This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Excessive accumulation of organic matter in water bodies leads to |
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Answer» Decrease in species diversity |
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| 2. |
Excess of silver nitrate solution is added to 100 ml of 0.01 M pentaaqua chloro chromium (III) chloride solution .The mass of silver chloride obtained in grams is [Atomic mass of silver is 108] |
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Answer» `287xx10^(-3)` `[Cr(H_(2)O)_(5)Cl]^(+)NO_(3)^(-)+2AgCldarr` Thus Meq. Of `Cl^(-)` ions outside=Meq. Of AGCL FORMED `THEREFORE` NUMBER of moles of `Cl^(-)` ions present `=(2xx100xx0.01)/(1000)=0.002 `moles `therefore` Mass of AgCl=`0.002xx143.5` =0.287 g=`287xx10^(-3)g` |
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| 3. |
Excess of NH_3 combine with sodium hypochlorite solution gives - |
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Answer» `NH_(4)` |
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| 4. |
Excess of PCl_(5) reacts with conc , H_(2)SO_(4) giving |
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Answer» sulphuryl CHLORIDE `underset("Sulphurice acid")(SO_(2)(OH)_(2)+2PCl_(5))tounderset("Sulphuryl chloride")(SO_(2)Cl_(2)+2POCl_(3)+2HCl` |
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| 5. |
Excess of Na^(+) ions in human system causes |
| Answer» Solution :High Blood Pressure | |
| 6. |
Excess of isopropyl alcohol is heated with conc. H_2SO_4 at 413 K, gives |
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Answer» `(CH_3)_2CHOCH(CH_3)_2` |
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| 7. |
Excess of KI reacts with CuSO_(4) solution and then Na_(2) S_(2) O_(3) solution is added to it . Which of the statements is incorrect for this reaction ? |
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Answer» `Na_(2) S_(2) O_(3)` is oxidised |
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| 8. |
Excess of glycol when dehydrated gives : |
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Answer» ETHYLENE oxide |
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| 9. |
Excess of ethanol is heated with conc. H_2SO_4 at 413 K. the compound that distills is |
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Answer» DIETHYL sulphate |
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| 10. |
Excess of copper and iron are removed mainly by which of the following chelating ligands via formation of coordination compounds? |
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Answer» DESFERRIOXIME-B and EDTA RESPECTIVELY |
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| 11. |
Excess of copper in toxic proportions in plants/animals can be |
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Answer» EDTA |
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| 12. |
Excess of copper and iron are removed by chelating ligands like ______ |
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Answer» |
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| 13. |
Excess of conc. H_(2)SO_(4) reacts with C_(2)H_(2)OH at 413 K to form. |
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Answer» `C_(2)H_(5)HSO_(4)` `CH_(3)-CH_(2)-OH underset(-H_(2)O)overset(H_(2)SO_(4).443K)to CH_(2)=CH_(2)` Note: At 413K, ethyl ether is obtained `C_(2_)H_(5)OH +HCO_(2)H_(5) underset(-H_(2)O) overset(H_(2)SO_(4).443K)to C_(2)H_(5)OC_(2)H_(5)` |
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| 14. |
Excess of concentrated sodium hydroxide can separate mixture of |
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Answer» `Al^(3+)` and `Cr^(3+)` |
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| 15. |
CH_3MgI is made to react with acetone and the addition product formed is hydrolysed will give : |
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Answer» SEC- butanol |
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| 16. |
When CH_3MgI is made to react with acetone and the addition product formed is hydrolysed we get : |
| Answer» Answer :D | |
| 17. |
Excess of carbon dioxide is passed through 50 ml of 0.5 M calcium hydroxide solution. After the completion of the reaction, the solution was evaporated to dryness. The solid calcium carbonate was completely neutralised with 0.1 N hydrochloric acid. The volume of hydrochloric acid required is (At. mass of calcium=40) |
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Answer» `200cm^(3)` `underset(74(=1mol))(Ca(OH)_(2))+underset(44(=1mol))(CO_(2))to underset(100(=1mol))(CaCO_(3))+underset(18(=1mol))(H_(2)O)` Given, 50 ml of 0.5 M `Ca(OH)_(2)` reacts with excess of `CO_(2)` `THEREFORE` No. of millimoles of `Ca(OH)_(2)` reacts with excess of `CO_(2)` `therefore` No. of millimoles of `Ca(HO)_(2)` reacted=25 `therefore` 1 MOLE of `Ca(OH)_(2)` gives 1 mole of `CaCO_(3)`, `therefore`No. of millieq. `=("WEIGHT in mg")/("eq. Wt")=(25xx100)/(50)=50` `implies`No. of milliequivalents of `CaCO_(3)=50` As, volume of `CaCO_(3)` solution=50 ml So, normality of `CaCO_(3)` solution=1N(millieq.=`NxxV` in ml) Normality of HCl=0.1N (given) Volume of HCl=? `N_(HCl)xxV_(HCl)=N_(CaCO_(3))xxV_(CaCO_(3))` `implies0.1xxV_(HCl)=1xx50impliesV_(HCl)=(50)/(0.1)=500cm^(3)`. |
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| 18. |
Excess of CH_(3)CO OH is reacted with CH-=CH in presence of Hg^(2+), the product is |
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Answer» `CH_(3)CH(OCOCH_(3))_(2)` |
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| 19. |
Excess of carbon dioxide is passed through 50 mL of 0.5 M calcium hydroxide solution. After the completion of the reaction, the solution was evaporated to dryness. The solid calcium carbonate was completely neutralised with 0.1 N hydrochloric acid. The volume of hydrochloric acid required is (At. mass of carbon = 40) |
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Answer» 200 mL 50 mL of 0.5 `Ca(OH)_(2)` contain `Ca(OH)_(2)` `=(0.5)/(1000)xx"50 mol"=0.025"mol"` 1 mol of `Ca(OH)_(2)` PRODUCES `CaCO_(3)` = 1 mol `therefore 0.25` mole of `Ca(OH)_(2)` will produce `CaO_(3)` = 0.025 mol `CaCO_(3)+2HClrarr CaCl_(2)+H_(2)O+CO_(2)` 1 mole of `CaCO_(3)` is NEUTRALISED by HCL = 2 mol `therefore 0.025` mol of `CaCO_(3)` will be neutralised by HCl `=2xx0.025" mol" = 0.05 " mol"` `" 1000 mL of 0.1 N HCl contain HCl = 0.1 g eq"` `"= 0.1 mol"` `"or 0.1 of HCl is present in HCl sol = 1000 mL"` `therefore" 0.05 mol of HCl will be present in HCl sol."` `=(1000)/(0.1)xx0.05mL="500 mL"` |
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| 20. |
Excess of calcium orthophosphate is reacted with magnesium to from calcium phosphide (Ca_(3)P_(2)) along with magnesium oxide. Calcium phosphide on reacting with excess of water liberate phosphine gas (PH_(3)) along with calcium hydroxide. Phosphine is burnt in excess of oxygen to from P_(2)O_(5) along with water. oxides of magnesium & phosphorous react to give magnesium metaphosphate. calculate grams of magnesium metaphosphate obtained if 1.92 gm of magnesium is taken . |
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Answer» `underset(0.01)(Ca_(3)P_(2))+6H_(2)Oto underset(0.02) (2PH_(3))+3Ca(OH)_(2)` `underset(0.02)(2PH_(3))+4O_(2) to underset(0.01)(P_(2)O_(5))+3H_(2)O)` `underset(MgO)(0.08) +underset(0.01)(P_(2)O_(5))to underset("0.01 Mole" ~~ 1.82 GM ~~ 2gm)(MgP_(2)O_(6))` |
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| 21. |
Excess of carbon dioxide is passed through 50 mL of 0.5 M calcium hydroxide solution. After the completion of the reaction, the solution was evaporated to dryness. The solid calcium carbonate was completely neutralised with 0.1 N hydrochloric acid. The volume of hydrochloric acid required is |
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Answer» `200 cm^(3)` `underset((=1"mol"))underset(74)(Ca(OH)_(2))+underset((=1"mol"))underset(44)(CO_(2))tounderset((=1"mol"))underset(100)(CaCO_(3))+underset((=1"mol"))underset(18)underset(H_(2)O` GIVEN 50 ml of 0.5 M `Ca(OH)_(2)` reacts with excess of `CO_(2)` `:.` no. of millimoles of `Ca(OH)_(2)` reacted =25 `:'` 1 mile of `Ca(OH)_(2)` gives 1 mile of `CaCO_(3)`, `:.` no. of millimoles of `CaCO_(3)` formed =25 `:.` no. of millieq `=("weight in mg")/("eq. wt")=(25xx100)/50=50` `implies` no. of MILLIEQUIVALENTS of `CaCO_(3)=50` As volume of `CaCO_(3)` solution =50 ml So, normality of `CaCO_(3)` solution =1N (millieq `=NxxV` in ml) Normality of HCl `=0.1N` (given) Volume of HCl=? `N_(HCl)xxV_(HCl)=N_(CaCO_(3))xxV_(CaCO_(3))` `implies0.1xxV_(HCl)=1xx50` `impliesV_(HCl)=50/0.1=00 cm^(3)` |
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| 22. |
Excess of ammonia with sodium hypochloride solution in the presence of glue or gelatine gives. |
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Answer» `NaNH_(2)` |
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| 23. |
Excess of bromo ethane reactswithalcholicammonia to give, |
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Answer» ETHYL AMINE |
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| 24. |
Excess of ammonia with sodium hypochlorite solution in the presense of gule or gelatin gives |
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Answer» `NaBH_(2)` `2NH_(3)+NaOC l toN_(2)H_(4)+NaCl+H_(2)O` Addition of gelatin or glue suppress the side reaction by complexing with the metal ions and yield of hydrazine is increased. |
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| 25. |
Excess of AgNO_(3) solution was added to 2.2 g of commercial sample of common salt dissolved in water. The mass of dried precipitate of silver chloride was 2.11 g . Calculate the percent purity of common salt. |
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Answer» |
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| 26. |
Excess of AgCl is added to 0.1 M solution of KBr at 298 K. Calculate the equilibrium concentrations of Br^(-) and Cl^(-) ions. E_(Cl^(-)//AgCl//Ag)^(@)=0.222" volt"E_(Br^(-)//AgBr//Ag)^(@)=0.095 volt |
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Answer» APPLY `log K =E_(cell)^(@)/0.0591` or `"log"x/((0.1-x))=E_(cell)^(@)/0.0591` |
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| 27. |
Excess nitratein drinkin watercan cause |
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Answer» methemoglobinemia |
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| 28. |
Excess chlorine,when bubbled through aqueous ferrous bromide will yeild |
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Answer» `FeCl_(2)` |
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| 29. |
Excess H^+ and Cl^+ ions from a colloidal solution of Fe(OH)_3 can be removed by |
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Answer» filtration |
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| 30. |
Excess chlorine is passed through boiling toluene, how many chloro deriatives would you get? |
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Answer» |
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| 31. |
Except which alcohol, other alcohols are weaker acid than water? |
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Answer» ETHANOL |
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| 32. |
Except ……………… other alkanes gives a mixture of nitro aklkanes due to C-C cleavage by nitration of alkanes. |
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Answer» |
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| 34. |
Except helium, all the noble gases crystallize with cubic close packed structures. Derive an equation relating atomic radius to the density of cubic close packed solid of given mass and apply it to deduce the relative size of Ar and Xe if their densities are 1.4 g/cm and 2.83 g/cm^(3) respectively. |
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Answer» Solution : For a CCP solid : `(rho)=(nM)/(n_(A)a^(3))` Where, `rho`=Density,n=No. of atoms/unit cell M = Molar MASS, `N_(A)` = Avogadro constant, and a=Edge LENGTH `implies rho=(4M)/(N_(A)(2sqrt(2R))^(3))=(M)/(4sqrt(2)N_(A)R^(3))` `implies(rho_(x_(e)))/(rho_(Ar))=(2.83)/(1.40)((r_(Ar))/(r_(Xe)))^(3)` `implies(r_(Xe))/(R_(Ar))=((131xx1.4)/(40xx2.83))^(1//3)=1.174` |
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| 35. |
Except glycine all other naturally occurring amino acids are optically active. |
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Answer» |
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| 36. |
Except for vitamin B_(12) all other vitamins of group B should be regularly supplied in diet. Why? |
| Answer» Solution :All the vitamins of group B except `B_(12)` are water SOLUBLE. So they are READILY excreted in urine. Hence they NEED to be RESTORED in the body. `B_(12)` is water insoluble and is not much excreted through urine. | |
| 37. |
Except for vitamin B_12, all other vitamins of group B, shlould be supplied regularly in diet. Why ? |
| Answer» Solution :Vitamin- `B2` does not occur in plants but is exclusively synthesized by the microorganisms PRESENT in the body. THEREFORE, it may not be supplied REGULARLY in die , while all other vitamins of group B should be supplied regularly in DIET. | |
| 38. |
Which statement correctly the statement ? Except for glycine, which is achiral, all the amino acids present in proteins.... |
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Answer» Are CHIRAL , but recemic |
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| 39. |
Except ............ elements, all transition metals are hard and have very high melting point |
| Answer» SOLUTION :group-11 | |
| 41. |
Except_________ all elementfrom Rfto Cnare syntheticallyprearedand have verylowhalflifeperiods . |
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Answer» CADMIUM |
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| 42. |
Examples of thermoplastic polymer is/are : |
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Answer» UREA FORMALDEHYDE resin |
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| 43. |
Examples for natural polymers are |
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Answer» Cotton, Silk, Bakelite and WOOL |
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| 44. |
Example the function of H_(2)-O_(2) fuel cell. |
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Answer» Solution :In this case, hydrogen act as a fuel and oxygen as an oxidend and the electrolyte is aqueous KOH maintained at `200^(@)`C and 20 - 40 atm. Porous graphite electrode containinng NI and NiO serves as the inert electrodes. Hydrogen and oxygen gases are bubbled through the anode and cathade, respectively. Oxidation occurs at the anode: `2H_2(G) + 4OH_((AQ))^(-) to 4H_2O_((l)) + 4e^(-)` Reduction occurs at the cathode `O_2(g) + 2H2O(l) + 4e^(-) to 4OH^(-)(aq)` The overall reaction is `2H_(2(g)) + O_(2)(g) to 2H_2O(l)` The above reactio is the same as the hydrogen combustion reaction, however, they do not react directly ie. the oxidation and reduction reactions take place separately at the anode and cathode respectively like `H_2 - O_2` fuel CELL. Other fuel cell like propane `-O_2` and methane `O_2` have also been developed . |
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| 46. |
Example of unit cell with crystallographic dimensions a!=b!=c, alpha=beta=gamma=90^(@) is : |
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Answer» Calcite |
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| 47. |
Example showing ionisation isomerism |
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Answer» `[Co(NO_3)(NH_3)_5]SO_4` & `[Co(SO_4)(NH_3)_5]NO_3` |
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| 48. |
Example of Ring silicate is …………. |
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Answer» Olivine |
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| 49. |
Example of neutral complex compound in the following list |
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Answer» `CoCl_3. 6NH_3` |
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| 50. |
Exampleof intrinsic colloid is |
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Answer» glue |
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