`
Discussion
12.

Let the solubilities of AgCl in water, in 0.01 M CaCl_(2), in 0.01 M NaCl and 0.05 M AgNO_(3) be S_(1), S_(2), S_(3) and S_(4) respectively. Which of the following relationship between these quantities is correct ?

Answer»

`S_(1)GT S_(2)gt S_(3)gt S_(4)`
`S_(1)gt S_(2)=S_(3)gt S_(4)`
`S_(4)gt S_(2)gt S_(3)gt S_(1)`
`S_(1)gt S_(3)=S_(2)gt S_(4)`

ANSWER :B
Discussion
13.

Let the solubilities of AgCl in H_2O 0.01 M CaCl_2 0.01 M NaCl and 0.05 MAgNO_3 be S_1 , S_2 ,S_3 ,S_4respectively. What is the correct relationship between the quantities?

Answer»

`S_1gtS_2gtS_3gtS_4`
`S_1gtS_2=S_3gtS_4`
`S_1gtS_3gtS_2gtS_4`
`S_4gtS_3gtS_2gtS_1`

ANSWER :C
Discussion
14.

Let the plasma cell wall of shark is a semipermeable membrane. When these cells were kept in a series of NaCl solution of different concentration at 25^(@)C these cells remain intact in 0.7% ((w)/(w)) NaCl solution, shrank in more concetrated solution and swelled in dilute solution. What is the osmotic pressure of the cell cytoplasm at 25^(@)C? given K_(f) of water =1.86kgmol^(-1)K and water freezes from the 0.7%((w)/(w)) salt solution at -0.418^(@)C. Assume solution is dilute in each case. Give your answer to nearest integer. (R=0.0atm(L)/(molK))

Answer»


Solution :In `0.7%` solution no osmosis was there. Here the exerted extra pressure is osmotic pressure
`NaClhArrNa^(+)+Cl^(-)`
Have van't Hoff factor `i=1+(2-1)alpha=(1+alpha)`
`DeltaT_(F)=(K_(f)W_(1)1000)/(m_(1)W_(2))(1+alpha)`
or `(1+alpha)=`
`(DeltaT_(f)M_(1)W_(1)1000)=(0.418xx58.5xxW_(2))/(1.86xx1000xxW_(1))`
as it is `0.7%` solution of NaCl`because(W_(2))/(W_(1))=(99.3)/(0.7)`
`because(1+alpha)=1.86`
ASSUMING dilute solution `100gm` `H_(2)O=100mLH_(2)O`
`becausepiV="in" RT` or `pi=`
`((1+alpha)xxnRT)/(V)=((1+alpha)W_(1)RT)/(M_(1)V)`
or `pi=(1.86xx0.7xx0.08xx298)/(58.5xx0.1)=5.30atm`
Discussion
15.

Let the mass of electron is two times, mass of proton is 1/4^(th) and mass of neutron is 3/2 of original mass. Then, the atomic weight of 6^(C^12) atom

Answer»

INCREASES by 37.5%
DECREASES by 87.5%
Decreases by 12.5%
REMAINS same

Answer :C
Discussion
16.

Let of waveldnth lamda shines on a metal surface with intensity x and the metal emits Y electrons per second of average energy, Z. What will happen to Y and Z if x is doubled?

Answer»

Y will be doubled and Z will become half
Y will remain same and Z will be doubled
Both Y and Z will be doubled.
Y will be doubled but Z will remain same

Solution :When intensity is doubled number of ELECTRONS emitted per second is ALSO doubled but average energy of photoelectrons emitted REMAINS the same.
Hence D is the correct answer.
Discussion
17.

Let hydrolysis constant (K_(h)) ofoverset(+)NH_(4) be y. Then equilibrium constant (K_(a)) for conjugate acid of NH_(3) at 25^(@)C is :

Answer»

`(1)/(y)xx10^(-14)`
`10^(-14)`
`y`
`yxx10^(-14)`

Solution :`NH_(4)^(+)+H_(2)OhArr NH_(4)OH+H^(+):K_("EQ")=K_(h)=K_(a(NH_(4)^(+)))`
Discussion
18.

Let F_(PP),F_(Pn) and F_("nn") denote the magnitude of net force by a proton on a proton, by a proton on a neutron and by a neutron on a neutron respectively. Neglect gravitational force. When the separation is 1 fm :

Answer»

`F_("PP") gt F_("PN") gt F_("NN")`
`F_("pp") = F_("pn") = F_("nn")`
`F_("pp") gt F_("pn") gt F_("nn")`
`F_("pp") LT F_("pn") = F_("nn")`

Answer :d
Discussion
19.

Let a fully charged lead-storage battery contains 1.5 L of 5MH_2SO_2. What will be the concentratisof H_2SO_4 in the battery after 2.5 ampere current is drawn from the battery for 6 hour?

Answer»

4.626M
`0.1865 M `
`0.373 M`
`9.627 M `

Solution :`1F to 1 ` MOLE of `H_2SO_4 ` , 96500 CaCl ` to ` 1 mole
` 2.5 xx 6 xx 60 xx 60 to n = ((2.5 xx 6 xx 60 xx 60 xx 1)/(96500)) = 0.5596` moles
` n = (1.5 xx 5-n) =6.9404 , M^(1) = (n^(1))/(V) = (6.9404)/(1.5) = 4.6269M`
Discussion
20.

Let 'a' be the sum of oxidation number of N atom in products X,Y,Z,W,U,V,T.Find a/2 HNO_2toHNO_3+H_2O+X rArrNH_4Cl+NaNO_2toY+H_2O+NaCl Ba(N_3)_(2)toBa+Z rArr NH_4NO_3oversetDeltatoW+H_2O HNO_3+P_4O_(10)toHPO_3+U rArr Cu+HNO_3(conc.)toCu(NO_3)_2+V+H_2O I_2+HNO_3(conc.)toHIO_3+T+H_2O

Answer»


Solution :`HNO_2toHNO_3+H_2O+NO`
`NH_4Cl+NaNO_2toN_2+H_2O+NaCl`
`Ba(N_(3))_(2)toBa+N_2`
`NH_4NO_3oversetDeltatoN_2O+H_2O`
`HNO_3+P_4O_10toHPO_3+N_2O_5`
`CU+"conc."HNO_3toCu(NO_3)_2+NO_2+H_2O`
`I_2+underset("conc.")(HNO_3)toHIO_3+NO_2+H_2O`
`a=2+0+0+1+5+4+4=16`
Discussion
21.

Lesst reactive alkyl halide towards SN^(2) mechanism is

Answer»

`(CH_(3))_(3)CH-CH_(2)-BR`
`(CH_(3))_(2)CH-CH-Br CH_(3)`
`(CH_(3))_(3)C-CH_(2)-CH_(2)-Br`
`(CH_(3))_(3)C- UNDERSET(C(CH_(3))_(3)) underset(|)(CH)-CH_(2)-Br`

ANSWER :B
Discussion
22.

Less reactivity of ketone is due to

Answer»

`+I`inductive EFFECT DECREASE positive charge on CARBONYL carbon atom
steric effect to two bulky alkyl GROUPS
`sp^(2)` hybridised carbonatom of carbonyl carbon atom
both a and b

ANSWER :D
Discussion
23.

Less reactive elements inboron family is ………………… .

Answer»

BORON
Aluminium
Gallium
Thallium

Answer :B
Discussion
24.

Less acidic among the following list of compounds A : acetic acid B : sulphuric acid C : acetylene D : phenol

Answer»

A
B
C
D

ANSWER :C
Discussion
25.

Lepidolite is an ore of:

Answer»

K
Na
Li
Rd

Answer :C
Discussion
26.

Lepidolite, a lithium ore, also contains:

Answer»

Ru
k`
Na
Cs

Answer :C
Discussion
27.

Length of hydrogen bond ranges from 2.5 overset@A to :

Answer»

3.0 `OVERSET@A`
2.75`overset@A`
2.6 `overset@A`
3.2`overset@A`

ANSWER :B
Discussion
28.

Lemon is sour due to

Answer»

OXALIC ACID
TARTARIC acid
CITRIC acid
malic acid

Answer :C
Discussion
29.

Lemon is sour due to :

Answer»

Citric acid
TARTARIC acid
OXALIC acid
ACETIC acid

ANSWER :A
Discussion
30.

Leibig method is used for the estimation of

Answer»

Nitrogen
Carbon and hydrogen
Sulphur
Halogens

Answer :B
Discussion
31.

Leclanche cell is a non-rechargeable cell. Answer the questions below with respect to Leclanche cell. (i) Anode (ii) Cathode (iii) Electrolyte (iv) Oxidation half cell reaction (v) Reduction halfcell reaction

Answer»

Solution :(i) Anode : Zinc CONTAINER
(ii) Cathode : Graphite ROD in contact with `MnO_(2)`
(iii) Electrolyte : Ammonium chloride and zinc chloride in water
(iv) Oxidation at anode :
`""Zn_((s)) rarr Zn_((AQ))^(2+)+2E^(-)`
(v) Reduction at cathode :
`""2NH_(4(aq))^(+)+2e^(-) rarr 2NH_(3(aq))+H_(2(g))`
Discussion
32.

Leclanche cell is ___________.

Answer»

PRIMARY battery
secondary battery
rechargeable
Both (B) and (C)

ANSWER :A
Discussion
33.

Lecithin is required for _____.

Answer»

normal transport and UTILIZATION of other lipids
ORGANIZATION of cell structure
both (a) and (B)
none of the above

SOLUTION :organization of cell structure
Discussion
34.

Lebel each compound as aromatic, antiaromatic, or not aromatic. Assume all completely conjugated rings are planar.

Answer»


SOLUTION :N/A
Discussion
35.

Least volatile hydrogen halide is

Answer»

HF
HCl
HBr
HI

Answer :A
Discussion
36.

Least stable peroxide among the following :

Answer»

`MgO_(2)`
`CaO_(2)`
`SrO_(2)`
`BaO_(2)`

Answer :A
Discussion
37.

Least stable oxide of chlorine is:

Answer»

`Cl_2O`
`ClO_2`
`Cl_2O_6`
`Cl_2O_7`

ANSWER :A
Discussion
38.

Least stable hydride is

Answer»

Stibine
Pumbane
Silane
Methane

Answer :B
Discussion
39.

Least stable hydride is :

Answer»

METHANE
Plumbane
Silane
Stibine

Answer :B
Discussion
40.

Least soluble alcohol in water is __________.

Answer»




ANSWER :D
Discussion
41.

Least random state of water is:

Answer»

Ice
Liquid water
Steam
All PRESENT in same RANDOM state

Answer :A
Discussion
42.

Least mobile ion is :-

Answer»

`[Be(H_(2)O)_(N)]^(+2)`
`[Na(H_(2)O)_(n)]^(+)`
`[MG(H_(2)O)_(n)]^(+2)`
`[Li(H_(2)O)_(n)]^(+)`

Solution :`["mobility" prop (1)/("size of hydrated ion")]`
Discussion
43.

Least ionic character is found in

Answer»

Mg
SR
Ca
RA

Solution :`overset("Mg lt Ca lt Sr lt BA lt Ra")underset("Ionic nature increases")to`
as we go down the GROUP ionic nature increases because I.E. decreases
Discussion
44.

Least malleable and ductile metal is:

Answer»

Au
Ag
Ni
Bi

Answer :D
Discussion
45.

Which of the following will have the least hindered rotation about carbon-carbon bonds?

Answer»

Ethane
Ethylene
Ethyne
Hexachloroethane

SOLUTION :DUE to SINGLE BOND there is no HINDRANCE.
Discussion
46.

Least energetic conformation of cyclohexane is

Answer»

CHAIR conformation
boat conformation
cis conformation
E-Z FORM

Solution :LEAST ENERGETIC form is the chair form.
Discussion
47.

Least difference between IE2 and IE1 will be found in:

Answer»

LI
B
Be
C

Answer :C
Discussion
48.

Least abundant metal in group 2 is:

Answer»

Sr
Ca
Ra
Be

Answer :C
Discussion
49.

Least abundant metal in II A group is

Answer»

Ra
Ca
Be
Sr

Answer :A
Discussion
50.

Lead sulphate is insoluble in:

Answer»

tConc.`HNO_3`
AMMONIUM acetate
Ammonium hydroxide
All

Answer :D
Discussion