Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Distinguish between absorption and adsorption.

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SOLUTION :
2.

Distinguish between (a) Ethanol and phenol (b) Phenol and acetic acid ( c) Phenol and ( d) Phenol and anisole.

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SOLUTION :
3.

Distinguish between A and B?c) Give two examples of crystals showing this defect.

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SOLUTION :fig.A-Ideal crystal.
Fig.B.-Frenkel DEFECT
4.

Distinguish betwee: (i) ethyl alcohol and acetaldehyde (ii) C_(6)H_(6)COCH_(3) and C_(6)H_(5)CH_(2)CHO

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Solution :(i) ADD Na metal, Ethyl alcohol gives `H_(2)` gas whereas ACETALDEHYDE does not react.
(ii) Add `I_(2)` and NaOH, acetophenone `(C_(6)H_(5)COCH_(3))` will give YELLOW PPT. of iodoform whereas `C_(6)H_(5)CH_(2)CHO` will not react.
5.

Distinction in 1-pentene and 1-pentyne is done by

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`[AG(NH_3)_2]^+`
CONC. `H_2SO_4`
HCL
`Br_2`

ANSWER :A
6.

Distinction of 1^(@), 2^(@) and 3^(@) alcohols is done by ______ test.

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LUCAS
VICTOR MEYER
Hoffmann
both (a) and ( C)

ANSWER :D
7.

Distinction between primary, secondary and tertiary alcohol is done by

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OXIDATION method
Lucas test
silver MIRROR test
both 'a' and 'b'

Answer :D
8.

Distillation under reduced pressure is used to purify liquids which :

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are HIGHLY volatile
have HIGH BOILING points
decompose below their boiling points
are explosives

Answer :C
9.

Distillation of sodium salt of benzoic acid with soda lime gives:

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Benzene
Toluene
Benzaldehyde
Xylene.

Answer :A
10.

Distillation of bleaching powder and acetone gives

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`CHCl_(3)`
CHLORAL
`CH_(3)Cl`
`C Cl_(4)`

SOLUTION :`CHCl_(3)`
11.

Distillation is used for the refining of:

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`FE`
`ZN`
`Zn`
`CU`

ANSWER :B
12.

Distillation of acetone with conc. sulphuric acid gives

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diacetone alcohol
mesityl oxide
mesitylene
propene-2-ol.

Solution :Distillation of ACETONE with CONC. `H_(2)SO_(4)` gives mesitylene.
`CH_(3)COCH_(3) UNDERSET("HEAT")overset(Conc. H_(2)SO_(4))to "Mesitylene"`
13.

Distillation involves all the following processes except :

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CHANGE of STATE
BOILING CONDENSATION
evaporation

Solution :N//A
14.

Dissymmetric molecule are those which, are

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NON SUPER IMPOSABLE MIRROR IMAGE
super imposable mirror image
plane of symmetry
plane of symmetry

Answer :A
15.

Dissoution of iodine crystals in carbon tetrachlorides solvent can be attributed to

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Hydeogen bonding between them
dipole-induced dipole interactin between them
London dispersion FORCE between them
Large molecular MASS of iodine and HENCE large van-der waals forces

Answer :C
16.

Dissolving metallic Zn in excess of NaOH produces :-

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NA2ZNO2
Zn(OH)2
ZNO
Zn(OH)2 & Na2ZnO2

SOLUTION :NAOH + Zn —` to` Na2ZnO2 + H2
17.

Dissolving NaCN in de-ionized water will result in a solution having

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`PHlt7`
`pH =7`
`POH =7`
`pH gt 7`

SOLUTION :Hydrolysisof NaOH
` NaCH +H_2 O hArrunderset("strong BASE ")(NaOH)+ underset("weak acid")(HCN)`
hencethe resulting solution will be BASIC:` pHgt 7`
18.

Dissolving NaCN in demonized water will result in a solution having

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pH>7
pH=7
pOH=7
pH<7

Solution :`CN^-+H_2O Such anionic hydrolysis MAKES the solution alkaline.
19.

Dissolving 120g of urea (mol.wt.60) in 1000g of water gave a solution of density 1.15 g/mL. The molarity of the solution is

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1.78 M
2.00 M
2.05 M
2.22 M

SOLUTION :Mole `=(120)/(60)=2`
mass of solution = 1120 g
`V=(1120)/(1.15xx100)=(112)/(115)L`
`M=(2xx115)/(112)=2.05` mol/litre
20.

Dissolving metallic zinc in access of NaOH produces:

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`Zn(OH)_2`
`Na_2ZnO_2`
ZnO
`Zn(OH)_2 and Na_2ZnO_2`

ANSWER :B
21.

Dissolving 120g of urea (mol wt = 60) in 1000g of water gave a solution of density 1.15 g/mL. The molarity of the solution is

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`1.78` M
`2.00` M
`2.05` M
`2.22` M

SOLUTION :VOLUME of solution=mass of solution `XX` DENSITY
22.

Dissolving 120 g of urca (mol . Wi 60) in 1000 gof water gave a solution of density 1.15 g/mL the molarity of the solution is

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`1.78` M
`2.00`M
`2.05` M
`2.22` M

SOLUTION :NUBER of MOLES of urea `= (120)/(60)=2`
Total mass of solution `=1000+120=1120g `
Total VOLUME of solution (in L) `= ("Mass)/("Density") =(1120)/(1.15xx10^(3))=(112)/(115)l.`
MOLARITY of the solution `= ("Number of moles")/("Volume of solution litre")=(2xx115)/(112) =2.05 mol L ^(-1)`
23.

Dissolved oxygen values of four water samples A,B,C and D are respectively 6 ppm, 5 ppm, 1 ppm and 3 ppm. Which is polluted?

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Solution :LESSER the DO VALUE GREATER the extent of pollution of water. THUS, C is the most polluted water sample.
24.

Dissolving 120 g of urea (molecular mass = 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is :

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`1.78 M`
`2.00 M`
`2.05 M`
`2.22 M`

Solution :Total MASS of solution
=1000+120=120=1120 g
Total VOLUME of solution
`="Mass"/"Density"=((1120g))/((1.15"g mL"^(-1)))`
=973.91.= mL
`"Molarity(M)"=("GRAM moles of solute")/("Volume of solution in liters")`
`=((120g//60"g MOL"^(-1)))/((973.91//1000L))=2.05 "mol L"^(-1)`
=2.05 M.
25.

Dissolved oxygen in water is needed only by aquatic animals and plants . Comments.

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Solution :DISSOLVED oxygen is not only NEEDED by aquatic flora and fauna but also makes fit for drinking.
26.

Dissolution of sugar being an endothermic reaction is favoured by :

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LOW T
High T
High P
Low P

Answer :B
27.

Dissolution of calcium chloride in water is exothermicprocess while that of ammonium nitrate is endothermic process, the observation is

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Solubility of CALCIUM chloridedecreases with increase in temperature and that of AMMONIUM nitrate increases with increase in temperature
Solubilities of both decreases with increase in temperature
Solubilities of both increases with increase in temperature
Solubilities of calcium CHLORIDE increases with increase in temperature and that of ammonium nitrate decrease with increase in temperature

Solution :For exothermic process increasing temperature , solubility decreases. For ENDOTHERMIC process increasing temperature, solubility increases.
28.

Dissolution of 1.28 g of sulphur in 50g of CS_(2) causes the freezingpoint of solvent to be lowered by 0.010^(@). If the sulphur molecule could be represented by S_(x) then x=_________(K_(f)=0.1 KKg "mol"^(-1))

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29.

Dissolution of a solute is an exothermic process if:

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HYDRATION ENERGY > Lattic energy
Hydration energy < Lattic energy
Hydration energy=Lattic energy
None

Answer :A
30.

Dissolution of a solute is an exothermic process if

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HYDRATION energy gt LATTICE energy
Hydrationenergy lt Lattice energy
Hydration energy = Lattice energy
None

Solution :`Delta H_("solution")= Delta H_("hydration") + Delta H_("latticeenergy")`
`Delta H_(H) = -ve``Delta H_(1) = + ve `
31.

Dissolution of 1.5g of a non-volatile solute (mol., wt. = 60) in 250 g of a solvent reduces its frezzing point by 0.01^(@)C . Find the molal depression constant of the solvent.

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`0.01`
`0.001`
`0.0001`
`0.1`

Solution :DEPRESSION in frezzing point ,
`Delta T_(f) = k_(f) xx m`
where , m= molality = `("WT. of solute" xx 1000)/("MOL. Wt. of solute") xx "wt. of solvent" `
`= (1.5 xx 1000)/(60 xx 250)`
`=0.1`
`IMPLIES Delta T_(f) = k_(f) xx 0.1`
`0.01 = k_(f) xx 0.1`
`therefore k_(f) = (0.01)/(0.1)`
`= 0.1 ^(@)C "molal"^(-1)`
32.

Dissociation of NH_(4)OH is decreased in presence of :-

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`CH_(3)COOH`
KOH
`HNO_(3)`
NONE of these

Answer :2
33.

Dissociation of H_(3)PO_(4) takes place in following steps

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1
2
3
4

Solution : `H_(3)PO_(4) OVERSET("I step")hArr H^(+) + H_(2)PO_(4)^(-)`
`H_(2)PO_(4)^(-) overset("II step")hArr + HPO_(4)^(--)`
`HPO_(4)^(--) overset("III step")hArr H^(+) + PO_(4)^(---)`
34.

Dissociation of H_(2)SO_(4) takes place during

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CHARGING of cell
discharging of cell
decomposition of cell
maintainance of the lead ACCUMULATOR

Solution :38% `H_(2)SO_(4)` with 1.2 g/ML density is used in lead accumulator.
`M=(W)/(m)xx(1000)/(100xxd)=(38)/(98)xx(1000)/(100xx1.2)=3.2 M`
35.

Dissociation of an indicator can be considered as Hln hArr H^(+)+ln^(-). Colour of Hln is P and ln^(-) is Q. Given the ratio of concentration of Hln to ln^(-) ranges from 10 to 1//10 then which of the following statements are correct.

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SOLUTION assumes P COLOUR, when `PH lepK_(ln-1)`
Solution assumes P colour, when `pH GE pH _(ln-1)`
Solution assumes Q colour , when `pH gepK_(ln-1)`
Solution assumes Q colour , when `pH lepK_(ln-1)`

Solution :MAXIMUM pH to see distinct colour is `pK_(ln-1)` and minimum pH to see a colour is `pK_(ln+1)`
36.

Dissociation of a salt A_(2)B_(3)(aq) in water follows first order kinetics in terms of concentration of [A_(2)B_(3)] as A_(2)B_(3)(aq)to2A^(+3)(aq)+3B^(2-)(aq). Starting from t=0, solution is taken out at different instant and its osmotic rise is measured. From the given data calculate abcd. ab=t_(3//4) of the dissociation of A_(2)B_(3) in water in minutes. cd= Osmotic pressure in Pascal after 20 min.density of solution is 1 g//mL. {:(,"Given data :",t=0,t=10 min,),(,"osmotic rise",2 mm,6 mm,):}

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ANSWER :2080
37.

Dissociation equilibrium constant of HI is 2.06xx10^(-2) at 458^(@)C. At equilibrium, concentrations of HI and I_(2) are 0.36M and 0.15M respectively. What is the equilibrium concentration of H_(2) at 458^(@)C.

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ANSWER :`[H_(2)]=1.78xx10^(-2)M`
38.

Dissociation constant of NH_4OH is 1.8xx10^-5 the hydrolysis constant of NH_4 CI would be

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`1.8xx10^(-19)`
`5.55xx10^(-10)`
`5.55xx10^(-5)`
`1.80xx10^(-5)`

ANSWER :B
39.

Dissociation constant of NH_4OH is 1.8 times 10^-5 the hydrolysis constant of NH_4Cl would be …….

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`1.8 TIMES 10^-19`
`5.55 times 10^-10`
`5.55 times 10^-5`
`1.80 times 10^-5`

SOLUTION :`K_h=K_w/K_b=(1.8 times10^-14)/(1.8 times10^-5)=0.55 times10^-9=5.5 times10^-10`
40.

Dissociation constant of a weak acid is decreased by

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Addition of a strong acid
Addition of a SALT of the above weak acid
Decreasing temperature
DILUTION of the solution

Solution :VALUE of dissociation constant 'K' of weak acid is constant at particular temperature. Hence, it DECREASES on decreasing the temperature and increases on INCREASING temperature.
41.

Displacementof the hydroxy1 group of alcohol can take place with variety of reagents. One such reaction is HBr+CH_(3) CH_(2)OH to CH_(3)CH_(2)Br+H_(2)O The above reaction has a two-step mechanism. (a) CH_(3)CH_(2)OH+H^(+)overset(k_(eq))(hArr) CH_(3)CH_(2)OH_(2)^(+) (b) CH_(3)CH_(2)OH_(2)^(+)+Br^(-) overset(k_(2))(to)CH_(3)CH_(2)Br+H_(2)O The slow and fast can be identified by the fact that rate of displacement of hydroxyl by halide ions depends on the type of halide ion . Calculate the rate of the formation of Ethyl Bromide when concentration of alcohol is 0.5 M and HBr is 10^(-1) M. Assume complete dissociation of HBr. Express your answer in terms of 10^(-6) M//sec. ["Given" : K_(eq) = 4M ^(-1)"and" K_(2) = 5xx10^(-2) M^(-1) sec^(-1)]

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ANSWER :1000
42.

Disproportionation raects w.r.t. Cl_(2) is

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`Cl_(2) + UNDERSET("(excess)")(NH_(3)) RARR`
` underset("(excess)")(Cl_(2)) + NH_(3) rarr`
`Cl_(2)+ H_(2) O rarr `
`Cl_(2) + O_(2) rarr`

SOLUTION :`3Cl_(2) + underset("(Excess)")(8NH_(3)) rarr N_(2) + 6 NH_(4) Cl , 3Cl_(2) + 4NH_(3) rarr NCl_(3) + 3NH_(4) Cl`
43.

Dispersion of tear gas happens during riots, the formula of tear gas is

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`COCl_2`
`C Cl_3NO_2`
`CHCl_2NO_2`
`CHCl_3`

ANSWER :B
44.

Dispersion force is present between :-

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POLAR + Polar molecules
NONPOLAR + Non-polar molecules
Polar + Nonpolar molecules
All of these

Answer :D
45.

Dispersed phase and dispersion medium are two phases of colloidal system. Name the colloid in which dispersed phase is liquid and dispersion medium is solid.

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Sol
Foam
Emulsion
Gel

Answer :A
46.

Disperse phase and the dispersion media in blood respectively are (M-2007)

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LIQUID, solid
Liquid, liquid
Solid, liquid
Solid, solid

Answer :C
47.

Disperse phase and dispersion medium in butter are respectively

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SOLID and liquid
liquid and solid
liquid and liquid
solid and solid

Solution :Disperse phase and DISPERSION MEDIUM in BUTTER are liquid and solid respectively.
48.

Disodium pentacyanonitrosyl ferratereagent gives purple colour when which of thefollowing element is present.

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`N`
`CL`
`F`
`S`

ANSWER :D
49.

Disodium hydrogen phosphate is used to test

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`Mg^(+2)`
`NA^(+)`
`CA^(+2)`
`Zn^(2+)`

ANSWER :A
50.

Disodiumhydrogen phosphate is used to test :

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`Na^(+)`
`CA^(2+)`
`MG^(2+)`
`CU^(2+) `

ANSWER :C