Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the reaction 4A+2B+3CrarrA_(4)B_(2)C_(3). What will be the number of moles of product formed, starting from one of

Answer»

0.25
0.3
0.24
2.32

Solution :`4A+2B+3CrarrA_(4)B_(2)C_(3)`
1MOL 0.6mol 0.72 MOL
2.

In the reaction 4A + 2B + 3C to A_4B_2C_3, the number of moles of product formed will be if starting from 2 moles of A, 1.2 moles of B and 1.44 moles of C

Answer»

0.48
0.3
0.6
1

Answer :A
3.

In the reaction : ""_(4)^(9)Be+Xto""_(5)^(10)B+gamma X is:

Answer»

proton
deutron
`ALPHA`-particle
neutron.

Answer :B
4.

In the reaction : 3CuO+2NH_(3)toN_(2)+3H_(2)O+3Cuthe change of NH_(3) to N_(2) involve

Answer»

Loss of 6 ELECTRONS per mol of `N_(2)`
Loss of 3 electrons per mol `N_(2)`
Gain of 6 electrons per mol of `N_(2)`
Gain of 3 electrons per mol of `N_(2)`

SOLUTION :
5.

In the reaction : 3BrO^(-)toBrO_(3)^(-)+2Br^(-) (aqueous alkaline medium at 80^(@)C) the value of the rate constant in the rate law in terms of -(d)/(dt)[BrO^(-)] is 0.056 Lmol^(-)s^(-1). What will be the rate constant when the rate law is stated in terms of (d)/(dt)[BrO_(3)^(-)] ?

Answer»

`18.7xx10^(-3)Lmol^(-1)s^(-1)`
`37.4xx10^(-3)Lmol^(-1)s^(-1)`
`0.08187Lmol^(-1)s^(-1)`
`18.7xx10^(-2)Lmol^(-1)s^(-1)`

ANSWER :C
6.

In the reaction : 3Br_(2)+6CO_(3)^(2-)+3H_(2)Oto5Br^(-)+BrO_(3)^(-)+6HCO_(3)^(-)

Answer»

Bromine is oxidised and CARBONATE is reduced
Bromine is neither oxidised nor reduced
Bromine is oxidised and WATER is reduced
Bromine is both reduced and oxidised.

Solution :For the REACTION :
`Zn(s)+2H^(+)(aq)toZn^(2+)(aq)+H_(2)(g)`
`E=E^(@)-(RT)/(nF)"in "([Zn^(2+)](pH))/([H^(+)]^(2))`
On adding `H_(2)SO_(4)`, the `[H^(+)]`increases . This will increases the value of E and , therefore reaction PROCEEDS more to the right.
7.

In the reaction :3Br_(2)+6CO_(3)^(2-)+3H_(2)Oto5Br^(-)+BrO_(3)^(-)+6HCO_(3)^(-)

Answer»

`Br_(2)`is oxidised and carbonate is reduced.<BR>Bromine is reduced and water is oxidised.
Bromine is neither reduced nor oxidised
Bromine is both reduced and oxidised.

Solution :The O.N of bromine decreases from 0 to -1 (in `Br^(-)` and INCREASES from 0 to +5 (in `BrO_(3)^(-))`.
8.

In the reaction , 3Br_2 +6CO_3^(2-) +3H_2O rarr5Br^(-)+BrO_3^(-)+6HCO_3^- which statement is correct ?

Answer»

`Br_2`is oxidised
`Br_2` is REDUCED
`Br_2` is NEITHER oxidised nor reduced
`Br_2` is oxidised as WELL as reduced

Answer :D
9.

In the reaction, 3A rarr 2B rate of reaction, +(d[B])/(dt) is equal to

Answer»

`-1/3(d[A])/(dt)`
`-2/3(d[A])/(dt)`
`+(2D[A])/(dt)`
`-3/2(d[A])/(dt)`

Solution : In a REACTION,
`3Ararr2B`
RATE of reaction =`-1/3(d[A])/(dt)=+1/2(d[B])/(dt)`
`therefore (d[B])/(dt)=-2/3(d[A])/(dt)`
10.

In the reaction

Answer»

`H_(3)PO_(2)` and `H_(2)O`
`H^(+)//H_(2)O`
`HgSO_(4)//H_(2)SO_(4)`
`Cu_(2)Cl_(2)`.

Solution :`H_(3)PO_(2)` and `H_(2)O` brings about replacement of DIAZONIUM chloride GROUP by H.
11.

In the reaction 3 Mg+N_(2) rarr Mg_(3)N_(2)

Answer»

Magnesium is reduced
Magnesium is oxidized
NITROGEN is oxidized
None of these

Solution :In the given reaction oxidation state of `MG` is CHANGING from 0 to +2 while in nitrogen it is changing from 0 to -3. So oxidation of Mg and reduction of nitrogen takes place.
12.

In the reaction 2X+B_(2)H_(6)to[BH_(2)(x)_(2)]^(4)][BH_(4)]^(-) the amine(s) X are )

Answer»

 `NH_(3)`
`CH_(3)NH_(2)`
`(CH_(3))_(2)NH`
`(CH_(3))_(3)N`.

SOLUTION :Due to BULKINESS of trimethylamine, it does not REACT.
13.

In the reaction

Answer»




SOLUTION :
14.

In the reaction 2S_(2)O_(3)^(2-)+I_(2)to S_(4)O_(6)^(2-)+2I^(-) the eq. wt of Na_(2)S_(2)O_(3) is equal to its

Answer»

MOL .WT
mol.wt/8
mol. wt/6
none of these

ANSWER :a
15.

In the reaction 2NO_((g))+O_(2(g))rarr2NO_(2(g)) , the order of the reaction with respect to O_2is ..........

Answer»

ZERO order
FIRST order
second order
Third order

ANSWER :B
16.

In the reaction 2NO_((g))+O_(2(g))rarr2NO_(2(g)) , the order of the reaction with respect to NO is ..........

Answer»

FIRST ORDER
second order
thirdorder
ZERO order

Answer :B
17.

In the reaction 2NO_((g))+O_(2(g))rarr 2NO_(2(g)), the order of the reaction with respect to NO is …………….

Answer»

FIRST ORDER
SECOND order
third order
zero order

Solution :second order
18.

In the reaction 2NO+O_(2)to2NO_(2), if the rate of disappearance of O_(2) is 16 "gm min"^(-1), then the rate of appearance of NO_(2) is

Answer»

`"90 gm. MIN"^(-1)`
`"46 gm. min"^(-1)`
`"28 gm. min"^(-1)`
`"32 gm. min"^(-1)`

ANSWER :B
19.

In the reaction 2NO+Cl_2 to 2NOCl, it has been found that doubling the concentration of both the reactants increases the rate by a factor of eight but doubling the chlorine concentration alone only doubles the rate. Which of the following statements is incorrect?

Answer»

The reaction is first ORDER in ` Cl_2`
The reaction is second order in NO
The overall order of reaction is 2
The overall order of reaction is 3.

Solution :`(i) r_(1) = k [ NO]^(x) [Cl_(2)]^(y)`
(ii) `8 r_(2) = k [ 2NO]^(x) [2Cl _(2)]^(y)`
(III) `2r_(3)= k [NO]^(x) [2Cl_(2) ]^(y)`
Dividing (ii) by (iii) , `4 = 2^(x)`
or x = 2
Dividing (iii) by (i) , 2 = `2^(y)` or y = 1 .
Overall order x+ y = 2 + 1= 3.
20.

IN the reaction,2NO + CI_(2) to2NOCI it has been found that doubling the concentration of both the reactants increases the rate by a factor of eight butdoubling the chlorine concentration alone only doubles the rate. Which of the following statements is incorrect ?

Answer»

The reaction is FIRST order in ` CI_(2)`
The reaction is second order in NO.
The OVERALL order of reaction is 2.
The overall order of reaction is 3.

Answer :D
21.

In the reaction 2N_(2)O_(5) to 4 NO_(2) + O_(2) , initial pressure is 500 atm and rate constant K is 3.38 xx 10^(-5) "sec"^(-1) . After 10 minutes the final pressure of N_(2)O_(5) is

Answer»

490 atm
250 atm
480 atm
420 atm

Solution :`p_(0) = 500 ` atm , `K = (2.303)/(t) "log"_(10) (p_(0))/(p_(t))`
`3.38 xx 10^(-5) = (2.303)/(10 xx 60) "log" (500)/(p_(t))`
or `0.00880 `= log `(500)/(p_(t)) implies (500)/(1.02) = 490` atm .
22.

In the reaction :2Na_2S_2O_3 + I_2 rarr Na_2S_4O_6 +2NaIthe equivalent weight of Na_2S_2O_3 is equal to :

Answer»

M
M/2
M/3
M/4

Answer :A
23.

In the reaction 2NaOH+H_3PO_4 to Na_2HPO_4 + 2H_2O, the Equivalent weight of the acid is

Answer»

49
98
`32.6`
`36.5`

ANSWER :A
24.

In thereaction 2KMnO_4 +16 HCIto 5CI_2+2MnCI_2 +2KCI+8H_2 O thereducedproductis

Answer»

`CI_2`
`MnCI_2`
`H_2 O`
`KCI`

SOLUTION :`K OVERSET(+7)(MnO_4) +HCI^(-4)tooverset(0 ) CI _2 + overset( +2)MnCI_2+KCI +H_2O`
thusdecreases ) HENCETHE reducedto`MnCI_2`( becauseO.Nof Mndecreases)hencethe reducesproductis `MnCI_2 `
25.

In the reaction, 2H_(2)S+SO_(2) to 3S+2H_(2)O, H_(2)S is

Answer»

REDUCING AGENT
oxidizing agent
precipitating agent
an acid

Answer :A
26.

In the reaction, 2KMnO_4 + 16 HCI rarr 2KCI +2MnCI_2 + 8H_2O + 5CI_2,the reduction product is :

Answer»

`CI_2`
`MnCI_2`
KCI
`H_2O`

ANSWER :B
27.

In the reaction, 2KI + H_2O + O_3 rarr 2KOH + O_2 + A

Answer»

`KIO_3`
`I_2O_5`
`HIO_3`
`I_2`

ANSWER :D
28.

In the reaction 2H_(2)O hArr H_(3)O^(+) + OH^(-), water is

Answer»

A weak base
A weak ACID
Both a weak acid and a weak base
Neither an acid nor a base

Solution :Because their CONJUGATE base and conjugate acids are STRONG.
29.

In the reaction2H_2 + O_2 to 2H_2O acts as a catalytic poison for Pt catalyst .

Answer»

CO
MO
`As_2O_3`
`H_2S`

SOLUTION :Co
30.

In the reaction, 2FeSO_(4)+H_(2)SO_(4)+H_(2)O_(2)toFe_(2)(SO_(4))_(3)+2H_(2)O. The oxidizing agent is :

Answer»

`FeSO_(4)`
`H_(2)SO_(4)`
`H_(2)O_(2)`
both `H_(2)SO_(4) and H_(2)O_(2)`

SOLUTION :`H_(2)O_(2)` gets reduced to `H_(2)O`.
31.

In the reaction 2FeCI_3+H_2S to2FECI_2 +2HCI +S

Answer»

` FeCl_3` acts as an OXIDISING agent
both `H_2 S and FeCl_3` are oxidised
`FeCI_3` is oxidised while `H_2S` is REDUCED
`H_2 `S acts as an oxidising agent

Solution :`overset(+3)(2FeCI_3 ) + H_2 overset(-2) Stooverset( +2) (2FeCI_2) + 2HCI+ overset(0 )S`
here`FeCI_3`actsas anoxidating AGENTAND OXIDISES`H_2S `toS .
32.

In the reaction: 2CuCl_2 + 2H_2O + SO_2 to A + H_2SO_4 + 2HCl, A is:

Answer»

`Cu_2Cl_2`
`CU`
`CuSO_4`
`CUS`

ANSWER :A
33.

In the reaction 2Ca_(3)[PO_(4)]_(2)+6SiO_(2) overset(Delta)to6CaSiO_(3) +P_(4)O_(10)

Answer»

<P>a weaker acid anhydride replaces a stronger one
a stronger acid anhydride replaces a weaker one
both acid anhydrides have equal strength
NONE of these

Solution :In this reaction a weaker acid anhydride replaces a stronger one because `P_(4)O_(10)` is VOLATILE while `SiO_(2)` is not.
34.

In the reaction 2CuCl_2 + 2H_2O + SO_2 rarr A + H_2SO_4 + 2HCl, A is

Answer»

`CuCl_2`
CU
`CuSO_4`
Cus

Solution :`2CuCl_2 + 2H_2O + SO_2 RARR Cu_2Cl_2 + H_2SO_4 + 2HCL`
35.

In the reaction 2(CH_3)_2CO overset(OH^(-))to X underset((ii) H_3O^(+))overset((i)I_2NaOH)to Y, the product Y is :

Answer»

`CH_3CH = CHCOOH`
`(CH_3)_2 C = CHCOOH`
`CH_3 COOH`
`CH_3 CH =UNDERSET(CH_3)underset(|)C-COOH`

Answer :B
36.

In the reaction 2Br^(-) + X_2 toBr_2 + 2X^(-) ,X_2 is

Answer»

`Cl_(2)`<BR>`Br_(2)`
`I_(2)`
`N_(2)`

ANSWER :A
37.

In the reaction, 2Al_(s) + 6hCl_(aq) to 2Al_(aq)^(3+) + 6Cl_(aq)^(-) + 3H_(2)(g)

Answer»

11.2 L `H_(2)(g)` at STP is produced for every mole `HCl_(aq)` consumed
6 L `HCl_(aq)` is consumed for every 3 L `H_(2)(g)` produced
33.6 L `H_(2)(g)` is produced at STP for every mole Al that reacts.
67.2 L `H_(2)`(g) at STP is produced for every mole Al that reacts.

Solution :`2Al_(s) + 6HCl_(aq) to 2Al_(aq)^(3+) + 6Cl_(aq)^(-) + 3H_(2)(g)`
At STP, 6 moles of HCl produce 3 moles of `H_(2) = 3 xx 22.4 L` of `H_(2)`
Against at STP, 2 moles of Al produce 3 moles of `H_(2) = 3 xx 22.4` L of `H_(2)`
`THEREFORE 1` mole of Al produce `=(3 xx 22.4)/2 = 33.6` L of `H_(2)` at STP.
38.

In the reaction : 2Al(s) + 6HCl(aq) rarr 2 Al^(3+)(aq) + 6 Cl^(-)(aq) + 3H_(2)(g)

Answer»

<P>

Solution :`2Al(s) + 6HCL(AQ) rarr 2Al^(3+)(aq) + 6Cl^(-)(aq) + 3H_(2)(G) `
`:' 6 "mol es of HCl produce = 3 mol es of" H_(2) = 3 xx 22.4 L of H_(2) at S.T.P.`
`:'1 mol es of HCl p r o d u c e = 3 xx 22.4/6 Lof H_(2)at S.T.P. = 11.2 Lof H_(2) at S.T.P.`
39.

In the reaction : 2Al (s) + 6HCl(aq) to 2Al^(3+) (aq) + 6Cl^(-) (aq) + 3H_2O(g)

Answer»

33.6L `H_2`(G) is produced regardless of temperature and PRESSURE for every mole Al that reacts.
67.2 L `H_2`(g) at STP is produced for every mole Al that reacts.
11.2 L `H_2`(g) at STP is produced for every mole HCl (AQ) consumed.
6L HCl (aq) is consumed for every `3L H_2` (g)is produced.

Solution :For each mole of Al reacted 1.5 mole of `H_2` (g) (or 33.6 L at STP )is formed and for each mole of HCl consumed 0.5 mole of `H_2` (g) (or 11.2 L at STP) is formed
40.

In the reaction, 2Ag + H_2SO_4 rarr Ag_2SO_4 + 2H_2O + SO_2, H_2SO_4 is:

Answer»

REDUCING agent
Oxidant
Catalyst
Dehydrating agent

Answer :B
41.

In the reaction: 2Ag+2H_2SO_4 rarrAg_2SO_4 +2H_2O +SO_2,H_2SO_4 acts :

Answer»

OXIDISING agent
Reducing agent
Dehydrating agent
None of these

Answer :A
42.

In the following reaction, H_2 SO_4 acts as 2 Ag + H_2 SO_5 rarr Ag_2 SO_4 + 2 H_2 O + SO_2.

Answer»

REDUCING AGENT
OXIDIZING agent
Catalytics agent
Dehydratinon agent

ANSWER :B
43.

In the reaction 2A+Bto2C+D, 5 mol/lt of A are allowed to react with 2 mol/lt of B. After 5 seconds the concentration of A was found to be 4 molar. What is the rate of reaction in tems of A?

Answer»

`0.1 M"SEC"^(-1)`
`0.2M"sec"^(-1)`
`0.3M"sec"^(-1)`
`0.15 M"sec"^(-1)`

Solution :`underset(5)(2A)+underset(3)(B)tounderset(0)(2C)+underset(0)(D)`
`(5-2x)(3-x)2XX,x=1//2,r_(A)=(5-4)/5=1/5=0.2` M/sec `, r=1/2xx(-d[A])/(DT)=0.2/2=0.1` M/sec
44.

In the reaction, 2A+Bto2C+D, the rate of disappearance of 'A' is 2.6xx10^(-2)"M-S"^(-1). Then the rate of disappearance of B and the rate of appearance of C and D are respectively

Answer»

`5.2xx10^(-2),5.2xx10^(-2),2.6xx10^(-2)`
`1.3xx10^(-2),2.6xx10^(-2),1.3xx10^(-2)`
`2.6xx10^(-2),2.6xx10^(-2),2.6xx10^(-2)`
`2.6xx10^(-2),5.2xx10^(-2),5.2xx10^(-2)`

ANSWER :B
45.

In the reaction 2A + B to Products, the order w.r.t. A is found to be one and w.r.t. B equal to 2. Concentration of A is doubled and that of B is halved, the rate of reaction will be

Answer»

DOUBLED
halved
remain UNAFFECTED
four TIMES

Solution :`R_(1) = K [A] [B]^(2) "" …. (i)`
`R_(2) = k [2A] [ (1)/(2) B]^(2) "" … (ii)`
`therefore (R_(2))/(R_(1)) = (k[2A] [(1)/(2) B]^(2))/(k [A] [B]^(2))= 2 XX (1)/(4) = (1)/(2)`
`therefore R_(2) = (1)/(2) R_(1)`
46.

In thereaction2A +Btoproducts theorderw.r.tA isfoundto beoneandw.r.tB equalto2 .ConcentrationofAisdoubledand thatof Bishalved, therateof reactionwillbe

Answer»

double
halved
REMAIN unaffected
fourtimes

ANSWER :B
47.

In thereaction2A+ B toA_(2)Bthe rateofconsumptionof reactant A is

Answer»

HALFOF theconsumptionrateof B
Equalto theconsumption RATEOF B
Twiceto theconsumptionrate B
equalto therateof formationof`A_(2 )` B

SOLUTION :`-(1)/(2)(d[A])/(dt) =-(d[B])/(dt)`
48.

In the reaction 2A+Bto Products the order w.r.t A is found toi be 1 and w.r.tequal to 2. Concentration of A is doubled and that of B is halved, the rate of reaction will be

Answer»

Doubled
Havaled
Remain unaffected
Four times

Answer :B
49.

In the reaction 2A + B to A_2B, if the concentration of A is doubled and of B is halved, then the rate of the reaction will:

Answer»

Increase by four times
DECREASE by two times
Increase by two times
REMAIN the same

Answer :C
50.

In the reaction 2 S_(2) O_(3)^(2-) + I_(2) toS_(4) O_(6)^(2-) + 2I^(-) . The eq. wt. of Na_2 S_(2) O_(3) is equal to its

Answer»

MOL wt./6
Mol wt./2
`2 XX` mol.wt
Mol wt

Answer :D