Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the reaction, 2" NO"_(2)(g)+F_(2)(g)to2" NO"_(2)F(g), order with respect to NO_(2) is……………………….and that with respect to F_(2) is………………. .

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ANSWER :1, 1
2.

In the reaction 1. H_(2)O_(2)+O_(3) to H_(2)O+2O_(2) 2. PbS+4O_(3) to PbSO_(4)+4O_(2)

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`O_2` is REDUCED both in (a) and (b)
`O_(3)` is enodined both in (a) and (b)
`O_(3)` is OXIDIZED in (a) and reduced in (b)
`O_(3)`, is reduced in (a) and oxidized in (b)

Solution :Reaction (a) occurs as FOLLOWS:
`O_3 to O_(2)+O`
`H_(2)O_(2)+O to H_2O+O_(2)`
=`H_(2)O_(2)+O_(3) to H_(2)O+2O_(2)`
In this reaction, `O_(3)` is also reduced to `O_(2)`, Reaction
(b) occurs as follows:
`4O_(3) to 4O_(2)+4O`
`PbS+4O to PbSO_(4)+4O_(2)`
In this reaction, `O_(3)` is also reduced to `O_(2)`
3.

In the reaction 1/2N_(2(g)) + 3/2 H_(2(g)) to NH_(3(g)). The standard entropies of N_(2(g)), H_(2(g)) and NH_(3(g)) are 191.6,130.5 and 192.5 JK^(-1) "mol"^(-1) respectivly. If free energy charge of the reaction is -16.67 kJ. Calculate the Delta H_("reaction")^@ for the formation of NH_3 at 298 K.

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SOLUTION :`-46.19 KJ`
4.

In the reaction :

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Solution :NBS (N - BROMOSUCCINIMIDE) CAUSES allylic bromination.
5.

In the reaction A (g) + B (g)hArr C (g), the backward reaction is favoured by (A) Increase in pressure

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Decrease of PRESSURE
Increase of pressure
EITHER of the two
NONE of the two

Answer :A
6.

In the Rasching process for the manufactureof phenol, the catalyst being used as _______

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ANHYDROUS `AlCl_3`
cobaltnaphthenate
`Al_3O_3`
`SiO_2`

ANSWER :D
7.

In the radioactive decay {:(._(z)X^(A) rarr _(Z+1)Y^(A)rarr_(Z-1)Z^(A-4) rarr_(Z-1)Z^(A-4)),("high energy" "low energy"):} the sequence of the radiation emitted is :

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`ALPHA, BETA,GAMMA`
`gamma, alpha,beta`
`beta,gamma, alpha`
`beta,alpha,gamma`

ANSWER :D
8.

In the Ramsay - Rayleigh's second method, 2NO_2 + 2NaOH to NaNO_2 + X + H_2O . Where 'X' is the nitrogen compound, then Oxidation state of nitrogen in 'X' is ___________

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Solution :`2NO_2+ 2NaOH to NA^(+3) NO_2+ Na^(+5)NO_3+ H_2O. NO_3^(-1) to X - 6 = -1 , x = -1+ 6 = + 5`
9.

In the radioactive decay, ""_(92)X^(232) to ""_(89)Y^(20) , how many alpha and beta particles are ejected from X to from Y ?

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`3 ALPHA and 3 beta`
`5 alpha and 3 beta`
`3 alpha and 5 beta`
`5 alpha and 5 beta`

SOLUTION :`""_(92)^(232)X to ""_(89)^(220)Y, alpha = (232 - 220)//4 = 3`
`beta = 89 - (92 - 3 xx 2) = 3`
10.

In the radioactive decay of an element, the emitted electrons come from-

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Inner ORBITAL of the atom
Is orbital of the atom
Nucleus of the atom
The OUTERMOST shell of the atom

Answer :C
11.

In the radioactive decay: ""_(Y)X^(Z)overset(-(8alpha and 6beta))to""_(82)Pb^(206)X, y and z are

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U, 92 and 235
Th, 90 and 232
Pu, 94 and 238
U, 92 and 238.

Solution :`y-8(2)+6(1)=82,y=92`
`z-8(4)=206 ,:.z=238`
So, X is `""_(92)U^(238)`
12.

In the radioactive decay ._(92)X^(232) rarr ._(89)Y^(220), how many alpha and beta-particles are ejected from X to form Y

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`3 ALPHA and 3 beta`
`5 alpha and 3 beta`
`3 alpha and 5 beta`
`5alpha and 5 beta`

SOLUTION :`._(92)X^(232) rarr ._(89)Y^(220) + x_(2) he^(4) + y ._(-1)E^(0)`
No. of `alpha -`PARTICLES `= (232 - 220)/(4) = 3`
No. of `beta-`particles `= 2 xx - 92 + 89 = 3`
13.

In the quantitative volumetric analysis, why is K_(2)Cr_(2)O_(7) preferred over Na_(2)Cr_(2)O_(7) ?

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Solution :`Na_(2)Cr_(2)O_(7)` is a deliquescent and so it is not used to prepare PRIMARY standard solution, WHEREAS `K_(2)Cr_(2)O_(7)` is not a deliquescent substance and hence it is preferred over `Na_(2)Cr_(2)O_(7)`.
14.

In the raction sequence, Ethane overset(HOCl)toAoverset(X)toEthan - 1,2- diol. A and X respectively are ………………… .

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Chloroethane and NaOH
ethanol and `H_2SO_4`
`2 - chloroethan - 1 - OL and NaHCO_3`
ethanol and `H_2O`

Solution :`{:("(X)"),(CH_2=CH_2overset(HOCl)toCH_2-CH_2overset(NaHCO_3)underset(-NaCl)toCH_2-CH_2),(""|""|""|""|),(""OH""Cl ""-CO_2" "OH""Cl):}`
15.

In the Q.No , 108 if theconcentration of the reactant is less than 1 M , then, :

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`r_(1)=r_(2)=r_(3)`
`r_(1)gtr_(2)gtr_(3)`
`r_(1)ltr_(2)ltr_(3)`
all of these

Answer :B
16.

In the Q.No 108 , if theconcentration of the reactant is 1 M , then :

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`r_(1)=r_(2)=r_(3)`
`r_(1)gtr_(2)gtr_(3)`
`r_(1)ltr_(2)ltr_(3)`
all of these

ANSWER :A
17.

In the qualitative analysis of group 3 cations blood red colouration is a test for

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IRON using CYANIDE as ligand
chromium using cyanide as ligand
iron using thiocyanide as ligand
chromium using thiocyanide as ligand

ANSWER :C
18.

In the purification of impure nickel by Mond's process, metal is purified by:

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Electrolytic reduction
Vapour PHASE thermal DECOMPOSITION
Thermite reduction
Carbon reduction

Solution :`underset(("IMPURE "))(Ni) + 4CO overset(50 ^@" to "60^@ C )tounderset("volatile compound") ( [ Ni (CO)_4uarr]`
` underset(" thermaldecomposition ") overset(200 "to " 230^@ C ) tounderset("pure") ( Ni+ 4CO uarr)`
19.

In the purification of copper by electrolysis, which is incorrect ?

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Acidic solution of Cu (II)sulphate is used
`H_3O^+` ion is discharged at CATHODE
ANODE is made of impure COPPER
`OH^-` is discharged at anode

Answer :B
20.

In the production of quinoline this compound is isolated from the reaction mixture by steam distillation. Calculate (a) at what temperature the mixture of water and quinoline will boil under a pressure of 740,mm Hg. (b) What is the maximum number of grams of quinoline which can be distilled with 1000g water vapour under this pressure. The temperature dependence of vapour pressure. The temprature dependence of vapour pressure of water and quionoline is given as follows : Molecular weight of quinoline =129

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Solution :(a) This is an immiscible mixture of WATER and quinoline, so
`P_(1)^(@)+P_(2)^(@)=740`
By the HELP of table, we can say
`=98.5+((99-98.5))/((741.21727.95))xx(740-727.95)=98.54`.
21.

In the purification bauxite by Hall's process

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The bauxite oreheated with concentrated NaOH solution at `150^(@)C`
The bauxite ore is HEATED with `NaHCO_(3)`
The bauxite ore is mixed with ooke and heated at `1800^(@)C` in u current of `N_(2)`
The bauxite ore is FUSED with `Na_(2)CO_(3)`

Answer :D
22.

In the purification of bauxite by Hall's process

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The BAUXITE ONE is heated with concentrated NaOH solution at `150^(@)C`
The bauxite ore is heated with `NaHCO_(3)`
The bauxite ore is mixed with coke and heated at `1800^(@)C` in a current of `N_(2)`
The bauxite ore is fused with `Na_(2)CO_(3)`

Solution :The Hall.s process is
`Al_(2)O_(3)+Na_(2)CO_(3) to 2NaAlO_(3)+CO_(2)`
`2NaAlO_(2)+3H_(2)+CO_(2) to 2Al(OH)_(3)+Na_(2)CO_(3)`
23.

In the process of wine making, ripened grapes are crushed so that sugar and enzyme should come in contact with each other and fermentation should start. What will happen if anaerobic conditions are not maintained during thisi process?

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SOLUTION :Ethanol formed DUE to FERMENTATION will GET oxidised to ethanonic acid.
24.

In the processA(go)toA^(+)(g)+e^(-)

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Energy is GAINED by the SYSTEM and the ATOM BECOMES larger.
Energy is evolved by the system and the atom becomes larger.
Energy is gained by the system and the atom becomes smaller.
Energy is evolved by the system and the atom becomes smaller.

Answer :C
25.

In the process shown in the figure on an ideal diatomic gas, the value of q and DeltaH respectively is :

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`79.5 P_1V_1 and 94.5 P_1V_1`
`55.5 P_1V_1 and 94.5 P_1V_1`
`12 P_1V_1 and 0`
`79.5 P_1V_1` and defined (`because` P varies)

SOLUTION :NA
26.

In the process of softening of hard water, exhausted permutit is regenerated by adding a solution of ............

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SOLUTION :COMMON SALT
27.

In the process of rusting iron get

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reduced
decomposed
oxidised
changed in finepowder

Solution :Wheniron is rustedit is OXIDISEDTO hydrates ferricoxide
`4 FE + 3O_(2) +X H_(2) O RARR 2Fe_(2) O_(3) . X H_(23)O`
28.

In the process of extraction of gold Roasted gold ore +CN^(-)+H_(2)Ooverset(O_(2))to[X]+OH^(-)[X]+Znto[Y]+Identify the complexes [X] and [Y]

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`X=[Au(CN)_(2)]^(-) Y = [ZN(CN)_(4)]^(2-)`
` X= [Au(CN)_(4)]^(3-) Y = [Zn(CN)_(4)]^(2-)`
`X = (Au(CN)_(2)]^(-) Y = Zn(CN)_(6)]^(4-)`
`X = [Au(CN)_(4)]^(-) Y = Zn(CN)_(4)]^(2-)`

SOLUTION :`2Au + 4CN^(-) + H_(2)O +(1)/(2)O_(2)to2[Au(CN)_(2)]^(-)+20H^(-)`
`2[Au(CN)_(2)]^(-) + Zn to[Zn(CN)_(4)]^(2-)+2Au`
Hence, (A) is the correct answer. . . . .
29.

In the process of ice melting at -15^(@)C

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`DeltaGlt0`
`DELTAGGT0`
`DeltaG=0`
NONE of these

Answer :B
30.

In the process of forming 'mercerised cellulose' the swelling of cellulose is caused by

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WATER soluble
`Na_(2)CO_(3)`
Aq. NaOH
Aq.HCl

Solution :Cellulose FORMS a translucent mass on treatment with conc. NaOH which imparts a silky LUSTURE to cotton. This process is mercerisation and the cotton so produced is KNOWN as mercerised cotton.
31.

In the process of extraction of gold. Roasted gold ore +CN^(-)+H_(2)O overset(O_(2))rarr [X]+OH^(-) [X]+Znrarr [Y]+Au Identify the complexes [X]and [Y].

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` [AU(CN)_(2)]^(-) , [ZN (CN)_(4)]^(2-)`
`[Au(CN)_(4)]^(3-) , [Zn(CN)_(4)]^(2-)`
`[Au(CN)_(2)]^(2-) , [Zn(CN)_(6)]^(4-)`
`[Au(CN)_(4)]^(-) . [Zn(CN)_(4)]^(2-)`

Answer :A
32.

In the process of extraction of gold, Roasted gold ore +CN^(-)+H_(2)O overset(O_(2)) to [X] +OH^(-) [X] +Zn to [Y] +Au Identify the complexes [X] and [Y]

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`X=[AU(CN)_(2)]^(-), Y=[Zn (CN)_(4)]^(2-)`
`X=[Au(CN)_(4)]^(3-), Y=[Zn (CN)_(4)]^(2-)`
`X=[Au(CN)_(2)]^(-), Y=[Zn (CN)_(4)]^(4-)`
`X=[Au(CN)_(4)]^(-), Y=[Zn (CN)_(4)]^(-)`

ANSWER :A
33.

In the process of extraction of gold roasted gold ore+ CN^(-) + H_2O overset(O_2)(rarr) [X] + OH^(-) [X] + Zn to [Y] + Au Identify the complexes [X] and [Y]

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`X :- [AU (CN)_(2)]^(-) Y : [Zn(CN)_(4)]^(2-)`
`X :- [Au (CN)_(4)]^(3-) Y : [Zn(CN)_(4)]^(2-)`
`X :- [Au (CN)_(2)]^(-) Y : [Zn(CN)_(4)]^(4-)`
`X :- [Au (CN)_(4)]^(-) Y : [Zn(CN)_(4)]^(-)`

Solution :`Au + 2CN^(-) + H_2O overset(O_2)(RARR) [Au(CN)_2]^(-) + OH[X]`
`2[ZU (CN)_(2)]^(-) + Zn to [Zn(CN)_(4)]^(2-) + 2Au[Y]`
34.

In the process of extraction of gold Roasted gold ore + CN^(-) + H_(2)O overset(O_(2))rarr [X] + OH^(-) [X] + Zn rarr [Y] + Au Identify the complexes [X] and [Y]

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`X = [Au(CN)_(2)]^(-), Y = [ZN(CN)_(4)]^(2-)`
`X = [Au (CN)_(4)]^(3-), Y = [Zn(CN)_(4)]^(2-)`
`X = [Au(CN)_(2)]^(-), Y = [Zn(CN)_(6)]^(4-)`
`X = [Au(CN)_(4)]^(-), Y = [Zn(CN)_(4)]^(2-)`

ANSWER :A
35.

In the process of electroplating, large amounts of Ag^(+) ions can be used in the electrolyte as the complex

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`K_3[AG(CN)_4]`
`K[Ag(CN)_2]`
`K_2[Ag(CN)_3]`
`K_2 [Ag(CN)_2]`

ANSWER :B
36.

Intheprocess ofextractionof gold, Roastedgoldore+CN^(-)+ H_ 2 Ooverset (O_ 2 ) to[X] +O H ^( -)""[X] +Znto[Y] +AuIdentifythecomplexes [X] and [Y]

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` X =[AU(CN)_2] ^(-),Y=[Zn (CN)_4] ^(2-) `
` X =[Au(CN)_4)] ^( 2 - ), Y=[Zn(CN)_4 ] ^(2-) `
` X =[Au(CN ) _ 2] ^(-),Y=[Zn (CN)_ 6 ] ^( 4 -) `
` X =[Au(CN)_4] ^( -) ,Y=[Zn(CN)_4]^(2- ) `

Answer :A
37.

In the process of electrolysis , the positive and negative ions of the electrolyte are

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separated
hydrate
united
discharged

Solution :Positive ION gains the `e^(-)` and becomes NEUTRAL.
Negative ion LOSES the `e^(-)` and becomes neutral.
The charges are LOST during the ELECTROLYSIS reaction.
38.

In the process :H_(2)O(s, -10^(@)C, 1atm)rarrH_(2)O(1, 10^(@)C, 1 atm)C_(p) for ice = 9 cal deg^(-1) mol^(-1), C_(p) for H_(2)O=18 cal deg^(-1)mol^(-1). Latent heat of fusion of ice = 1440 cal mol^(-1) at 0^(@)C. The entropy change for the above process is 6.258 cal.deg^(-1)mol^(-1) Give the total number of steps in which the third law of thermodynamics is used

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Solution :Step 1. (using the third law of thermodynamics) :
(For changing)
`H_(2)O(s)(-10^(@)C, 1 ATM)rarrH_(2)O(s, 0^(@)C1 atm)`
`DeltaS_(1)=underset(-10)overset(0)intn(C_(p))/(T)dT=1xx9xx2.3xxlog.(273)/(263)=0.336" cal deg"^(-1) mol^(-1)`
Step 2 (using the second law of thermodynamics) :
`H_(2)O(s)(0^(@)C, 1 atm)rarrH_(2)O(l)(0^(@)C, 1 atm)`
`DeltaS_(2)=(q_(rev))/(T)=(1440)/(273)=5.258" cal deg"^(-1)mol^(-1)`
Step 3 (using the third law of thermodynamics) :
`H_(2)O(l)(0^(@)C, 1 atm)rarrH_(2)O(l)(10^(@)C, 1 atm)`
`DeltaS_(3)=underset(0)overset(10)intn(C_(p))/(T)dT=1xx18xx2.3xxlog.(283)/(273)=0.647 " cal deg"^(-1)mol^(-1)`
`DeltaS=DeltaS_(1)+DeltaS_(2)+DeltaS_(3)=0.336+5.258+0.647 = 6.258 " cal deg"^(-1) mol^(-1)`.
39.

In the process nA(g) tomB(g) , rate of disappearance of A is 5 xx 10^3M-"min"^(-1)& rate of appearance of B is 10^(-2) M - "min"^(-1)at same instant. Then values of n & m respectively are

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2,3
1,2
2,1
4,3

Answer :B
40.

In the process of cracking

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Organic compounds decompose into their constituent elements
Hydrocarbons decompose into CARBON and hydrogen
High MOLECULAR WEIGHT organic compounds decompose to gives low molecular weight organic compounds
Hydrocarbons YIELD alkyl RADICALS and hydrogen

Answer :C
41.

In the process , Cl(g) + e^(-) overset(DeltaH)(to)Cl^(-)(g), DeltaH is

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positive
NEGATIVE
zero
unpredictable

Solution :The PROCESS REPRESENTS the first electron AFFINITY which is always exothermic. Hence `DELTAH` is negative.
42.

In the process Cl _((g)) + e overset( Delta H) to Cl ^(-) _((g) Delta H is

Answer»

POSITIVE
negative
ZERO
UNPREDICTABLE

Answer :B
43.

In the present graph, the areas of circles A and B are 25 unit and 20 unit respectively. Work done will be. . .unit.

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ANSWER :5
44.

In the preservation of food, sun drying and mechanical drying is carried to remove______from food.

Answer»

micro-organism
enzymes
 water
oxidants

Answer :C
45.

In the presence of the following Bleaching powder dcomposes to liberate oxygen

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`Ni`
`FEO`
`COCl_(2)`
`CuO`

SOLUTION :`2CaOCl_(2) overset(CoCl_(2)) to 2CaCl_(2)+O_(2) UARR`
46.

In the presence of small amount of phosphorous, aliphatic carboxylic acids reacts with chlorine or bromine to yeild a compound in which alpha-hydrogen has been replaced by halogen. This reaction is known as

Answer»

Wolf-Kishner reaction
Etard reaction
Rosenmund reaction
Hell-Volhard-Zelinsky reaction

Answer :D
47.

In the presence of peroxide, hydrogen chloride and hydrogen iodide do not give anti-Markovnikov's addiition to alkenes because

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both are highly ionic
ONE is oxidising and the other is reducing
one of the STEPS is ENDOTHERMIC in both the CASES
all the steps are exothermic in both the reactions.

Solution :One of the steps is endothermic in both the cases.
48.

In the presence of peroxide, hydrogen chloride and hydrogen iodide do not give anti-Markovnikov's addition to alkenes because:

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Both are highly IONIC
One is OXIDISING and the other is reducing
One of the steps is endothermic in both the CASES
All the steps are EXOTHERMIC in both the cases

Answer :C
49.

In the presence of peroxide, hydrogen chloride and hydrogen iodide do not give Anti Markownikov's addition to alkenes because

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both are HIGHLY ionic
one is oxidising and the other reducing
one of the steps is endothermic in both the CASES
all the steps are exothermic in both the cases.

Solution :the endothermic REACTION is not favourable.
50.

In the presence of peroxide HCl do not give anti Markownikoffs addition to alkene because

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it is highly ionic
it is oxidising agent
peroxide cannot BREAK HCL BOND
it is highly polar

Answer :C