Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

HI cannot be prepared by adding conc. H_(2) SO_(4) to iodides because

Answer»

HI is a stronger ACID than `H_(2) SO_(4)`
`H_(2) SO_(4)` is a stronger acid than HI
`H_(2) SO_(4)` is a stronger OXIDISING agent than `I_(2)`
HI is a strong reducing agent

Solution :`H_(2) SO_(4)` in a stronger oxidising agent than `I_(2)`, HI is a strong reducing agent.
2.

Heating rubber with sulphur is known as

Answer»

GALVANISATION
bessmerisation
VULCANISATION
SULPHONATION .

ANSWER :C
3.

HI can not be prepared by which of the following methods ?

Answer»

`Pl_(3) + H_(2)O to `
`Kl + H_(2)SO_(4)("conc") to`
`H_(2) + I_(2) to`
`I_(2) + H_(2)s to`

Solution :KI will be oxidised to `I_2` in PRESENCE of cone. `H_2SO_4` .
4.

Heatingpyrites to removesulphur is called

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SMELTING
CALCINATION
LIQUATION
ROASTING.

ANSWER :D
5.

HgS issoluble in aque regain forming HgCI_(2) What happens if Cu ruranings are added to HgCI_(2)?

Answer»

Solution :`HgCI_(2) + Cu RARR CuCI_(2) + Hg + Hg` is deposite on `Cu`
6.

HgS_((s)) + O_(2(g)) rarr Hg_((l)) +SO_(2) uarr The above reaction is an example of _______ reduction.

Answer»

metal
hydrogen
carbon
auto

Answer :D
7.

Heating pyrites to remove sulphur is called

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SMELTING
Calcination
Liquation
Roasting

Answer :D
8.

Hg(NO_(3))_(2) overset(Delta) toW + X + O_(2) X + H_(2)O rarr HNO_(2) + HNO_(3) W + HNO_(3) rarr Y + NO + H_(2)O Y + Na_(2)S_(2)O_(3) ("excess") rarr 2 + NaNO_(3)

Answer»

`{:("W"," X","Y","Z"),(Hg,N_(2)O,Hg(NO_(3))._(2),Na_(2)[Hg(S_(2)O_(3))_(2)]):}`
`{:("W"," X","Y","Z"),(Hg,NO,Hg(NO_(3))._(2),Na[Hg(S_(2)O_(3))_(2)]):}`
`{:("W"," X","Y","Z"),(Hg,NO_(2),Hg(NO_(3))._(2),Na_(2)[Hg(S_(2)O_(3))_(2)]):}`
`{:("W"," X","Y","Z"),(Hg,N_(2)O_(3),Hg(NO_(3))._(2),Na_(3)[Hg(S_(2)O_(3))_(2)]):}`

Solution :`Hg(NO_(3))_(2)overset(DELTA)rarrHg(1)+underset((W))(NO_(2)uarr) +underset((X))(O_(2)uarr)`
`2NO_(2) +H_(2)O rarr HNO_(2) +HNO_(3)`
`underset((W))(Hg)+4HNO_(3) overset(Delta)rarr underset((Y))(Hg(NO_(3))_(2)) +2NO uarr+2H_(2)O`
`Hg(NO_(3))_(2)+underset(("Soluble"))(Na_(2)S_(2)O_(3))rarr Na_(2) [Hg(S_(2)O_(3))_(2)] +2NaNO_(3)`
9.

Heating pyrites in air to remove sulphur is known as

Answer»

ROASTING 
CALCINATION 
SMELTING 
BESSEMERISATION 

ANSWER :A
10.

Heating of rubber with sulphur is known as

Answer»

Galvanisaiton
VULCANISATION
BESSEMERISATION
SULPHONATION

ANSWER :B
11.

HgO+Cl_(2)+H_(2)O rarr HgOHgCl_(2) + ( X )The oxidation state of central atom of 'X' is

Answer»


Solution :`2HgO + 2 Cl_(2) + H_(2)O rarr HgO . HgCl_(2) + 2HOCl`
X is HOCl. Central atom Cl is in `+1` STATE.
12.

HgO do not require reducing agent while isolation because

Answer»

HIGH + ve `DELTA G^(@)`
low `-ve DeltaG^(@)`
high-ve `DeltaG^(@)`
low `+ve DeltaG^(@)`

Solution :Due to low `-ve DeltaG^(@)` , HgO can be DECOMPOSED to Hg SIMPLY by heating
13.

Heating of pyrites in air for oxidation of sulphur is called Heating of ore in presene of air toremove sulphure impurities is called

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Roasting
Calcination
Smelting
Slagging

Solution :Roasting involves heating of the ORE either ALONE or with some other material usually in PRESNECE of air below its fusion temperature.In roasting, definite chemical changes LIKE oxidation. Chlorination ETC, take place
`S+O_(2)toSO_(2)`
14.

HgI_(2)darr+KI hArrK_(2)[HgI_(4)]

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For PRECIPITATE formation formation reaction
For precipitate DISSOLUTION reaction
For precipitate exchange reaction
For no reaction

Answer :b
15.

Heating of pyrites in presence of air to remove sulphur is called as:

Answer»

ROASTING
CALCINATION
SMELTING
FLUXING

ANSWER :A
16.

HgCl_2 is reduced to Hg_2Cl_2 by:

Answer»

`CH_3COOH`
`C Cl_4`
HCOOH
`NH_4`

ANSWER :C
17.

Heating of pyrites in air for oxidation of sulphur is called

Answer»

ROASTING
calcination
smelting
slagging

SOLUTION :roasting
18.

HgCl_2is reduced to Hg_2Cl_2 by

Answer»

`CH_4COOH`
`"CC"l_4`
HCOOH
`NH_3`

SOLUTION :`HCOOH + 2HgCl_2 rarrHg_2Cl_2 + CO_2 + 2HCL`
19.

HgCl_(2) givesorange ppt , with (a) ___, whichdissolves in oxicess of itforming (b) ____ called (c ) ____.

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ANSWER :kJ,B`K_(2)HgI_(4)`,c. NESSLER's reagent
20.

Heating of pyrite ores in air to remove sulphur is known as :

Answer»

Calcination
Fluxing
Smelting
Roasting

Answer :D
21.

Heating pyrites to remove sulphur is called :

Answer»

Calcination
Fluxing
Smelting
Roasting

Answer :D
22.

Heating of oxalic acid with conc. H_(2)SO_(4) evolves

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 CO
 `CO_(2)`
`SO_(2)`
 `SO_(3)`

ANSWER :A::B
23.

HgCl_(2) and l_(2) both when dissolved in water containing I^(-) ions, the pair of species formed is….

Answer»

`HG I_(2), I_(3)^(-)`
`Hg_(2), I_(2), I^(-)`
`Hg I_(4)^(2-), I_(3)^(-)`
`Hg I_(2), I^(-)`

Solution :`I_(2(s)) + I^(-) rarr I_(3)^(-)`
`HgCl_(2) + 4I^(-) rarr [Hg I_(4)]^(2-) + 2Cl^(-)`
24.

Heating of oxalic acid with cone. H_2SO_4 gives:

Answer»

`CO+O_2`
`CO_2` and `CO
`SO_2+SO_3`
SO_3` and CO

Answer :B
25.

HgCl is a covalent compound, sparingly soluble in water, the solubility increase by the addition of chloride ions due to:

Answer»

COMMON ion effect
formation of complex `[HgCl_(4)]^(2-)`
weakening of Hg-Cl bonds
strong ion-dipole forces

Answer :B
26.

Heating of oxalic acid with conc. H_2 SO_4 gives

Answer»

CO
`CO_(2)`
`CO+CO_(2)`
NONE

SOLUTION :`H_(2)C_(2)O_(4) OVERSET(Conc. H_(2)SO_(4)//Delta)to H_(2)O+Couarr+CO_(2)uarr`
27.

HgCI_(2)+ "excess of" KI rarr (A) underset(NH_(3)) to (B) ,(A) and (B)respectively are

Answer»


`(Y),(X)`
both (X)
both (Y)

ANSWER :a
28.

Hg_(2)Cl_(2) is black enedby NH_(3) due toformation ofiodideof millon's base

Answer»


Solution :White ppt of `Hg_(2)CI_(2)` is blackenedby`NH_(3)` due to formation of `[HgNH_(3)ICI + HGI`
29.

Heating of ores with flux to remove non fusible mass is called:

Answer»

SMELTING
Calcination
Roasting
Cupellation

Answer :A
30.

Hg_(2)^(2+) when reacts with H_(2)S, black ppt. (A) formed which when reacts with Na_(2)S followed by filtration leaving behind black ppt. (B). The filitrate with H^(+) gives black ppt. (C). A, B and C are:

Answer»

`Hg_(2)S,HG,HGS`
`Hg+HgS,HgS,Hg`
`Hg+HgS,Hg,HgS`
`Hg_(2)S,HgS,Hg`

ANSWER :C
31.

Heating ofpyrites in air to remove sulphur is called :

Answer»

CALCINATIONS
FLUXING
SMELTING
ROASTING

ANSWER :D
32.

Heating of (CH_3 )_2 SiCl_2 in the presence of water gives

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`(CH_3 )_2 Si=O`


ANSWER :D
33.

Hg_(2)Cl_(2) aprecipitate if (a) ____is greaterthan K_(sp) (Hg_(2)Cl_(2)).

Answer»


ANSWER :a.`[Hg_(2)^(2+)][CI^(THETA)]^(2)`
34.

Heating of alkanes with fuming sulphuric acid or oleum at high temperature, which forms sulphonic acid, is called

Answer»

Nitration
Halogenation
Sulphonation
Oxidation

Answer :C
35.

Hg sticks to the surface of glass when it comes into contact with

Answer»

`H_(2)O`
`HNO_(3)`
Grease
`O_(3)`

Answer :D
36.

Heating of carbonate ores to remove carbon is called as :

Answer»

Roasting
Calcination
Smelting
Fluxing

Answer :B
37.

Heating mixture of sodium benzoate and soda-lime gives

Answer»

benzene
methane
sodium phenoxide
calcium benzoate

Answer :A
38.

HF present as impurity in gaseous fluorine can be removed by passing over

Answer»

`P_(2)P_(5)`
`NaF`
`H_(2)SO_(4)`
`CaCl_(2)O_(2)`

Solution :HF IMPURITY present in FLUORINE GAS removed by NaF
39.

Heating mixture of Cu_(2)O and Cu_(2)S will give……..

Answer»

`CU+SO_(2)`
`Cu+SO_(3)`
CuO+CuS
`Cu_(2)SO_(3)`

ANSWER :A
40.

HF is not kept inside

Answer»

GLASS BOTTLE
PLASTIC bottle
tin bottle
iron bottle

Solution :Glass REACTS with HF.
41.

Heating in aqueous solution of aluminium chloride to dryness will give

Answer»

`Al(OH)Cl_(2)`
`Al_(2)O_(3)`
`Al_(2)Cl_(6)`
`AlCl_(3)`

SOLUTION :The solution of aluminium chloride in water is acidic due to HYDROLYSIS.
`AlCl_(3)+3H_(2)O to Al(OH)_(3)+3HCl`
On heating it TILL dryness `Al(OH)_(3)` is converted into `Al_(2)O_(3)`
2Al(OH)_(3) overset(Delta) to Al_(2)O_(3)`.
42.

HF present as impurity in gaseous F_2 can be removed by passing over

Answer»

`P_2O_5`
NAF
`H_2SO_4`
CaCl

Answer :B
43.

Heating a mixture of Cu_2O and Cu_2S will give

Answer»

`CU +SO_2`
`Cu +SO_3`
`CUO +CUS `
`Cu_2 SO_3`

ANSWER :A
44.

Heating Cu_2O and Cu_2Swill give :

Answer»

`CU + SO_2`
`Cu+ SO_3`
`CUO + CUS`
`Cu_2 SO_3`

ANSWER :A
45.

HF is a weak acid but HCl is a strong acid because:

Answer»

HF is less IONIC than HCl
HF ATTACKS GLASS but HCl does not
Bond ENERGY of HF is higher than HCl
Electron affinity of fluorine is lower than chlorine

Answer :C
46.

Heating mixture of Cu_(2) O and Cu_(2) S will give

Answer»

`CU+ SO_(2)`
`Cu + SO_(3)`
`CUO + CUS`
`Cu_(2) SO_(3)`

ANSWER :A
47.

Heating mixtureofCu_2 OandCu_ 2 Swill give

Answer»

` CU + SO_2`
` Cu +SO_3`
`CUO + CUS `
` Cu_2SO_ 3 `

SOLUTION : `2Cu_2O+Cu_2Sto6 Cu+SO_2`.
48.

Heating Cu_2O and Cu_2S will give :

Answer»

`CU + SO_4`
`Cu + SO_3`
`CUO + CUS`
`Cu_2SO_3`

ANSWER :A
49.

Heating an ore in a regular supply of air in a furnace at a temperature below the melting point is called

Answer»

calcination
roasting
sublimation
smelting

Answer :B
50.

Heating a mixture of ethyl alcohol and acetic acid in presence of conc. H_(2)SO_(4) produces a fruity smelling compound. This reaction is called

Answer»

Neutralisation
Ester hydrolysis
Eterification
Williamson's synthesis

Solution :`C_(2)H_(5)OH+CH_(3)COOH underset(H_(2)SO_(4))overset(conc)toCH_(3)COOC_(2)H_(5)`
It is called esterification reaction.