This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Intermolecular forces between two benzene molecules are nearly of same strength as those between two toluene molecules. For a mixture of benzene and toluene, which of the following are not true? |
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Answer» `Delta_(mix)H-zero` |
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| 2. |
Intermolecular attractions among the moleules of any gas are minimum at |
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Answer» `-10^(@)C and 5` ATM |
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| 3. |
Intermolecular dehydration of alcohols gives : |
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Answer» Alkenes |
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| 4. |
Intermolecular dehydration of alcohol gives |
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Answer» Alkenes |
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| 5. |
Intermediates formed during the reaction of RCONH_2 with Br_2and KOH are : |
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Answer» RNHCOBr and RNCO |
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| 6. |
Intermediate product of hydrolysis of cyanide is |
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Answer» `RCOONH_4` |
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| 7. |
Intermediate. |
| Answer» Solution :The species formed during the COURSE of a reaction, which has definite life- TIME and can be isolated. It has energy LOWER than that of the preceing transition STATE, but higher than the REACTANTS or products is called an intermediate. | |
| 8. |
Intermediate product formed in the acid catalysed dehydration of n-propyl alcohol is: |
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Answer» `CH_3 - CH_2 - CH_3` |
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| 9. |
Intermediate compound formation theory is unable to explain the mechanism of ............... |
| Answer» SOLUTION :HETEROGENEOUS CATALYSIS | |
| 10. |
Intermediate involved in Reimer- Tiemann reaction is |
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Answer» CARBOCATION |
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| 11. |
Interhalogen compounds are more reactive than the corresponding halogens. Explain. |
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Answer» TWO halogens are present in place of one |
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| 12. |
Interhalogen compounds are more reactive than the constituent halogens except fluorine - Explain. |
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Answer» Two halogens PRESENT in place of ONE |
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| 13. |
Interhalogen compounds are more reactive than the individual halogen because: |
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Answer» two halogens are present in place of one |
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| 14. |
Interhalogen compounds are compounds formed by combination of different halogen atoms. Which are more reactive, halogens or interhalogen compounds? Give reason |
| Answer» Solution :Interhalogen compounds are more reactive than HALOGENS `(except F_2)`. This is because the COVALENT BOND X-X' in interhalogen compound is WEAKER. than that in halogens, | |
| 15. |
Interhalogen compounds are |
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Answer» IONIC compounds |
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| 16. |
Interferon is a product of biotechnology and is used against : |
| Answer» Answer :A | |
| 17. |
Interfering radicals interfere the testof |
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Answer» Group III radicalsonly |
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| 19. |
Intereferon is connected with |
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Answer» Carbohydrate |
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| 20. |
interaction between dispersed phase and dispersion medium colloids classified on the basis ? |
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Answer» SOLUTION :Classification on the basis of nature of interactions between dispersed phase and DISPERSION medium. These may be classified as (i) LYOPHILIC SOLS and (II) lyophobic sols. |
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| 21. |
Intermolecular hydrogen bonds are not present in : |
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Answer» `CH_3COOH` |
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| 22. |
Inter halogens are more reactive than halogens why? |
| Answer» SOLUTION :The BOND in the INTER halogen X-A is weaker than A-A bond in HALOGENS. This is an account of less effective overlapping between orbitals of dissimilar atoms than those of similar atoms. | |
| 23. |
Intensity of the scattered light depends upon the difference of which of the following property of the dispersed phase and the dispersion medium ? |
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Answer» densities |
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| 24. |
Integrated velocity equation for first order reaction is |
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Answer» `[A]_(o) = [A]e^(-kt)` `k = (2.303)/(t)` log `((A)_(0))/((A))`. |
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| 25. |
Integrated rate expression for rate constant of first order reaction is given by k=2.303/tlog[[R]]_0/[[R]]for general reaction RtoP.Derive an expression for half life period of first order reaction. |
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Answer» SOLUTION :`k=2.303/tlog[[R]]_0/[[R]]`At half life PERIOD, t=t_(1/2)`and `[R]=[R]_0\2` therefore`t_(1/2)`=2.303/klog`([[R]]_0/[[R]])/2t_(1/2)2.303/klog2=0.693/k` |
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| 26. |
Insulin production and its action in human body are responsible for the level of diabetes. This compound belongs to which of the following categories ? |
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Answer» an ENZYME |
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| 27. |
Insulin regulate the metabolism of |
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Answer» minerals |
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| 28. |
Insulin regulates the metabolism of |
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Answer» minerals |
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| 29. |
Insulin is dissolved in a suitable solvent and the osmotic pressure (pi) of solutions of various concentration (g//cm^3) C is measured at 20^@C. The slope of a plote of pi against C is found to be 4.65xx10^(-3) . The molecular weight of the insulin is :- |
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Answer» `3xx10^5` slope = `(RT)/M` `M=(RT)/"slope"=(0.0821xx293)/(4.65xx10^(-3)xx10^(-3))=5.16xx10^6` g |
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| 30. |
Insulin is dissolved in a suitable solvent and the osmotic pressure (TT) of solutions of various concentration (g//cm^(3)) C is measured at 20^(@)C. The slope of a plote of TT against C is found to be 4.65xx10^(-3). The molecular weight of the insulin is |
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Answer» `3xx10^(5)` slope`=(RT)/M` `M=(RT)/("slope")=(0.0821xx293)/(4.65xx10^(-3)xx10^(-3))=5.16xx10^(6)G` |
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| 31. |
Insulin is secreted from |
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Answer» thyroid |
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| 32. |
Insulin is secreted from : |
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Answer» Thyroid |
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| 33. |
Insulin is dissolved in a suitable solvent and the osmotic pressure pi in atm of solutions of various concentrations C in g//cm^(3) is measured at 27^(@) C. The slope of plot of pi against C is found to be 4.1 xx 10^(-3) atm cm^(3)g^(-1). The molecular mass of insulin is: |
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Answer» `6 xx 10^(3)` |
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| 34. |
Insulin is an example of ___ hormone. |
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Answer» PARACRINE |
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| 35. |
Insulin is a protein whichplays the role of ………. . |
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Answer» an ANTIBODY |
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| 36. |
Insulin is a |
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Answer» Non STEROIDAL, PEPTIDE hormone |
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| 38. |
Insulin is |
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Answer» POLYMER of `ALPHA`-AMINO acid |
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| 39. |
Insulin has 51 amino acids in two polypeptide chains which are linked by : |
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Answer» ONE SULPHIDE bond |
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| 40. |
Insulin contains 3.4% sulphur. Then, the minimum molecular mass of the insulin in about. |
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Answer» 940amu `THEREFORE 32G` sulphur will be present in `(100)/(3.4)xx32g` insulin=940 `therefore` Molar mass of insulin is about 940 amu |
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| 41. |
Insulincontains 3.4%sulphur. The minimummolecular weightof insulin is |
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Answer» 350 `:' 3.4 GM` of sulphur PRESENT in `100 gm`. `:' 32 gm` of sulphur present in `= (100xx 32)/(3.4) = 940 gm`. |
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| 42. |
Insulin contains 3.4% sulphur. The minimum molecular weight of insulin is |
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Answer» 944 |
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| 43. |
Insulin (C_(2)H_(10)O_(5))_(n) is dissolved in a suitable solvent and the osmotic pressure (pi) of solutions of various concentrations (C) is measured at 20^(@)C. The slope of the plot of pi (atm) versus C (in g//cm^(3)) is found to be 4.65xx10^(-3). The molecular weight of insulin is |
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Answer» `3.17xx10^(6)` Thus, C' in the formula should be replaced by this factor, i.e., `pi=(Cxx1000)/(M_(2))RT=(1000RT)/(M_(2))C` Thus, a plot of `pi` VS C will be linear with SLOPE `=(1000RT)/(M_(2))=4.65xx10^(-3)"(Given)"` `therefore (1000xx0.0821xx293)/(M_(2))=4.65xx10^(-3)` `"or"M_(2)=5.17xx10^(6)` |
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| 44. |
Insulin contain 3.4% sulphur. Calculate the minimum mass of insullin. |
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Answer» Solution :Minimum MOLECULAR MASS of INSULIN will be the mass containing at least ONE ATOM of sulphur. But one atoms of S = 32 amu Given that 3.4 amu of sulphur is present in 100 amu of insulin `therefore"32 amu of sulphur will be present in insulin"=(100)/(3.4)xx32=941.2amu` Hence, minimum mass of insulin = 941.2 amu. |
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| 45. |
Insulin conatains3.4% sulphur .The minimum mol. Weight of insulin is : |
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Answer» 941.176 |
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| 46. |
Insulin, (C_(2)H_(10)O_(5))_(n) is dissolved in a suitable solvent and the osmotic pressure (pi) of solutions of various cocentrations ("g cm"^(-3)) is measured at 20^(@)C. The slope of the plot of pi against C is found to be 4.65xx10^(-3). Calculate the molecular mass of insulin. |
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Answer» Solution :`pi="CRT where C = MOLAR conc. "("mol L"^(-1))` Given values of C (say C') are in `"g cm"^(-3)`. To CONVERT then into `"mol L"^(-1),` we have `C=(C')/(M_(2))xx1000` `therefore""pi=(1000C')/(M_(2))xxRT.` It is like `y=mx` Hence, plot of `pi " vs " C'` will be LINEAR with slope `=(1000RT)/(M_(2))` `therefore(1000RT)/(M_(2))=4.65xx10^(-3)"or"M_(2)=(1000RT)/(4.65xx10^(-3))=(1000xx0.0821xx293)/(4.65xx10^(-3))=5.17xx10^(6)` |
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| 47. |
Insulin (C_2H_10O_5)_n is dissolved in a suitable solvent and osmotic pressure (pi) of solutions of various concentrations (g cm^-3) C is measured at 20^@C. The slope of a plot of pi against C is found to be 4.65xx10^-3. The molecular weight of the insulin is: |
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Answer» `4.8xx10^5` |
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| 49. |
Insulin, a hormonechemically is ………… .. |
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Answer» TACGAACT |
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| 50. |
Instead of principal quantum number (n), azimuthal quantum number (l) & magnetic quantum number (m), a set of new quantum number s, t & u was introduced with similar logic but different values as defined below s = 1, 2, 3,.......oo all positive integral values. t = (s^(2) - 1^(2)), (s^(2) - 2^(2)), (s^(2) - 3^(2)).........No negative value u = - ((t + 1))/(2) "to" + ((t + 1))/(2) (including zero, if any) in integral steps. Each orbital can have maximum four electrons. (s + t) rule is defined, similar to (n + l) rule. Number of electrons foe which s = 2, t = 3 for an element with atomic number 24 |
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Answer» 8 According to `(s + t)` rule INCREASING order of ENERGY 1s 2s 3s 4s 2f 5s `{:((i),"NUMBER of electron in " s = 2,7 xx 4 = 28,,),(,"Number of electron in " s = 3,19 xx 4 = 76,"Hence (B)",):}` `{:((ii),"For " Z = 24,1s^(8) 2s^(8) 3s^(8) " i.e. number electrons (s) in " s = 2,t = 3 ""[2f^(@)] = 0,),(,"Hence" (C),,,):}` |
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