Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In laboratory, benzene diazonium chloride is not isolated in the crystalline solid state because in solid state it

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EXPLODES
is READILY oxidised
is readily reduced
is polymerised

Solution :It is UNSTABLE and explodes in the SOLID STATE.
2.

In lab various tests were carried out by student. Following observations made by him is /are correct :

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When ethanol was treated with `I_(2)//NaOH` YELLOW colour appeared.
When ethanol was treated with `K_(2)Cr_(2)O_(7)` in acidic medium colour change from ORANGE to green was observed.
When benzaldehyde was treated with Fehling SOLUTION red colour appeared.
Whenphenol is treated with `NaHCo_(3)` effervescence.

Solution :N//A
3.

In lab H_(2)O_(2) solution is

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COLD `H_(2)SO_(4)+BaO_(2)`
`HCl+BaO_(2)`
CONC. `H_2SO_(4)+Na_(2)O_(2)`
`H_(2)+O_(2)`

Solution :`H_(2)SO_(4) +BaO_(2) to BaSO_(4) + H_(2)O_(2)`
4.

In L-Phenyl alanine the amino group lies at

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right SIDE to chiral CENTRE 
LEFT side to chiral centre 
para position to `-COOH` in BENZENE ring 
ORTHO position to `-COOH` in benzene ring 

Answer :B
5.

In kroll and ICI process in the production of titanium, the inert gas used is:

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Ne
Ar
Kr
Xe

Answer :B
6.

In Kolbe's reaction, instead of phenol, the phenoxide is treated with the carbon dioxide. Why ?

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Solution :`to` The phenoxide is more reactive than phenol because of greater ability of -O- to donate electron to the benzene RING and THUS the BONDING of `CO_(2)` (weak nucleophile) easier.
7.

In Kolbe's reaction, instead of phenol, phenoxide ion is treated with carbon dioxide. Why?

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SOLUTION :Due to GREATER ability of `-O^(-)` ion (than OH group) to donate electrons to the BENZENE RING, phenoxide ion is more reactive than phenol towards electrophilic aromatic substitution reactions. In other words, phenoxide ion being a strong nucleophile reacts easily with the weak electrophile carbon dioxide to BRING about the electrophilic substitution reaction.
8.

In Koble.s reaction, instead of phenol, phenoxide ion is treated with carbon dioxide. Why?

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SOLUTION :Phenoxide ion is more reactive than phenol TOWARDS electrophilic substitution. The negative CHARGE on oxygen is transferred to benzene through resonance. The helps in the attachment of `CO_(2)` which is a weak electrophilie to the benzene ring FINALLY giving salicylic acid.
9.

In KMnO_4 titrations the indicator used is

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phenolphthalein
methyl orange
Both (A) and (B)
NONE of these

Solution :In `KMnO_(4)` TITRATIONS , `KMnO_(4)` itself acts as an indicator.
10.

In known interhalogen compounds maximum number of halogen atoms are

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6
7
8
9

Answer :C
11.

In Knoevenagal reaction ............. act as the basic catalyst.

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SOLUTION :PYRIDINE
12.

In KMnO_(4) the crystallographic parameters are

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`alpha=BETA=gammane90^(@)`
`alpha=beta=gamma=90^(@)`
`alphane beta ne gamma=90^(@)`
`alpha =gamma=90^(@) beta gt 90^(@)`

ANSWER :B
13.

In KMnO_(2) on heatingto red hot gives

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`+2`
`+4`
`+6`
`+7`

ANSWER :d
14.

In KMnO_(4) molecule the oxidation states of the elements potasiun (K) managenese (Mn) and oxygen (O) are repectively

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Eelctrolytic cell
stroage cell
primary cel
fuel cell

Solution :Attempts to EXTEND the life of primary cells for EXAMPLE by rechanging alkaline batteries meet with variable results third party DEVICES are manufactured and r epresented as being able to reacharge primary cells the internal chemical reactions of primary cell are not easily reversed by externally APPLIED currents soreactant do not entirely return to their initial state and location recharged primary cells will not have the life or performance of secondary cells primary cell MANUFACTURES often warn against rechargeing
15.

In Kjeldahl's method,CuSO_(4) acts as

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Oxidising AGENT
Reducing agent
Hydrolysing agent
Catalytic agent

Solution :Kjeldahl's METHOD depends upon the FACT that most of the organic compounds containing nitrogen are quantiatively decomposed to give `(NH_(4))_(2)SO_(4)` when heated strongly with conc. `H_(2)SO_(4)`. In this method `CuSO_(4)` acts as cathalytic agent.
16.

In Kjeldahl's method of estimation of nitrogen,K_2SO_4 acts as:

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OXIDISING agent
Catalytic agent
Hydrolysing agent
Boiling POINT elevator

Answer :D
17.

In kjeldahl's method of estimation of nitrogen, copper sulphate acts as :

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OXIDISING agent
Silver spiral
Catalytic agent
Hydrolysing agent

Answer :C
18.

In Kjeldahl's method nitrogen present is quantitatively converted to :

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`NO_2`
`(NH_4)_2SO_4`
`NO_2`
NONE of these

Answer :B
19.

In Kjeldahl's method, nitrogen present is estimated as :

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`N_(2)`
`NH_(3)`
`NO_(2)`
NONE of these

Solution :`NH_(3)`
20.

In kjeldahl's method ,nitrogen present is estimated as :

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`N_2`
`NH_3`
`NO_2`
NONE of these

Answer :B
21.

In kjeldahl's method ,nitrogen present in estimated as :

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`N_(2)`
`NH_(3)`
`NO_(3)`
non of these

SOLUTION :N//A
22.

In Kjeldahl's method during digestion, the nitrogen of the organic compound is converted into

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`NH_(4)Cl`
`(NH_(4))_(2)SO_(4)`
`NH_(4)NO_(3)`
`NH_(3)`

Solution :`underset(" AMMONIA")(2NH_(3)) + underset(" Sulphuric acid")(H_(2)SO_(4)) rarr underset(" Ammonium SULPHATE")((NH_(4))_(2)SO_(4))`
(a) , (c ) and (d) are not possible.
23.

In Kjeldahl's method, ammonia from 5g of food neutralizes 30 cm^(3) of 0.1 N acid. The percentage of nitrogen in the food is

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`0.84`
`8.4`
`16.8`
`1.68`

Solution :PERCENTAGE of nitrogen `= (1.4 xx N_(1) xx V)/(w)`
`= (1.4 xx 0.1 xx 30)/(5) = 0.84 %`
24.

In Kjeldahl's method, ammonia from 5g of food neutralizes 30cm^(3) of 0.1N acid. The percentage of nitrogen in the food is

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`0.84`
`8.4`
`16.8`
1.68`

Solution :PERCENTAGE of NITROGEN `=(1.4xxN_(1)xxV)/(w)`
`=(1.4xx0.1xx30)/(5)=0.84%`
25.

In Kjeldahl's method 0.12 g of organic substance liberated ammonia. It is absorbed in 40ml of 0.05N acid. Which is neutralised by 27.5 ml of 0.05 N base. Calculate the percentage of nitrogen in the given compound.

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Solution :`(NV)_(NH_(3))=(NV)_(H_(2)SO_(4))-(NV)_(NaOH)=(0.05 XX 40)-(0.05 xx 27.5)`
`(NV)_(NH_(3))=2-1.375=0.625(meq NH_(3))` `N%=(1.4(NV))/(W_("ORG"))=(1.4 xx 0.625)/(0.12)=7.3`
26.

In Khcldahl's methofd for the estimation of N_(2), potassium suphate and copper sulphate are used. On the basis of their functions which of the following statement(s) is /are correct? (i). Potassium sulphate raises theb.pt. and ensures complete reaction(ii). Copper sulphate act as Catalyst (iii). Potassium sulphate acts as catalyst and copper sulphate raises the b.pt.

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Only (iii) is CORRECT
(i) and (II) are correct
Only (ii) is correct
None of these

Solution :`K_(2)SO_(4)` raises b.pt. and `CuSO_(4)` act as CATALYST.
27.

In Kipp's apparatus, H_2S is prepared continuously

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by `FeS + HCL`
by `FeS+conc H_2SO_4`
By `FeS+ DIL H_2SO_4`
By `Fe + dil H_2SO_4`

Answer :C
28.

In keto-enol tautomerism of dicarbonyl compounds, the enol form is preferred in contrast to the keto-form, this is due to

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presence of carbonyl group on each side of ` - CH_(2)` group
resonance STABILIZATION of enol form
resence of METHYLENE group
rapid chemical exchange.

SOLUTION : Resonance stabilisation of enol form as shown below:
29.

In K_(2)Cr_(2)O_(7), every Cr is linked to

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TWO O-atoms
three O-atoms
four O-atoms
five O-atoms

Solution :The structure of `Cr_(2)O_(7)^(2-)` ION is
30.

In IV th groupthe ppt of Mn(OH)_(2) in excessof NaOH , turns brownor bluein airdue to the formation of

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`MnO_(2).xH_(2)O`
`MnO_(2)`
`MnO_(2).H_(2)O`
All

Answer :d
31.

In IUPAC system aldehydes are called

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alkanes
alkenes
alkanals
alkanols

Answer :C
32.

In its reaction with silver nitrate acetylene shows

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OXIDISING property
Reducing property
Basic property
Acidic property

Solution :Acidic property because H ATOMS are replaced by SILVER metal atoms
33.

In its reaction with silver-nitrate ,acetylene shows:

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OXIDISING property
reducing property
basic property
acidic property

Answer :D
34.

In its 0.2 M solution, acid ionies to an extent of 60%. Its hydrogen ion concentration is

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0.6 M
0.2 M
0.12 M
None of these

Solution :`[H^(+)] = C. ALPHA, ""= 0.2 XX 0.60 = 0.12 M`.
35.

In isotonic solutions …………………. .

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SOLUTE and SOLVENT both are same
osmotic PRESSURE is same
solute and solvent MAY or may not be same
solute is always same, solvent may be different

Answer :b,c
36.

In isotonc solutions

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SOLUTE and SOLVENT both are same.
osmotic PRESSURE is same.
solute and solvent MAY of may not be same
solute is alsays same, solvent may be defferent.

Solution :are both CORRCET.
37.

In isotonic solutions …………

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Solute and solvent both are same.
OSMOTIC PRESSURE is same.
Solute and solvent may or may not be same.
Solute is always same solvent mat be different.

Answer :B::C
38.

Inisomericaminecorrectorderhas lowestB. P

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`1gt 2^(@) GT 3^(@)`
`3^(@) gt 2^(@) gt 1^(@)`
`2^(@) gt ^(@) gt 1^(@)`
`1^(@) gt 3^(@) gt 2^(@)`

Solution :In isomericcompourds normalcompounds have higher B.Pthanbranched compound . BUTIN aminesactiveactivehydrogenatomsare different.
`1^(@)`amines= - `NH_(2)`group= 2 activeH - atoms.
`2^(@)`amines= ` gt`NHgroup =1 acitveH -atoms.
`3^(@)`amines N group= 0 activeH -atoms.
HenceB.Porderis `1^(@) gt2^(@)gt3^(@)`
39.

In isothermalideal gas compression :

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`W "is +ve"`
`DeltaH` is ZERO
`DeltaS_(gas) "is +ve"`
`DELTAG "is + ve"`

Solution :` W is + ve`
40.

In isothermal expansion of a gas:

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the KINETIC energy of GAS MOLECULES REMAINS same
the kinetic energy of a gaseous molecules decreases
pressure of gas decreases
the kinetic energy of gaseous molecules increases

Answer :A::C
41.

In isomeric alcohols correct order of boiling point is,

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`2^@` gt`3^@`gt`1^@`
`3^@`gt`2^@`gt`1^@`
`1^@ gt 2^@ gt 3^@ `
`2^@ gt 1^@ gt 3^@`

Solution : Normal alcohols having higher boiling POINT than CORRESPONDING branched ISOMERIC alcohols.
42.

In isoelectronic species, which of the following is correct :

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ZEFF `prop`(+) CHARGE
Zeff `prop`charge
Both (1) and (2) are correct
None

Answer :C
43.

In iodometric titrations, an oxidizing agent such as KNnO_(4), K_(2)Cr_(2)O_(7),CuSO_(4),H_(2)O_(2) is allowed to react in neutral medium or in acidic medium with excess of potassium iodide to liberate free iodine Kl+ oxidizonagent to l_(2) Free iodine is titrated against stanard reducing agent usually with sodium thiosulphate i.e., K_(2)Cr_(2)O_(7)+6Kl+7H_(2)SO_(4)toCr_(2)(SO_(4))_(3)+4K_(2)SO_(4)+7H_(2)O+l_(2) 2CuSO_(4)+4Kl to Cu_(2)l_(2)+2K_(2)SO_(4)+l_(2) l_(2)+Na_(2)S_(2)O_(3)to 2Nal+Na_(2)S_(4)O_(6) In iodometric titrations, starch solution is used as an indicator. Starch solution gives blue or violet colour with free iodine. At the end point, blue or violet colour disappear when iodine is completely changed to iodide. What volume of 0.40M Na_(2)S_(2)O_(3) would be required to reach with l_(2) liberated by adding 0.04 mole of Kl to 50 mL to 0.20 M CuSO_(4) solution?

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`12.5mL`
`25 ML`
`50 mL`
`2.5 mL`

Solution :Meq. of `Kl-="meq. of " CuSO_(4)-=` meq. Of `l_(2)-=` meq. of hypo
`0.4xx10^(3)xx1 50xx0.21`
`=40 =10` ( limiting REAGENT)
`:.` meq.of hypo `=10-Mxx X xxV_(mL)`
`=0.4xx2xxv_(mL)=12.5mL`
44.

In ionic crystals______ions adopt ccp or hcp arrangement, while_____ions occupy interstitial sites

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SOLUTION :LARGER (ANIONS), SMALLER (CATIONS)
45.

In iodometric titration which indicator is used to detect end point of titration reaction?

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Diphenylamine
Starch
`MnO_4^⊖`
METHYL orange

Answer :B
46.

In interhalogen compounds of the type AB_5 and AB_7 B is invaribly fluorine. Why?

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SOLUTION :Being the strongest oxidising agent, fluorine can FORM compounds in +5 and +7 oxidation state. MOREOVER, being the smallest, it can easily fit around A without causing much steric hindrance.
47.

In Iodination for preparation of iodomethane compound used is

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`HIO_(3)`
HgO
Both (1) and (2)
HI

Answer :3
48.

In insulin molecule there are two chains 'A' and 'B', 'A' contain 'X' - amino acids and 'B' contain 'Y' amino acids. The value of X and Y are

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21,31
21,30
28,36
32,34

Answer :B
49.

In industry phenol is prepared from 1. Raschig's method 2. Dow's method 3. Oxidation of cumene 4. Oxidation of hexane

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1, 2
2, 3
3, 4
1, 2, 3

Answer :D
50.

In insulin molecule S - S linkage is in between

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CYSTEINE-Glycine 
Cysteine - Cysteine 
Cysteine-Valanine 
PROLINE - Cysteine

Answer :B