94420 + Interview Questions in Chemistry in Class 12

1.	If an element can exist in several oxidation states, it is convenient to display the reduction potentials corresponding to the various half reactions in diagrammatic from, known as Latimer diagram. The Latimer diagram for chlorine in acid solutionis Cl_(4)^(-)overset(+1.20V)toClO_(3)^(-)overset(+1.60V)toClO_(2)^(-)overset(+1.60V)to ClO^(-)overset(+1.67V)toCl_(2)overset(+1.36V)toCl^(-) In basic solution is : ClO_(4)^(-)overset(+0.37V)toClO_(3)^(-)overset(+0.30V)toClO_(2)^(-)overset(+0.68)to ClO^(-)overset(+0.42V)toCl_(2)overset(+1.36)toCl^(-). The standard potentials for two nonadjacent species can also be calculated by using the concept that DeltaG^(@) is an additive property but using potential is not an assitive property and DeltaG^(@)=-nFx^(0), If a given oxidation state is a the next higher oxidation state disproportionation can occur. The reverse of relative stabilities of the oxidation state can also be understood by drawing a graph of DeltaG^(@)//F against oxidation state, known as Frost diagram, Choosing the stability of zero oxidation state arbitrery as zero. The moststable oxidation state of a apecies lies lowest in the digram Disproportionation is spontaneous if the species lies above a straight line joining its two product species. Which of the followingstatements correct ?
Answer» `Cl_(2)` undergoes DISPROPORTIONATION into `Cl^(-0` and `ClO^(-)` at pH = 0 and pH = 14 `Cl_(2)` undergoes disproportionation into `Cl^(-)` and `ClO^(-)` at pH = 14 and pH = 0 `Cl_(2)` undergoes disproportionation into `Cl^(-)` and `ClO^(-)` at pH = 0 not at pH = 14 None of the above ANSWER :B

Discussion

2.	If an element can exist in several oxidation states, it is convenient to display the reduction potentials corresponding to the various half reactions in diagrammatic from, known as Latimer diagram. The Latimer diagram for chlorine in acid solutionis Cl_(4)^(-)overset(+1.20V)toClO_(3)^(-)overset(+1.60V)toClO_(2)^(-)overset(+1.60V)to ClO^(-)overset(+1.67V)toCl_(2)overset(+1.36V)toCl^(-) In basic solution is : ClO_(4)^(-)overset(+0.37V)toClO_(3)^(-)overset(+0.30V)toClO_(2)^(-)overset(+0.68)to ClO^(-)overset(+0.42V)toCl_(2)overset(+1.36)toCl^(-). The standard potentials for two nonadjacent species can also be calculated by using the concept that DeltaG^(@) is an additive property but using potential is not an assitive property and DeltaG^(@)=-nFx^(0), If a given oxidation state is a the next higher oxidation state disproportionation can occur. The reverse of relative stabilities of the oxidation state can also be understood by drawing a graph of DeltaG^(@)//F against oxidation state, known as Frost diagram, Choosing the stability of zero oxidation state arbitrery as zero. The moststable oxidation state of a apecies lies lowest in the digram Disproportionation is spontaneous if the species lies above a straight line joining its two product species. For a hypothetical element, the Frost diagram is shown in figure Which of the following oxidation state is least stable ?
Answer» -1 0 2 3 Answer :D

Discussion

3.	If an element can exist in several oxidation states, it is convenient to display the reduction potentials corresponding to the various half reactions in diagrammatic from, known as Latimer diagram. The Latimer diagram for chlorine in acid solutionis Cl_(4)^(-)overset(+1.20V)toClO_(3)^(-)overset(+1.60V)toClO_(2)^(-)overset(+1.60V)to ClO^(-)overset(+1.67V)toCl_(2)overset(+1.36V)toCl^(-) In basic solution is : ClO_(4)^(-)overset(+0.37V)toClO_(3)^(-)overset(+0.30V)toClO_(2)^(-)overset(+0.68)to ClO^(-)overset(+0.42V)toCl_(2)overset(+1.36)toCl^(-). The standard potentials for two nonadjacent species can also be calculated by using the concept that DeltaG^(@) is an additive property but using potential is not an assitive property and DeltaG^(@)=-nFx^(0), If a given oxidation state is a the next higher oxidation state disproportionation can occur. The reverse of relative stabilities of the oxidation state can also be understood by drawing a graph of DeltaG^(@)//F against oxidation state, known as Frost diagram, Choosing the stability of zero oxidation state arbitrery as zero. The moststable oxidation state of a apecies lies lowest in the digram Disproportionation is spontaneous if the species lies above a straight line joining its two product species. What is the potential of couple (ClO^(-))/(Cl^(-)) at pH= 14 14?
Answer» 1.78V `-0.94V` `0.89V` `-0.89V` ANSWER :C

Discussion

4.	If an element can exist in several oxidation states, it is convenient to display the reduction potentials corresponding to the various half reactions in diagrammatic from, known as Latimer diagram. The Latimer diagram for chlorine in acid solutionis Cl_(4)^(-)overset(+1.20V)toClO_(3)^(-)overset(+1.60V)toClO_(2)^(-)overset(+1.60V)to ClO^(-)overset(+1.67V)toCl_(2)overset(+1.36V)toCl^(-) In basic solution is : ClO_(4)^(-)overset(+0.37V)toClO_(3)^(-)overset(+0.30V)toClO_(2)^(-)overset(+0.68)to ClO^(-)overset(+0.42V)toCl_(2)overset(+1.36)toCl^(-). The standard potentials for two nonadjacent species can also be calculated by using the concept that DeltaG^(@) is an additive property but using potential is not an assitive property and DeltaG^(@)=-nFx^(0), If a given oxidation state is a the next higher oxidation state disproportionation can occur. The reverse of relative stabilities of the oxidation state can also be understood by drawing a graph of DeltaG^(@)//F against oxidation state, known as Frost diagram, Choosing the stability of zero oxidation state arbitrery as zero. The moststable oxidation state of a apecies lies lowest in the digram Disproportionation is spontaneous if the species lies above a straight line joining its two product species. Which of the followingcouple have same value of potential at pH = 0 and pH = 14?
Answer» `(ClO_(4)^(-))/(ClO_(3)^(-))` `(ClO_(2)^(-))/(Cl_(2))` `(CLO^(-))/(Cl_(2))` `(Cl_(2))/(Cl^(-))` ANSWER :D

Discussion

5.	If an electron having kinetic energy 2 eV is accelerated through the potential difference of 2 volt. Then calculate the wavelength associated with the electron
Answer» Solution :Initial kinetic energy `KE=2 ev` INCREASE in `KE` due to acceleration `=qxxV=exx2v=2eV` `:.` Fimal kinetic energy, `KE_(f)=2+2=4 eV`. `:.` Associated de-Broglie WAVELENGTH, `lambda=12.27/sqrt(4)=6.15 Å`

Discussion

6.	If an atom has electronic configuration 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(3)4s^(2), it will be placed in
Answer» SECOND GROUP THIRD group Fifth group Sixth group Answer :C

Discussion

7.	If an atom from body-centred is removed in bcc, the packing fraction will be ....
Answer» `52%` `68%` `32%` `74%` ANSWER :A

Discussion

8.	If an atom crystallizes in bcc lattice with r = 4 A^@, edge length will be ..........
Answer» `2A^@` `8A^@` `2.39 A^@` `9.23 A^@` SOLUTION :For bcc LATTICE `a = 4/(sqrt3) R implies a = (4(4))/(sqrt3) = 9.23`.

Discussion

9.	If an aqueous solution of NaCl is electrolysed using platinum electrode by a currect of 5 amp, then what volume of Cl_(2) gas in litres at STP will be produced ?
Answer» ANSWER :7

Discussion

10.	If an aqueous solution of glucose allowed to freeze then crystalof which will be separated out first
Answer» Glucose water both of these none of these Solution :Freezing point is the temperature at which the liquid and the solid form of the same substance are in equilibrium and HENCE have the same vapour pressure . Due to lower vapour pressure of the solution, solid form of a solution SEPARATES out at a lower temperature. the decreases is called depression in freezing point. when solid is the SOLUTE, it is solvent that freezes. hence in the given question water will be separated out first.

Discussion

11.	If an acid-base reaction HA(aq)+B^(-)(aq)hArr HB(aq)+A^(-)(aq) has K_(aq)=10^(-4).how many of the following statements are true? (i) HB is stronger acid than HA (ii) HA is stronger acid than HB (iii) HA and HB have the same acidic strength (iv) B^(-) stronger base than A^(-) (v) A^(-) is stronger base than B^(-) (vi) B^(-) and HB are conjugate acid-base pair (vii) A^(-) is the conjugate base of acid HA. (viii)HA can beHSO_(4)^(-) and HB can be HCOOH. A^(-) can be F^(-) and B^(-) can be CN^(-)
Answer» Solution :`HA(aq)+B^(-)(aq)hArr HB(aq)+A^(-)(aq)""K_(eq)=10^(-4)` `K_(eq)` is very small .So reaction SHIFT in BACKWARD direction. `(1) HB` is more stronger acid than `HA` (2) `A^(-)` is more stronger base than `B^(-)` (3) `B^(-)` and `HB` are conjugate acid-base PAIR.

Discussion

12.	If ammonia is added to pure water the concentration of a chemical species already present will decrease.The species is :
Answer» `O^(2-)` `OH^-` `H_3O^+` `H_2O` ANSWER :C

Discussion

13.	If amount of radioactive substance is increased three times, the number of disintegrating atoms per unit time will:
Answer» be doubled be tripled one third unchanged. ANSWER :B

Discussion

14.	If alpha is the reaction of HI dissociation at equilibrium n the reaction, 2HI hArrH_(2)+I_(2) then starting with 2 moles of reactants and products at equlibrium is
Answer» SOLUTION :`2HIhArrH_(2)+I_(2)` `{:("Initial mole",2,0,0),("At EQ.",2(1-alpha),alpha,alpha):}` Total mole `=2(1-alpha)+alpha+alpha=2`

Discussion

15.	If alpha is the fraction of HI dissociated at equlibrium in the reaction :2H hArr H_(2)+I_(2) then starting with 2 mol of HI, the total number of moles of reactants and products at equlibrium are
Answer» 1 2 `1+alpha` `2+2alpha` SOLUTION :`2HIhArrH_(2)+I_(2)` `{:("Initial MOLES",2,0,0),("At eqm.",2(1-alpha),alpha, alpha):}`

Discussion

16.	If alpha is the degree of ionization, C the concenr=tration of a weak electrolyte and K_(a) the acid ionization constant, then the correct relationship between alpha, C and K_(a) is
Answer» `alpha^(2) = SQRT((K_(a))/(C))` `alpha^(2) = sqrt((C)/(K_(a))` `alpha = sqrt((K_(a))/(C))` `alpha = sqrt((C)/(K_(a))` Solution :According to the Ostwald's DILUTION FORMULA `alpha^(2) = (K(1- alpha))/(C)`. But for WEAK electrolytes `alpha` is very small. So that `(1- alpha)` can be neglected. So that `alpha = sqrt((K_(a))/(C))`.

Discussion

17.	If alpha is the degree of dissociation of Na_(2)SO_(4), the Vant Hoff's factor (i) used for calculating the molecular mass is
Answer» `1+alpha` `1-alpha` `1+2ALPHA` `1-2alpha` SOLUTION :`{:(Na_(2)SO_(4),hArr,2Na^(+),+,SO_(4)^(2-)),("Mol. before diss. 1",,0,,0),("Mol. after diss " 1-alpha,,2alpha,,1alpha):}` `i=(Exp. C.P.)/("Normal C.P.")=1-alpha+2alpha+alpha=1+2alpha`

Discussion

18.	If alpha is the degree of dissociation of Na_(2)SO_(4) , the Van't Hoff factor (i) used for calculating molecular mass is :
Answer» `1+ALPHA` `1-alpha` `1+2alpha` `1-2alpha` SOLUTION :`Na_(2)SO_(4)hArr2Na^(+)+SO_(4)^(2-)` `alpha=(i-1)/(n-1)=(i-1)/2` `i=1+2alpha`

Discussion

19.	If alpha is the degree of dissociation of Na_2SO_4, the Vant Hoff factor (i) used for calculating the molecular mass is
Answer» `1+alpha` `1-alpha` `1+2alpha` `1-2alpha` ANSWER :C

Discussion

20.	If alpha is the degrcc of dissociation of Na_(2) SO_(4) the Vant Hoff s factor (i) uscd for calculating the molecular mass is
Answer» `1+ alpha ` `1- alpha` `1+ 2 alpha` `1- 2 alpha ` Solution :`Na_(2) SO_(4) to 2NA^(4)+ SO_(4)^(2-)` `{:(" Mol. Beforre dissociation",1,0,0),("Mol after dissociation",1-alpha, 2 alpha, 1 alpha ):}` `i =1- alpha+ 2 alpha + alpha =1+ 2 alpha `

Discussion

21.	If alpha is the degree of dissociation of N_(2)O_(4)inthe reaction :N_(2)O_(4)hArr 2NO_(2)then at equilibrium, the total number of moles of N_(2)O_(4)andNO_(2)present is :
Answer» 2 `1-ALPHA` `(1-alpha)^(2)` `1+alpha` SOLUTION :`N_(2)O_(4)HARR 2NO_(2)` If `alpha` is the degree of dissociation `1-alpha "" 2ALPHA` Total no. of moles `=1-alpha+2alpha=1+alpha`

Discussion

22.	If all the F atoms are replaced by 'O' atom from SF_(4) without changing the covalency of 'S' atom then, which of the following property undergoes change in the process?
Answer» Oxidation STATE of 'S' atom d-orbital participation in bonding Hybridisation of 'S' atom Number of LONE pairs on 'S' atom Solution :`underset(sp^(3)d)(SF_(4))rarr` Covalency of S = 4

Discussion

23.	If all the three interaxial angles defining the unit ceil are equal in magnitude, the crystal cannot be!ong to (I) Orthorhombic system (II) Monoclinic system (III) Hexagonal system (IV) Tetragonal system
Answer» II, III I, IV III, IV I, II Answer :A

Discussion

24.	If alkyl halide is optically active SN^(1) reaction leads to,
Answer» RACEMISATION WALDEN INVERSION retention none of these ANSWER :A

Discussion

25.	If all the atoms, on the shaded plane are removed then the molecular formula of the solid will be
Answer» `A_(5)B_(7)` `A_(7)B_(5)` `AB` `A_(3)B_(4)` Solution :Edges removed `2 xx 1/4 = 1/2`. Body centres removed `1 xx 1 = 1/(3/2)`, .B. remaining `5/2`. Corners Removed `4 xx 1/8 = 1/2`. Face centres removed `2 xx 1/2 =1/(3/2)`. .A. remaining `5/2`, `therefore` The formula is A.B

Discussion

26.	If air is taken as a binary solution, the solvent is
Answer» `N_2` `O_2` `CO_2` `H_2` ANSWER :A

Discussion

27.	If air contains N_2 and O_2 in volume ratio 4:1, the average vapour density of air is :
Answer» 14.5 16.5 14.4 29 Answer :C

Discussion

28.	If air is taken as a binary solution, the solved is
Answer» `n_(2)` `O_(2)` `CO_(2)` `H_(2)` ANSWER :A

Discussion

29.	If AgNO_(3) solution is added in excess to 1 M solution of CoCl_(3)xNH_(3), one mole of AgCl is formed. What is value x
Answer» ANSWER :4

Discussion

30.	If Agl crystallises in zinc blende structure with I^(-) ions at lattice points. What fraction of tetrahedral voids is occupied by Ag^(+) ions
Answer» 0.25 0.5 1 0.75 Solution :In Agl crystal, number of `Ag^(+)` ions is equal to `I^(-)` ions. However, the number of tetrahedral VOIDS are twice the number of ATOMS FORMING the cubic lattice. `therefore` Number of tetrahedral voids occupied by `Ag^(+)` ion =50%

Discussion

31.	IfAgCl hArr Ag^(+) + Cl^(-) K_(eq) = 10^(-10) AgBr hArr Ag6(+) + Br(-) K_(eq) = 10^(-12) Ag(NH_(3))_(2)^(+) hArr Ag6(+) + 2NH-(3) K_(eq) = 10^)(-8) (At 25^(@)C assume (RT)/(F) = 0.06) Match the following columns:
Answer» ANSWER :(a-r)(b-s)(c-q)(d-p)

Discussion

32.	If Ag_(2)O (s) is ecposed to atmosphere having pressure 1 atm and temperature 1 atm and temperature 27^(@)C. Under these conditions comment whether it will dissociate spontaneously or not. 2Ag_(2)O (s) hArr 3Ag(s)+O_(2)(g) {:("Given :",,DeltaH_(f)^(@)" (kJ/mol)",DeltaS^(@)" (J/K mol) at "27^(@)C),(,Ag(s),0,42.0),(,Ag_(2)O(s),-30,121.0),(,O_(2)(g),0,204.0):} (Air consist of 20% O_(2) by volume) Take : R=8.3 JK^(-1) mol^(-1)
Answer» SOLUTION :`DeltaG^(@)=DELTAH^(@)-T DeltaS^(@)` `DeltaH^(@)=DeltaH_(f)^(@)("product")-DeltaH_(f)^(@) ("reactants")` `=2xx30=60 kJ` `DeltaS^(@)=204+4(42)-2(121)=+130` `DeltaG^(@)=DeltaH^(@)-T DeltaS^(@)=60000-300xx130` `DeltaG^(@)=21000 J=-RT ln K` `log K=-(21000/(300xx8.3xx2.3))` `K_(p)=2.15xx10^(-4)` atm The dissociation of `Ag_(2)O` is nonspontaneous at `27^(@)C`

Discussion

33.	If Ag^(+)+2NH_(3)iff[Ag(NH_(3))_(2)]^(+),K_(1)=1.7xx10^(7) Ag^(+)+Cl^(-)iffAgCl,K_(2)=5.4xx10^(9) Then for AgCl+2NH_(3)iff[Ag(NH_(3))_(2)]^(+)+Cl^(-) equilibrium constant will be
Answer» `0.31xx10^(-2)` `3.2xx102` `9.18xx1016` `1.00xx10^(-17)` SOLUTION :For reaction, `AG^(+)+2NH_(3)iff[Ag(NH_(3))_(2)]^(+),K_(1)=1.7xx10^(7)` For `Ag^(+)+Cl^(-)iffAgCl,K_(2)=5.4xx10^(9)` THUS for, `AgCliffAg^(+)+Cl^(-),K._(2)=(1)/(K_(2))=(1)/(5.4xx10^(9))` Now for the reaction, `AgCl+2NH_(3)iff[Ag(NH_(3))_(2)]^(+)+Cl^(-)` `K=K_(1)xxK._(2)=1.7xx10^(7)XX(1)/(5.4xx10^(9))=0.31xx10^(-2)`

Discussion

34.	If after addition of 'V' litres of water in 1 litre solution of 2.5 xx 10^(-3) M Ba(OH)_(2), pOH of solution becomes 3 times, and if V is expressed in scietific notattion as x xx 10^(y) then calculate value of y.
Answer» ANSWER :5

Discussion

35.	If adsorption occur on solid surface is limited to uni molecular layer than which of the following statement is true ?
Answer» Value of `(x)/(m)` remain independent of effect of less pressure of gas. At high pressure, value of `(x)/(m)`is more deviated in VAPOUR pressure. At NORMAL pressure, value of `(x)/(m)` remain relative less with respect to pressure. At low pressure of air, value of `(x)/(m)` is directly proportional to pressure. SOLUTION :At low pressure of air, value of `(x)/(m)`is directly proportional to pressure.

Discussion

36.	If addition of conc. H_(2)SO_(4) is made to an unknown salt, a colourless and odouriess gas is produced then which of the following can be present ?
Answer» `CO_(3)^(2-)` `S^(2-)` `CL^(-)` `NO_(3)^(-)` ANSWER :A

Discussion

37.	If activation energy of reaction is given as (2500 + 3T) R then calculate the value of In k (rate constant) at 100 K. Give your answer by multiplying with10 ["Given" : In 1000 ~=7]
Answer» ANSWER :285

Discussion

38.	Ifacidifiedsolution of K_(2)Cr_(2)O_(7)turmgreenon additionof a saltthree saltmay contain Fe^(2+).
Answer» Solution :`6Fe^(2+) + Cr_(3)O_(7)^(2-) + 14H^(oplus) rarr 6Fe^(oplus) + underset((Green))(2Cr^(3+)) + 7H_(2)O` `Cr_(2)O_(3)^(2+)//H^(oplus)` can oxidise `Fe^(2+)` in `Fe^(2+)` giving greencolouration at the and point

Discussion

39.	If activation energy of a reaction is zero, how does rate constant of the reaction change with temperature ?
Answer» SOLUTION :RATE CONSTANT does not CHANGE with change in TEMPERATURE. `K=AE^(-e_a//RT)=Ae^@=A`

Discussion

40.	If acetylene is passed through an electric arc in the atmosphere of nitrogen , the compound formed is
Answer» HCN Pyrrole Pyrazole Pyridine Answer :A

Discussion

41.	If acetic acid reacts with methyl alcohol containing labelled oxygen atom . Inpresence of dry HCl, the labelledoxygenatom, at thecomplete reaction will be found in
Answer» methyl ACETATE WATER MAY be 'a' and 'b' water ANSWER :A

Discussion

42.	If above tube is placed vertically with the open and upward then find the length of the air column.
Answer» SOLUTION :`P_1=75` CM of HG, `V_1=30xxA` `P_2=75+10+(20.4xx10)/13.6=100` cm of Hg `IMPLIES 75xx24=100xx X`

Discussion

43.	If acetyl chloride is reduced in presence of BaSO_4+ Pd, the product formed is :
Answer» `CH_3CHO` `CH_3CH_2OH` `CH_3COOH` `CH_3COCH_3` ANSWER :A

Discussion

44.	If above graph is correct for 1s then
Answer» `PSI` is zero when`R cancel(=) 0` `Psi` is maximum when `r cancel(=) 0` MAXIMA is at surface `Psi` have negative sign Answer :3

Discussion

45.	If AB_(4)^(n) types species are tetrahedral, then which of the following is /are correctly match ?
Answer» `{:(A,B,n),(XE,O,0):}` `{:(A,B,n),(SE,F,0):}` `{:(A,B,n),(P,O,-3):}` `{:(A,B,n),(N,H,+1):}` Answer :A::C::D

Discussion

46.	If a,b and c and alpha, betaand gammaare the edges and angles of a unit cell, then an orthorhombic unit cell is described as :
Answer» a=B`CANCEL(=)c,alpha,BETA=gamma =90^(@)` `a cancel(=)bcancel(=)c,alpha=beta=gamma=90^(@)` `a cancel(=)b cancel(=)c,alphacancel(=)beta cancel(=) gamma cancel(=)90^(@)` `a=b=c,alpha=beta=90^(@),gamma =120^(@)` ANSWER :B

Discussion

47.	If a_0 is the radius of first Bohr's orbit of H-atom, the de-Broglie's wavelength of an electron revolving in the 2nd Bohr's orbit will be
Answer» `4pia_(0)` `2pia_(0)` `6pia_(0)` NONE of these Solution :`a_(0)=0.529xx(1^(2))/(1)` `r_(a)=0.529xx(4)/(1)` `r_(a)=4a_(0)` `nlamda=2pir_(a)` `=pi4a_(0)=4pia_(0)`.

Discussion

48.	If a unimolecular reaction, A(g) toProducts, takes place according to the mechanism (I) A+Aoverset(k_(1))underset(k_(-1))(hArr)A^(a)+A (II) A^(a)underset(k_(2))(to)P where k_(1), k_(-1) and k_(2) are the rate constants and P, A and A^(a) stand for product molecule, normal molecule of reactant and activated molecules of reactant and activated molecules of reactant respectively. The order 'n' initial concentration a_(0) and time of half reaction t_(1//2), for a reaction are related as
Answer» `LN t_(1//2)=ln("constant")-(N-1)lna_(0)` `t_(1//2)lnn=ln("constant")+lna_(0)` `ln t_(1//2)=lnn+ln("constant")-lna_(0)` `ln t_(1//2)=n lna_(0)` ANSWER :A

Discussion

49.	If [A_(0)] is the initial concentration and [A] is the concentration at time t then :
Answer» `[A] = [A]_(0) E^(k//t)` `[A]=[A]_(0)e^(-KT)` `[A]_(0)=[A] e^(-k//t)` `[A]= [A]_(0)e^(-k//t)` ANSWER :B

Discussion

50.	If a unimolecular reaction, A(g) toProducts, takes place according to the mechanism (I) A+Aoverset(k_(1))underset(k_(-1))(hArr)A^(a)+A (II) A^(a)underset(k_(2))(to)P where k_(1), k_(-1) and k_(2) are the rate constants and P, A and A^(a) stand for product molecule, normal molecule of reactant and activated molecules of reactant and activated molecules of reactant respectively. For the reaction scheme, X+Yoverset(k_(f))underset(k_(b))(hArr)Z, Y+Zoverset(k)(to)T, the rate equation for the formation of T will be
Answer» `(d(T))/(dt)=(k_(f)K[X][Y])/(k_(B)+k[Y])` `(d(T))/(dt)=(k_(f)k_(b)k[X][Y])/(k_(b)+k[B])` `(d(T))/(dt)=(k_(f)k[X][Y]^(2))/(k_(b)+k[B])` `(d(T))/(dt)=(k_(b)k[A][B])/(k_(b)k+k[B])` Answer :B

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

If an electron having kinetic energy 2 eV is accelerated through the potential difference of 2 volt. Then calculate the wavelength associated with the electron

If an atom has electronic configuration 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(3)4s^(2), it will be placed in

If an atom from body-centred is removed in bcc, the packing fraction will be ....

If an atom crystallizes in bcc lattice with r = 4 A^@, edge length will be ..........

If an aqueous solution of NaCl is electrolysed using platinum electrode by a currect of 5 amp, then what volume of Cl_(2) gas in litres at STP will be produced ?

If an aqueous solution of glucose allowed to freeze then crystalof which will be separated out first

If ammonia is added to pure water the concentration of a chemical species already present will decrease.The species is :

If amount of radioactive substance is increased three times, the number of disintegrating atoms per unit time will:

If alpha is the reaction of HI dissociation at equilibrium n the reaction, 2HI hArrH_(2)+I_(2) then starting with 2 moles of reactants and products at equlibrium is

If alpha is the fraction of HI dissociated at equlibrium in the reaction :2H hArr H_(2)+I_(2) then starting with 2 mol of HI, the total number of moles of reactants and products at equlibrium are

If alpha is the degree of ionization, C the concenr=tration of a weak electrolyte and K_(a) the acid ionization constant, then the correct relationship between alpha, C and K_(a) is

If alpha is the degree of dissociation of Na_(2)SO_(4), the Vant Hoff's factor (i) used for calculating the molecular mass is

If alpha is the degree of dissociation of Na_(2)SO_(4) , the Van't Hoff factor (i) used for calculating molecular mass is :

If alpha is the degree of dissociation of Na_2SO_4, the Vant Hoff factor (i) used for calculating the molecular mass is

If alpha is the degrcc of dissociation of Na_(2) SO_(4) the Vant Hoff s factor (i) uscd for calculating the molecular mass is

If alpha is the degree of dissociation of N_(2)O_(4)inthe reaction :N_(2)O_(4)hArr 2NO_(2)then at equilibrium, the total number of moles of N_(2)O_(4)andNO_(2)present is :

If all the F atoms are replaced by 'O' atom from SF_(4) without changing the covalency of 'S' atom then, which of the following property undergoes change in the process?

If all the three interaxial angles defining the unit ceil are equal in magnitude, the crystal cannot be!ong to (I) Orthorhombic system (II) Monoclinic system (III) Hexagonal system (IV) Tetragonal system

If alkyl halide is optically active SN^(1) reaction leads to,

If all the atoms, on the shaded plane are removed then the molecular formula of the solid will be

If air is taken as a binary solution, the solvent is

If air contains N_2 and O_2 in volume ratio 4:1, the average vapour density of air is :

If air is taken as a binary solution, the solved is

If AgNO_(3) solution is added in excess to 1 M solution of CoCl_(3)xNH_(3), one mole of AgCl is formed. What is value x

If Agl crystallises in zinc blende structure with I^(-) ions at lattice points. What fraction of tetrahedral voids is occupied by Ag^(+) ions

IfAgCl hArr Ag^(+) + Cl^(-) K_(eq) = 10^(-10) AgBr hArr Ag6(+) + Br(-) K_(eq) = 10^(-12) Ag(NH_(3))_(2)^(+) hArr Ag6(+) + 2NH-(3) K_(eq) = 10^)(-8) (At 25^(@)C assume (RT)/(F) = 0.06) Match the following columns:

If Ag^(+)+2NH_(3)iff[Ag(NH_(3))_(2)]^(+),K_(1)=1.7xx10^(7) Ag^(+)+Cl^(-)iffAgCl,K_(2)=5.4xx10^(9) Then for AgCl+2NH_(3)iff[Ag(NH_(3))_(2)]^(+)+Cl^(-) equilibrium constant will be

If after addition of 'V' litres of water in 1 litre solution of 2.5 xx 10^(-3) M Ba(OH)_(2), pOH of solution becomes 3 times, and if V is expressed in scietific notattion as x xx 10^(y) then calculate value of y.

If adsorption occur on solid surface is limited to uni molecular layer than which of the following statement is true ?

If addition of conc. H_(2)SO_(4) is made to an unknown salt, a colourless and odouriess gas is produced then which of the following can be present ?

If activation energy of reaction is given as (2500 + 3T) R then calculate the value of In k (rate constant) at 100 K. Give your answer by multiplying with10 ["Given" : In 1000 ~=7]

Ifacidifiedsolution of K_(2)Cr_(2)O_(7)turmgreenon additionof a saltthree saltmay contain Fe^(2+).

If activation energy of a reaction is zero, how does rate constant of the reaction change with temperature ?

If acetylene is passed through an electric arc in the atmosphere of nitrogen , the compound formed is

If acetic acid reacts with methyl alcohol containing labelled oxygen atom . Inpresence of dry HCl, the labelledoxygenatom, at thecomplete reaction will be found in

If above tube is placed vertically with the open and upward then find the length of the air column.

If acetyl chloride is reduced in presence of BaSO_4+ Pd, the product formed is :

If above graph is correct for 1s then

If AB_(4)^(n) types species are tetrahedral, then which of the following is /are correctly match ?

If a,b and c and alpha, betaand gammaare the edges and angles of a unit cell, then an orthorhombic unit cell is described as :

If a_0 is the radius of first Bohr's orbit of H-atom, the de-Broglie's wavelength of an electron revolving in the 2nd Bohr's orbit will be

If [A_(0)] is the initial concentration and [A] is the concentration at time t then :