Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the reaction involving C-OH bond, in alcohols the order of reactivity is :

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`1^@ GT 2^@ gt 3^@`
`3^@ gt 2^@ gt 1^@`
`2^@ gt 3^@ gt 1^@`
None

Answer :B
2.

In the reaction I_(2)+2S_(2)O_(3)^(2-)to2I^(-)+S_(4)O_(6)^(2-), the equivalent weight of iodine will be equal to

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MOLECULAR weight
1/2 the molecular weight
1/4 the molecular weight
Twice the moelcular weight

Solution :`underset((0))(I_(2))+2S_(2)O_(3)^(-)to underset((-2))(2I^(-))+S_(4)O_(6)^(2-)`
`therefore`EQ. wt. `=(1)/(2)XX`molecular wt.
3.

In the reaction I_(2)+I^(-) rarr I_(3)^(-), the Lewis base is

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`I_(2)`
`I^(-)`
`I_(3)^(-)`
NONE of these

Solution :It donates their `e^(-)` pair.
4.

In the reaction, HNO_3 + P_4O_10 to 4HPO_3+X,the product X is

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`N_2O_5`
`H_2O`
`NO_2`
`N_2O_3`

Solution :`4HNO_3 + P_4O_10 to 4HPO_3 + 2N_2O_5`
NITROGEN PENTOXIDE can be FORMED by heating `P_4O_10` with CONC. Nitric ACID .
5.

In the reaction HNO_(3)+P_(4)O_(10) to 4HPO_(3)+x , the product x is

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`N_(2)O_(3)`
`N_(2)O_(5)`
`NO_(2)`
`H_(2)O`

Solution :We know that, `4HNO_(3) +P_(4)O_(10) to 4HPO_(3) +2N_(2)O_(5)` the product is dinitrogen pentaoxide `(N_(2)O_(5))`
6.

In the reaction HCOOH overset(H_2 SO_4) to CO + H_2 O, H_2 SO_4 acts as

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Dehydrating agent
OXIDIZING agent
Reducing agent
All of these

Solution :Only dehydrating agent
`HCOOH overset(H_(2)SO_(4))to CO +H_(2)O`
7.

In the reaction HgCl_2 + 2KI rarr M + 2KCl, M is :

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`HgI_2`
`K_2HgI_3`
`K_2HgI_4`
`KHgI_3`

ANSWER :C
8.

In the reaction +Hclrarr the major product formed is

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SOLUTION :N//A
9.

In the reaction :HCN+H_(2)O hArr H_(3)O^(+)+CN^(-)the conjugate acid - base pair is

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1. `HCN, H_(3)O^(+)`
2. `HCN,CN^(-)`
3. `H_(2)O, CN^(-)`
4. `CN^(-), H_(3)O^(+)`

Answer :B
10.

In the reaction HCl + H_(2)O hArr H_(3)O^(+) + Cl^(-)

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`H_(2)O` is the CONJUGATE base of HCl acid
`Cl^(-)` is the conjugate base of HCl acid
`Cl^(-)` is the conjugate acid of `H_(2)O` acid
`H_(3)O^(+)` is the conjugate base of HCl

SOLUTION :HCl is a STRONG acid and their conjugate base is a very weak base.
11.

In the reaction : HC -= CH overset(NaNH_(2))rarr X overset(CH_(3)I)rarr Y underset(HgSO_(4))overset(H_(2)O, H_(2)SO_(4))rarr Z, Z is :

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`CH_(3)CHO`
`CH_(3)CH_(2)CH = CH_(2)`
`CH_(3)COCH_(3)`
`CH_(3)CH_(2)CHO`

Solution :`HC -= CH overset(NaNH_(2))rarr CH -= CNa overset(CH_(3)I)rarr CH -= C - CH_(3) underset(HgSO_(4))overset(H_(2)O, H_(2)SO_(4))rarr""{:(CH_(2) =,C - CH_(3)),(,"|"),(,OH),(,uarr),(CH_(3),underset(O)underset(||)(C CH_(3))):}`
12.

In the reaction HAsO_(2)+Sn^(2+) rarr As+Sn^(4+)+H_(2)O oxidising agent is

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`Sn^(2+)`
`Sn^(4+)`
`As`
`HAsO_(2)`

Solution :Oxidizing agent itself, undergoes REDUCTION during a redox REACTION
`OVERSET(+3)(HAsO_(2))+overset(+2)(Sn) rarr overset(0)(As)+overset(+4)(Sn)+H_(2)O`
Hence, here `HAsO_(2)` is acting as oxidizing agent.
13.

In the reaction H_(3)C-overset(Br)overset(|)CH-CH_(2)-Brunderset((ii)C_(2)H_(5)Br)overset((i)"X mole "NaNH_(2))toCH_(2)-C-=C-C_(2)H_(5) The value of [X] is:

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ONE
Two
Three
Four

Answer :B
14.

In the reaction: H_(2)S hArr 2H^(+) + S^(-), when NH_(4)OH is added, then

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`S^(--)` is precipitate
No reaction takes places
Concentration of `S^(--)` decreases
Concetration of `S^(-)` increases

Solution :In `IV^(th)` GROUP the `S^(2-)` concentration increase when ADDED the `NH_(4)OH` because
`NH_(4)OH hArr NH_(4)^(+) + OH^(-)`
`H_(2)S hArr 2H^(+) + S^(2-)`
`OH^(-) + H^(+) hArr H_(2)O`. So that `S^(2-)` is increased.
15.

In the reaction H_(2)S+O_(3) to ………. the products are:

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`H_(2)O`
S
`O_(2)`
`SO_(2)+H_(2)`

SOLUTION :`H_(2)S+O_(3) to H_(2)O +S+O_(2)`
16.

In the reaction H_2S + O_3 rarr…….the products are:

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`H_2O, S, O_2`
`H_2SO_4 + O_2`
`H_2O + S`
`SO_2 + H_2O`

ANSWER :A
17.

In the reaction H_(2)O + HCl rarr H_(3)O^(+) + Cl^(-), the species that acts as Bronsted base is

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`H_(2)O`
HCl
`H_(3)O^(+)`
`Cl^(-)`

SOLUTION :Bronsted BASES are proton aceptors.
18.

In the reaction H_(2(g))+3H_(2)hArr2NH_(3(g)), the value of the equlibrium constatn depends on

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VOLUME of the REACTION vessel
Total PRESSURE of the system
The initial CONCENTRATION of nitrogen and HYDROGEN
The tempereatue

Answer :D
19.

In the reaction, H_2O_2 +Na_2CO_3 rarrNa_2O_2 +CO_2 +H_2O,the substance undergoing oxidation is :

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`H_2O_2`
`Na_2CO_3`
`Na_2O_2`
NONE of these

Answer :D
20.

In the reaction : H_2O + Br_2 toHOBr + HBr, Br_2 gets ............

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Only reduced<BR>Only oxidized
Disproportionates
Neither oxidised nor reduced

Solution :`H_(2)O + underset(0)(Br_(2)) to underset(+1)(HOBR) + underset(-1)(HBr)`
21.

In the reaction, H_(2)+I_(2)hArr 2.Hl. In a 2 litre flasek 0.4 moles of HI each H_(2) and I_(2) are taken. At equlibrium 0.5 moles of HI are formed. What will be the value of equilibrium constant, k_(c)

Answer»

`20.2`
`25.4`
`0.284`
`11.1`

SOLUTION :`{:(H_(2),+I_(2),hArr2HI),(0.4,0.4,0.50),(0.4-0.25=0.15//2,0.4-0.25=0.15//2,0.50//2):}`
`K_(C)=([H]^(2))/([H_(2)][I_(2)])=([(0.5)/(2)]^(2))/([(0.15)/(2)][(0.15)/(2)])=(0.5xx0.5)/(0.15xx0.15)=11.11`
22.

In the reaction H-C=C-H overset(NaNH_(2))to A overset(CH_(3)l)to B overset(Hg^(2+))underset(H_(3)O^(+))to C the final product 'C' is :

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`CH_(3)CHO`
`CH_(3)CH_(2)CHO`
`CH_(3)-overset(O)overset(|)C-CH_(3)`
`CH_(3)CH_(2)COOH`

ANSWER :C
23.

In the reaction: H_(2)+Cl_(2)rarr2HCl, DeltaHCl, DeltaH=194 kJ.Heat of formation of HCl is

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`+ 97` KJ
`+ 194 kJ`
`- 194 kJ`
`- 97 kJ`

SOLUTION :HEAT of FORMATION = `(194)/(2)=97` kJ.
24.

In the reaction H-C-=CH underset((2)CH_3CH_2Br)overset((1)NaNH_2//liq.NH_3)toXunderset((2)CH_3CH_2Br)overset((1)NaNH_2//liq.NH_3)toY X and Y are

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X=1-Butyne : Y=3-Hexyne
X=2-Butyne : Y=3-Hexyne
X=2-Butyne : Y=2-Hexyne
X=1-Butyne : Y=2-Hexyne

Solution :
25.

In the reaction, H-C-=C-overset(NaNH_(2))rarrAoverset(CH_(3)l)rarrBoverset(Hg^(2+))underset(H_(3)O^(+))rarrCn the final product 'C' is :

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`CH_(3)CHO`
`CH_(3)CH_(2)CHO`
`CH_(3)-overset(O)overset(||)C-CH_(3)`
`CH_(3)CH_(2)COOH`

Answer :C
26.

In the reaction given below, X is Neo-pentyl alcohol overset(H_(2)SO_(4))to X

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2-methypentane
2-methylpent-2-ene
2-methylbut-2-ene
Neo-pentane

Solution :`H_(3)C-UNDERSET(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-OH underset(-H_(2)O)overset(H^(+))toH_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-overset(+)CH_(2)overset(CH_(3)^(-)"shift")toCH_(3)underset(+)overset(CH_(3))overset(|)C-CH_(2)-CH_(3)overset(-H^(+))to underset({:(2-"methyl-2-butene"),("(major product)"):})(CH_(3)-overset(CH_(3))overset(|)C=CH-CH_(3))`
27.

In the reaction given below : Which of the following statements is/are incorrect ?

Answer»

The reaction proceeds via `S_(N)2` mechanism hence INVERSION of configuration takes place.
The reaction proceeds via `S_(N)1` mechanism hence inversion of configuration takes place.
The reaction proceeds via `S_(N)2` mechanism hence their is no CHANGE in the configuration.
The reaction proceeds via `S_(N)1` mechanism hence there is no change in THECONFIGURATION.

SOLUTION :Inversion of configuration takes place in `S_(N)2` mechanism.
28.

In the reaction given below, X is C_(6)H_(5)MgBr+CH_(3)OHrarrX

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`C_(6)H_(6)`
`C_(6)H_(5)OH`
`C_(6)H_(5)OCH_(3)`
`CH_(3)COOH`

Solution :Grignard reagents react with compounds having ACTIVE hydrogen atom to GIVE corresponding hydrocarbon.
29.

In the reaction given below, how many different oximes would be fomred? CH_(3)CH=CH-overset(O)overset(||)C-CH=CHCH_(3)+H_(2)NOHrarr"Oximes"

Answer»


ANSWER :3
30.

In the reaction for the transition of carbon in the diamond form to carbon in the graphite form, DeltaH is -453.5 cal. This points out that

Answer»

Graphite is CHEMICALLY different from diamond
Graphite is as stable as diamond
Graphite is more stable than diamond
Diamond is more stable than graphite

Solution :`C_(D)rarrC_(G),DeltaH=-453.5 cal`.
i.e. ENERGY of `C_(G)` is less and thus more stable.
31.

In the reaction, Fe(OH)_(3)hArrFe_(aq)^(3+)+3OH_(aq)^(-) if the concentration of OH^(-) ions is decreased by (1)/(4) times , then the equilibrium concentration of Fe^(3+) will increases by

Answer»

8 TIMES
16 times
64 times
4 times

Solution : `K_(c) = [X][3X]^(3)`
When concentration of `OH^(-)` oins is decreased by
`(1)/(4)` times , `K_(C)=[x.][(3x)/(4)]^(3)`….(II)
equating eq (i) and (ii)
`xxx(3x)^(3)=x.((3x))/(4)^(3)`
64x=x.
32.

In the reaction Fe_(2)O_(3)+3Cto2Fe+3CO, oxidation number of C

Answer»

increases by 3 per atom
decreases by 3 per atom
increases by 2 per atom
no change.

Answer :C
33.

In the reaction "Ethyl bromide"overset(KCN)rarr Xoverset(H_(2)//Ni)underset(or LiAlH_(4))rarr Y, Y is :

Answer»

n - PROPYLAMINE
Ethylamine
Propionamide
Propane.

Solution :`CH_(3)CH_(2)Br overset(KCN)rarr CH_(3)CH_(2)Cnoverset(H_(2),Ni)underset(LiAlH_(4))rarr underset("n - Propylamine")(CH_(3)CH_(2)CH_(2)NH_(2))`
34.

In the reaction , Etheroverset(" hot " HI)to A+B + H_2 O , If A and Bare same , the ether __________

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is SIMPLE
is mixed
is simpleor mixed
cannot be PREDICTED unless the natureof ALKYL RADICALS is known

Answer :A
35.

In the reaction :Ethnol overset(PCl_5)to X overset("alc KOH")to Y underset("H_2 O_2 Delta)overset(H_2 SO_4. "Room temp.")to Z, the product Y is,

Answer»

`C_(2)H_(4)`
`CH_(3)CH_(2)OCH_(2)CH_(3)`
`CH_(3)CH_(2)OSO_(3)H`

Solution :
`CH_(3)CH_(2)OHoverset(H_(2)SO_(4)"ROOM temp")underset(H_(2)O,Delta)toCH_(2)=CH_(2)`
36.

In the reaction Ethanol overset(PCl_5)to X overset(alc. KOH)to Y overset(H_2SO_4//H_2O)underset(298K) to Z. The 'Z' is ………………….. .

Answer»

ETHANE
ethaoxyethane
ethylbsulphite
ETHANOL

Solution :`CH_3 - CH_2 - OH OVERSET(PCl_5)to CH_3-CH_2-Cl overset(alc.KOH)toCH_2 = CH_2overset(H_2SO_4//H_2O)tounderset((Z)"ethanol")(CH_3-CH_2-OH)`
37.

in the reaction, DeltaH and DeltaS both are more than zero then in which of the following cases the reaction would be spontaneous

Answer»

`DeltaHgtTDeltaS`
`TDeltaSgtDeltaH`
`DeltaH=TDeltaS`
`DELTAGGT0`

ANSWER :B
38.

In the reaction (##DBT_SM_CHE_XII_U_12_E01_015_Q01##) The structure of product A is:

Answer»




ANSWER :A
39.

In the reaction , Cu(s)+2Ag^(+)(aq)rarrCu^(2+)(aq)+2Ag(s), the reduction half cell reaction is

Answer»

`Cu+2e^(-)rarrCu^(2+)`
`Cu-2e^(-)rarrCu^(2+)`
`AG^(+)+e^(-)rarrAg`
`Ag^(-)e^(-)rarrAg^(+)`

Solution :Copper UNDERGO oxdiation while SILVER `(Ag^(+))` undergo REDUCTION.
40.

In the reaction Cu_((s))+2Ag_((aq))^(+)toCu_((aq))^(2+)+2Ag_((s)) the reduction half-cell reaction is:-

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`Cu+2e^(-)TOCU^(2-)`
`Cu-2e^(-)toCu^(2+)`
`Ag^(+)+E^(-)toAg`
`Ag-e^(-)toAg^(+)`

ANSWER :C
41.

In the reaction C(s) +CO(g) hArr 2CO(g) the equilibrium pressure is 12 atm. If 50% of CO_2 reacts, calculated K_p.

Answer»


ANSWER :8 ATM
42.

In the reaction C(s) + CO_2(g) hArr 2CO(g) the equilibrium pressure is 12 atm. If 50% OF CO_2 reacts. Calculate the K_P for the change:

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12 atm
16 atm
20 atm
6 atm

Answer :B
43.

In the reaction , Cr_2O_7^(2-) + 14H^+ +6I → 2Cr^(3+) + 7H_2 O +3I_(2 which element is reduced ?

Answer»

I
O
H
Cr

Answer :D
44.

In the reaction : CrO_(4)^(2-) + X to Cr_(2)O_(7)^(2-) X is

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`OH^(-)`
`H_(2)O`
`H^(+)`
`O_(2)`

ANSWER :C
45.

In the reaction Cr_2O_3+ 2Al to Al_2O_3 + 2Cr, DeltaG^@ = - 421 kJ is thermodynamically feasible. This is apparent from Gibbs energy value. Why does it not take place at room temperature ?

Answer»

Solution :The reaction is thermodynamically FAVOURABLE. As we know, even thermodynamicallyfavourable reactions require some activation ENERGY to PROCEED, therefore, this reaction does not occur at ROOM temperature. Heating is REQUIRED for this reaction to start.
46.

In the reaction COCl_2(g)hArr CO(g)+Cl_2(g) at 550^@C, when the initial pressure of CO & Cl_2 are 250 and 280 mm of Hg respectively. The equilibrium pressure is found to be 380 mm of Hg.Calculate the degree of dissociation of COCl_2 at 1 atm.What will be the extent of dissociation, when N_2 at a pressure of 0.4 atm is present and the total pressure is 1 atm.

Answer»

0.32 and no change
0.32 and 0.4
0.4 and 0.3
In presence of `N_2` DISSOCIATION cannot take place

Solution :`{:(,CoCl_2(G)hArr,CO(g)+Cl_2(g)),("Initial PRESSURE",-,250""280),("Equilibrium pressure",x,250-x " " 280-x):}`
x+250-x+280-x=380
x=150
`K_P=0.114`
`K_P=(P_(CO).P_(Cl_2))/(P_(COCl_2))implies K_P=(alpha^2 . P)/(1-alpha^2) implies 0.114 =(alpha^2 . 1)/(1-alpha^2)`
hence `alpha=0.32 " " alpha=0.32`
In presence of `N_2` (CONSTANT pressure process)
`K_P=(alpha^2xx0.6)/(1-alpha^2)implies alpha=sqrt(0.114/0.714)implies alpha=0.4`
`alpha` increases from 0.32 to 0.4
47.

In the reaction CO_(2)(g)+H_(2)(g)rarrCO(g)+H_(2)O(g),DeltaH=80 kJDeltaHis known as

Answer»

HEAT of formation
Heat of combustion
Heat of NEUTRALIZATION
Heat of REACTION

Solution :`DELTAH` for this reaction is Heat of reaction.
48.

In the reaction : CO_(2)(g) + H_(2)(g) hArr CO(g) + H_(2)O(g), Delta H = 2.8 kJ.Delta H represents

Answer»

HEAT of reaction
heat of combustion
heat of formation
heat of solution

Answer :A
49.

In the reaction Cl_(2) + CH_(4) overset(hv)(to) CH_(3) Cl + HCl , presence of a small amount of oxygen

Answer»

Increases the rate of REACTION for a brief PERIOD of time
DECREASES the rate of reaction for a brief period of time
Does not affect the rate of reaction
COMPLETELY stops the reaction

Solution :Presence of SMALL amount of oxygen completely stops the reaction .
50.

In the reaction :Cl_(2)+2OH^(-)toOCl^(-)+Cl^(-)+H_(2)O

Answer»

`OH^(-)`is OXIDISING and `CL^(-)` is REDUCING agent
`Cl_(2)` is oxidising and `OH^(-)` is reducing agent
`OH^(-)`is both oxidising and reducing agent
`Cl_(2)`is both oxidising and reducing agent.

Solution :`Cl_(2)+2OH^(-)toOCl^(-)+Cl^(-)+H_(2)O`
O.N . Of Cl changes from 0 to +1 (in `Ocl^(-))and-1 "in" (Cl^(-))`.