Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

It is known that entropy of neutralisation of a strong acid and strong base is -13.68kcal/mol.If enthalpy of neutralisation of N_2H_4(hydrazine) with strong acid is equal to -11.68 kcal/mol, then enthalpy of the reaction N_2H_4+H_2OtoN_2H_5^+(aq)+OH^(-)(aq) in Kcal/mol is :

Answer»


SOLUTION :`DeltaH=2` kcal/mol
ENTHALPY of neutralisation is less than-13.68 kcal/mol, because some ENERGY is CONSUMED for ionisation
`:. DeltaH_("ion")=13.68-11.68=2` kcal/mol
Discussion
2.

Inversion of sucrose is……

Answer»

Zero ORDER reaction
`1^(st)` order reaction
`2^()nd` order reaction
`3^(RD)` order reaction

Answer :B
Discussion
3.

It is known that 1g of .^(226)Ra emits 11.6 xx 10^(17) atoms of alpha per years. Given, the half life of .^(236)Ra to be 1600 years, compute the value of Avogadro's number.

Answer»

SOLUTION :Rate `= lambda xx` number of ATOMS in one gram
`= lambda xx ("Avogadro's number")/(226)`
Discussion
4.

Inversion of resistance is known as:

Answer»

CONDUCTIVITY
Resistance
MOLAR conductivity
Limiting molar conductivity

Solution :Conductivity.
Discussion
5.

Inversion of cane sugar is an example of a………………………..reaction.

Answer»

SOLUTION :PSEUDOUNIMOLECULAR
Discussion
6.

It is impossible to measure the actual voltage of any half cell by itselft because :

Answer»

Both HALF cell reactions TAKES PLACE simultaneously
Of resistance of wire
A reaction does not take place on its own
None

Answer :A
Discussion
7.

It is impossible to measure the actual voltage of any half cell by itself because

Answer»

both half CELL reactions take PLACE SIMULTANEOUSLY
of resistance of wire
a REACTION does not take place on its own
polarisation

Solution :Half cell reaction occurs only when it is coupled with other electrode .
Discussion
8.

It is impossible to measure the actual voltage of any half cel by itself because

Answer»

both HALF cell reactions OCCUR simultaneously .
electrical NEUTRALITY is maintained
of resistance of wire
a reaction does not take place of its own

Solution :Cell reaction takes place when half cell are CONNECTED.
Discussion
9.

It is given that for conformational isomers, the net dipole moment mu_(obs)=sum mu_(i)x_(i) Where mu_(obs) = obsereved dipole moment of the compound mu_(i) = dipole moment of the stable conformational isomersX_(1) = mole fraction of stable conformers of the compound Z-CH_(2)-CH_(2)-Z draw the Newman projection formula of all stable conformational isomers, if mu_(obs) = 1D, " and " X_(anti) = 0.82, " find " mu_(gauche). Now draw the Newman projection formula of the most stable conformation of meso Y-CHD-CHD-Y. (a) If Y is CH_(3) ("rotation about "C_(2)-C_(3) " bond") (b) If Y is OH ("rotation about "C_(1)-C_(2) " bond")

Answer»


Answer :`(##RES_CHM_SIM_E03_005_A01##)`
`mu_(obs)=1D ""X_(GAUCHE) =0.18`
`rArrmu_(obs)=summu_(i)X_(i) ""rArr "" 1 = mu_(gauche) xx 0.18 + 0.82 xx 0 "" rArr""mu_(gauche) = (1)/(0 . 18) = 5.55D ""X_(gauche) =0.18`
`(##RES_CHM_SIM_E03_005_A02##)`
(a) If Y is `CH_(3)`, the Newman projection is `(##RES_CHM_SIM_E03_005_A03##)`
(b) If Y is OH, the Newman projection is `(##RES_CHM_SIM_E03_005_A04##)`
Discussion
10.

Inversion of a sugar follows first order rate equation which can be followed by noting the change in rotation of the plane of polarization of light in the polarimeter if r_infty,r_t and t=oo, t=t and t=0, then, first order reaction can be written as:

Answer»

`K=1/t"LOG"(r_1-r_infty)/(r_0-r_infty)`
`K=1/tIn(r_0-r_oo)/(r_t\-r_oo)`
`K=1/tIn(r_oo-r_0)/(r_oo\-r_t)`
`K=1/tIn(r_oo-r_1)/(r_oo\-r_0)`

ANSWER :B
Discussion
11.

It is impossible to attain the lowest temperature known as zero degree absolute. This is a simple statement of:

Answer»

FIRST LAW of thermodynamics
Second law of thermodynamics
Third law of thermodynamics
None

Answer :C
Discussion
12.

It is general principle that the less energy a system contains, it is

Answer»

LESS stable
More stable
Unstable
More unstable

Solution :The less ENERGY of a SYSTEM and more is its STABILITY.
Discussion
13.

It is found that in 11.2 litres of any gaseous compound of phosphorus at NTP, there is never less than 15.5 g of P. Also, this volume of the vapour of phosphorus itself at NTP lueighs 62 g. What should be the atomic weight and molecular weight of phosphorus?

Answer»

SOLUTION :Since 1 mole of any phosphorus COMPOUND contains at least 1 mole of P atoms, and also `22.4` litres (at NTP) of the gaseous compound contains 31 g of phosphorus, therefore, 1 mole of phosphorus WEIGHS 31 g, i.e., 31 is the atomic weight of phosphorus. SIMILARLY, the molecular weight of phosphorus is 124 as 1 mole of its vapour weighs 124 g.
Discussion
14.

Invar' is an alloyof :

Answer»

STEEL and chromium
Vanadium and manganese
Tungstrn and chromium
steel and NICKEL

ANSWER :D
Discussion
15.

Invar steel, which is very little affected by temperature changes, contains 36%:

Answer»

Co
Ni
Cu
Al

Answer :B
Discussion
16.

Invaris an alloyof :

Answer»

STEEL and chromium
Vanadium and manganese
Tungstrn and chromium
steel and NICKEL

ANSWER :D
Discussion
17.

Invar is an alloy of :

Answer»

FE and Ni
Fe , CR and Ni
Cu and SN
Cu and Ni

Answer :A
Discussion
18.

Invar, an alloy of Fe and Ni is used in watches and meter scale, its characteristic property is

Answer»

SMALL COEFFICIENT of expansion
Resistance to corrosion
Hardness and elasticity
Magnetic nature

Answer :A
Discussion
19.

Introductionof fluoridegroup inbenzeneringis moreeasyby

Answer»

electrophilicsubstitution
replacementof diazoniumgroup
NUCLEOPHILICSUBSTITUTION
COUPLINGREACTION

Solution :`Ar - N_(2) ^(+) X^(-)to Ar - X + N_(2)`
Discussion
20.

Intramolecular hydrogen bonding is not present in :-

Answer»

Urea
Chloral hydrate
Salicyladehyde
o-fluoro phenol

Answer :A
Discussion
21.

Intramolecular hydrogen bonding is formed in

Answer»

`H_(2)O`
salicylaldehyde
`NH_(3)`
benzophenone

Solution :Intramolecular hydrogen bonding occurs within TWO atoms of the same molecule
Discussion
22.

Intramolecular aldol condensation : The aldol condensation also offer a convenient way to synthesize molecules with five and six membered ring.This can be done by an intramolecular aldol condensation using a dialdehyde, a keto aldehyde or a diketone as the substrate.The major product is formed by the attack of the enolate from the ketone side of the molecule that adds to the aldehyde group.The reason the aldehyde group undergoes addition preferentially may arise from the greater reactivity of aldehyde towards nucleophilic addition.In reaction of this type five membered rings from far more readily than seven membered rings and six membered rings are more favourable than four or eight membered rings when possible. 1-Etylcyclopent-1-ene on reductive ozonolysis followed by aq. NaOH//Delta gives

Answer»




SOLUTION :
Discussion
23.

Intramolecular aldol condensation : The aldol condensation also offer a convenient way to synthesize molecules with five and six membered ring.This can be done by an intramolecular aldol condensation using a dialdehyde, a keto aldehyde or a diketone as the substrate.The major product is formed by the attack of the enolate from the ketone side of the molecule that adds to the aldehyde group.The reason the aldehyde group undergoes addition preferentially may arise from the greater reactivity of aldehyde towards nucleophilic addition.In reaction of this type five membered rings from far more readily than seven membered rings and six membered rings are more favourable than four or eight membered rings when possible. Which of the following compound on reaction with O_3//Zn, H_2O followed by aq. NaOH//Delta will form

Answer»




SOLUTION :
Discussion
24.

Intramolecular aldol condensation : The aldol condensation also offer a convenient way to synthesize molecules with five and six membered ring.This can be done by an intramolecular aldol condensation using a dialdehyde, a keto aldehyde or a diketone as the substrate.The major product is formed by the attack of the enolate from the ketone side of the molecule that adds to the aldehyde group.The reason the aldehyde group undergoes addition preferentially may arise from the greater reactivity of aldehyde towards nucleophilic addition.In reaction of this type five membered rings from far more readily than seven membered rings and six membered rings are more favourable than four or eight membered rings when possible. The true statement about the major product of CH_3-oversetOoverset(||)C-CH_2-CH_2-CH_2-CH_2-oversetoverset(O)(||)C-H in reaction with aq.NaOH followed by heating is.

Answer»

It gives yellow ppt with `I_2//overset(THETA)OH`
It gives SILVER mirror with Tollen's reagent
It show stereoisomerism
It does not GIVE yellow ppt with 2,4-DNP

Solution :
Discussion
25.

Into a gas bulb of 2.83 litres, are introduced 0.174 g of H_(2) and 1.365 g of N_(2) which can be assumed to behave ideally. The temperature is 0^(@)C. What are the partial pressures of H_(2) and N_(2) and what is the total gas pressure ? What are the mole fractions of each gas ? What are pressure fractions ?

Answer»

<P>

SOLUTION :`pH_(2)//p = nH_(2)//N = 0.639`
Discussion
26.

Intra-molecular H-bonding is possible in which of the following.

Answer»

cis-cyclohexane-1,2-diol
trans-cyclohexane-1,2-diol
cis-cyclohexane-1,3-diol
cis-cyclohexane-1,4-diol

Solution :Due to Hydrozen bonding Gauche conformation of `H_(2)N-CH_(2)-CH_(2)-NH_(2) " and " HO-CH_(2)-CH_(2)-F` are more stable than ANTI CONFORMATIONS. In case of `CICH_(2)CH_(2)CI` on INCREASING temperature % of Gauche conformation increases. Hence dipole moment increases. In case of option (D) BOAT conformation is more stable.
Discussion
27.

Interstitial compounds are formed when small atoms are trapped inside the crystal lattice of metals. Which of the following is not the characteristic property of interstitial compounds ?

Answer»

They have high MELTING points in comparison to PURE metals.
They are very hard.
They retain METALLIC CONDUCTIVITY.
They are chemically very REACTIVE

Solution :They are chemically very reactive
Discussion
28.

Interstitial compounds are formed when small atoms are trapped inside the crystal lattic of metals . Which of the followings is not the characteristic property of interstitial compounds ?

Answer»

They have high MELTING points in comparison to PURE metals
They are very hard
They retain metallic conductivity
They are chemically very reactive

Solution :INTERSTITIAL COMPOUNDS are chemically inert
Discussion
29.

Interparticle forces present in nylon-6, 6 are

Answer»

van der WAAL 's
hydrogen bonding
dipole-dipole interactions
None of the above

Solution :Nylon-6, 6 is a polyamide having -CONH-, oxygen of CO of amide linkage is LINKED to H of NH of the other -CONH-linkage
Discussion
30.

Interstitial compounds are formed by

Answer»

`FE, CO`
`Co, NI`
`Fe, Ni `
all of THES

ANSWER :D
Discussion
31.

Intersititial compounds are formed when small atoms are trapped inside the crystal lattice of metals. Which of the following is not th echaracteristic property of interstitial compounds?

Answer»

They have high melting points in comparison to PURE metals
They are very hard
They retain METALLIC conductivity
They are chemically very reactive

Solution :Interstitial compounds are chemically INERT
Discussion
32.

Interparticle forces present In Nylon -66 are

Answer»

VANDER Waal's
hydrogen BONDING
dipole-dipole attraction
none of theabove

ANSWER :B
Discussion
33.

Internal Energy (E,also denoted by U): Every system having some quantity of matter is associated with a definite amount of energy, called internal energy. E=E_("Transiational")+E_("Rotational")+E_("Vibrational")+E_("bonding")+.... DeltaE=E_("Final")-E_("initial") DeltaE=q_v, heat supplied to a gas at constant volume, since all the heat supplied goes to increase the internal energy to the gas. It is an extensive property & a state function.It is exclusively a function of temperature. If DeltaT=0 , DeltaE=0 as well. The internal energy of a certain substance is given by the following equation : U=3 PV+84 where U is given in kJ/kg, P is in kPa, and V is in m^3//kg A system composed of 3 kg of this substance expands from an initial pressure of 400 kPa and a volume of A 0.2 m^3 to a final pressure 100 kPa in a process in which pressure and volume are related by PV^2=constant. Explain the difference in work transfer in question (6.25) and (6.26).

Answer»

SOLUTION :The work in (6.25) is not equal to `INT PDV` since the PROCESS is not quasi-static
Discussion
34.

Internal Energy (E,also denoted by U): Every system having some quantity of matter is associated with a definite amount of energy, called internal energy. E=E_("Transiational")+E_("Rotational")+E_("Vibrational")+E_("bonding")+.... DeltaE=E_("Final")-E_("initial") DeltaE=q_v, heat supplied to a gas at constant volume, since all the heat supplied goes to increase the internal energy to the gas. It is an extensive property & a state function.It is exclusively a function of temperature. If DeltaT=0 , DeltaE=0 as well. The internal energy of a certain substance is given by the following equation : U=3 PV+84 where U is given in kJ/kg, P is in kPa, and V is in m^3//kg A system composed of 3 kg of this substance expands from an initial pressure of 400 kPa and a volume of A 0.2 m^3 to a final pressure 100 kPa in a process in which pressure and volume are related by PV^2=constant. In another process the same system expands according to the same pressure-volume relationship as in above question, but from the same initial state of the final state as in above question, but the heat transfer in this case is +30 kJ.Then the work transfer for this process is :

Answer»

`-80 kJ`
`-60 kJ`
`-90 kJ`
`-150 kJ`

Solution :SINCE the end states are the same, `DELTAU` would remain the same as in above PROBLEM.
`W=DeltaU-q`
`W= -120-30= -150 kJ`
Discussion
35.

Internal energy of an ideal gas depends on

Answer»

VOLUME
Temperature
Pressure
None of these

Solution :Internal energy of an IDEAL GAS is a function of temperature only.
Discussion
36.

Internal energy of an ideal gas depends on:

Answer»

Pressure
Temperature
Volume
None

Answer :B
Discussion
37.

Internal Energy (E,also denoted by U): Every system having some quantity of matter is associated with a definite amount of energy, called internal energy. E=E_("Transiational")+E_("Rotational")+E_("Vibrational")+E_("bonding")+.... DeltaE=E_("Final")-E_("initial") DeltaE=q_v, heat supplied to a gas at constant volume, since all the heat supplied goes to increase the internal energy to the gas. It is an extensive property & a state function.It is exclusively a function of temperature. If DeltaT=0 , DeltaE=0 as well. The internal energy of a certain substance is given by the following equation : U=3 PV+84 where U is given in kJ/kg, P is in kPa, and V is in m^3//kg A system composed of 3 kg of this substance expands from an initial pressure of 400 kPa and a volume of A 0.2 m^3 to a final pressure 100 kPa in a process in which pressure and volume are related by PV^2=constant. If the expansion is quasi-static, then the value of q is :

Answer»

80 kJ
60 kJ
40 kJ
120 kJ

Solution :U=3PV+84
`DeltaU=U_2-U_1=3(P_2V_2-P_1V_1)`
`THEREFORE DeltaU=3(P_2V_2-P_1V_1)`
Now, `P_1V_1^2=P_2V_2^2`
`:. V_2=V_1(P_1/P_2)^(1//2)=0.2(4/1)^(1//2)=0.4`
`DeltaU=300(1xx0.4-4xx0.2)kJ = -120 kJ`
For a quasi-static process
`W=intPdV=(P_2V_2-P_1V_1)/(n-1)`
`=((1xx0.4-4xx0.2)100)/(2-1)=-40 kJ`
`:. DeltaU=q+W`
q=-120+40=-80 kJ
Discussion
38.

Internal energy does not include

Answer»

Nuclear ENERGY
Rotational energy
Vibrational energy
Energy ARISING by GRAVITATIONAL pull

Solution :`E=E_(el e).+E_("nucl")+E_("CHEMICAL")+E_("POTENTIAL")+E_("kinetic")(E_(t)+E_(v)+E_(r))`.
Discussion
39.

Internal energy does NOT include ____________ .

Answer»

NUCLEAR energy
rotational energy
vibrational energy
energy ARISING by gravitaional pull

Answer :D
Discussion
40.

Internal energy and pressure of a gas per unit volume are related as

Answer»

`P=(2)/(3) E`
`P= (3)/(2) E`
`P = (1)/(2) E`
`P =2E`

SOLUTION :`K.E. - (3)/(2) RT = (3)/(2)PV`
`:. P=(2)/(3) (E)/(V)` for unit VOLUME `(V =1 ) impliesP=(2)/(3) E `
Discussion
41.

Internal energy and pressure of a gas of unit volume are related as:

Answer»

`P=2//3U`
`P=3//2U`
`P=U//2`
P=2U

Answer :A
Discussion
42.

internal energy and pressure ofa gas of unit valume are related as

Answer»

<P>`P =2/3E`
`P=E/2`
`P= 3/2E`
P=2E

Solution :INTERNAL ENERGY `E=3/2RT=3/2PRightarrowP2/3 E`
Discussion
43.

Intermolecular hydrogen bonds are not present in _________

Answer»

`CH_(3)COOH`
`C_(2)H_(5)OC_(2)H_(5)`
`CH_(3)CH_(2)OH`
`C_(2)H_(5)NH_(2)`

Answer :B
Discussion
44.

Intermolecular hydrogen bonding is strongest in:

Answer»

Methylanine
Phenol
Formaldedyte
Methanol

Solution :Hydrogen bonding is formed in compounds in which H is attached to HIGHLY electronegative element LIKE F, 0 and N.
In `H-CHO`, Ois not having H atom so it shows very LITTLE H-bonding.
(ii) N is less electronegative than 0, so .H-bond formed by amines will be weak lhan that by alcohols.
(iii) `C_(6)H_(5)OH` forms weak H-bonding due to steric hinderance due to bulky phenyl group.
Discussion
45.

Intermolecular hydrogen bondig in ethylene glycol leads to its

Answer»

HIGH VISCOSITY
high BOILING point
HYGROSCOPIC nature
all the above

ANSWER :D
Discussion
46.

Intermolecular hydrogen bond is present in which of the following pair of molecules ?

Answer»

`SiH_4 and SiF_4`
`CH_3-oversetoverset(O)(||)C-CH_3 and CHCl_3`
`H-oversetoverset(O)(||)C-OH and CH_3-oversetoverset(O)(||)C-OH`
`CH_3OCH_3 and H_2O_2`

SOLUTION :Both COMPOUNDS have INTERMOLECULAR H-bonding AMONGST themselves and with WATER.
Discussion
47.

Intermolecular H-bonding in strongest in:

Answer»

Methylamine
Phenol
Formaldehyde
Methanol

Answer :D
Discussion
48.

Intermolecular forces between two benzene molecules are nearly of same strength as those between two toluene molecules. For a mixture of benzene and toluene, which of the following are not true ?

Answer»

`Delta_(mix)H=` ZERO
`D_(mix)V=` zero
These will form MINIMUM boiling azeotrope.
These will not form ideal solution.

Solution :Explanation : In a mixture of benzene and toluene intermolecular FORCES between benzene and toulene molecules would be nearly of the same strength as those of TWO benzene molecules and two toluene molecules separately. The solution will, therefore, form an ideal solution & obey Raoult.s law. So, the option (iii) & (iv) not true.
Discussion
49.

Intermolecular forces in solid hydrogen are :

Answer»

Covalent FORCES
VAN DER WAALS forces
Hydrogen bonds
All of these

Answer :B
Discussion
50.

Intermolecular forces betweentwo benzene molecules are nearly of same strength as those between two toluene molecules. For a mixture of benzene and toluene, which of the following are not true?

Answer»

`Delta_("mix")H="ZERO"`
`Delta_("mix")V=zero`
These will FORM minimum boiling azeotrope
These will not form ideal solution

Solution :They will form ideal solution for which `Delta_("mix")H=0, Delta_("mix")V=0`. Hence, (a) and (B)are TRUE. But (c) and (d) are not true (Ideal solutions do not form azeotropes).
Discussion