Explore topic-wise InterviewSolutions in Current Affairs.

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1.

{:[(H_(2)(g)+(1)/(2)O_(2)(g)=H_(2)O(g),DeltaH=-241.8kJ),(C_(2)H_(2)(g)+2(1)/(2)O_(2)(g)=2CO_(2)(g)+H_(2)O(g),DeltaH=-1300 kJ):}] Equal volumes of C_(2)H_(2) and H_(2) are combusted under identical conditions. The ratio of heats evolved in the two cases is

Answer»

`5.37//1`
`1//5.37`
`1//1`
NONE of these

Answer :A
Discussion
2.

H_2(g)+1/2O_2(g)=H_2O(l), triangleH_298k=-68.32 kcal. Heat of vaporisation of water at 1 atm and 25^@C is 10.52 kcal. The standard heat of formation(in kcal) of 1 mole of water vapour at 25^@C is:

Answer»

`-78.84`
78.84
`+57.80`
`-57.80`

ANSWER :D
Discussion
3.

H_(2)COH CH_(2)OH on heating with periodicacid gives :

Answer»

2HCHOOH
`underset(CHO)underset(|)CHO`

`2CO_(2)`

Solution :1, 2 - DIOLS, when treated with an aqueous solution of PERIODIC acid give aldehyde or ketones
`underset(CH_(2)OH)underset(|)CH_(2)OH overset(HIO_(4))to CH_(2)O+ CH_(2)O`
Note that a `1^(@)` ALCOHOL gives `CH_(2)O` since in glycol both the OH groups are primary hence give 2 MOLECULES of `CH_(2)O` as by product.
Discussion
4.

H_2COHCH_2OH on heating with periodic acid forms:

Answer»

`2CO_2`
2HCHO
2HCOOH

Answer :B
Discussion
5.

H_(2)C(COOEt)_(2)overset(1.EtO^(Theta)Na^(oplus))underset(2.Br-CH_(2)-COOEt)rarrAoverset(1.KOH,Delta)underset(2.H_(3)^(oplus)O)rarrB The end product B will be:

Answer»

`EtOOC-CH_(2)-HC(COOEt)_(2)`


ANSWER :B
Discussion
6.

H_(2)C=CH-Cloverset(HCl)toA. A is

Answer»




ANSWER :B
Discussion
7.

H_(2)C_(2)O_(4) acts as an acid as well as an oxidizing agent. The correct statement (s) about H_(2)C_(2)O_(4) is /are .

Answer»

it forms two SERIES of SALTS
equivalent weight of `H_(2)C_(2)O_(4)` as an acid
100 ml of `0.1 ` N SOLUTION of `CA(OH)_(2)` will be completelyneutralized by 50 ml of `0.2 H_(2)C_(2)O_(4)`
100 ml of `0.1` M solution of `KMnO_(4)` (acid) will be completely reduced by 50 ml of M `N_(2)C_(2)O_(4)`

Solution :N/A
Discussion
8.

H_(2)C_(2)O_(4) acts as an acid as well as an oxidizing agent. The correct statement ( s) about H_(2)C_(2) O_(4) is // are

Answer»

It forms two series of salt
EQUIVALENT weight of `H_(2)C_(2)O_(4)` as an acid for COMPLETE neutralisation and as oxidant are same
100 mL of 0.1N solution of `Ca(OH)_(2)` will be completely neutralisation and an oxidant are same
100 mL of 0.1 M solution of `KMnO_(4) ` ( acid) will be completely reduced by 50mL of 1M `H_(2)C_(2)O_(4)`

Answer :A,B,C
Discussion
9.

H_(2)C-overset(O)overset(||)(C)-OC_(2)H_(5) underset(2." Base/"CH_(3)Cl(excess),"3. "H_(3)O^(+)//Delta)overset(1." "NaOC_(2)H_(5))to Number of carbon atoms in produce are

Answer»


ANSWER :5
Discussion
10.

H_(2)B_(4)O_(7) overset("Red hot")rarrA. Identify A?

Answer»

`H_(2)BO_(3)`
`B_(2)O_(3)`
B
`HBO_(2)`

SOLUTION :`B_(2)O_(3)`
Discussion
11.

H_2 SO_4 acts as dehydrating agent in its reaction with

Answer»

`H_(2)C_(2)O_(4)`
`Ba(OH)_(2)`
KOH
ZN

ANSWER :A
Discussion
12.

H_(2)+SO_(2)

Answer»

SOLUTION :`2H_(2)+SO_(2) to 2H_(2)O+3S`
Discussion
13.

H_2 S will precipitate the sulphide of all the metals from the solution of chlorides of Cu, Zn and Cd if

Answer»

The solution is aqueous
the solution is acidic
the solution is DILUTE acidic
none of the above solution is PRESENT

Solution :SULPHIDES of Cu, Zn and Cd will be precipitated as if the solution is aqueous i.e., it does not CONTAIN any acid.
Discussion
14.

H_2 S react with O_2 in restricted supply of O_2 to form

Answer»

`H_(2)O + S`
`H_(2)O + SO_(2)`
`H_(2)O + SO_(3)`
`H_(2)SO_(4) + S`

Solution :`2H_(2)S +O_(2) to 2H_(2)O +2S`
If the `O_(2)` supply is not RESTRICTED
`2H_(2)S +3O_(2) to 2H_(2)O +2SO_(2)`
Discussion
15.

H_2 S is not a/an

Answer»

Reducing agent
Acidic
Oxidising agent
None of these

Solution :`H_(2)S` is not an oxidizing agent.
`PbO +H_(2)S to PBS +H_(2)O`
It ACTS as a reducing agent.
Also in chalcogens the acidic nature of HYDRIDE INCREASES from `H_(2)O` to `H_(2)Te`.
Discussion
16.

H_2 S in the presence of HCl precipitate II group but not IV group because

Answer»

HCl activates `H_2 S`
HCl increases CONCENTRATION of CI
HCI decreases concentration of `S^2`
HCI lowers the SOLUBILITY of `H_2 S` in solution.

Solution :Due to COMMON ion effect , HCl decreases concentration of `S^(2-)` ions and only II group basic radicals are precipitated.
Discussion
17.

H_2 S in the presence of HCl precipitate group II but not group IV because

Answer»

HCl ACTIVATES `H_(2)S`
HCl incraeses the concentration of `Cl^(-)`
HCl decreases the concentration of `S^(2-)` ions
HCl LOWERS the solubility of `H_(2)S` in the solution

Solution :Due to common ion effect, HCl suppresses the IONISATION of `H_(2)S` thus decreasing the concentration of `S^(2-)` ions. Only GROUP II radicals are precipitated.
Discussion
18.

H_2 S and SO_2 can be distinguished by

Answer»

Litmus paper
Lime water
`Pb(CH_(3)COO)_(2)`
HCl

Solution :`Pb(CH_(3)COO)_(2) +H_(2)S to underset("black ppt.")(PbS)+2CH_(3)CO OH`
`SO_(2)` has no EFFECT on `Pb(CH_(3)CO O)_(2)`
Discussion
19.

H_2 PO_4^- the conjugate base of

Answer»

`PO_4^(3-)`
`P_2 O_3`
`H_3 PO_4`
`HPO_4^(2-)`

ANSWER :C
Discussion
20.

H_(2)+I_(2)hArr 2HI In the above equlibrium system if the conectration of the reactants at 25^(@)C is increased, the value of K_(c) will

Answer»

INCREASE
Decrease
Remains the same
Depends on the nature of the REACTANTS

ANSWER :C
Discussion
21.

H_(2) gas is liberated at cathode and anode both by electrolysis of the following aq. Solution except in :

Answer»

`NaH`
`HCOONa`
`NaCl`
`LiH`

SOLUTION :In aq. Solution of `NaCl, H_(2)` GAS liberates at CATHODE only.
Discussion
22.

H_(2) gas can not be prepared by :

Answer»

Be + NaOH
Na + NaOH
Mg + NaOH
By (2 & 3 ) method

Solution :Only AMPHOTERIC ELEMENT produces HYDROGEN with `NaOH`.
Discussion
23.

H_(2) gas is adsorbed on activated charcoal to a very little extent in compreison to easily liquefiable gases due to …………

Answer»

very strong van DER WALLS interaction
very weak van der Walls forces
very LOW CRITICAL temperature
very high critical temperature

Answer :B::C
Discussion
24.

H_(2) gas is adsorbed on activated charcoal to a very little extent in comparison to easily liquefiable gases due to .........

Answer»

very strong van dar WAALS' interaction. 
very weak van dar Waals' forces.
very low critical TEMPERATURE. 
veryhigh critical temperature. 

SOLUTION :`H_(2)` GAS has very low critical temperature and weak van dar waal forces. Then it gets adsorbed to a very little EXTENT.
Discussion
25.

H_2 C=C=O+ CH_2 N_2 overset(-78^@ C)toProduct. Correct statements about the reaction is

Answer»

PRODUCT
INTERMEDIATE is
`[pi_2 + pi_2]` CYCLO ADDITION reaction
All the above

Solution :
Discussion
26.

H_2 acts as an oxidant in its reaction with:

Answer»

`Br_2`
CA
`N_2`
S

Answer :B
Discussion
27.

H_(2)+(1)/(2)O_(2)rarrH_(2)O, DeltaH=-68.39 kcalK+H_(2)O+"Water"rarrKOH(aq)+(1)/(2)H_(2),DeltaH=-48 kcalKOH+"water"rarrKOH(aq),DeltaH=-14 kcal The heat of formation of KOH is (in kcal)

Answer»

`-68.39 + 48-14`
`-68.39 - 48+14`
`68.39-48+14`
`68.39+48+14`

Solution :Aim: `K_((S))+(1)/(2)O_(2(g))+(1)/(2)H_(2(g))rarrKOH_((S))`
EQ. (II) + eq. (i) - eq. (iii) GIVES
`DeltaH=-48+(-68.39)-(-14)=-68.39-48+14`.
Discussion
28.

H_2+1/2O_2rarrH2O, triangle H=-68.39 kcal (i) K+aqrarrKOH(aq)+1/2H_2, triangleH=-48 kcal (ii) KOH+aqrarrKOH(aq): triangleH=-14 kcal (iii)T he heat of formation(in kcal) of KOH is:

Answer»

`-68.39+48-14`
`-68.39-48-14`
`68.39-48+14`
68.39+48+14

Answer :B
Discussion
29.

H_(2) + (1)/(2) O_(2) rarr H_(2)O, Delta = -68.39 kcal K + H_(2)O rarr KOH + (1)/(2) H_(2), Delta H = -48 kcal KOH + Water rarr KOH (aq), Delta H = -14 kcal The heat of formation of KOH in kcal is :

Answer»

`-34.39 KCAL`
102.39 kcal
34.39 kcal
130.39 kcal

Answer :B
Discussion
30.

[H=1, C=12,O=16, Na=23, P=31,S=32] {:("Column-I","Column-II"),((A)4.1 g H_2SO_3,(p)"200 ml of 0.5 N NaOH is used forcomplete neutralization"),((B)4.9 g H_3PO_4,(q)"200 millimoles of oxygen atoms"),((C )4.5 g "oxalic acid"(H_2C_2O_4),(r)"Central atom has its highest oxidation number"),((D)4.3 g Na_2CO_3,(s)"May react with an oxidising agent"),(,(t)"Shape around central atom is regular"):}

Answer»

<P>

SOLUTION :(A)4.1 gm =`4.1/82` mole `H_2SO_3`=50 m mole
2NaOH+`H_2SO_3toNa_2SO_3+2H_2O`
m moles of NaOH requries =2 x m mole of `H_2SO_3`
=100
=m mole of NaOH present (200 ml x 0.5 N)
HIGHEST O.N. of S= +6
(B)`4.9 gm =4.9/98` mole =50 m mole of `H_3PO_4` =200 m mole 'O' atom
Highest O.N. of P = +5
(C )4.5 gm =`4.5/90` =50 m mole `H_2C_2O_4` (di basic acid)
m mole of NaOH requires =2 x 50 =100
Highest O.N. of C = +4
(D)5.3 gm =`1/20` mole `Na_2CO_3` It do not reacts with NaOH and m mole of O atom =`1/20xx1000xx3=150`
Discussion
31.

H-overset(O)overset(||)(C)-OH " and " Me-overset(O)overset(||)(C)-OHcan be differentitated by :

Answer»

IODOFORM test
LITMUS test
FEHLING
ESTERIFICATION test

Solution :N//A
Discussion
32.

H-overset(O)overset(||6)(C )-overset(5)(CH_(2))-overset(4)(CH_(2))-underset(CH_(2)CHO)underset(|)overset(3)(CH)- overset(2)(CH_(2))-overset(O)overset(1||)©-H

Answer»


ANSWER :3-(FORMYL METHYL)hexane-1,6-dial
Discussion
33.

H-overset(O)overset("||")(C)-NHR underset("Pyridine")overset(POCl_(3))(rarr) X+H_(2)O In this reaction X is

Answer»

`R-N=C=O`
`R-CH-N-OH`
`R-C equiv N`
`R-N overset(rarr)(=)C`

Solution :`underset("N-Alkyl FORMAMIDE")(R-NH-overset(O)overset("||")(C)-H) underset("PYRIDINE")overset(POCl_(3))(rarr) underset("Alkyl isocyanide")(R-N overset(rarr)(=)C+H_(2)O)`
Discussion
34.

H-overset(O)overset(||)C-H+CH_(3)-CH=Ooverset("Conc. NaOH")rarr Find out the products of reaction

Answer»

`CH_(3)CO_(2)NA & CH_(3)OH`
`CH_(3)CH_(2)OH+CH_(3)OH`
`CH_(3)CH_(2)OH & HCO_(2)Na`
`CH_(3)CO_(2)Na+HCO_(2)Na`

ANSWER :C
Discussion
35.

H-N-H bond angle in NH_(3) is ……………. .

Answer»

`109^(@)28'`
`107^(@)28'`
`104^(@)`
`107^(@)`

SOLUTION :`107^(@)`
Discussion
36.

H^(+) is a

Answer»

Lewis ACID
Lewis base
Bronsted-Lowry base
None of the above

Solution :Because it is a ELECTRON PAIR acceptor.
Discussion
37.

[H^+]in aqueous ammonium sulphate solution is :

Answer»

More than `10^(-7)`
LESS than` 10^(-7)`
` 10^(-7)`
` 10^(-4)`

ANSWER :A
Discussion
38.

H^(+) ions are reduced at platinum electrode prior to

Answer»

`AG^(+)`
`Cl`
`Zn^(2+)`
`Cu^(2+)`

Answer :C
Discussion
39.

H-H and Cl-Cl bond length are 0.74Å and 1.98Å What is the approximate bond length of HCl molecule.

Answer»

SOLUTION :`1.36Å`
Discussion
40.

H-CHO overset("1) "RM_(g)X," ether")underset("2) "H_(2)O)rarrX overset(+R'-COOH)underset(H^(+))rarr Y. What are the structures of X and Y?

Answer»

Solution :`HCHO overset("1) "RM_(g)X)underset("2) "H_(2)O)rarr underset(X)(R-CH_(2)OH)overset(+R.-COOH)underset(H^(+))rarr R^(1)-underset(Y)(COOCH_(2)R)`
Aldehydes on treatment with `R-Mg-x 1^(@)` alcohol is obtained.
`1^(@)` alcohol on treatment with an acid will from ester in presence of `H^(+)` REACTION is KNOWN as esterification reaction.
Discussion
41.

H -C equiv N and H-N equiv C are:

Answer»

Tautomers
Metamers
Functional ISOMER
GEOMETRICAL isomers

Answer :A
Discussion
42.

H-bonding is maximum in

Answer»

`C_(6)H_(5)OH`
`C_(6)H_(5)COOH`
`CH_(3)CH_(2)OH`
`CH_(3)COCH_(3)`

Solution :Due to greater resonance stabilization.
Discussion
43.

H-B-H bond angle in BH_4^- IS:

Answer»

`180^@`
`120^@`
`109^@`
`90^@`

ANSWER :C
Discussion
44.

H _2O_2 is stored in :

Answer»

IRON CONTAINER after ADDITION of stabilizer
Glass container after addition of stabilizer
Plastic container after addition of stabilizer
None of these

Answer :C
Discussion
45.

Gypsum on heating at 120-130^@C gives:

Answer»

Hemihydrate
Monohydrate
Dihydrates
Anhydrous salt

Answer :A
Discussion
46.

Gypsum is added to clinker during manugacture of cement in order to:

Answer»

Decrease the rate of SETTING of CEMENT
Make the cement impervious
Bind the particles of CALCIUM silicate
To facilitate the FORMATION of colloidal gel

Answer :A
Discussion
47.

Gypsum is

Answer»

` Ca SO _4*H _ 2 O `
`C aS O_4* 2 H _ 2 O`
`2 CaSO_ 4* 2 H _ 2 O `
`CaSO_4 `

Solution :Gypsumis` CASO _4* 2H _ 2O `.
Discussion
48.

Gypsum is:

Answer»

`MgSO_4. 7H_2O`
`CaSO_4. H_2O`
`CaSO_4.2H_2O`
`CaSO_4.3H_2O`

ANSWER :C
Discussion
49.

Gutta pracha rubber is:

Answer»

A TRANS 1,4-polyisoprene polymer
A very HARD meterial
A SYNTHETIC polymer
All of the STATEMENTS are correct

Answer :D
Discussion
50.

Guttapercha is:

Answer»

trans-Polyisoprene
Non-elastic and softense to a plastic-like materialo on HEATING.
USED in underwater cables and golf BALLS.
All the above

ANSWER :D
Discussion