Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In presence of which compound, benzene reacts with I_(2) to give iodo benzene ?

Answer»

`HNO_(3)`
HI
`SO_(2)`
`H_(2)O`

Answer :A
2.

In presence of sodium ethoxide two molecules of ethyl acetate interact to from acetoacetic ester. This process is known as :

Answer»

ALDOL CONDENSATION
Claisen condensation
Polymerisation
None

Answer :B
3.

In presence of NaOH, phenol react with CHCl_(3) to form o-hydroxy benzaldehyde.This reaction is called

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Riemer-Tiemann reaction
Sandmeyer reaction
Hoffmann DEGRADATION reaction
Gattermann ALDEHYDE synthesis

Answer :A
4.

In presence of moisture, SO_2 can:

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LOSE electron
Gain electron
Act as oxidant
Act as reductant

Answer :A
5.

In presence of light & heat toluene chlorinated & react with aqueous NaOH give

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o-CRESOL
p-cresol
Mixture of o- cresol & p-cresol
1,3,5-trihydroxy toluene

Solution :
6.

In presenceof moisture, SO_(2) can

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LOSE ELECTRONS
Gain electrons
Act as oxidant
All

Solution :`SO_(2) +2H_(2)O to H_(2)SO_(4)+2[H]`
7.

In presence of ligands

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The FIVE d-orbitals of metal atomorion have same energy
The five orbitals split into TWO SET of orbitals kaving different energy
The five d-orbitals have different energy
none of these

Answer :B
8.

In presence of HCl ,sucrose gets hydrolysed into glucose and fructose . The concentration of sucrose was found to reduce form 0.4 M to 0.2 M in 1 hour and 0.1 M in 2 hours . The order of the reaction is

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Zero
One
Two
None of these

Solution :`t_(1//2) prop (1)/((C_(0))^(n-1)) THEREFORE` reaction is of FIRST ORDER .
9.

In presence of Lewis acid, which Xenon compound is an excellent fluorinating agent ?

Answer»

`XeOF_(2)`
`XeF_(2)`
`XeF_(6)`
`XeF_(4)`

ANSWER :B
10.

In presence of HCl, sucrose gets hydrolysed into glucose and fructose. The concentration of sucrose was found to reduce from 0.4 M to 0.2 M in 1 hour and to 0.1 M in total of 2 hours. The order of the reaction is :

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zero
one
two
none of these

Answer :B
11.

In presence of HCl, H_2S results the precipitatiion of Group-2 elements but not Group -4 elements during qualitative analysis. If is due to

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LOWER concentration of `H^(+)`
Lower concentration of `S^(2-)`
Higher concentration of `H^(+)`
Higher concentration of `S^(2-)`

Solution :Dissociation of `H_2S` is suppressed in presence of HCl due to common ion effect. This DECREASES the `S^(-2)` ion concentration and hence, only group II RADICALS having low solubility product are precipitated.
12.

in presence of external magnetic field, f subshell is

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5 FOLD degenerate
3fold degenerate
7 fold degenerate
Non- degenerate

Answer :D
13.

In presence of excess water, hydrolysis of methyl acetate in basic or alkaline medium, is second order reaction. Explain.

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Solution : In alkaline MEDIUM , both the reactions, i.e., methyl acetate and alkaliare present in more or less similar concentration. During the reaction, the concentrations of both change appreciably, IMPLYING that bothreactants affect the reaction- rate. It is observed that the reaction- rate is DIRECTLY proportional to the the first power of concentration of both reactants. THUS, the overall order of the reaction is TWO.
14.

In presence of dry HCl gas, CH_3CHO condenses with C_2H_5OH to give:

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Aldol
Paraldehyde
Ethyl acetate
Acetal

Answer :D
15.

In presence of Ba(OH)_(2), two molecules of acetone condense together to form_______

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SOLUTION :DIACETONE ALCOHOL.
16.

In presence of air , fermentation of ethyl alcohol by azotobactor bacteria forms

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`CH_(2)=CH_(2)`
`C_(2)H_(6)`
`CH_(3)CHO`
`CH_(3)COOH`

Solution :`C_(2)H_(5)OH underset("Acetobacteracetii")overset("air")to CH_(3)COOH`
17.

In presence of concentrated alkalie (OH^(-)), trimethyl acetaldehyde undergoes the

Answer»

ALDOL condensation
Witting reaction
Cannizzaro reaction
Perkin reaction

Answer :C
18.

In presence of acidic medium, KMnO_(4) converts H_(2)S into ….

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MN only
S only
MnS +S
Mn only

Solution :`2KMnO_(4) + 3H_(2)SO_(4) + 5H_(2)S RARR 5S + 2MnSO_(4) + K_(2)SO_(4) + 8H_(2)O`
19.

In presence of air, fermentation of ethyl alcohol by azotobactorbacteria forms:

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`CH_(2)=CH_(2)`
`C_(2)H_(6)`
`CH_(3)CHO`
`CH_(3)COOH`

Answer :D
20.

In Preparation of sulphuric acid from sulphur dioxide in lead chamber process. What substance is used as a catalyst?

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Manganese DIOXIDE
Vanadium pentoxide
NITRIC oxide
Raney Nickel

Solution :Lead chamber process:
The different steps are
(i) `2H_(2)O + NO to HNO_(3) + 3H^(+)`
(ii) `S + O_(2) to SO_(2)`
(iii) `2HNO_(3)+ 2SO_(2) to H_(2)O + NO + NO_(2) + 2SO_(3)`
(IV) `SO_(3) + H_(2)O to H_(2)SO_(4)`
Net reaction:
`2SO_(2)+ 2H_(2)O + O_(2) overset(NO) to 2H_(2)SO_(4)`
21.

In presence of acid, hydrolysis of methyl cyanide gives

Answer»

Acetic ACID
METHYLAMINE
Methyl alcohol
Formic acid

Solution :`CH_(3)Cnoverset(H_(2)O //H^(+))rarrCH_(3)COOH+NH_(3)`
22.

In preparationof sulphuricacid from sulphurdioxidein leadchamber process. What substance is usedas a catalyst?

Answer»

Manganese dioxide
Vanadium pentoxide
Nitric oxide
Raney nickel

Solution :In the preparationof sulphuric acid `(H_(2)O)`. In
`2SO_(2) + UNDERSET("from AIR")(O_(2)) + 2H_(2)O + underset("Catalyst")([NO] rarr 2H_(2)SO_(4) + underset("Catalyst")([NO])`
23.

In preparation of CHCl_(3) from ethanol and bleaching powder, the latter provides :

Answer»

`Ca(OH)_(2)`
`Cl_(2)`
Both (1) and (2) (4
NONE of these

Answer :3
24.

In practice, detergent is more used than soap because...

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detergent is easily available.
detergent is more economic.
detergent reacts with HARD water.
detergent reacts with hard water and form soluble SALTS and HENCE it not more than the REQUIREMENT

Solution :detergent reacts with hard water and form soluble salts and hence it not more than the requirement.
25.

In poly nuclear metal carbonyls, the hybridisation of 'C' in terminal carbonyl is 'sp' where as that in bridged carbonyl is 'sp'^(2) II) In all mono nuclear metal carbonyl, the carbonyls are non bridged III) Fe(CO)_(5) is diamagnetic and Fe' is dsp^(3) hybridised IV) Metal carbonyls are more stable due to more nucleophilic nature of carbon monoxide The correct statements are

Answer»

I, II, III
I,III, IV
II,III, IV
I, II, III are IV

Solution :
.C. atoms in bridging CO molecules have `3sigmma` bonds each `(sp^(2))`. The terminal CO molecules have C atoms with `2sigma` bonds each (sp) synergic effect in METAL CARBONYLS is responsible for their stability.
26.

In plot of mass of the gas adsorbed per gram of the adsorbent versus temperature at constant pressure is called ………..

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SOLUTION :ADSORPTION ISOBAR
27.

In PO_(4)^(3-) the formal charge on the each oxygen atom and the P-O bond order respectively are

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`-0.75, 0.6`
`-0.75, 1.0`
`-0.75, 1.25`
`-3.1,1.25`

Solution :Formal charge on an atom=
total no. of valence electrons in FREE atom - total no.of non - BONDING ELECTONS `-1/2` total no of bonding electrons
Formal charge on oxygen `=6-[6+1/2xx2]=-1`
There are total 3 oxygen atom, therefore charge=-3
Formal charge on each O-atom
`=("total charge")/("number of atoms")=(-3)/4=-0.75` and
P-O bond order
`=("total no. of bonds")/("total no of resonating structures")=5/4=1.25`
28.

In planar square closepacking, eachsphereissurrounded by ______.

Answer»

SIX triangularholes
FOUR squareshapedholes
six squareshapedholes
fourtetrahedral holes

Answer :B
29.

In plant glycolipids sugar is

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glucose
fructose
galactose
mannose

Answer :C
30.

In place of tetrachlorethene in dry-cleaning we use

Answer»

Sodium lauryl SULPHATE
Sodium sterate
Hydrogen peroxide
Sodium BISULPHITE

Answer :C
31.

In physulphurous acid oxidation state of sulphur is

Answer»

only +2
only +4
`+2 and +6`
only +6

Answer :B
32.

In physisorption the adsorbate is held to the adsorbent by weak_______ forces.

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SOLUTION :VAN DER Waal.s
33.

In physisorption, adsorbent doesnot show specificity for any particular gas because

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INVOLVED van der Waals' force are universal 
gases involved behave LIKE IDEAL gases 
enthalpy of ADSORPTION is low 
it is a reversible process 

Solution :involved van der Waals. force are universal
34.

In physisorption, adsorbent does not show specificity for any particular gas because………..

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INVOLVED van der WAALS FORCES are universal
gases involved BEHAVE LIKE ideal gases
enthalpy of adsorption is low
it is a reversible process

Answer :A
35.

In physisorption adsorbent does not show specificity for any particular gas because ……..

Answer»

involved van DER Waals' forces are UNIVERSAL
gases involved BEHAVE like ideal gases
enthalpy of ADSORPTION is low
it is a reversible process.

Solution :involved van der Waals. forces are universal
36.

In physisorption, adsorbent does not show specificity for any particular gas because

Answer»

INVOLVED VAN der Waals' FORCES are universal
gases involved behave LIKE IDEAL gases
enthalpy of adsorption is low
it is a reversible process.

Solution :involved van der Waals. forces are universal
37.

In physical adsorption ........... exist between adsorbent and adsorbate

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Solution :VAN DER Waals forces of ATTRACTION
38.

In photography we use :

Answer»

AgCl
AgBr
Agl
`NH_3`

ANSWER :B
39.

In physical adsorption

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the extent of adsorption increases with INCREASE in surface area.
enthalpy of adsorption is 20-40 kJ `"mol"^(-1)`
the process is irreversible.
all the above.

Solution :all the above.
40.

In photography, undecomposed AgBr forms a soluble complex called............

Answer»


ANSWER :SODIUM dithio sulphato argentate (I)
41.

In photography silver bromide dissolves in hypo to give

Answer»

`Na_2[AG(S_2O_3)_2]`
`NA[Ag(S_2O_3)_2]`
`Na_3[Ag(S_2O_3)_2]`
`Na_4[Ag(S_2O_3)_2]`

ANSWER :C
42.

In photography, hypo is used in the reduction of

Answer»

AG from AGBR
AgBr into `Ag_2SO_4`
AgBr into soluble thiosulphate complex
Both (2) and (3)

Answer :C
43.

In phosphorus acid, the number of OH group present is/are ……………..

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ONE
TWO
Three
Four

Answer :B
44.

In phenol, the hybrid state of C and O are respectively ……

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`SP^(3), sp^(2)`
`sp^(2), sp^(3)`
`sp, sp^(2)`
`sp^(2), sp`

SOLUTION :`sp^(2), sp^(3)`
45.

In phenols

Answer»

The ortho , meta and PARA positionall are activated
The ortho and para positions are activated while the meta POSITION is deactivated
The ortho and para position are more activated than the meta position
The ortho , meta and para position are equally acitivated

Solution :The resonating structures of phenol are

Hence,when electrons are pushed inside the benzene ring, all the positions in the benzene ring are activated. Also ortho and para positions are most activated Hence choices (a) and (C) are CORRECT while (b) and (d) are incorrect.
46.

In phenol carbon atom attached to -OH undergoes……………………

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`SP^(3)` HYBRIDISATION
sp hybridisation
`sp^(2)` hybridisation
no hybridisation

Answer :C
47.

In phenol carbal atom attached to -OH group undergoes :

Answer»

`sp^(3)` hybridisation
sp hybridisation
`sp^(2)` hybridisation
No hybridisation

Solution :In PHENOL, the -OH group is ATTACHED to `sp^(2)` hybridised cabon while in ETHANOL, it is attached to `sp^(3)` hybridised.
48.

In petrochemical industry alcohols are directly converted to gasoline by passing over heated

Answer»

Platinum
ZSM-5
Iron
Nickel

Solution :ZSM-5 is a shape SELECTIVE CATALYST. ZEOLITES are good shape selective CATALYSTS because of the HONEYCOMB like structure.
49.

In permanganate titrations, potassium pemanganats is used an an oxidizing agent in acidic medium. The medium is maintained acidic by the use of dilute sulphuric acid. Potassium permanganate acts as self indicator . The potential equation, when potassium permanganate acts as an oxidizing agent is 2KMnO_(4) + 3H_(2)SO_(4) to K_(2)SO_(4) + 2MnSO_(4) + 3H_(2)O + 5[O] or MnO_(4)^(-) + 8H^(+) + 5e^(-) to Mn^(2+) + 4H_(2)O Before the end point, the solution remains colourless but after teh equivalence point only one extra drop of KMnO_(4) solution imparts pink colour , i.e. appearance of pink colour indicates end point. These titrations are used for estimation of ferrous salts, oxalic acid, oxalates, hydrogen peroxide, As_(2)O_(3) etc. 10 ml of NaHC_(2)O_(4) solution is neutralized by 10 ml of 0.1 M NaOH . 10 of same NaHC_(2)O_(4) solution is oxidized by 10 ml of KMnO_(4) solution in acidic medium . Hence, molarity of KMnO_(4) is

Answer»

`0.1` M
`0.2` M
`0.04` M
`0.02` M

SOLUTION :N/A
50.

In permanganate titrations, potassium pemanganats is used an an oxidizing agent in acidic medium. The medium is maintained acidic by the use of dilute sulphuric acid. Potassium permanganate acts as self indicator . The potential equation, when potassium permanganate acts as an oxidizing agent is 2KMnO_(4) + 3H_(2)SO_(4) to K_(2)SO_(4) + 2MnSO_(4) + 3H_(2)O + 5[O] or MnO_(4)^(-) + 8H^(+) + 5e^(-) to Mn^(2+) + 4H_(2)O Before the end point, the solution remains colourless but after teh equivalence point only one extra drop of KMnO_(4) solution imparts pink colour , i.e. appearance of pink colour indicates end point. These titrations are used for estimation of ferrous salts, oxalic acid, oxalates, hydrogen peroxide, As_(2)O_(3) etc. Inalkaline condition, KMnO_(4) reacts as follows : 2KMnO_(4) + 2KOH to 2K_(2)MnO_(4) + H_(2)O + [O] Therefore , its equivalent mass will be

Answer»

`31.6`
`52.7`
`72.0`
`158.0`

SOLUTION :N/A