Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Formation of ethylene from ethyl bromide is a case of :

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ADDITION reaction
Substitution reaction
Elimination reaction
Rearrangement reaction

Answer :C
2.

Formation of free radical in food material is protected by adding

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Dulacin
alitame
BHT
sucralose

Answer :C
3.

Formation of ester from alkyl halide and RCOOAg is,

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ELECTROPHILIC SUBSTITUTION
NUCLEOPHILIC substitution
electrophilic addition
nucleophilic addition

Answer :B
4.

Formation of distributed derivaties from mono substituted benzene results the following number of isomers

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One
Three
Two
Four

Answer :B
5.

Formation of diethyl ether from ethanol is based on a

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DEHYDRATION reaction
Dehydrogenation reaction
Hydrogenation reaction
Heterolytic FISSION reaction

Solution :Dehydration of ALCOHOL GIVES ETHERS.
6.

Formation of diethyl ether from ethanol is based on a :

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DEHYDROGENATION reaction
Hydrogenation reaction
Dehydration reaction
Heterolytic FISSION reaction

Answer :C
7.

Formation of complex compound can be detected by:

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Change in COLOUR
Change in SOLUBILITY
Change in.pH
All are CORRECT

ANSWER :C
8.

Formation of coloured solution is possible when metal ion in the compound contain

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lone pair of electrons
UNPAIRED electrons
paired electrons
none of these.

Solution :For the formation of coloured solution, metal ION in the compound should CONTAIN unpaired electrons.On absorbing visible LIGHT, unpaired electrons.On absorbing visible light, unpaired electron can jump FORM ground state to the excited state.The transmitted and reflected light appears coloured and gives colour to compound.
9.

Formation of complex compound can be detected by

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(a) CHANGE in colour
(B) Change in solubility
(c) Change in PH
(d) Change in electrical conductivity

Solution :FORMATION of complex compound can be detected by. Change in color, solubility, pH, electrical conductivity.
10.

Formation of chlorobenzene from benzene diazonium salts in presence of CuCl/HCl is called

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Wurtz-fitting REACTION.
Wurtz reaction
Sandmeyer reaction
Gatterman reaction

Solution :Formation of CHLOROBENZENE from benzne DIAZONIUM SALT is called sundmeyer.s reaction.
11.

Formation of cheese from milk is not

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denaturation
breaking of HYDROGEN bond
breaking of IONIC bond
breaking of PEPTIDE bond

Answer :D
12.

Formation of but-2-ene as major product by dehydration of butan-2-ol is according to ___________.

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MARKOWNIKOFF's rule
SAYTZEFF rule
Steric EFFECT
Anti-Markownikoff's rule

Answer :B
13.

Formation of bromobenzene from benzenediazonium chloride on treatment with CuBr/HBr is called _____reaction.

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SOLUTION :SANDMEYER REACTION.
14.

Formation of amylene oxide ring in glucose is an indication that ring in glucose is at:

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`C_1` and `C_5`
`C_2` and `C_5`
`C_3` and` C_6`
`C_2` and`C_4`

ANSWER :A
15.

Formation of alkene by removal of water molecule from alcohol is called ...... of alcohol.

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Hydration
DEHYDRATION
Oxidation
Reduction

Solution :Dehydration
16.

Formation of alkane by the action of Zn on alkyl halide is called:

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WURTZ REACTION
Kolbe.s reaction
CANNIZZARO. s reaction
Frankland.s reaction

Answer :D
17.

Formation of alkane by the action of Zn on alkyl halide is called-

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Frankland reation
Cannizzaro's reaction
Wurtz reaction
Kolbe's reaction

Answer :A
18.

Formation of acetaldehyde from ethanol is known as

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OXIDATION
SUBSTITUTION
ADDITION
REDUCTION

ANSWER :A
19.

Formation of alkane by the action of zinc on alkyl halide is called :

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Frankland REACTION
KOLBE's reaction
WURTZ reaction
CANNIZZARO's reaction

ANSWER :A
20.

Formation of a solution from two components can be considered as (1). pure solventtoseparated solvennt molecules, DeltaH_(1) (2). Pure solute toseparated solute molecules, DeltaH_(2) (3). Separated solvent and solute moleculestosolution, DeltaH_(3) Solution so formed will be ideal if

Answer»

`DeltaH_("SOLN")=DeltaH_(1)-DeltaH_(2)-DeltaH_(3)`
`DeltaH_("soln")=DeltaH_(3)-DeltaH_(1)-DeltaH_(2)`
`DeltaH_("soln")=DeltaH_(1)+DeltaH_(2)+DeltaH_(3)`
`DeltaH_("soln")=DeltaH_(1)+DeltaH_(2)+DeltaH-DeltaH_(3)`

SOLUTION :For IDEAL solution,
`DeltaH_("solution")=DeltaH_(1)+DeltaH_(2)+DeltaH_(3)`
21.

Formation of a solution from two components can be considered as (i) pure solvent rarr separated solvent molecules, DeltaH_(1) (ii) pure solute rarr separated solute molecules, DeltaH_(2) (iii) separated solvent and solute molecules rarr solution, DeltaH_(3). Solutionso formed will be ideal if

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`DeltaH_("soln")=DeltaH_(1)+DeltaH_(2)+DeltaH_(3)`
`DeltaH_("soln")=DeltaH_(1)+DeltaH_(2)-DeltaH_(3)`
`DeltaH_("soln")=DeltaH_(1)-DeltaH_(2)-DeltaH_(3)`
`DeltaH_("soln")=DeltaH_(3)-DeltaH_(1)-DeltaH_(2)`

Solution :If NET `DeltaH_("soln")` is the SUM of three steps, this means that solute-solvent interactions are SIMILAR to solvent-solvent and solute-solute interactions.
22.

Formation of acetaldehyde from ethanol is called:

Answer»

Addition
Reducation
Oxidation
Substitution

Answer :C
23.

Formation of a solution from two componenets can be considered as : (i) pure sovent rarr separated solvent molecules, /_\H_(1) (ii) Pure solute rarrseparated molecules,/_\H_(2)(iii) separated sovent andsolute moleculesrarrsolution, /_\H_(3) solution so formed will be ideal if :

Answer»

`DeltaH_("SOLN") = DeltaH_(3)- DeltaH_(1)-DeltaH_(2)`
`DeltaH_("soln") = DeltaH_(1) +DeltaH_(2)+DeltaH_(3)`
`DeltaH_("soln") = DeltaH_(1) +DeltaH_(2)-DeltaH_(3)`
`DeltaH_("soln") = DeltaH_(1)-DeltaH_(2)-DeltaH_(3)`

Solution :According to HESS' law
`DeltaH_("soln") = DeltaH_(1) +DeltaH_(2) + DeltaH_(3)`.
24.

Formation of a bridge bond is best explained by molecular orbital theory. According to which a bridge bond is formed by filling electrons into molecular orbital which spread over three nuclei hence such bonds are speciified as three centered bond. Q. In which of the following compound hybridization of bridging atom is differennt from hybridisation of central atom:

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`Al_(2)(NH_(2))_(6)`
`I_(2)Cl_(6)`
Solid `BeCl_(2)`
`Al_(2)(OH)_(6)`

ANSWER :B
25.

Formation of a bridge bond is best explained by molecular orbital theory. According to which a bridge bond is formed by filling electrons into molecular orbital which spread over three nuclei hence such bonds are speciified as three centered bond. Q. Which of the following compound is having number of atoms in same plane?

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`Al_(2)Me_(6)`
`B_(2)H_(6)`
`Be_(2)H_(4)`
`C_(3)H_(4)`

ANSWER :A
26.

Formation of a bridge bond is best explained by molecular orbital theory. According to which a bridge bond is formed by filling electrons into molecular orbital which spread over three nuclei hence such bonds are speciified as three centered bond. Q. In which of the following dimer emtpy atomic orbit of central atom of monomer does not involve in hybridization:

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`Ga_(2)H_(6)`<BR>`Al_(2)Br_(6)`
`Be_(2)H_(4)`
`Cl_(2)O_(6)`

ANSWER :D
27.

Formation of 1^@ and secondary structure of proteins involves inkages

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PEPTIDE LINKAGE, H-BOND
H-Bond, DISULPHIDE bond
Disulphide bond, peptide linkage
H-bond, H-bond

Answer :A
28.

Formation ether from ethanol based on

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dehydration
hydrogenation
dehydrogenation
hydration

Answer :A
29.

Formality unit is used in which scientific field ?

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PHARMACY
MEDICAL
AGRICULTURE
(A) and (B) both

ANSWER :D
30.

Formationfo alkane by actionofZinc and alkyl haide called :

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WURTZ REACTION
Frankland reaction
KOLBE's reaction
CLEMMENSEN reaction

Answer :B
31.

The formation of cyanohydrin from a ketone is an example of

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eelectrophilic addition
nucleophilic addition
ELECTROPHILIC substitutio
nucleophilic substitution

ANSWER :B
32.

Formalin is a 40% aqueous solution of :Methanol,Ethanol,Methanal,Ethanal.

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Methanol
Ethanol
Methanal
Ethanal

Answer :C
33.

Formalin is an aqueous solution of :

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FORMIC ACID
Formaldehyde
Fluorescein
Furfuraldehyde

Answer :B
34.

Formalin is a

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`100%` SOLUTION of HCHO
`40%` solution of HCHO
`60%` solution of HCHO
`40%` solution of `CH_(3)COOH`

ANSWER :B
35.

Formalin is 40% aqueous solutions of

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METHANAL
Methanoic ACID
METHANOL
METHANAMINE

ANSWER :A
36.

Formalin is:

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Formaldehyde
Formaldehyde + METHANOL
Formaldehyde + methanol + water
Formaldehyde + water

Answer :C
37.

Formalin is

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`HCHO`
`CH_(3)CHO`
`HCOOH`
`CH_(3)COOH`

Solution :FORMALIN is a solution of FORMALDEHYDE.
38.

Formalin is 40% aqueous solution of

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Methanal
Methanoic acid
Methanol
Methanamine

Answer :A
39.

Formalin is 40% aqueous solution of :

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METHANAL
Methanoic acid
Methanol
Methanamine

SOLUTION :(IX) (a) Methanal
40.

Formaldehyde when treated with KOH gives methanol and potassium formate. The reaction is known as :

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PERKIN's REACTION
Claisen reaction
CANNIZZARO's reaction
Knoevenagel reaction

ANSWER :C
41.

formaldehyde when treated with conc.KOH gives

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`CH_3CHO`
`C_2H_4`
`CH_3OH`,HCOOK
`CH_3OH`, `CH_3CHO`

ANSWER :C
42.

Formaldehyde undergoes Cannizzaro's reaction while acetaldehyde gives aldol condensation. Explain.

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Solution :Formaldehyde has no `ALPHA`-HYDROGEN ATOM while acetaldehyde has.
43.

Formaldehyde to ethanol

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SOLUTION :FORMALDEHYDE to ETHANOL :
44.

Formaldehyde reacts with NH_3 to give

Answer»

hexamethylenetetramine
formaldehyde ammonia
formalin
hydrobenzamide

Answer :A
45.

Formaldehyde reacts with NH_(3) to form urotropine which has the composition

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`(CH_(2))_(5)N_(5)`
`(CH_(2))_(5)N_(5)`
`(CH_(2))_(4)N_(6)`
`(CH_(2))_(6)N_(4)`

Answer :D
46.

What happens when formaldehyde reacts with ammonia?

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SOLUTION :UROTROPINE
47.

Formaldehyde reacts with NaOH (50%). Which one pair of products will be obtained?

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`CH_(3)COOH+CH_(3)OH`
`CH_(3)OH+CH_(3)COONA`
`CH_(3)COOH+C_(2)H_(5)OH`
`HCOONa+CH_(3)OH`

Solution :`2HCHO+NaOH to HCOONa+CH_(3)OH`
48.

Formaldehyde reacts with ammonia to give

Answer»

AMINO methane
Methyl amine
Hexamethylene tetramine
Formaldehyde ammonia

Answer :C
49.

Formaldehyde reacts with ammonia to form .................. which is used to treat urinary infection.

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SOLUTION : UROTROPINE (or) HEXAMETHYLENE tetramine
50.

Formaldehyde polymerizes to form glucose according to the reaction 6HCHOiffC_(6)H_(12)O_(6) The theoretically computed equilibrium constant for this reaction is found to be 6xx10^(22). If 1 M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be

Answer»

`1.6XX10^(-2)M`
`1.6xx10^(-4)M`
`1.6xx10^(-6)M`
`1.6xx10^(-8)M`

Solution :A very high vallue of K for the given equilibrium shows that dissociation of GLUCOSE to FORM HCHO is very very small. Hence at equilibrium, we can take `[C_(6)H_(12)O_(6)]=1M`
`K=([C_(6)H_(12)O_(6)])/([HCHO]^(6))i.e.,6xx10^(22)=(1)/([HCHO]^(6))`
or `[HCHO]=((1)/(6xx10^(22)))^(1//6)=1.6xx10^(-4)M`