Quiz about Chemistry in Class 12

Question 1

Enzyme trypsin converts

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NA

Question 2

Enzyme inhibitors may attack on

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NA

Question 3

Enzyme inhibitors may attack on a) Active site of enzyme b) Allosteric site of enzyme c) Tongue d) Stomach walls Correct answers are

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NA

Question 4

Enzyme catalysis are more effective and efficient than ordinary catalysis. Prove this statement.

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NA

Question 5

Enzyme catalyst are

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NA

Question 6

Enzyme catalysed reaction has maximum rate at optimum temperature. Prove it.

Accepted Answer

NA

Question 7

Enzyme catalysis is highly specific in nature. Justify this statement.

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NA

Question 8

Enzyme catalysed reaction are

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NA

Question 9

Enzymes are

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NA

Question 10

Enzyme are

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NA

Question 11

Enumerate the reactions of D-glucose which cannot be explained by its open chain structure.

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NA

Question 12

Enumerate the reaction and facts of D - glucosewhichcannot be explained by its open chain structure .

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NA

Question 13

Entropy is a measure of

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NA

Question 14

Entropy will not change for the reaction

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NA

Question 15

Entropy of vaporisation of water at 100^@C if molar heat of vaporisation is 9710 cal mol^-1 will be

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NA

Question 16

Entropy of ice is _____ than entropy of water vapour.

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NA

Question 17

Entropy of the universe is

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NA

Question 18

Entropy of a system may depend upon

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NA

Question 19

Entropy is measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is measure of unavailable energy. Unavailable energy = Entropy x Temperature.  The ratio of entropy of vaporization and boiling point of substance remains almost constant.  Which of the following process have DeltaS = -ve

Accepted Answer

NA

Question 20

Entropy is measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is measure of unavailable energy. Unavailable energy = Entropy x Temperature.  The ratio of entropy of vaporization and boiling point of substance remains almost constant.  Observe the graph and identify the correct statement (s)  The law of thermodynamics invented by Nernst which helps to determine absolute entropy is

Accepted Answer

NA

Question 21

Entropy is measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is measure of unavailable energy. Unavailable energy = Entropy x Temperature.  The ratio of entropy of vaporization and boiling point of substance remains almost constant.  The sign of DeltaS in the reaction.  N_(2)(g) + O_(2)(g) to 2NO (g)

Accepted Answer

NA

Question 22

Entropy is measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is measure of unavailable energy. Unavailable energy = Entropy x Temperature.  The ratio of entropy of vaporization and boiling point of substance remains almost constant.  Which of the following has DeltaS = +ve?

Accepted Answer

NA

Question 23

Entropy is a measure of disoder. For perfect crystalline substance at 0 K entropy becomes

Accepted Answer

NA

Question 24

Entropy is

Accepted Answer

NA

Question 25

Entropy has great importance in thermodynamics. It is a state function and it is a measure of the degree of disorder or randomness of the system. More is the disorder of the system greater will be the entropy and vice versa. It is normally expressed in terms of change of entropy.  (i) For a reaction entropy change is given by DeltaS=sumS(product)-sumS(reactant)  (ii) DeltaS=(Q_(rev))(T)=(W_(rev))(T)=(nRT ln (V_(2)V_(1)))(T)  =nRT ln (V_(2))(V_(1))=nR ln (P_(1))(P_(2))  (iii) DeltaS=DeltaH-TDeltaS  (iv) Entropy change in reversible and irreversible process Consider a Carnot cycle as shown in figure below in which ab and cd are isothermal.   Irrespective of the path of the system in its reversible change dqT is same  For entire Carnot cycle  (dq_(1))(T_(1))-(dq_(2))(T_(2))=0  . DeltaS_(universe)=DeltsS_(system)+DeltaS_(surrounding)  DeltaS_(Surrounding)=(q_(1))(T_(1))+(q_(2))(T_(2)) (q term includes their own sign)  bc and da are adiabatics. Let dq_(1) be the heat supplied to the working system at T_(1) K and dq_(2) be heat rejected by it to the sink at T_(2) K. All these steps are reversible. In a Carnot cycle.  (dq_(1)-dq_(2))(dq_(1))=(T_(1)-T_(2))(T_(1)) or (dq_(1))(T_(1))=(dq_(2))(T_(2))  Let us now confine our attention only to the change of the system from point a to point c and attempt to find out the ratio of heat change to the temperature at which thermal changes occur by proceeding from a to c either along abc or adc.  Along the path abc (Heat change)(Temp.)=(dq_(1))(T_(1))  Along the path adc (Heat change)(Temp)=(dq_(2))(T_(2))  In case of spontaneous and irreversible expansion to volume V_(1)+V_(2) W=0 and so will be DeltaU  In the reversible expansion of the gas at T K from volume V_(1) to V_(1)+V_(2) heat absorbed DeltaU+RT ln (V_(1)+V_(2))(V_(1))  (v) Suppose n moles of an ideal gas are enclosed in a vessel A of volume V_(1) which is connected through a stop cock to a completely evacuated vessel B of volume V_(2). The system is insulated and has temperature T K.   If the stop cock is opened the gas will attain the volume V_(1)+V_(2).  In a reversible isothermal expansion of the gas at T K as shown in figure II the DeltaS_(system) DeltaS_(surroundings) and DeltaS_(universe) will be respectively ?

Accepted Answer

NA

Question 26

Entropy has great importance in thermodynamics. It is a state function and it is a measure of the degree of disorder or randomness of the system. More is the disorder of the system greater will be the entropy and vice versa. It is normally expressed in terms of change of entropy.  (i) For a reaction entropy change is given by DeltaS=sumS(product)-sumS(reactant)  (ii) DeltaS=(Q_(rev))(T)=(W_(rev))(T)=(nRT ln (V_(2)V_(1)))(T)  =nRT ln (V_(2))(V_(1))=nR ln (P_(1))(P_(2))  (iii) DeltaS=DeltaH-TDeltaS  (iv) Entropy change in reversible and irreversible process Consider a Carnot cycle as shown in figure below in which ab and cd are isothermal.   Irrespective of the path of the system in its reversible change dqT is same  For entire Carnot cycle  (dq_(1))(T_(1))-(dq_(2))(T_(2))=0  . DeltaS_(universe)=DeltsS_(system)+DeltaS_(surrounding)  DeltaS_(Surrounding)=(q_(1))(T_(1))+(q_(2))(T_(2)) (q term includes their own sign)  bc and da are adiabatics. Let dq_(1) be the heat supplied to the working system at T_(1) K and dq_(2) be heat rejected by it to the sink at T_(2) K. All these steps are reversible. In a Carnot cycle.  (dq_(1)-dq_(2))(dq_(1))=(T_(1)-T_(2))(T_(1)) or (dq_(1))(T_(1))=(dq_(2))(T_(2))  Let us now confine our attention only to the change of the system from point a to point c and attempt to find out the ratio of heat change to the temperature at which thermal changes occur by proceeding from a to c either along abc or adc.  Along the path abc (Heat change)(Temp.)=(dq_(1))(T_(1))  Along the path adc (Heat change)(Temp)=(dq_(2))(T_(2))  In case of spontaneous and irreversible expansion to volume V_(1)+V_(2) W=0 and so will be DeltaU  In the reversible expansion of the gas at T K from volume V_(1) to V_(1)+V_(2) heat absorbed DeltaU+RT ln (V_(1)+V_(2))(V_(1))  (v) Suppose n moles of an ideal gas are enclosed in a vessel A of volume V_(1) which is connected through a stop cock to a completely evacuated vessel B of volume V_(2). The system is insulated and has temperature T K.   If the stop cock is opened the gas will attain the volume V_(1)+V_(2).  In figure I which is a reversible cyclic process what will be the value of DeltaU DeltaH oint(dq)(T) respectively ?

Accepted Answer

NA

Question 27

Entropy has great importance in thermodynamics. It is a state function and it is a measure of the degree of disorder or randomness of the system. More is the disorder of the system greater will be the entropy and vice versa. It is normally expressed in terms of change of entropy.  (i) For a reaction entropy change is given by DeltaS=sumS(product)-sumS(reactant)  (ii) DeltaS=(Q_(rev))(T)=(W_(rev))(T)=(nRT ln (V_(2)V_(1)))(T)  =nRT ln (V_(2))(V_(1))=nR ln (P_(1))(P_(2))  (iii) DeltaS=DeltaH-TDeltaS  (iv) Entropy change in reversible and irreversible process Consider a Carnot cycle as shown in figure below in which ab and cd are isothermal.   Irrespective of the path of the system in its reversible change dqT is same  For entire Carnot cycle  (dq_(1))(T_(1))-(dq_(2))(T_(2))=0  . DeltaS_(universe)=DeltsS_(system)+DeltaS_(surrounding)  DeltaS_(Surrounding)=(q_(1))(T_(1))+(q_(2))(T_(2)) (q term includes their own sign)  bc and da are adiabatics. Let dq_(1) be the heat supplied to the working system at T_(1) K and dq_(2) be heat rejected by it to the sink at T_(2) K. All these steps are reversible. In a Carnot cycle.  (dq_(1)-dq_(2))(dq_(1))=(T_(1)-T_(2))(T_(1)) or (dq_(1))(T_(1))=(dq_(2))(T_(2))  Let us now confine our attention only to the change of the system from point a to point c and attempt to find out the ratio of heat change to the temperature at which thermal changes occur by proceeding from a to c either along abc or adc.  Along the path abc (Heat change)(Temp.)=(dq_(1))(T_(1))  Along the path adc (Heat change)(Temp)=(dq_(2))(T_(2))  In case of spontaneous and irreversible expansion to volume V_(1)+V_(2) W=0 and so will be DeltaU  In the reversible expansion of the gas at T K from volume V_(1) to V_(1)+V_(2) heat absorbed DeltaU+RT ln (V_(1)+V_(2))(V_(1))  (v) Suppose n moles of an ideal gas are enclosed in a vessel A of volume V_(1) which is connected through a stop cock to a completely evacuated vessel B of volume V_(2). The system is insulated and has temperature T K.   If the stop cock is opened the gas will attain the volume V_(1)+V_(2).  In irreversible cyclic process which of the following is correct ?

Accepted Answer

NA

Question 28

Entropy has great importance in thermodynamics. It is a state function and it is a measure of the degree of disorder or randomness of the system. More is the disorder of the system greater will be the entropy and vice versa. It is normally expressed in terms of change of entropy.  (i) For a reaction entropy change is given by DeltaS=sumS(product)-sumS(reactant)  (ii) DeltaS=(Q_(rev))(T)=(W_(rev))(T)=(nRT ln (V_(2)V_(1)))(T)  =nRT ln (V_(2))(V_(1))=nR ln (P_(1))(P_(2))  (iii) DeltaS=DeltaH-TDeltaS  (iv) Entropy change in reversible and irreversible process Consider a Carnot cycle as shown in figure below in which ab and cd are isothermal.   Irrespective of the path of the system in its reversible change dqT is same  For entire Carnot cycle  (dq_(1))(T_(1))-(dq_(2))(T_(2))=0  . DeltaS_(universe)=DeltsS_(system)+DeltaS_(surrounding)  DeltaS_(Surrounding)=(q_(1))(T_(1))+(q_(2))(T_(2)) (q term includes their own sign)  bc and da are adiabatics. Let dq_(1) be the heat supplied to the working system at T_(1) K and dq_(2) be heat rejected by it to the sink at T_(2) K. All these steps are reversible. In a Carnot cycle.  (dq_(1)-dq_(2))(dq_(1))=(T_(1)-T_(2))(T_(1)) or (dq_(1))(T_(1))=(dq_(2))(T_(2))  Let us now confine our attention only to the change of the system from point a to point c and attempt to find out the ratio of heat change to the temperature at which thermal changes occur by proceeding from a to c either along abc or adc.  Along the path abc (Heat change)(Temp.)=(dq_(1))(T_(1))  Along the path adc (Heat change)(Temp)=(dq_(2))(T_(2))  In case of spontaneous and irreversible expansion to volume V_(1)+V_(2) W=0 and so will be DeltaU  In the reversible expansion of the gas at T K from volume V_(1) to V_(1)+V_(2) heat absorbed DeltaU+RT ln (V_(1)+V_(2))(V_(1))  (v) Suppose n moles of an ideal gas are enclosed in a vessel A of volume V_(1) which is connected through a stop cock to a completely evacuated vessel B of volume V_(2). The system is insulated and has temperature T K.   If the stop cock is opened the gas will attain the volume V_(1)+V_(2).  In the figure-I what will be the value of (dq)(T) along the line bc ?

Accepted Answer

NA

Question 29

Entropy has great importance in thermodynamics. It is a state function and it is a measure of the degree of disorder or randomness of the system. More is the disorder of the system greater will be the entropy and vice versa. It is normally expressed in terms of change of entropy.  (i) For a reaction entropy change is given by DeltaS=sumS(product)-sumS(reactant)  (ii) DeltaS=(Q_(rev))(T)=(W_(rev))(T)=(nRT ln (V_(2)V_(1)))(T)  =nRT ln (V_(2))(V_(1))=nR ln (P_(1))(P_(2))  (iii) DeltaS=DeltaH-TDeltaS  (iv) Entropy change in reversible and irreversible process Consider a Carnot cycle as shown in figure below in which ab and cd are isothermal.   Irrespective of the path of the system in its reversible change dqT is same  For entire Carnot cycle  (dq_(1))(T_(1))-(dq_(2))(T_(2))=0  . DeltaS_(universe)=DeltsS_(system)+DeltaS_(surrounding)  DeltaS_(Surrounding)=(q_(1))(T_(1))+(q_(2))(T_(2)) (q term includes their own sign)  bc and da are adiabatics. Let dq_(1) be the heat supplied to the working system at T_(1) K and dq_(2) be heat rejected by it to the sink at T_(2) K. All these steps are reversible. In a Carnot cycle.  (dq_(1)-dq_(2))(dq_(1))=(T_(1)-T_(2))(T_(1)) or (dq_(1))(T_(1))=(dq_(2))(T_(2))  Let us now confine our attention only to the change of the system from point a to point c and attempt to find out the ratio of heat change to the temperature at which thermal changes occur by proceeding from a to c either along abc or adc.  Along the path abc (Heat change)(Temp.)=(dq_(1))(T_(1))  Along the path adc (Heat change)(Temp)=(dq_(2))(T_(2))  In case of spontaneous and irreversible expansion to volume V_(1)+V_(2) W=0 and so will be DeltaU  In the reversible expansion of the gas at T K from volume V_(1) to V_(1)+V_(2) heat absorbed DeltaU+RT ln (V_(1)+V_(2))(V_(1))  (v) Suppose n moles of an ideal gas are enclosed in a vessel A of volume V_(1) which is connected through a stop cock to a completely evacuated vessel B of volume V_(2). The system is insulated and has temperature T K.   If the stop cock is opened the gas will attain the volume V_(1)+V_(2).  Ethanol boils at 78.4^(@)C and standard enthalpy of vaporisation of ethanol is 42.4 kJmol. Calculate the enthropy of vaporisation of ethanol

Accepted Answer

NA

Question 30

Entropy has great importance in thermodynamics. It is a state function and it is a measure of the degree of disorder or randomness of the system. More is the disorder of the system greater will be the entropy and vice versa. It is normally expressed in terms of change of entropy.  (i) For a reaction entropy change is given by DeltaS=sumS(product)-sumS(reactant)  (ii) DeltaS=(Q_(rev))(T)=(W_(rev))(T)=(nRT ln (V_(2)V_(1)))(T)  =nRT ln (V_(2))(V_(1))=nR ln (P_(1))(P_(2))  (iii) DeltaS=DeltaH-TDeltaS  (iv) Entropy change in reversible and irreversible process Consider a Carnot cycle as shown in figure below in which ab and cd are isothermal.   Irrespective of the path of the system in its reversible change dqT is same  For entire Carnot cycle  (dq_(1))(T_(1))-(dq_(2))(T_(2))=0  . DeltaS_(universe)=DeltsS_(system)+DeltaS_(surrounding)  DeltaS_(Surrounding)=(q_(1))(T_(1))+(q_(2))(T_(2)) (q term includes their own sign)  bc and da are adiabatics. Let dq_(1) be the heat supplied to the working system at T_(1) K and dq_(2) be heat rejected by it to the sink at T_(2) K. All these steps are reversible. In a Carnot cycle.  (dq_(1)-dq_(2))(dq_(1))=(T_(1)-T_(2))(T_(1)) or (dq_(1))(T_(1))=(dq_(2))(T_(2))  Let us now confine our attention only to the change of the system from point a to point c and attempt to find out the ratio of heat change to the temperature at which thermal changes occur by proceeding from a to c either along abc or adc.  Along the path abc (Heat change)(Temp.)=(dq_(1))(T_(1))  Along the path adc (Heat change)(Temp)=(dq_(2))(T_(2))  In case of spontaneous and irreversible expansion to volume V_(1)+V_(2) W=0 and so will be DeltaU  In the reversible expansion of the gas at T K from volume V_(1) to V_(1)+V_(2) heat absorbed DeltaU+RT ln (V_(1)+V_(2))(V_(1))  (v) Suppose n moles of an ideal gas are enclosed in a vessel A of volume V_(1) which is connected through a stop cock to a completely evacuated vessel B of volume V_(2). The system is insulated and has temperature T K.   If the stop cock is opened the gas will attain the volume V_(1)+V_(2).  Which of the following statement is correct about entropy ?

Accepted Answer

NA

Question 31

Entropy decreases during

Accepted Answer

NA

Question 32

Entropy changes for the process H_(2)O_((l))rarrH_(2)O_((s)) at normal pressure and 274 K are given below DeltaS_(system)=-22.13 DeltaS_(surr)=+22.05the process is non-spontaneous because

Accepted Answer

NA

Question 33

Entropy changes for the process  H_(2)O(l) rarr H_(2)O(g)  at normal pressure and 274 K are given below Delta G_(system) = - 22.13 Delta S_(surroundings) = + 22.05  Then process is non spontaneous because

Accepted Answer

NA

Question 34

Entropy change in a process where 1 litre of liquid He is poured into ice cold water is

Accepted Answer

NA

Question 35

Entropy change for an isothermal expansion of one mole of an ideal gas from volume V_(1) to V_(2) is

Accepted Answer

NA

Question 36

Entropy change for an adiabatic reversible process is

Accepted Answer

NA

Question 37

Entropy change for an adiabatic reversible process is

Accepted Answer

NA

Question 38

Entries of Column-I are to be matched with entries of Coloumn-II. Each entry of Column-I may have the matching with one or more than one entries of Column-II.

Accepted Answer

NA

Question 39

Entries of Column-I are to be matched with entries of Coloumn-II. Each entry of Column-I may have the matching with one or more than one entries of Column-II.

Accepted Answer

NA

Question 40

Entries of Column-I are to be matched with entries of Coloumn-II. Each entry of Column-I may have the matching with one or more than one entries of Column-II. Column-I contains four statements following reason and Column-II consists of four options P Q R S  Answer the following  P-If both statement and reason are true and reason is correct explanation of statement.  Q-If both statement and reason are true and reason is not correct explanation of statement. R-If statement is correct and reason is incorrect.  S-If both statement and reason are incorrect.

Accepted Answer

NA

Question 41

Entries of Column-I are to be matched with entries of Coloumn-II. Each entry of Column-I may have the matching with one or more than one entries of Column-II.

Accepted Answer

NA

Question 42