1.

If Ag^(+)+2NH_(3)iff[Ag(NH_(3))_(2)]^(+),K_(1)=1.7xx10^(7) Ag^(+)+Cl^(-)iffAgCl,K_(2)=5.4xx10^(9) Then for AgCl+2NH_(3)iff[Ag(NH_(3))_(2)]^(+)+Cl^(-) equilibrium constant will be

Answer»

`0.31xx10^(-2)`
`3.2xx102`
`9.18xx1016`
`1.00xx10^(-17)`

SOLUTION :For reaction,
`AG^(+)+2NH_(3)iff[Ag(NH_(3))_(2)]^(+),K_(1)=1.7xx10^(7)`
For `Ag^(+)+Cl^(-)iffAgCl,K_(2)=5.4xx10^(9)`
THUS for,
`AgCliffAg^(+)+Cl^(-),K._(2)=(1)/(K_(2))=(1)/(5.4xx10^(9))`
Now for the reaction, `AgCl+2NH_(3)iff[Ag(NH_(3))_(2)]^(+)+Cl^(-)`
`K=K_(1)xxK._(2)=1.7xx10^(7)XX(1)/(5.4xx10^(9))=0.31xx10^(-2)`


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