This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If a certain oxide of nitrogen weighing 0.11 g gives 56 mL of nitrogen and another oxide of nitrogen weighing 0.15 g gives the same volume of nitrogen (both at sTP), show that these results support the law of multiple proportions. |
| Answer» Solution :22400 mL of `N_(2)` at STP weigh = 28 G. CALCULATE the mass of nitrogen. Then SUBSTRACT from the mass of oxide of nitrogen to calculate the mass of oxygen. | |
| 2. |
If a certain buffer solution contains equal concentration of X^- and HX. Then the pH of buffer will be (K_b for X^- is 10^-10) |
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Answer» 10 |
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| 3. |
If a centi normal solution of NH_4OH has molar conductivity equal to 9.6 Omega^(-1) cm^(2) mol^(-1). what will be the per cent dissociation of NH_4OH at this dilution. |
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Answer» |
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| 4. |
If a carbanion is bonded to hydrogen or an alkyl group then, the shape of methyl carbainon is likely to be |
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Answer» tetrahedral |
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| 5. |
If a be the edge length of the unit cell and r be the radius of an atom, then for fcc arrangement, the correct relation is |
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Answer» `4A = sqrt( 3) R` |
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| 6. |
If A, B, C and D are element's of 3^(rd) period of p-block in modern Periodic Table. Among these 'A' is a metal, 'B' is metalloid and 'C', 'D' are non metals and their order of electronegativity is given as rarr A lt B lt C lt D Which element is expected to form Amphoteric Oxide? |
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Answer» A `l+m=0implies""i.e "s-subshell"` `l=1, m=-1 ""i.e. "ONE orbital of p."` `l=2, m=-2 ""i.e. "one of d-orbitals."` Hence there are total of `13 e^(-)` having `l+m=0` |
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| 7. |
If a 6.84% (wt/vol.) solution of cane sugar (mol.wt.=342) is isotonic with 1.52%(wt/vol.) solution of thiocarbamide, then the molecular weight of thiocarbamide is: |
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Answer» 152 |
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| 8. |
If a 0.1 M solution of HCN is 0.01 % ionised , the K_(a) for HCN is : |
| Answer» Answer :A | |
| 9. |
If a 0.1 M solution of glucose ( mol.wt. 180 ) and 0.1molarsolution of urea ( mol. wt. 60 ) are placedon the two sides of a semipermeable membrane to equal heights, then itwill be correct to say |
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Answer» There will be on net MOVEMENT across the MEMBRANE |
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| 10. |
If ._(92)U^(235) nucleus absorbs a neutron and disintegrates in ._(54)Xe^(139), ._(38)Sr^(94) and X, then what will be the product X |
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Answer» `alpha`-particle |
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| 11. |
If 9650 coulombs of electricity is passed through a copper sulphate solution, the number of moles of copper deposited will be |
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Answer» 3.15 `therefore N= (1xx9650)/(2xx96500) =0.05` mole |
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| 12. |
If 965 coulombs of electricity is passed through a metal cup dipped in silver(l) salt solution, in order to plate it with silver. Then the amount of silver deposited on its surface is (Given : the molar mass of Ag = 108 g mol^(-1), 1F = 96500 coulombs) |
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Answer» `1.08 G` |
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| 13. |
If 9650 coulombs of electricity is passed through a copper sulphate solution , the number of moles of copper deposited will be _________. |
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Answer» 0.05 |
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| 14. |
If ._(92)U^(236) nucleus emits one alpha-particles, the remaining nucleus will have |
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Answer» 119 neutrons and 119 protons `._(90)X^(232)` have 90 protons and 142 neutrons |
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| 15. |
If 900 J/g of heat is exchanged at boiling point of water, then what is increase in entropy |
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Answer» `43.4 J//mol` |
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| 16. |
If 90 g of water is electrolysed completely with 50% current efficiency 10 faraday of electricity will be consumed 20 faraday of electricity will be consumed c) 168 L (STP) of gases will be produced d) 84 L (STP) of gases will be produced. Correct statements are |
| Answer» ANSWER :A | |
| 17. |
IF 900 J/g of heat is exchanged at boiling point of water then increase in entropy is |
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Answer» 43.4 J/MOL K |
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| 18. |
If 8.3mL of a sample of H_(2)SO_(4) (36 N) is diluted by 991.7 mL of water required 19.8 mL of 0.1 N HCl .The value of x is |
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Answer» `0.4` |
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| 19. |
If 772 mL of SO_(2) gas at STP is adsorbed on 2 g of charcoal at an equlibrium pressure of 16 atmospheres and the value of the constant 'k' in the Freundlich equation is 0.48. the value of the constant 'n' will be |
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Answer» Moar volume at `STP=22400mL` `THEREFORE` ML of `SO_(2)` at STP well have mass `=(64)/(22400)xx772=1.92g` `therefore x/m=(1.92)/(2)=0.96` But `x/m=kP^(1//n)` `therefore 0.96 =0.48 xx(16)^(1//n) or 2=(16)^(1//n)` `therefore n=4.` |
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| 20. |
If 8.2g of anhydrous sodium acetate is added to 11 of 0.l(M) acetic acid solution, then what will be the change in degree of ionisation of the acid? [Given: K_1(CH_3COOH)=1.8xx10^(-5)] |
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Answer» SOLUTION :If the degree of dissociation of monobasic acid, HA in its aqueous solution `=prop`, MOLAR concentration=c(M) and dissociation constant of the acid`=K_a`, then `K_a=(prop^2c)/(1-prop)` Let the solution is x times diluted. Hence, `c=(0.1)/(x)(M)` As given, degree of ionisation of HA in the dilute solution`=2prop` `:.2prop=sqrt((K_a)/((0.1//x)))=sqrt((x xxK_a)/(0.1))` From [1] & [2], `2xxsqrt((K-a)/(0.1))=sqrt((x xxK-a)/(0.1))` or `sqrtx=2` `:.x=4` Therefore, if the solution is diluted 4 times, then degree of dissociation of HA in the diluted solution will be 2 times that of the initial solution. |
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| 21. |
If 720 litres of a gas were collected over water at 25^(@)C and 720 mm then the volume of the dry gas at the same temperature and pressure is (aq. Tension of water at 25^(@)C = 23.8 mm) |
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Answer» 696.2 litres |
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| 22. |
If 75% quantity of a radioactive isotope disintegrates in 2 hour , its half-life would be : |
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Answer» 1 hour |
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| 23. |
If 7% of a first order reaction was completed in 60% of the same reaction under the same conditions would be completed in......... |
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Answer» 20 minutes `t_(50%=((t_(75%))/2))=(60/2)= 30` MIN |
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| 24. |
If 6gm of CH_(3)COOH is dissoved in benzene to make 1 litre at 300K. Osmotic pressure of solution is found to be 1.64 atm. If it is known that CH_(3)COOH in benzene forms a dimer. Calculate degree of association of acetic acid in benzene? |
Answer» SOLUTION : `i=1+((1)/(n)-1)beta` `1.64=0.0821xx300xx[1+((1)/(n)-1)beta]xx0.1` `RARR 1.64=0.0821xx300[1-(beta)/(2)]0.1` `(1.64)/(00.821xx30)=(2-beta)/(2)` `(1.64)/(2.46)=(2-beta)/(2) 4=6.3beta` `beta=(2)/(3)` |
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| 25. |
If 6.3 g of NaHCO_(3) are added to 15.0 g of CH_(3)COOH solution, the residue is found to weigh 18.0 g. The mass of CO_(2) released in the reaction is |
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Answer» 9.3 g Mass of reactants = Mass of PRODUCTS `6.3 g + 15.0 g= 18.0 g+` Mass of `CO_(2)` Mass of `CO_(2) = 6.3g + 15.0g - 18.0 g = 3.3 g` |
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| 26. |
If 61.25 gm of K ClO_(3) reacts with excess of red phosphorus, what mass of tetraphosphorous dioxide (P_(4) O_(10)) would be produced. K ClO_(3) (s) + P_(4) (s) rarr P_(4) O_(10) (s) + K Cl (s) |
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Answer» `142 gm` `61.25 gm` `N = (61.25)/(122.5)` `{:(n = (1)/(2) " mole" ,n = (3)/(10) xx (1)/(2),),(,n = (3)/(20) " mole",):}` mass of `P_(4)O_(10) = (3)/(20) (3 1 xx 4 + 10 xx 16)` `= (3)/(20) (284)` `= 14.2 xx 3` `= 32.6 gm` |
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| 27. |
If 6.3 g of NaHCO_(3) are added to 15.0 g of CH_(3)COOH solution, the residue is found to weigh 18.0 g. What is the mass of CO_(2) released in the reaction? |
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Answer» |
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| 28. |
If 6.022xx10^(23) atoms are present in 100 mL of urea solution then find out the molarity of urea solution. |
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Answer» |
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| 29. |
If 6.022xx10^(20) molecules are present in 100 mL urea solution, then find out the concentration of urea solution. |
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Answer» 0.01 M `6.022xx10^(23)` molecule urea = 1 mole urea `6.022xx10^(20)` molecule urea = (?) `THEREFORE M=(10^(-3))/(0.1("liter"))=0.01M` |
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| 30. |
If 60% of a first order reaction was completed in 60 minutes 50% of the same reaction would be completed in approximately : |
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Answer» 45 minutes `:. K = (2.303)/(60) "log" ([A]_(0))/(0.4[A]_(0))` `= (2.303)/(60) "log" (10)/(4)` `= (2.303)/(60) ` (log 10 -log 4) Now `t_(1//2) = (0.693)/(k) = (0.693xx60)/(2.303xx0.4)` `= 45.14 ~~45 ` min . |
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| 31. |
If 6 litre of H_(2) of Cl_(2) are mixed and exploded in an eudiometer, the volume of HCl formed is: |
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Answer» 6.0 litre |
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| 32. |
If 60% of a first order reaction was completed in 60 minutes , 50% of the same reaction would be completed in approximately |
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Answer» 50 MINUTES `k = (0.693)/(T_(1//2)) T_(1//2) = (0.693)/(0.152) = 45.37` min . |
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| 33. |
If 60 cm^(3) of ethyl alcohol is mixed in water to form 360 cm^(3) of dilute ethyl alcohol solution, then the percentage by volume of ethyl alcohol in water is _________. |
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Answer» `16.67%` |
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| 34. |
If 60% of a first order reaction was completed in 60 min, 50% of the same reaction would be completed in approximately |
| Answer» Answer :A | |
| 35. |
If 5g of a radioactive substance has a t_((1)/(2))=14h, 20g of the same substance will have a t_((1)/(2)) equal to |
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Answer» 56h |
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| 36. |
If 5.85 gms of NaCl are dissolved in 90 gms of water, the mole fraction of NaCl is |
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Answer» `0.1` `90 g H_(2)O=(90)/(18)` MOLES = 5 moles mole fraction of NaCl = `(0.1)/(5+0.1)~~0.0196`. |
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| 37. |
If 5.85 gm of NaCl is dissolved in 90 gm of water, then find out the mole fraction of NaCl. |
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Answer» |
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| 38. |
If 54 g of silver is deposited during an electrolysis reaction, how much aluminium will be deposited by the same amount of electric current? |
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Answer» (a) 2.7 G 54 g of Ag will be deposited by `1/108xx54=1/2F` 3 F deposite 27 g of Al (`Al^(3+) + 3E^(-) to Al`) `1/2F` will deposit `27/3xx1/2`=4.5 g of Al |
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| 39. |
If 500 mL of a 5 M solution is diluted to 1500 mL, what will be the molarity the solution obtained? |
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Answer» `1.5M` |
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| 40. |
If 50% of a radioactive substance has t_(1//2) = 14 hr , 2 g of the same substance will have a t_(1//2) equal to |
| Answer» SOLUTION :`t_((1)/(2))` = contain for a NUCLEIDE | |
| 41. |
If 50 % of the reactant is converted into a product in first order reaction in 25 minutes how much of it would react in 100 minutes ? |
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Answer» 93. 75 % Number of half - lives in 100 min =`(100)/(25)=4` `:.` FRACTION of substance remaining after 100 min `= (1)/(2^(4)) = (1)/(16)` Thefraction of substance REACTED in 100 min . `= 1- (1)/(16)=(15)/(16)=0.9375` % of substance reacted = 93.75 % |
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| 42. |
If 50 ml of A_(2)B_(3) reacts completely with 200 ml of C_(2) in closed vessel according to the equation , 2A_(2)B_(3)(g)+5C_(2)(g) to 3C_(3)B_2(g)+CA_(4)(g) . The composition of the mixtureof gasesis : |
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Answer» 10 ml ` C_(2)` , 25 ml `C_(3)B_(2)`, 100 ml `CA_(4)` |
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| 43. |
If 50 ml of each 1 M NaOH are mixed then correct option is |
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Answer» I,I, R |
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| 44. |
If 50 of 1 M H_3X mixed with 150 mL of 1 M NaOH then correct option is |
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Answer» Solution :`[Na_3X]=50/200=0.25 M` `pH=7+1/2pK_(a_3)+1/2logC` =11.2 |
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| 45. |
If 50% of the reactant is converted into a product in a first order reaction in 25 minutes, how much of it would react in 100 minutes? |
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Answer» 0.9375 `100 OVERSET(25"min")RARR 50 overset(25"min")rarr 25 overset(25"min")rarr 12.5 overset(25 "min")rarr 6.25` 6.25% remaining i.e., 93.75% REACTED. |
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| 46. |
If 50 ml of 1 M H_3X and 25 mL of 1 M NaOH mixed then correct option is- |
| Answer» Solution :`pH=5+log(25/25)=5` | |
| 47. |
If 50 ml of 0.2 M KOH is added to 40 ml of 0.5 M HCOOH, the pH of the resulting solution is (K_(a) = 1.8 xx 10^(-4)) |
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Answer» 3.4 |
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| 48. |
If 50 mL of 0.2 M KOH is added to 40 mL of 0.5 M HCOOH. Find the resulting solution. (K_c = 1.8 xx 10^-4) : |
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Answer» 3.75 |
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| 49. |
If 50 milli ampere of current is passed through copper coulometer for 60 min, calculate the amount of copper deposited. |
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Answer» Solution :ELECTRICAL charge input `=Ixx"t coulombs"` `=50xx10^(-3)Axx60xx60sec` `="180 coulombs."` The chemical reaction is, `Cu^(2+)+2E rarr Cu_((s))` 1 gm atom of COPPER requires 2F CURRENT `therefore" AMOUNT of copper deposted "=(63.5g.mol^(-1)xx180C)/(2xx96500C)` `=0.0592gm.` |
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| 50. |
If 50 gm oleum sample rated as 118% is mixed with 18 gm water, then the correct option is |
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Answer» The resulting solution contains 18 gm of water and 118 gm `H_(2)SO_(4)` |
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