94420 + Interview Questions in Chemistry in Class 12

1.	For a diatomic molecule AB, the electronegativity difference between A and B=0.2028 sqrt triangle where triangle=[Bond energy of AB- Geometric mean of the bond energies of A_2 and B_2]. The electonegativities of fluorine and chlorine are 4.0 and 3.0 respectively and the bond energies are of F-F : 38 kcal mol^-1 and Cl-Cl : 58 kcal mol^-1. The bond energy of Cl-F is:
Answer» 71 kcal/mol 61 kcal/mol 48 kcal/mol 75 kcal/mol Answer :A

Discussion

2.	For a decomposition reaction the value of rate constant k at two different temperature are given below : k_1 = 2.15xx10^(-8)" L mol"^(-1)s^(-1)" at "650K""k_2=2.39xx10^(-7)"l mol"^(-1)s^(-1)"at "700K Calculate the value of activation energy for this reaction . (R=8.314"JK "^(-1)mol^(-1))
Answer» SOLUTION :Here `k_1=2.15xx10^(-8)"L mol"^(-1)s^(-1)""k_2=2.39xx10^(-7)"L mol"^(-1)s^(-1)` `T_1=650K, T_2=700 K and ""R=8.314"JK "^(-1)"mol"^(-1)` Using the formula `log k_2/k_1 = (E_a)/(2.303R)[(T_2-T_1)/(T_1T_2)]` `log (2.39xx10^(-7))/(2.15xx10^(-8))=E_a/(2.303xx8.314)[(700-650)/(650xx700)]` log `1.111xx10 = E_a/(19.147)xx50/(455000)` `1.0457=E_a/(19.147)XX1/(9100)` `E_a = 182202.812J " or " 182.203kJ`

Discussion

3.	For a d-electron, the orbital angular momentum is
Answer» `sqrt6 ħ` `SQRT2 ħ` `ħ` `2ħ` Solution :`L= sqrt(l(l+1)) ħ, l=0, 1, 2 ,…., ħ= (H)/(2pi), ħ` is called DIRAC h

Discussion

4.	For a 'd' electron, the orbital angular momentum is:
Answer» `SQRT((6)H` `sqrt((2)h` h 2h Answer :A

Discussion

5.	For a d-electron the orbital angular momentum is
Answer» h `sqrt6h/(2pi)` `sqrt2h` `sqrt6h` SOLUTION :For a d-clcctron, l = 2 ORBITAL ANGULAR MOMENTUM = `sqrt(l(l+1))h/(2pi)` `=sqrt(2(2+1))h/(2pi)=sqrt6h/(2pi)=sqrt6h`

Discussion

6.	For a cyclic process, which of the following is not true?
Answer» `DeltaH=0` `DeltaE=0` `DeltaG=0` Total `W=0` Solution :For a CYCLIC process `DeltaE=0, DeltaH=0` and `DeltaG=0`. As all depend UPON final state and INITIAL state, W doesn.t depend on path FOLLOWED.

Discussion

7.	For a cyclic process
Answer» W = 0 `DELTAE = 0` `DELTAH NE 0` `DeltaE ne 0` Solution :For a cyclic PROCESS dE=0 and dH=0.

Discussion

8.	For a crystal, the angle of diffraction (20) is 90^@ and the second order line has a d value of 2.28 A^@. The wavelength (in A^@) of X-rays used for Bragg's diffraction is
Answer» `1.61Å` `1.14Å` `2.28Å` `2.0Å` ANSWER :A

Discussion

9.	For a cubic lattice edge length of unit cell is 5A^(0) and density is 2gcc^(-1). Calculate the radius of an atom, if gram atomic weight is 75 g mol^(-1).
Answer» SOLUTION :`2.17 A^(@)`

Discussion

10.	For a crystal system a=b=c and alpha=beta=gammane90^(@)
Answer» Tetragonal HEXAGONAL Rhombohedral Monoclinic Solution :Crystal system AXIAL DISTANCES Axial ANGLES Tetragonal `a=bnec alpha=beta=gamma=90^(@)` Hexagonal `a=bnec alphanebeta=90^(@),gamma=120^(@)` Rhombohedral `a=b=c alpha=beta=gammane90^(@)` Monoclinic `anebnec alpha=gamma=90,betane90^(@)`

Discussion

11.	For a crystal of sodium chloride, state : The structural arrangement of the sodium chloride crystal.
Answer» SOLUTION :`Cl^(-)` ION have fcc arrangement and `NA^+`IONS occupy all the ocetahedral sites. Each `Na^+` ion is surrounded by 6 `Cl^(-)` ions and each `Cl^(-)` ion is surrounded by 6 `Na^+` ions.

Discussion

12.	For a crystal of sodium chloride, state : The number of sodium ions and chloride ions present in unit cell of sodium chloride.
Answer» SOLUTION :`4 NA^+ , 4 CL^(-)`

Discussion

13.	How many sodium ions and chloride ions are present in a unit cell of sodium chloride ?
Answer» SOLUTION :`4 NA^+ , 4 CL^(-)`

Discussion

14.	For a crystal of diamond, state : The type of lattice in which it crystallizes.
Answer» Solution :GIANT network TYPE with fcc ARRANGEMENT of C atoms

Discussion

15.	For a crystal of diamond, state : The number of carbon atoms present per unit cell.
Answer» Solution :Number of particles PER UNIT CELL is 4.

Discussion

16.	For a crystal of diamond, state : The hybridization of the carbon atom.
Answer» SOLUTION :`sp^3` HYBRIDIZATION

Discussion

17.	For a covalent solid, the units which occupy lattice points are
Answer» Atoms Ions Molecules or atoms Electrons Answer :A

Discussion

18.	For a compound to be purified by steam distillation :
Answer» IMPURITIES must be non-volatile The LIQUID must be completely immis-cible with WATER The vapour pressure of the liquid must be sufficiently high All are correct Answer :D

Discussion

19.	For a compound solution of a weak electrolyte A_(x)B_(y) of concentration 'C', the degree of dissociation alpha is given as
Answer» `alpha = sqrt(K_(eq)//C(x+y))` `alpha = sqrt(K_(eq)C//(xy))` `alpha = (K_(eq)//C^(x+y-1)X^(x)Y^(y))^((1//(x+y)` `alpha = (K_(eq)//Cxy)` Solution :`{:(A_(x)B_(y),HARR,xA^(y+),+,yB^(x-),),(C,,0,,0,"(Initially)"),(C(1-alpha),,Cxalpha,,CY alpha,"(At equilibrium)"):}` Where `alpha` = DEGREE of dissociation. `:. K_(eq) = (((Cx alpha)^(x)(Cy alpha)^(y))/(C(1-alpha)))` For concentrated solution of WEAK electrolyte, `alpha` is very small. Therefore, `(1-alpha) ~~ 1`. `:. alpha = ((K_(eq))/(C^(x+y-1).X^(x).y^(y)))^((1)/(x+y))`.

Discussion

20.	For a complex reaction……
Answer» order of overall reaction is same as molecularity of the slowest STEP. Order of overall reaction is LESS than the molecularity of the slowest step order of overall reaction is GREATER than molecularity of the slowest step. molecularity of the slowest step is NEVER ZERO or non integer. Solution :Overall order of complex reaction =molecularity of slow step because rate of reaction =rate of slowest step so order of reaction=molecularity of slow step. (D)The product is form when reactant is there.So molecularity of reaction can.t be zero or fractional

Discussion

21.	For a complex reaction
Answer» ORDER of overall reaction is same as MOLECULARITY of the SLOWEST step order of overall reaction is same as molecularity of the slowest step order of overall reaction is less than the molecularity of the slowest step molecularity of the slowest step is never ZERO or non-integer. Answer :A::D

Discussion

22.	For a complex reaction ………………. .
Answer» ORDER of overall REACTION is same as molecularity of the slowest step order of overall reaction is LESS than the molecularity of the slowest step order of overall reaction is GREATER than molecularity of the slowest step molecularity of the slowest step is NEVER zero or non integer. Answer :A::D

Discussion

23.	For a complex reaction :
Answer» ORDER of overall reactionis same as molcularity of the slowest step (PROVIDED slowest step is having no reaction intermediate) order of overall reaction is LESS than the molecularity of the slowest step. order of overall reaction is GREATER than molecularity of the slowest step. molecularity of the slowest step is never zero or non interger. Answer :A::D

Discussion

24.	For a complex reaction _________
Answer» Order of OVERALL REACTION is same as molecularity of the slowest STEP. Order of overall reaction is less than the molecularity of the slowest step. Order of overall reaction is greater than molecularity of the slowest step. None of these above. ANSWER :A

Discussion

25.	For a chemical reaction Y_2 + 2Z toProduct,rate conctrolling step is Y + 1/2 Z to Q If the concentration of Z is doubled, the rate of reaction will
Answer» remain the same become four times become `sqrt2` times become double. Solution :`"Rate"_1=k[Y][Z]^(1/2) and "Rate"_2 =k[Y][2Z]^(1/2)` `:.("Rate"_2)/("Rate"_1)=(k[A][2Z]^(1//2))/(k[Y][Z]^(1//2))=(2)^(1//2)=sqrt2`

Discussion

26.	For a chemical reaction……can never be a fraction
Answer» Order Half-life Molecularity Rate constant increases EXPONENTIALLY with DECREASING activation ENERGY and INCREASING temperature. Answer :C

Discussion

27.	For a chemical reaction Y_(2)+2Zto Product rate controlling step is Y+1//2ZtoQ. If the concenntration of Z is doubled the rate of reactin will
Answer» REMAIN the same Become FOUR times Become `1.414` times Become double Answer :C

Discussion

28.	For a chemical reaction variation in rate with conc. Is shown below : (i) What is the order of the reaction ? (ii) What are the units of rate constant k for the reaction ?
Answer» Solution :(i) ACCORDING to graph there is no CHANGE in concentration with rate so this is zero order reaction. (II) Unit of (zero order reaction) rate CONSTANT is mol `L^(-1) s^(-1)`.

Discussion

29.	For a chemical reaction, variation in concentration , in [R] vs time (min) plot is shown: i) What is the order of the reaction? ii) What are units of rate constant, k for reaction?
Answer» SOLUTION :i) The REACTION is of first order. ii) Units of rate constant(k) `=min^(-1)` III) `t_(1//2)` remains constant since it is independent of `[R]_(0)` i.e., initial CONCENTRATION of reactants. iv) For the plot (or graph).

Discussion

30.	For a chemical reaction, variation in concentration [A] vs time (s) plot in given below: i) Predict the order of the reaction. ii) What does the slope of the line and intercept indicate ? iii) What is the unit of rate constant(k)?
Answer» SOLUTION :i) The reaction is of zero ORDER. ii) The SLOPE of the line indicates rate constant (k) and INTERCEPT represents `[R]_(0)` iii) Units of k = `molL^(-1)s^(-1)`

Discussion

31.	For a chemical reaction to take place, what should be the value of DeltaG ?
Answer» SOLUTION :NEGATIVE

Discussion

32.	For a chemical reaction, Delta C_(p) is negative (Delta C_(p) lt 0). The heat required to increase temperature of reactans of this reaction by a certain amount =q_(1) and heat required to increase temperature of products of the same reaction by same amount =q_(2), Relate q_(1) and q_(2)
Answer» SOLUTION :N//A

Discussion

33.	For a chemical reaction, DeltaG will always be negative if
Answer» `DeltaH` and `TDELTAS` both are positive `DeltaH` and `TDeltaS` both are negative `DeltaH` is negative and `TDeltaS` is positive `DeltaH` is positive and `TDeltaS` is negative Solution :Gibbs-Helmholtz EQUATION is as FOLLOWS : `DeltaG=DeltaH-TDeltaS` From Gibbs-Helmholtzequation, it is clear that `DeltaG` will ALWAYS be negative, if `DeltaH` is negative and `TDeltaS` is positive.

Discussion

34.	For a chemical reaction, mA to xB, the rate law is r=k[A]^2. If the concentration of A is doubled, the reaction rate will be
Answer» doubled quandrupled increased by 8 times UNCHARGED Solution : `:r=K[A]^(2)` When CONCENTRATION of A is doubled , `r=K[2A]^(2)` `r=4k[A]^(2)`

Discussion

35.	For a chemical reaction Ato products, the following equation is found to be followed, logK=16.398-2800/T At 27^(@)C the rate contant of the reaction is ______
Answer» `1.16xx10^(5)` `1.16xx10^(6)` `1.321xx10^(7)` `1.16xx10^(7)` SOLUTION :`logK=16.398-2000/300=(16.398-9.333)=7.06467,K=10^(7)xx1.16`

Discussion

36.	For a chemical reaction Ato Products, the rate of disappearance of A is given by: (dC_(A))/(dt)=(K_(1)C_(A))/(1+K_(2)C_(A)) at low C_(A), the reaction is of the _________order with rate constant_________(Assume K_(1), K_(2) are lesser than 1)
Answer» `I,K_(1)//K_(2)` `I,K_(1)` `II,K_(1)//K_(2)` `II,K_(1)//K_(1)+K_(2)` Solution :1st ORDER `Kt,x/(C_(0))=(1-E^(-Kt)),C_(t)=C_(0).e^(-Kt)`

Discussion

37.	For a chemical reaction Ato products, the following equation is found to be followed, logK=16.398-2800/T Activation energy of the reaction is _____________K.Cal
Answer» 128.13 12.767 12813 1.2813 Solution :`(EA)/(2.303RT)=2800/TimpliesEa=2800xx2.303xx1.98=12.76` KCAL

Discussion

38.	For a chemical reaction Ato products, the following equation is found to be followed, logK=16.398-2800/T Arrhenius factor for the reaction is ______
Answer» `2.5xx10^(16)` `5xx10^(16)` `7.5xx10^(-16)` `4XX10^(-16)` SOLUTION :`logK=logA-(EA)/(2.303RT),A=` antilot (16)`xx` ANTILOG `(0.398)=10^(15)xx2.5`

Discussion

39.	For a chemical reaction at 27^(@)C, the activation energy is 600 R. The ratio of the rate constants at 327^(@)C to that of at 27^(@)C will be
Answer» 2 40 E `e^2` Solution :In`(k_2)/(k_1)=(E_a)/(R) ((1)/(T_1)-(1)/(T_2))` or, In`(k_2)/(k_1)=(600R)/(R) ((1)/(300)-(1)/(600))` or, In `(k_2)/(k_1)=(600R)/(R)((2-1)/(600))=1` or, In`(k_2)/(k_1)`=In e(`therefore` In e=1) `(k_2)/(k_1)=e`

Discussion

40.	For a chemical reaction at constant P, Delta H is equal to
Answer» zero `Delta U` `q//T` `Delta U + p Delta V` ANSWER :D

Discussion

41.	For a chemical reaction at constant P and V. Delta H is equal to
Answer» `DELTA U` ZERO `Delta U + P Delta V` `p//T`. Answer :A

Discussion

42.	For a chemical reaction at 27^(@)C , the activation energy is 600 R . The ratio of the rate constants at 327^(@)C to that of at 27^(@)C will be
Answer» 2 40 E `e^(2)` Solution :LN `(K_(2))/(K_(1)) = (E_(a))/(R) ((1)/(T_(1)) - (1)/(T_(2)))` or , ln `(K_(2))/(K_(1)) = (600R)/(R) ((1)/(300) - (1)/(600))` or , ln `(K_(2))/(K_(1)) = (600R)/(R) ((2-1)/(600)) = 1 ` ln `(K_(2))/(K_(1))` = ln e `"" (K_(2))/(K_(1)) = e`

Discussion

43.	For a chemical reaction ArarrB, it is found that the rate of reaction doubles when the conc, of 'A' is increased four times. The order of reaction is
Answer» 0 0.5 1 2 Answer :B

Discussion

44.	For a chemical reaction aAtoB,log[-(d[A])/(dt)]=log[(d[B])/(dt)]+0.3 then find the approximate ratio and of a and b
Answer» Solution :`aAtobB-(d[A])/(dt)=(_d[B])/(dt)xx(a/b)` `LOG((dA)/(dt))=log((DB)/(dt))+log(a/b)` So `log (a/b)=0.3=log2,a/b=2`

Discussion

45.	For a chemical reaction A_2 +2 B toProducts, the rate con trolling step is A=1/2B to C.If the cone. of B is tripled, the rate of reaction will
Answer» remain the same BECOME four times become 1.732 times become DOUBLE Solution :The SLOW step of the reaction is : `A + 1/2B to C, " rate LOW is,"(dx)/(dt)=k[A][B]^(1//2)` On TRIPLING the concentration of B, the rate will become `(3)^(1//2)= 1.732` times of the original rate.

Discussion

46.	For a chemical reaction A to B , the rate of the reaction is 2 xx 10^(-3) mol dm^(-3) s^(-1) . When the initial concentration is 0.05 mol dm^(-3) . The rate of the same reaction is 1.6 xx 10^(-2) mol dm^(-3) s^(-1) when the initial concentration is 0.1 mol dm^(-3) . The order of the reaction is
Answer» 0 3 1 2 Solution :Let the rate EQUATION for the REACTION be , rate = `k [A]^(n)` where , k = rate constant , n = order of reaction [A] = concentration of reactant given , `"rate"_(1) = 2 xx 10^(-3) "mol" dm^(-3) s^(-1)` `[A_(0)] = 0.05 ` mol `dm^(-3)` `"rate"_(2) = 1 . 6 xx 10^(-2)` mol `dm^(-3) s^(-1)` `(A_(0)) = 0.1` mol `dm^(-3)` `therefore 2 xx 10^(-3) = k [0.05]^(n) "".... (i)` `1.6 xx 10^(-2) = k[0.1]^(n) "".... (ii)` DIVIDE (i) by (ii) `implies (2 xx 10^-3)/(1.6 xx 10^(-2)) = ([0.05]^(n))/([0.1]^(n)) = ([0.05]^(n))/(2^(n)[0.05]^(n))` `implies (1)/(2^(n)) = (1)/(8) implies n = 3, "" therefore` Order of reaction = 3 .

Discussion

47.	For a chemical reaction, A to products, the rate of reaction doubles when the concentration of 'A' is increased by a factor of 4, the order of reaction is-
Answer» 2 0.5 4 1 Answer :B

Discussion

48.	For a chemical reaction A to B, it was found that concentration of B increases by 0.20 mol L^(-1) in half an hour. What is the average rate of the reaction?
Answer» SOLUTION :For the REACTION `A to B` `Delta[B]=0.20 mol L^(-1), Deltat=0.5 hour.` `THEREFORE` AVERAGE rate =`(Delta[B])/(Deltat) = (0.20 mol L^(-1))/(0.5 hr)=0.40 mol L^(-1)hr^(-1)`

Discussion

49.	For a chemical reactionA to B it is found that the rate of reaction doubles , when the concentration of A is increased four times . The order in A for this reaction is
Answer» Two One HALF ZERO SOLUTION :`r = k[A]^(m)` also 2r = `k[4A]^(m) , (1)/(2) = ((1)/(4))^(m)` `therefore m = (1)/(2).`

Discussion

50.	For a chemical reactio , variation in the concentration [R] Vs time (s) plot is given: For this chemical reaction, write/draw: i) What is the order of the reaction? ii) What are the units of the rate constant (k)? iii) Give the relationship between k and t_(1//2) (half life period) iv) What does the slope of the aboveline indicate? v) Draw the plot log [R]_(0)/[R] Vs time (s).
Answer» Solution :i) The reaction is of FIRST ORDER. II) Units of RATE constant (k) = `("time")^(-1)` or `s^(-1)` iii)Rate constant (k) = `(0.693)/(t_(1//2)` (iv) The slope of the line is equal to`-(k)` v) for the graph

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

For a decomposition reaction the value of rate constant k at two different temperature are given below : k_1 = 2.15xx10^(-8)" L mol"^(-1)s^(-1)" at "650K""k_2=2.39xx10^(-7)"l mol"^(-1)s^(-1)"at "700K Calculate the value of activation energy for this reaction . (R=8.314"JK "^(-1)mol^(-1))

For a d-electron, the orbital angular momentum is

For a 'd' electron, the orbital angular momentum is:

For a d-electron the orbital angular momentum is

For a cyclic process, which of the following is not true?

For a cyclic process

For a crystal, the angle of diffraction (20) is 90^@ and the second order line has a d value of 2.28 A^@. The wavelength (in A^@) of X-rays used for Bragg's diffraction is

For a cubic lattice edge length of unit cell is 5A^(0) and density is 2gcc^(-1). Calculate the radius of an atom, if gram atomic weight is 75 g mol^(-1).

For a crystal system a=b=c and alpha=beta=gammane90^(@)

For a crystal of sodium chloride, state : The structural arrangement of the sodium chloride crystal.

For a crystal of sodium chloride, state : The number of sodium ions and chloride ions present in unit cell of sodium chloride.

How many sodium ions and chloride ions are present in a unit cell of sodium chloride ?

For a crystal of diamond, state : The type of lattice in which it crystallizes.

For a crystal of diamond, state : The number of carbon atoms present per unit cell.

For a crystal of diamond, state : The hybridization of the carbon atom.

For a covalent solid, the units which occupy lattice points are

For a compound to be purified by steam distillation :

For a compound solution of a weak electrolyte A_(x)B_(y) of concentration 'C', the degree of dissociation alpha is given as

For a complex reaction……

For a complex reaction

For a complex reaction ………………. .

For a complex reaction :

For a complex reaction _________

For a chemical reaction Y_2 + 2Z toProduct,rate conctrolling step is Y + 1/2 Z to Q If the concentration of Z is doubled, the rate of reaction will

For a chemical reaction……can never be a fraction

For a chemical reaction Y_(2)+2Zto Product rate controlling step is Y+1//2ZtoQ. If the concenntration of Z is doubled the rate of reactin will

For a chemical reaction variation in rate with conc. Is shown below : (i) What is the order of the reaction ? (ii) What are the units of rate constant k for the reaction ?

For a chemical reaction, variation in concentration , in [R] vs time (min) plot is shown: i) What is the order of the reaction? ii) What are units of rate constant, k for reaction?

For a chemical reaction, variation in concentration [A] vs time (s) plot in given below: i) Predict the order of the reaction. ii) What does the slope of the line and intercept indicate ? iii) What is the unit of rate constant(k)?

For a chemical reaction to take place, what should be the value of DeltaG ?

For a chemical reaction, Delta C_(p) is negative (Delta C_(p) lt 0). The heat required to increase temperature of reactans of this reaction by a certain amount =q_(1) and heat required to increase temperature of products of the same reaction by same amount =q_(2), Relate q_(1) and q_(2)

For a chemical reaction, DeltaG will always be negative if

For a chemical reaction, mA to xB, the rate law is r=k[A]^2. If the concentration of A is doubled, the reaction rate will be

For a chemical reaction Ato products, the following equation is found to be followed, logK=16.398-2800/T At 27^(@)C the rate contant of the reaction is ______

For a chemical reaction Ato Products, the rate of disappearance of A is given by: (dC_(A))/(dt)=(K_(1)C_(A))/(1+K_(2)C_(A)) at low C_(A), the reaction is of the _________order with rate constant_________(Assume K_(1), K_(2) are lesser than 1)

For a chemical reaction Ato products, the following equation is found to be followed, logK=16.398-2800/T Activation energy of the reaction is _____________K.Cal

For a chemical reaction Ato products, the following equation is found to be followed, logK=16.398-2800/T Arrhenius factor for the reaction is ______

For a chemical reaction at 27^(@)C, the activation energy is 600 R. The ratio of the rate constants at 327^(@)C to that of at 27^(@)C will be

For a chemical reaction at constant P, Delta H is equal to

For a chemical reaction at constant P and V. Delta H is equal to

For a chemical reaction at 27^(@)C , the activation energy is 600 R . The ratio of the rate constants at 327^(@)C to that of at 27^(@)C will be

For a chemical reaction ArarrB, it is found that the rate of reaction doubles when the conc, of 'A' is increased four times. The order of reaction is

For a chemical reaction aAtoB,log[-(d[A])/(dt)]=log[(d[B])/(dt)]+0.3 then find the approximate ratio and of a and b

For a chemical reaction A_2 +2 B toProducts, the rate con trolling step is A=1/2B to C.If the cone. of B is tripled, the rate of reaction will

For a chemical reaction A to B , the rate of the reaction is 2 xx 10^(-3) mol dm^(-3) s^(-1) . When the initial concentration is 0.05 mol dm^(-3) . The rate of the same reaction is 1.6 xx 10^(-2) mol dm^(-3) s^(-1) when the initial concentration is 0.1 mol dm^(-3) . The order of the reaction is

For a chemical reaction, A to products, the rate of reaction doubles when the concentration of 'A' is increased by a factor of 4, the order of reaction is-

For a chemical reaction A to B, it was found that concentration of B increases by 0.20 mol L^(-1) in half an hour. What is the average rate of the reaction?

For a chemical reactionA to B it is found that the rate of reaction doubles , when the concentration of A is increased four times . The order in A for this reaction is

For a chemical reaction Ato Products, the rate of disappearance of A is given by: (dC_(A))/(dt)=(K_(1)C_(A))/(1+K_(2)C_(A)) at low C_(A), the reaction is of the _order with rate constant_(Assume K_(1), K_(2) are lesser than 1)