Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Higher the value of ..................., safer is the drug

Answer»

SOLUTION :THERAPEUTIC INDEX
Discussion
2.

Higher the concentration of reactions greater is thepossibility of ...........and hence the ........

Answer»

SOLUTION :COLLISION , RATE
Discussion
3.

Higher the standard reduction potential lesser is corrosion. Give reason.

Answer»

Solution :The greater the `E^(@)` value means greater is the TENDENCY SHOWN by the species to ACCEPTS electrons and undergo REDUCTION. So higher the `(E^(@))` values lesser is the tendency to undergo corrosion.
Discussion
4.

Higher order (gt3) reactions are rate due to

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LOW PROBABILITY of simultaneos collision of all the reacting species
Increase in entropy and activation energy as more molecules are involved
SHIFTING of equilibrium towards reactants due to elastic collisions
loss of active species on collision

Solution :Higher order `gt` 3 for reactions is rare because there is low probability of molecules to come together SIMULTANEOUSLY and COLLIDE.
Discussion
5.

Higher order (gt 3) reactions are rare due to

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LOW probability of simultaneous collision of all the REACTING species
Increase in entropy and activation energy as more molecules are involved
Shifting of equilibrium towards reactants due to elastic collisions
Loss of active species on collision

SOLUTION :HIGHER order `(gt3)` reactions are RARE due to low probability of simultaneous collision of all the reacting species.
Discussion
6.

Higher order ( gt 3 ) reactions are rare due to :

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LOW probability of simultaneous collision of all the REACTING species .
increase in ENTROPY and activation energy as more molecules are involed
shifting of equilibrium towards reactants due to elastic collisions
loss of active species on collision .

Solution :[A] Higher ORDER reactions ( order `GT` 3) are rare because there is very low probability of simultaneous collision of all the reacting species .
Discussion
7.

Higher members of carboxylic acids are water insoluble due to

Answer»

hydrophobic alkyl GROUPS.
hydrophillic alkyl groups.
INTRAMOLECULAR hydrogen BONDING
NONE of the above

Answer :A
Discussion
8.

Higher is the bond order, greater is:

Answer»

BOND DISSOCIATION energy
Covalent CHARACTER
Bond length
Paramagnetism

Answer :A
Discussion
9.

Higher homologous of ethers can be prepared from :

Answer»

ALKYL HALIDES
diaamomethane
GRIGNARD reagent
None of these

Solution :Grignard REAGENTS react with cholor-derivatives of ETHERS to from higher homolegouses
`CH_(3)OCH_(3)overset(CI_(2))underset(-HCI)rarrCH_(3)OCH_(2)CIoverset(CH_(3)MgCI)rarrCH_(3)OCH_(2)CH_(3).`
Discussion
10.

HI_((g))hArrH_(2(g))+O_(2(g)) The equlibrium constant of the above reaction is 6.4 at 300 k. If 0.25 mole each of H_(2)and I_(2) are added to the system, the equlibrium constnat will be

Answer»

`0.8`
`3.2`
`1.6`
`6.4`

Solution :The value of equlibrium CONSTANT remains unchanged even on changing the concentration of the REACTION SYSTEM.
Discussion
11.

Higher alcohols are not soluble in water because of

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HYDROPHILIC alkyl GROUP
hydrophobhic alkyl groups
hydrophilic ARYL group
hydrophobic aryl groups

Answer :B
Discussion
12.

High thermal conductivity of metals is due to transfer of heat through:

Answer»

MOLECULAR collsions
Electronic collisions
Atomic collisions
All

Answer :B
Discussion
13.

High spin complex of d^6 configuration in an octahedral field will have the CFSE equal to

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`(-12)/5 triangle_circ`
`(-14)/5 triangle_circ`
`(-41)/5 triangle_circ`
`(-2)/5 triangle_circ`

Answer :D
Discussion
14.

High quantity of heat is produced in the formation of Al_(2)O_(3). This property is used for _______.

Answer»

oxidation
roasting
calcination
thermite welding

Answer :D
Discussion
15.

High purity (> 99.95%) dihydrogen is obtained be electrolysing

Answer»

`DIL H_2SO_4` solutions
dil NAOH solutions
Aquash `Ba(OH)_2` solutions
Aquash KOH solutions

Answer :C
Discussion
16.

High purity copper metal is obtained by :

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CARBON REDUCTION
HYDROGEN reduction
ELECTROLYTIC reduction
THERMITE reduction

Answer :A
Discussion
17.

High purity and more quantity of haloalkanes are obtained by ……

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reaction of alcohol with sodium HALIDE and conc. `H_(2)SO_(4)`.
reaction of alcohol with phosphorus halide.
reaction of alcohol with HCl in presence of `ZnCl_(2)`.
reaction of alcohols with `SOCl_(2)`.

ANSWER :B
Discussion
18.

High negative value of raduction potential, indicates lanthanides are

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oxidising agent
reducing agnet
high COMPLEX FORMING tendency
high magnetic property

ANSWER :B
Discussion
19.

High of density polyethylene is

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LINEAR polymer
BRANCHED polymer
CROSS linked polymer
RUBBER

ANSWER :A
Discussion
20.

Heavy water has found application in atomic reactor as:

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COOLANT
Moderator
Both coolant and moderator
Neither coolant nor moderator

Answer :B
Discussion
21.

High density polythene is prepared

Answer»

USING Ziegler-Natta Catalyst
presulphate catalyst.
peroxide calalysl.
at 350-570 K and 1000 to 2000 atmosphere.

Answer :A
Discussion
22.

Heavy water is :

Answer»

`H_(2)O^(16)`
`H_(2)O_(3)`
`H_(2)O^(18)`
`D_(2)O`

Answer :C
Discussion
23.

High density polythene is obtained by

Answer»

polymerisation of ethene in a hydrocarbon solvent in the presence of Ziegler - Natta catalyst
polymerisation of ethene under high PRESSURE and temperature
free radical polymerisation of ethene at low temperature in presence of PEROXIDE
polymerisation of ethene in presence of CARBON tetrachloride

Answer :A
Discussion
24.

High density polymer is not

Answer»

a. Tough
B. Hard
c. INERT
d. Highly BRANCHED

Solution :High DENSITY polymer is not branched. It is made up to linear molecules which are closely PACKED.
Discussion
25.

High concentration of streptomycin is a

Answer»

HYPNOTIC tranqilizer
BACTERICIDAL antibiotic
bactteriostatic anatibiotic
antioxidant

ANSWER :B
Discussion
26.

Heavy water (D_2O) is :

Answer»

A product of oxygen and hydrogen
Ordinary WATER containing DISSOLVED salts of heavy metals
Water of mineral springs
Water PRODUCED by repeated DISTILLATION and condensation

Answer :D
Discussion
27.

High concentration of phenol is

Answer»

antiseptic
analgesic
disinetectant
presevative

Answer :C
Discussion
28.

Heavy water (D_(2)O)freezes at

Answer»

`-3.8^(@)` C
`3.9^(@)` C
`0^(@)` C
`38^(@)` C

SOLUTION :HEAVY WATER FREEZES at `3.8^(@)C`.
Discussion
29.

High boiling point and viscosity of sulphuric acid is due to …………….. .

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SOLUTION :HYDROGEN BONDING
Discussion
30.

High concentration hydrocarbon pollutants in atmospheric air causes :

Answer»

Cancer
Silicosis
Respiratory DISEASES(e.g.,ASTHMA)
REDUCED CROP yield

Answer :A
Discussion
31.

Heavyhydrogen was sseparated from liquid H_(2)byfractional evaporation by

Answer»

cavendish
urey
lavoisier
SCHEELE

ANSWER :B
Discussion
32.

High basicity of Me_2NH relative to Me_3N is attributed to:

Answer»

effect of SOLVENT
inductive effect of Me
SHAPE of `Me_2NH`
shape of `Me_3N`

Solution :Secondary amines are more basic than tertiary amines DUE to stabilisation of `2^@` amine by hydrogen bonding with solvent molecule.
Discussion
33.

Heavy hydrogen is used :

Answer»

In FILLING the balloons
In studying REACTION mechanism
In calculating HEAT of formation
As oxidant

Answer :B
Discussion
34.

HI was heated in a closed tube at 440^(@) C till equilibrium is obtained. At this temperaturee 22% of HI was dossociated. The equilbrium constant for this dissociation wil be

Answer»

`0.282`
`0.0769`
`0.0199`
`1.99`

Solution :`2HIhArrH_(2)+I_(2)`
`{:("Initial CONC.", "2 MOLES",0,0),("At EQULIBRIUM",22/100xx2,0.22,0.22):}`
`=2-0.44=1.56`
`K=([H_(2)][I_(2)])/([HI]^(2))=(0.22xx0.22)/([1.56]^(2))=0.0199.`
Discussion
35.

hich of the following compound is most acidic ?

Answer»

Phenol
Ethanol
P-nitrophenol
PICRIC ACID

Solution :In picric acid there are three ELECTRONS on `-NO_(2)` group and HENCE it is more acidic.
Discussion
36.

HI was heated in a sealed tube at 440^Oc till the equiibrium was reached. HI was found to be 22% decomposed. Calculate the equilibrium constant for dissociation.

Answer»

0.282
0.0796
0.0199
1.99

Answer :C
Discussion
37.

Heavier halide is oxidised by lighter halogen. Justify.

Answer»

Solution :The oxidation ABILITY of HALOGENS is in the order : `F_(2)gtCl_(2)gtBr_(2)gtI_(2)`.
Lighter halogen is a stroger oxidant .Heavier halide is less stable , acts as a reducing AGENT and is easily oxidised .
The reaction that is easily POSSIBLE amonghalides and halogens is ,
`2I^(-)+F_(2)to2F^(-)+I_(2)`
Discussion
38.

HI solution is titrated with NaOH conductometrically, graphical representation of the

Answer»



` (##VMC_CHE_WOR_BOK_04_C19_E03_026_O03.png" width="30%">

Solution :Refer your notes on conductance. The QUESTION is RELATED to variation of conductance using strongacids and strong bases.
Discussion
39.

Heats of combustion of CH_(4),C_(2)H_(4), C_(2)H_(6) are -890, -1411 and -1560 kJ/ "mole" respectively. Which has the lowest fuel value in kJ/g ?

Answer»

`CH_(4)`
`C_(2)H_(4)`
`C_(2)H_(6)`
all same

ANSWER :B
Discussion
40.

HI was heated in a sealed tube at 400^(@)C till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium for decomposition is :

Answer»

`0.282`
`0.0796`
`0.0199`
`1.99`

ANSWER :C
Discussion
41.

HI reacts with HNO_3 to form

Answer»

`O_2`
`N_2O`
`HIO_3`
`NO_2+I_2`

ANSWER :D
Discussion
42.

HI is an oxidising or reducing agent ?

Answer»

SOLUTION :STRONG REDUCING AGENT
Discussion
43.

Heats of combustion (DeltaH^(@)) for C(s), H_(2)(g) and CH_(4)(g)are -94, -68 and -213 kcal/mol. Respectively. The value of DeltaH^(@) for the reaction, C(s)+2H_(2)(g)rarrCH_(4)(g) is

Answer»

`- 85 KCAL`
`- 111 kcal`
`-17 kcal`
`- 170 kcal`

Solution :`C_((s))+2H_(2(g))rarrCH_(4(g))"....(i)"`
`C_((s))+O_(2(g))rarrCO_(2(g))DeltaH=-94 " kcal mol"^(-1)"....(ii)"`
`H_(2(g))+(1)/(2)O_(2(g))rarrH_(2)O_((l))DeltaH=-68 " kcal mol"^(-1)"....(iii)"`
`CH_(4)+3//2O_(2)rarrCO_(2)+2H_(2)O`
`DeltaH=-213 " kcal mol"^(-1)"....(iv)"`
Discussion
44.

HI heated in a sealed tube at 440^@Ctill the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium constant for dissociation is:

Answer»

0.282
0.0796
0.0199
1.99

Answer :C
Discussion
45.

Heating which of the following salts in a dry test tube may cause a change in their colour ?

Answer»

`ZnCO_(3)` (WHITE)
`Co(NO_(3))_(2). 6H_(2)O` (red)
`FeSO_(4).6H_(2)O` (green)
`MnSO_(4)` (faint pink)

Solution :`UNDERSET("white")(ZnCO_(3)) underset(Delta)to ZnO +CO_(2) uarr . ZnO` in yellow when hot.
`Co(NO_(3))_(2).6H_(2)O underset(Delta)to COO ("black")+2NO_(2)uarr+(1)/(2)O_(2)uarr+6H_(2)O uarr`
`2FeSO_(4).6H_(2)O underset(Delta)to Fe_(2)O_(3) ("BROWN") +SO_(3) uarr + SO_(3)uarr +6H_(2)O uarr`
`underset(("faint pink"))(3MnSO_(4)) underset(Delta)to underset(("black"))(Mn_(3)O_(4))+2SO_(2)uarr +SO_(3)uarr`
Discussion
46.

HI cannot be prepared by the action of conc. H_(2)SO_(4) on KI because

Answer»

HI is stronger ACID than `H_(2)SO_(4)`
`H_(2)SO_(4)` is an oxidising agent
`H_(2)SO_(4)` is stronger than HI
HI is a strong reducing agent

Solution :Option (c) is WRONG because `H_(2)SO_(4)` is a weaker acid than HI. All other options are correct.
Discussion
47.

Heating the acyl azide in dry toluene under reflue for 3-hours give a 90% yield for a heterocyclic product. Identify the product (A) .

Answer»




SOLUTION :(a) INTRAMOLECULAR CURTIUS REACTION.
Discussion
48.

HI can be prepared by which of the following methods?

Answer»

`I_(2)+H_(2)S`
`PI_(3)+H_(2)O`
`KI+`CONC. `H_(2)SO_(4)`
`H_(2)+I_(2)` in presence of Pt.

Answer :A::B::D
Discussion
49.

Heating t-butylpheyl ether with HI produces

Answer»

IODO BENZENE
METHYL iodide
Bezene
T-butyl iodide

Solution :`S_N1` REACTION
Discussion
50.

HI cannot be prepared by heating KI with conc. H_2SO_4 because:

Answer»

`H_2SO_4` is stronger acid than HI
HI is stronger acid than `H_2SO_4`
`H_2SO_4` is an OXIDISING agent
HI is more VOLATILE than `H_2SO_4`

Answer :C
Discussion