94420 + Interview Questions in Chemistry in Class 12

1.	Copper crystallises into a fcc lattice with edge length 3.61 xx 10^(-8) cm. Show that the calculated density is in agreement with its measured value of 8.92 g cm^(-8).
Answer» Solution :Apply the relation `d=(zxxM)/(a^(3)xxN_(A))`, SUBSTITUTE the values `d=(4xx63.5)/((3.61xx10^(-8))^(3)xx6.022xx10^(23))=8.97gcm^(-3)` The CALCULATED value `(8.97gcm^(-3))` is in reasonable agreement with the MEASURED value `8.92gcm^(-3)`.

Discussion

2.	Copper crystallises in fcc with a unit length of36lpm. What is the radius of copper atom ?
Answer» 157 pm 128 pm 108 pm 181 pm Solution :For fcc, `r=(sqrt(2)a)/(4)=(a)/(2sqrt(2))=0.3535a` GIVEN `a=3.61` pm `r=0.3535xx361` =128 pm

Discussion

3.	Coppercrystallisesin fcctypeunitcell. Theedgelengthof unitcell is360.8 pm . The densityof metalliccopperis8.92g cm^(-3) Determineatomicmass ofcopper.
Answer» Solution :63. 07 G `MOL^(-1)`

Discussion

4.	Copper crystallises in fcc lattice with a unit cell edge of 361 pm. The radius of copper atom is :
Answer» 108pm 128 PM 157 pm 181 pm SOLUTION :`4r = sqrt(2) a ` `R = ( sqrt( 2) a )/( 4) = ( sqrt( 2) XX 361 )/( 4) = ( 1.414 xx 361)/( 4)` `= 127.61~~ 128`pm

Discussion

5.	Copper crystallises in fcc with a unit cell length of 361 pm. What is the radius of copper atom?
Answer» 108 pm 127 pm 157 pm 181 pm Answer :B

Discussion

6.	Copper cannot replace__________from solution
Answer» FE Au Hg Ag Solution :Fe is PLACED above CU in ELECTROCHEMICAL SERIES.

Discussion

7.	Copper cannot replace ….. From solution:
Answer» Ag Hg Au Fe Answer :D

Discussion

8.	Copper can reduce zinc ions if the resultant copper ions can be kept at a sufficiently low concentration by the formation of an insoluble salt. What is the maximum concentration of Cu^(2+) in solution if this reaction is to occur, when Zn^(2+) is 1 molar?
Answer» Solution :`CU,Cu^(2+)\|\|ZN^(2+), Zn, E_(cell)=E_(RED)(Zn)-E_(red)(Cu)=0]` `6 times 10^-38 M`

Discussion

9.	Copper can be extracted from :
Answer» KUPFER - NICKEL DOLOMITE Malachite Galena Answer :C

Discussion

10.	Copper can be extracted by hydrometallurgy but not zinc. Explain why ?
Answer» ANSWER :`E_(2N^(2+))^(@) //2n=-ve, E_(CU^(+2))^(@) //cu=+ve`

Discussion

11.	Coppercan beextracted byhydrometallurgybut notzinc. Explain.
Answer» SOLUTION : The` E^(@)`of zinc `(Zn^(2+)//Zn =- 076V) `oriron` (Fe^( 2 + )//Fe= - 044V )`islower thanthatofcopper` (CU^( 2 +) //Cu =+ 0 * 34V) `and hencebothzinc andFe,can displaceCu from solutionsof` Cu^( 2 +) `ions . Although zincisastrongerreducingagentthaniron,yet ironscrapischiefly used in hydrometallurgyofcopperbecauseitis muchcheaperthanzinc. `""Fe (s)+Cu^( 2+) (aq)to Fe^(2+) (aq)+Cu (s)` Incontrast,todisplacezinc from solutionof `Zn ^( 2 +) ` ions, weneeda morereactivemetalthan it, i.e., ` Al( E ^(@)""_(Al^(3 + )//Al) =- 166V), Mg (E ^(@)""_(Mg^(2 + )//Mg)= -237V)`, `Ca (E^(@)""_(Ca^(2+)//Ca) =- 287V), K(E ^(@)""_(K^(+)//K) =- 293V)`,etc. Butall thesemetalsreact withwater `[ 2 H_2 O+2 e ^(-) toH_ 2 (g)+2O H^( -) (aq) ,E ^(@) =-0 *83 V ] `formingtheircorrespondingionswiththe evolutionof`H_2`gas. Thus, Al, Mg, etc.,cannotbeusedto displacezinc fromsolution of` Zn^(2+)`ions. Thus,coppercan beextracted by hydrometallurgy but notzinc.

Discussion

12.	Copper can be extracted by hydrometallurgy but not zinc. Explain.
Answer» SOLUTION :ZINC is more electropositive `(E^@ = - 0.76 V)` and therefore, is highly reactive METAL. Hence, it cannot be EASILY displaced from its solution of `ZnSO_4`. On the other hand, copper is less electropositive `(E^@ = + 0.34V)` and can be READILY displaced from its solution by some more active metal such as zinc.

Discussion

13.	Copper can be extracted by hydrometallurgy but not zinc. Explain?
Answer» SOLUTION :The `E^(ɵ)` of zinc `((ZN^(2+))/(Zn)=-0.76V)` or iron `((Fe^(2+))/(Fe)=-0.44V)` is less than that of copper `((Cu^(2+))/(Cu)=+0.34V)` and hence both zinc and iron can displace copper from solution of `Cu^(2+)` ions. Although zinc is a stronger reducing agent than iron, yet iron scrap is chiefly used in hydrometallurgy of copper because it is much cheaper than Zinc. `Fe+Cu^(2+)toFe^(2+)+Cu_(s)` In CONTRAST, to replace zinc from solution of `Zn^(2+)` ions, a more reactive METAL than zinc is required, i.e., Al or Ca. But all these METALS react with water `(2H_2O+2e^(ɵ)toH_(2(g))+2overset(ɵ)(O)H_(aq):E^@-0.83V)` Forming their corresponding ions with the evolutionsof hydrogen gas. Although Al, Mg etc. Cannot be used to displace zinc from solution of `ZN^(2+)` ions. Thus, copper, can be extracted by hydrometallurgy but not zinc.

Discussion

14.	Copper can be deposited from acidified copper sulphate and alkaline cuprous cyanide. If the samecurrent is passed for a definite time:
Answer» The AMOUNT of copper deposited from acidic copper sulphate will be HIGHER The amount of copper deposited from ALKALINE cuprous CYANIDE will be higher The same amount of copper will be deposited NONE of the above Answer :B

Discussion

15.	Copper can be deposited from acidified copper sulphate and alkaline cuprous cyanide . If the same current is passed for a definite time
Answer» the amount of copper DEPOSITED from acidic copper sulphate will be higher the amount of copper deposited from alkaline cuprous CYANIDE will be higher the same amount of copper will be deposited none Solution :In `CuSO_(4)` , change is `Cu^(2+) + 2e to Cu`, In CUCN , change is `Cu ^(+) + e to Cu`, Thus ` w alpha E_(Cu)` , which is more in CuCN.

Discussion

16.	Copper can be deposited from acidified copper sulphate and alkaline cuprous cyanide. If the same current is passed for a definite time :
Answer» The amount of copper deposited from acidic copper sulphate will be HIGHER. The amount of copper deposited from alkaline CUPROUS cyanide will be higher The same amount of copper will be deposited. None of these SOLUTION :Alkaline solution will keep `H^(o+)` low so that there is a very small concentration. Hence, chances of `H^(o+)` getting reduced to `H_(2)` along with `Cu` are LESSER in alkaline cuprous cyanide as compared to acidified copper sulphate.

Discussion

17.	Copper can be deposited from acidified copper sulphate and alkaline cuprous cyanide. If the same current is passed for a definite time:
Answer» The AMOUNT of COPPER deposited from ACIDIC copper sulphate will be higher The amount of copper deposited from alkaline cuprous cyanide will be higher The same amount of copper will be deposited None Answer :B

Discussion

18.	Copper belongs ot
Answer» CUBIC SYSTEM Tetragonal system monoclinicsystem Triclinic system Solution : Copper BELONGS to cubic system.

Discussion

19.	Copper atom has completely filled d-orbitals in its ground state but it is a transition element. Why ?
Answer» Solution :Copper EXHIBITS +2 oxidation state WHEREIN it has incompletely filled d-orbitals `(3d^(9)4s^(0))`. HENCE it is a transition ELEMENT.

Discussion

20.	Copper and silver lie low in the electrochemical series and yet they are found in the combined state as sulphides in nature. Comment.
Answer» Solution :(i) At HIGHER TEMPERATURE, the reaction between COPPER and sulphur BECOMES feasible. (ii) So they combine together and copper exists as copper sulphides in nature. (iii) Besides this due to high polarising power of copper and silver ions, their sulphides are more stable.

Discussion

21.	Copper atom has completely filled d-orbitals. How can it be considered as a d-block metal ?
Answer» Solution :Even THOUGH copper ATOM has `3d^(9)4s^(1)` configuration,cupric ion has `3d^(9) 4s^(0)`i.e. PARTIALLY filled d-orbitals

Discussion

22.	Copperand silver lie below in theelectrochemical series and yetthey are found in the combined state as sulphides in nature. Comment.
Answer» Solution :Dueothigh POLARISING power ofCuand AG IONS,theirsulphides are evenmorestablethan THEMETALS.

Discussion

23.	Copper and silver are below hydrogen in the electrochemical series and yet they are found in the combined state as sulphides. Comment.
Answer» Solution :COPPER and silver react with sulphur at HIGH temperature to form sulphides under earth.s crust, ALTHOUGH they are LESS REACTIVE than hydrogen.

Discussion

24.	Copolymerisation of 1,3,-butadiene and acrylonitrile gives :
Answer» PHBV Glyptal Buna-N Buna-S. Answer :C

Discussion

25.	Copolymer.
Answer» SOLUTION :A polymer made from two or more different monomerunits is CALLED a COPOLYMER. Examples : Nylon - 6, 6, Buna - S, Buna - N, ETC.

Discussion

26.	Coplex ion [CuCl_(2)(NH_(2)CoNH_(2)] is named as
Answer» dichloro BIS (UREA) COPPER (II) bis (urea) dichloro copper (II) dichloro bis (urea) copper (I) bis (urea) dichloro copper (I) Answer :A

Discussion

27.	Cope elimination is an intramolecular, E_(2) reaction because
Answer» It is given by TERTIARY AMINE It is given by tertiary amine OXIDE containing `beta`- hydrogen The nucleophile and leaving GROUP are in the same molecule The less substituted ALKENE is the major product. Answer :C

Discussion

28.	Cope elimination
Answer» is a syn ELIMINATION reaction It is given by tertiary amine OXIDE containing `beta`- hydrogen is INTRAMOLECULAR `E_(2)` reaction follows all the above facts. Answer :D

Discussion

29.	Coordination number, oxidation state and number of isomers in K_(3)[Cr(C_(2)O_(4))_(3)] are respectively :
Answer» 6, `+3`, 2 4, `+2` and 2 3, `+3`, 3 3, 0 and 3 Solution :`OVERSET(+3)K_(3)[overset(+3)Cr(C_(2)overset(-6)O_(4))_(3)]` `IMPLIES C.N.= 6, O.S. = +3, M(A A)_(3)(Op. active) = 2`

Discussion

30.	Coordination number of Fe in Haemoglobin is
Answer» Solution :In Hb, FE gets SURROUNDED by 6 nitrogen ATOMS.

Discussion

31.	Coordination number of Fe in [Fe(C_(2)O_(4))_(3)]^(3-) is
Answer» 6 5 4 3 Answer :A

Discussion

32.	Coordination number of Cris six. A complex ion of Cr with C_(2)O_(4)^(2-), en and superoxide ion O_(2)^(-) has the formula [Cr(C_(2)O_(4))x(en)_(y)(O_(2))_(z)]^(-). The ratio x : y : z will be
Answer» `1 : 1 : 1` `1 : 1 : 2` `1 : 2 : 2` `2 : 1 : 1` Solution :x : y : Z should be such that total CHARGE =-1 (i.e. charge on the complex ION). For (a) total charge = + 3 + 1 (-2) + 1(0) + 1 (-1)=0 For (b), Total charge = + 3 + 1 (-2) + 1 (0) + 2 (-1) =-1.

Discussion

33.	Coordination number of Co in [Co(F)_(6)]^(3-)
Answer» `3` `6` `8` `9` Answer :B

Discussion

34.	The coordination number of a central metal atom in a complex is determined by
Answer» the number of ligands around a metal ION BONDED by DATIVE bonds he number of only anionic ligands bonded to the metal ion the number of ligands around a metal ion bonded by ionic bonds the number of ligands around a metal ion bonded by covalent bonds Answer :A

Discussion

35.	Coordination number for Cu is
Answer» 1 6 8 12 Answer :D

Discussion

36.	Coordination number and oxidation state of Cr in K_(3)[Cr(C_(2)O_(4))_(3)]are respectively :
Answer» 6 and +3 3 and 0 4 and +2 3 and +3. Answer :A

Discussion

37.	Coordination numbe of Ni in [Ni(C_(2)O_(4))_(3)]^(4-) is :
Answer» 3 6 4 2 Solution :COORDINATION NUMBER of NICKEL in `[Ni(C_(2)O_(4))_(3)]^(4-)` is 6 bcause `C_(2)O_(4)^(2-)` is a bidentate ligand.

Discussion

38.	Coordination isomerism.
Answer» Solution :The phenomenon of isomerism in the ionic coordination compounds having the same molecular formula but DIFFERENT complex IONS involvingthe interchange of ligands between cationic and anionic entities of different metal ions is CALLED coordination isomerism.

Discussion

39.	Coordination isomerism is exhibited by
Answer» `[Cr(H_2O)_6]Cl_3` `[Cr(NH_3)_6][CO(CN)_6]` `[Cr(en)_2]NO_2` `[NI(NH_3)_6][BF_4]_2` Answer :B

Discussion

40.	Coordination compounds used in the estimation of hardness of water.
Answer» SOLUTION :(1) The HARDNESS of water is due to the pressnce `MG^(2+)andCa^(2+)` ion in water. (2) The strong field ligand EDTA form stable complexes with `Mg^(2+)andCa^(2+)`. Hence these ions can be removed by adding EDTA to hard water. Similarly, these ions can be SELECTIVELY estimated due to the difference in their STABILITY constants.

Discussion

41.	coordination compounds often show various types of isomerism. The isomerism can be categorized in two main types (a) structural isomerism (b) stereo or space isomerism Structural isomerism arises due to the difference in structures of coordination-sempounds while stereo or space isomerism arises on account of the different positions and arrangements of ligands (atoms or groups) in space around the metal lonStructural isomerism can be classified in following types (i) tonization isomers- which give different ions in solution, e.g. [CoBr(NH_(3))_(5)]]SO_(4) and [Co(SO_(4))_(5)(NH_(3))_(5)]Br Hydrate isomers which differ in H_(2)O as ligand or as hydration, e.g. [Cr(H_(2)O)_(5)]CI_(2)(H_(2)O)]Cl_(2).H_(2)O[CrCl_(2)(H_(2)O)]CI.2H_(2)O (iii) Linkage isomers, which differ in atom linked to 'metal atom, e.g. [CO(NO_(2))(NH_(3))_(5)]^(2+)andCO(ONO)(NH_(3))_(6)]^(2+) Coordination isomers- which involve interchange of ligands, e.g. [Co(NH_(3))_(6)] [Cr(CN)_(6)] and[Cr(NH_(3))_(6)] [Co(CN)_(6)] (v) Coordination position isomerism-which arises in the bridged complexes due to the difference in the attachment of ligands with the metal atomsQThe total number of possible isomers for the complex compound [Cu^(ll)(NH_(3))_(4)] [Pt^(ll)Cl_(4)are
Answer» 3 6 4 5 Answer :D

Discussion

42.	coordination compounds often show various types of isomerism. The isomerism can be categorized in two main types (a) structural isomerism (b) stereo or space isomerism Structural isomerism arises due to the difference in structures of coordination-sempounds while stereo or space isomerism arises on account of the different positions and arrangements of ligands (atoms or groups) in space around the metal lonStructural isomerism can be classified in following types (i) tonization isomers- which give different ions in solution, e.g. [CoBr(NH_(3))_(5)]]SO_(4) and [Co(SO_(4))_(5)(NH_(3))_(5)]Br Hydrate isomers which differ in H_(2)O as ligand or as hydration, e.g. [Cr(H_(2)O)_(5)]CI_(2)(H_(2)O)]Cl_(2).H_(2)O[CrCl_(2)(H_(2)O)]CI.2H_(2)O (iii) Linkage isomers, which differ in atom linked to 'metal atom, e.g. [CO(NO_(2))(NH_(3))_(5)]^(2+)andCO(ONO)(NH_(3))_(6)]^(2+) Coordination isomers- which involve interchange of ligands, e.g. [Co(NH_(3))_(6)] [Cr(CN)_(6)] and[Cr(NH_(3))_(6)] [Co(CN)_(6)] (v) Coordination position isomerism-which arises in the bridged complexes due to the difference in the attachment of ligands with the metal atomsQThe compounds [Cr(H_(2)O_(6))Cl_(3)[Cr(H_(2)O)_(5)CI]Cl_(2).H_(2)O and [Cr(H_(2)O)_(4),CI_(2)]CI2H_(2)O exhibit
Answer» LINKAGE isomerism geometrical isomerism ionisation isomerism hydrate isomerism Answer :D

Discussion

43.	coordination compounds often show various types of isomerism. The isomerism can be categorized in two main types (a) structural isomerism (b) stereo or space isomerism Structural isomerism arises due to the difference in structures of coordination-sempounds while stereo or space isomerism arises on account of the different positions and arrangements of ligands (atoms or groups) in space around the metal lonStructural isomerism can be classified in following types (i) tonization isomers- which give different ions in solution, e.g. [CoBr(NH_(3))_(5)]]SO_(4) and [Co(SO_(4))_(5)(NH_(3))_(5)]Br Hydrate isomers which differ in H_(2)O as ligand or as hydration, e.g. [Cr(H_(2)O)_(5)]CI_(2)(H_(2)O)]Cl_(2).H_(2)O[CrCl_(2)(H_(2)O)]CI.2H_(2)O (iii) Linkage isomers, which differ in atom linked to 'metal atom, e.g. [CO(NO_(2))(NH_(3))_(5)]^(2+)andCO(ONO)(NH_(3))_(6)]^(2+) Coordination isomers- which involve interchange of ligands, e.g. [Co(NH_(3))_(6)] [Cr(CN)_(6)] and[Cr(NH_(3))_(6)] [Co(CN)_(6)] (v) Coordination position isomerism-which arises in the bridged complexes due to the difference in the attachment of ligands with the metal atomsQcoordinate isomerism 33. How many hydrate isomers are possible with the formulae CrC_(3)6H_(2)O
Answer» Six Four Three Two ANSWER :C

Discussion

44.	coordination compounds often show various types of isomerism. The isomerism can be categorized in two main types (a) structural isomerism (b) stereo or space isomerism Structural isomerism arises due to the difference in structures of coordination-sempounds while stereo or space isomerism arises on account of the different positions and arrangements of ligands (atoms or groups) in space around the metal lonStructural isomerism can be classified in following types (i) tonization isomers- which give different ions in solution, e.g. [CoBr(NH_(3))_(5)]]SO_(4) and [Co(SO_(4))_(5)(NH_(3))_(5)]Br Hydrate isomers which differ in H_(2)O as ligand or as hydration, e.g. [Cr(H_(2)O)_(5)]CI_(2)(H_(2)O)]Cl_(2).H_(2)O[CrCl_(2)(H_(2)O)]CI.2H_(2)O (iii) Linkage isomers, which differ in atom linked to 'metal atom, e.g. [CO(NO_(2))(NH_(3))_(5)]^(2+)andCO(ONO)(NH_(3))_(6)]^(2+) Coordination isomers- which involve interchange of ligands, e.g. [Co(NH_(3))_(6)] [Cr(CN)_(6)] and[Cr(NH_(3))_(6)] [Co(CN)_(6)] (v) Coordination position isomerism-which arises in the bridged complexes due to the difference in the attachment of ligands with the metal atomsQThe pair [CO(NH_(3))_(5)NO_(3)]SO_(4) and [CO(NH_(3))SO_(4)]NO_(3) will exhibit
Answer» HYDRATE isomerism linkage isomerism jonization isomerism COORDINATE isomerism ANSWER :C

Discussion

45.	coordination compounds often show various types of isomerism. The isomerism can be categorized in two main types (a) structural isomerism (b) stereo or space isomerism Structural isomerism arises due to the difference in structures of coordination-sempounds while stereo or space isomerism arises on account of the different positions and arrangements of ligands (atoms or groups) in space around the metal lonStructural isomerism can be classified in following types (i) tonization isomers- which give different ions in solution, e.g. [CoBr(NH_(3))_(5)]]SO_(4) and [Co(SO_(4))_(5)(NH_(3))_(5)]Br Hydrate isomers which differ in H_(2)O as ligand or as hydration, e.g. [Cr(H_(2)O)_(5)]CI_(2)(H_(2)O)]Cl_(2).H_(2)O[CrCl_(2)(H_(2)O)]CI.2H_(2)O (iii) Linkage isomers, which differ in atom linked to 'metal atom, e.g. [CO(NO_(2))(NH_(3))_(5)]^(2+)andCO(ONO)(NH_(3))_(6)]^(2+) Coordination isomers- which involve interchange of ligands, e.g. [Co(NH_(3))_(6)] [Cr(CN)_(6)] and[Cr(NH_(3))_(6)] [Co(CN)_(6)] (v) Coordination position isomerism-which arises in the bridged complexes due to the difference in the attachment of ligands with the metal atomsQ Which of the following coordination compounds, exhibits ionization isomerism
Answer» `[Cr(NH_(3))_(6)]Cl_(3)`<BR>`[Cr(ox)_(3)]^(3-)` `(Cr(en)_(3)]CI_(3)` `(Cr(NH_(3))_(5)Br]SO_(4)` Answer :D

Discussion

46.	Coordination compounds in the extraction of metals.
Answer» Solution :The technique of formation of a coordination compound is widely used in the extraction of noble metals like silver and gold. (2) In the extraction of silver, the finely powdered ore is treated with dilute solution of a complexing reagent NaCN which FORMS a solution cyano complex with silver `NA[AG(CN)_(2)]` which PASSES into the solution. (3) This solution is then treated with more electropositive zinc which displaces `Ag^(+)` from hte complex. `Ag_(2)S+4NaCNhArrunderset("sodium dicyanoargentate")(2Na[(Ag(CN)_(2)]+NaS` `2Na[Ag(CN)_(2)]+Zntounderset("Sodium tetracyanozincate(II)")(Na_(2)[Zn(CN)_(4)+2Agdarr`

Discussion

47.	Coordination compounds in (i) Medicine and (ii) Electroplating.
Answer» Solution :(i) Medicine : The complexes are used on a large scale in medicine. Many medicines in the complex FORM are more stable, more efferctive and can be assimiltated easily. For example, platinum complex `[PT(NH_(3))_(2)Cl_(2)]` Known as CISPLATIN by haevy metals like lead. (ii) Electroplating : This involves depoistion of a metal on the other metal. For SMOOTH plating, it is necessary to supply continuously the metal ions in small amounts. For this purpose, a solution of a coordination COMPOUND is used which dissociates to a very less extent. For example for uniform and thin plating of silver and gold, the complexes `K[Ag(CN)_(2)]andK[(Au(CN)_(2)]` are used.

Discussion

48.	Coordination compounds have great importance in biological systems. In this context which of the following statements is incorrect?
Answer» Carboxypeptidase-A is an ennzyme and CONTAINS zinc Haemoglobin is the red PIGMENT of blood ANND contains iron Cyanocobalamin is `B^(12)` and contains cobalt Chlorophylls are green pigments in plants and contains calcium Answer :D

Discussion

49.	Coordination compounds find applications in electroplating, textile dyeing and medicinal chemistry.
Answer» ANSWER :1

Discussion

50.	Coordination compounds?
Answer» Solution :The coordination COMPOUNDS have the following important applications : (1) In the extraction of the metals. (2) In analytical chemistry for quantitiative and qualitative ANALYSIS. (3) They have biological IMPORTANCE in plants and animals. (4) In medicine. (5) In electroplating. (6) For ESTIMATION of HARDNESS of water.

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Copper crystallises into a fcc lattice with edge length 3.61 xx 10^(-8) cm. Show that the calculated density is in agreement with its measured value of 8.92 g cm^(-8).

Copper crystallises in fcc with a unit length of36lpm. What is the radius of copper atom ?

Coppercrystallisesin fcctypeunitcell. Theedgelengthof unitcell is360.8 pm . The densityof metalliccopperis8.92g cm^(-3) Determineatomicmass ofcopper.

Copper crystallises in fcc lattice with a unit cell edge of 361 pm. The radius of copper atom is :

Copper crystallises in fcc with a unit cell length of 361 pm. What is the radius of copper atom?

Copper cannot replace__________from solution

Copper cannot replace ….. From solution:

Copper can reduce zinc ions if the resultant copper ions can be kept at a sufficiently low concentration by the formation of an insoluble salt. What is the maximum concentration of Cu^(2+) in solution if this reaction is to occur, when Zn^(2+) is 1 molar?

Copper can be extracted from :

Copper can be extracted by hydrometallurgy but not zinc. Explain why ?

Coppercan beextracted byhydrometallurgybut notzinc. Explain.

Copper can be extracted by hydrometallurgy but not zinc. Explain.

Copper can be extracted by hydrometallurgy but not zinc. Explain?

Copper can be deposited from acidified copper sulphate and alkaline cuprous cyanide. If the samecurrent is passed for a definite time:

Copper can be deposited from acidified copper sulphate and alkaline cuprous cyanide . If the same current is passed for a definite time

Copper can be deposited from acidified copper sulphate and alkaline cuprous cyanide. If the same current is passed for a definite time :

Copper can be deposited from acidified copper sulphate and alkaline cuprous cyanide. If the same current is passed for a definite time:

Copper belongs ot

Copper atom has completely filled d-orbitals in its ground state but it is a transition element. Why ?

Copper and silver lie low in the electrochemical series and yet they are found in the combined state as sulphides in nature. Comment.

Copper atom has completely filled d-orbitals. How can it be considered as a d-block metal ?

Copperand silver lie below in theelectrochemical series and yetthey are found in the combined state as sulphides in nature. Comment.

Copper and silver are below hydrogen in the electrochemical series and yet they are found in the combined state as sulphides. Comment.

Copolymerisation of 1,3,-butadiene and acrylonitrile gives :

Copolymer.

Coplex ion [CuCl_(2)(NH_(2)CoNH_(2)] is named as

Cope elimination is an intramolecular, E_(2) reaction because

Cope elimination

Coordination number, oxidation state and number of isomers in K_(3)[Cr(C_(2)O_(4))_(3)] are respectively :

Coordination number of Fe in Haemoglobin is

Coordination number of Fe in [Fe(C_(2)O_(4))_(3)]^(3-) is

Coordination number of Cris six. A complex ion of Cr with C_(2)O_(4)^(2-), en and superoxide ion O_(2)^(-) has the formula [Cr(C_(2)O_(4))x(en)_(y)(O_(2))_(z)]^(-). The ratio x : y : z will be

Coordination number of Co in [Co(F)_(6)]^(3-)

The coordination number of a central metal atom in a complex is determined by

Coordination number for Cu is

Coordination number and oxidation state of Cr in K_(3)[Cr(C_(2)O_(4))_(3)]are respectively :

Coordination numbe of Ni in [Ni(C_(2)O_(4))_(3)]^(4-) is :

Coordination isomerism.

Coordination isomerism is exhibited by

Coordination compounds used in the estimation of hardness of water.

Coordination compounds in the extraction of metals.

Coordination compounds in (i) Medicine and (ii) Electroplating.

Coordination compounds have great importance in biological systems. In this context which of the following statements is incorrect?

Coordination compounds find applications in electroplating, textile dyeing and medicinal chemistry.

Coordination compounds?